btl ctb1_ nguyen the quang

BTL cng trnh bn I

B mn CTGTTP&CTT

BI TP LN CNG TRNH BN IGio vin hng dn: V Minh Tun Sinh vin thc hin : Nguyn Th Quang Lp : Cng trnh GT Thy K47

A. S LIU U VOThit k k thut cng trnh bn tng c thp mt tng neo phc v cho tu ch du 10000T da trn cc s liu sau y: 1. Tu thit k Lng r Trng ti Chiu di B rng Mn nc Mn nc nc y hng khng hng D (tn) G (tn) L (m) B(m) T max (m) min T min (m) 10000 7200 130 18,4 6,8 2,5 2. S liu a cht c im a cht ca nn t c th hin nh sau: Lp 1: =1,73 (t/m ), =10 ( 0 ), C=1,1 (t/m 2 ), e=0,9 , h=2,6 (m). =1,8 (t/m ), =24 ( 0 ), C=0 (t/m 2 ), lp 2: e=0,98 , h=6,5(m), =1,68 (t/m ), =19 ( 0 ), C=1,1 (t/m 2 ), lp 3: e=1,0 , h= (m) 3. S liu thy hi vn - MNCTK ng tn sut 1 % +3,95 m - MNTTK ng tn sut 99% +0,9 m - MNTB ng tn sut 50% +2,2 m - MN thi cng ly bng MNTB +2,2 m 4. S liu kh tng - Tc dng chy dc theo thnh tu: V t =1,1 (m/s) - Tc dng chy vung gc vi tu: V 1 =0,3 (m/s) 1 - Tc gi tnh ton theo phng ngang tu: V n =18 (m/s) n - Tc gi tnh ton theo phng dc tu: V d =18 (m/s) 0 iu kin sng: khng c 5. S liu ti trng trn mt - Ti trng phn b q 0 =1,6 (t/ m 2 ), - Cn trc c: s lng truc: 2 S bnh trn cm: 6 Ti trng trn mt bnh: 18,5T Khong cch gia cc bnh: 0,7 m3 3 3

Sinh vin: Nguyn Th Quang_CTT K47

1

BTL cng trnh bn I

B mn CTGTTP&CTT

B. NI DUNG THIT K CHNG 1: CC THNG S C BN CA BN1.1. CAO TRNH MT BNTnh theo tiu chun chnh: CTMB = MNCN + a Trong : a l vt cao mt bn ly a = 2 m : CTMB = + 2,2 + 2 = +4,2 m Tnh theo tiu chun kim tra: CTMB = MNCTK + a , : CTMB = +3,95 + 1 = +4,95 m Chn CTMB = +5 m

(Ly a = 1m )

1.2. CAO TRNH Y BNTra cc h s theo tiu chun 22TCN 207-92 ta c: Z 0 = 0,026B = 0,026x 18,4 = 0,4784 m Z 1 = 0,06T = 0,06 x 6,8 = 0,408 m Z2 = 0 Z 3 = 0,3 m Z 4 = 0,4 m H ct = T + Z 0 + Z 1 + Z 2 + Z 3 = 6,8 + 0,4784 + 0,408 + 0 + 0,3= 7,9864 m H 0 = H ct + Z 4 = 7,9864 + 0,4 = 8,3864 m CTDB = +0,9 8,3864 = -7,4864 m Chn CTDB = -7,5 m Chiu cao bn l: H=CTMB CTDB = +5-(-7,5) = +12,5 m

1.3. CHIU DI BNL b = L t + l Tu di 130m (100 150) m 2 l =15 m L b =130+15=145 m Chn L b =150m v chia lm 5 phn on,mi phn on di 30m.

1.4. LA CHN KT CU BN1.4.1. Phn tch cc yu t nh hng n vic la chn kt cu bn. Da vo c im a cht,ta trng tc dng,loi tu thit k,ta la chn kt cu bn kiu tng c thp,loi c LarsenIV.Pha sau tng lp hc gim ti kt hp vi tng lc ngc v pha trn cng ct ht th. 1.4.2. M t kt cu bn. Kt cu bn c m t nh hnh 1.1 di y:


2

BTL cng trnh bn I

B mn CTGTTP&CTT

Hnh 1.1. Kt cu bn

CHNG 2: TI TRNG TC DNG LN CNG TRNH2.1. TI TRNG V TC NG DO TU2.1.1. Cc s liu tnh ton 2.1.1.1. S liu v tu Tu ch du 10000 T vi kch thc LxBxT = 130x18,4x6,8 m 2.1.1.2.S liu v dng chy Vn tc dng chy dc theo thnh tu : V doc =1,1m/s Din tch cn nc theo hng ngang ca tu: A 1 =TxL( m 2 ) y hng: A 1 = 6,8x130=884 m 2 Khng hng: A 1 =2,5x130=325 m 2 Din tch cn nc theo hng dc ca tu: A t =TxB ( m 2 ) y hng: A t =6,8x18,4=125,12 ( m 2 ) Khng hng: A t =2,5x18,4=46 ( m 2 ) 2.1.1.3.S liu v gi Vn tc ca gi theo phng ngang tu: V q =18 m/s Vn tc ca gi theo phng dc tu: V n =18m/s 2.1.1.4. Chn m tu


3

BTL cng trnh bn I

B mn CTGTTP&CTT

Theo bng 1 tiu chun 22TCN222_95.c trng ca cc loi m tu ta chn: Loi m V1000H c: Vt liu l cao su hnh thang rng Phng php treo: lin kt cng bng bu lng c vt vi dm m Khong cch cc m theo chiu dc bn l 4m Kch thc : L=3m, H=0,8m, D=1000mm Dung nng bin dng: E l =78 kj Bng 2.1. Kt qu x l cc s liu: Yu t n v Gi tr Vn tc gi theo hng ngang m/s 18 Vn tc gi theo hng dc m/s 18 2 Din tch cn gi theo hng ngang Aq y hng m 960 2 Din tch cn gi theo hng ngang Aq khng hng m 1640 2 Din tch cn gi theo hng dc An y hng m 310 2 Din tch cn gi theo hng dc An khng hng m 410 Vn tc dng chy theo hng ngang tu m/s 0,3 Vn tc dng chy theo hng dc tu m/s 1,1 Din tch cn nc theo hng ngang A1 y hng m2 884 Din tch cn nc theo hng ngang A1 khng hng m2 325 2 Din tch cn nc dc At y hng m 125,12 2 Din tch cn nc dc At khng hng m 46 2.1.2. Ti trng do neo tu 2.1.2.1. Ti trng do gi tc dng ln tu Ti trng do gi tc dng ln tu,hng gi tc dng theo hng vung gc vi mp bn c tnh: W q =73,6x10 5 xA q x V q 2 x (KN) W n =73,6x10 5 xA n x V n 2 x (KN) Trong : V n = V q =18 m/s; : h s ph thuc kch thc nm ngang ln nht ca mt cn gi theo hng ngang v dc tu.Tra bng 26_66_22TCN_222_95 v ni suy ta c: =0,605 A n , A q :tra bng ph lc 4 _22TCN222_95 - Khi y hng: W q = 73,6x10 5 x 960x18 2 x0,605=138,5 (KN) W n =73,6x10 5 x 310x18 2 x0,605=29,78 (KN) - Khi khng hng: W q =73,6x10 5 x1640x18 2 x0,605=236,6 (KN) W n =73,6x10 5 x410x 18 2 x0,605=39,38 (KN) 2.1.2.2. Ti trng do dng chy tc dng ln tu Hng dng chy theo phng dc tu c tnh theo cng thc: N w =0,59x A t x V 1 2 (KN) Sinh vin: Nguyn Th Quang_CTT K474

BTL cng trnh bn I

B mn CTGTTP&CTT

Q w =0,59xA 1 xV t 2 (KN) Trong : A t ,A 1 : Din tch chn nc theo hng dc v ngang tu (m 2 ) V t , V 1 : Thnh phn dc v ngang ca lu tc dng chy tnh ton(m/s) - Khi y hng: N w =0,59x125,12x0,3 2 =6,644 (KN) Q w =0,59x884x1,1 2 =631,1 (KN) - Khi khng hng: N w =0,59x46x0,3 2 =2,443 (KN) Q w =0,59x325x1,1 2 =232,02 (KN) Bng 2.2. Kt qu tnh ton do gi v ti trng tc dng ln tu. Trng hp y hng Khng hng Hng ngang (KN) 769,6 468,62 Hng dc (KN) 36,424 41,823

2.1.3 Ti trng do va tu ng nng ca tu c tnh theo cng thc: E q = ( .D.v 2 )/2 (KJ) =0,5 Ta c :D= 10000T, v= 0,13 , V: tra bng 29_22TCN222_95 : tra bng 30_22TCN222_95 E q = 0,5x10000x0,13 2 /2=42,25 (KJ) T E q tra biu ta c phn lc khi tu va vo cng trnh bn l: F q = 225(KN) Thnh phn song song mp bn F n (KN) ca lc va tu khi tu cp vo cng trnh c xc nh: F n = xF q =0,5 nn : F n = 0,5x 225= 112,5 (KN) 2.1.4 Ti trng do ta tu Ti trng phn b q (KN/m) do tu dang neo u bn ta ln cng trnh di tc ng ca gi,dng chy c xc nh theo cng thc:q = 1,1. Qtot ld

Q tot : lc tng cng do gi,sng,dng chy tc ng ln 1 tu tnh ton Q tot =29,78+236,6=266,38 (T) l d : chiu di on tip xc gia tu v cng trnh bn (tra TC) l d = 28m < l b =150m l=28m q = 1,1. Qtot 266,38 = =9,51 (KN/m) ld 28

2.1.5 Ti trng tc dng do lc ko ca cc dy neo


5

BTL cng trnh bn I

B mn CTGTTP&CTT

Ti trng ko ca cc dy neo phi xc nh bng cch phn phi cc thnh phn vung gc vi mp bn ca lc ngang cho cc bch neo (hoc cc vng neo).Lc ngang do gi v dng chy tc dng ln tu. Vi L t = 150m ta chn s bch neo lm vic l: 5. khong cch nh nht gia cc bch neo l 35m. Lc neo S (KN)tc dng ln 1 bich neo l: S = - Khi tu y hng:0

= 30 , =20 138,5 + 631,1 S= = 327, 6( KN ) 5.sin 300.cos200 - Khi tu khng hng: = 30 0 , =40 0 236, 6 + 232, 02 S= = 244, 7( KN ) 5.sin 300.cos400 So snh kt qu, ta thy rng tu y hng c lc neo ln hn khi khng neo hng. Nn ta chn S=327,6 KN tnh ton. Hnh chiu ca lc neo S ln cc phng vi mp bn l: - Theo phng vung gc vi mp bn l: Q 236, 6 + 232, 02 S q = tot = = 93, 7( KN ) n 5 - Theo phng song song vi mp bn l: S n = S .cos .cos = 327, 6.cos300 cos400 = 217,3( KN ) - Theo phng thng ng: Sv = S .sin = 327, 6.sin 400 = 210, 6( KN )0

n.sin .cos

Q

tot

S

v

S Sn

a S

q

Hnh 2.1.S phn phi lc neo trn mt bch neo

2.2. TI TRNG DO THIT B, HNG HA TRN MT BNSinh vin: Nguyn Th Quang_CTT K476

BTL cng trnh bn I

B mn CTGTTP&CTT

2.2.1.S tnh: H s p lc ngang ch ng v khi lng th tch t trng thi y ni l: - Ct th: acat =tg (45 -30 /2)=0,333 , =1,81 (t/m 3 ) , dncat =0,86 (t/m 3 ). - : ada = tg (45 -42 /2)=0,1982 , =2 (t/m 3 ) , dn =1 (t/m 3 ) Cc lp cn li: dn =( -1)/(1+e) , ly =2,7 - Lp 1: a1 = tg (45 -10 /2)=0,704 , =1,73 (t/m 3 ) , dn =0,895 (t/m 3 ) - lp 2: a 2 = tg (45 -24 /2)=0,4217 , =1,8 (t/m 3 ) , dn =0,895 (t/m 3 ) - lp 3: a 3 = tg (45 -19 /2)=0,5088 , =1,68 (t/m 3 ) , dn =0,85 (t/m 3 )2 0 0 2 0 0 2 0 0 2 0 0 2 0 0

Hnh 2.2: S ti trng tnh ton 2.2.2. Ti trng tc dng ln cng trnh bn 2.2.2.1. Ti trng do chn cn trc pha trc tc dng ln bn. Cn trc cng c p lc ln nht tc dng ln mi bnh xe l 18,5 T. Cn trc c 6 bnh xe pha ngoi mp bn v 6 bnh xe pha trong. a./. xt trng hp ngoi mp bn,cn trc ng bc xp hng ha ng xa nhau. a = 2,75-0,4=2,35 (m) l khong cch t mt phng tnh ton n chn cn trc. h d =2,35xcotg(45 -42 /2)=5,278 (m) p lc ln 1 bnh xe : 18,5 T p lc ln chn cn cu gm 6 bnh P tc =6x18,5=111 T Mt phng tnh ton tip nhn ALCD l mt phng i qua trc trung ha ca mt ct ngang tng. Ti trng phn b do cn trc c xc nh: ai Trong : b:b rng t vt b= 1,2 (m) l: chiu di di phn b ti trng dc tuyn mp bn0 0


7

BTL cng trnh bn I

B mn CTGTTP&CTT

P tc : Tng ti trng ln nht do 1 nhm lc tp trung khi s dng 1 cn cu ring l hoc 2 cn cu cnh nhau. p lc do cc lc ny c truyn ln chiu di di phn b : P tc =111 T. l=2.h.tg + l 1 + 1,0 = 2. 5,278.tg42 0 +3,5+1,0=14( m) Ptd = P tc 2.111 = = 13, 21(T ) b.l 1, 2.140 0

p lc ca chn cn trc ln mt phng tnh ton ct = P td . =13,21.tg 2 (45 -42 /2)=2,619 (t/m 2 ) b./. xt trong trng hp 2 cn trc ng cnh nhau cng lm vic P tc =12.18,5=222 T l 0 =2,5 m < 2.h. tg +1 =2.5.278. tg42 0 +1=10,5( m) l=2.h. tg + l 1 +l 2 + l 0 +1= 2.5.278. tg42 0 +3,5+3,5+2,5+1=20 (m) Vy Ptd =2.222 = 18,5 (t/m 2 ) 1, 2.200 0

p lc ca chn cn trc ln mt phng tnh ton ct = P td . =18,5. tg 2 (45 -42 /2)=3,67 (t/m 2 ) Khong cch tnh p lc chn cn trc: h=5,278 (m) h 1 =h-b/2. cotg(45 -42 /2)=3,93 (m) h 2 =h+b/2. cotg(45 -42 /2)=6,626 (m) h=2,7 (m). 2.2.2.2. Ti trng do hng ha q=1,6 (t/m 2 ).0 0 0 0

2.3. P LC T2.3.1. p lc t ch ng Chn c nc thi cng bng mc nc trung bnh:MNTC=+2,2 (m) - p lc t ch ng c tnh theo cng thc : ai =(q 1 + i .h i ). ai -2.C i .tg(45 0 - /2) Trc ht, ta xc nh chiu cao ca vng chu p lc ca lng th gim ti. lm c iu ny, ta v mt mt trt ca mt gc l (45 -42 /2)=24 0 C th xc nh mt cch gn ng l: t y bn pha trong k mt trt ca ln gp ng trn cng ca lp tng lc ngc. Ta xc nh c cao trnh ti im ny l: tnh p lc ch ng ca t t im ny tr ln, pha di chu p lc ch ng ca .0 0

Stt 1

Bng 2-3: xc nh p lc t ch ng ca t. i ai a Cao h i . i hi h i .i Ci qi 3 2 2 2 2 trnh (m) (t/m ) (t/m ) (t/m ) (T/m ) (T/m ) (T/m 2 ) +5 0 2 0 0 0 1.6 0.1982 0.3178


BTL cng trnh bn I

B mn CTGTTP&CTT

2 2 3 4 5 6 6 7

+2.2 +2.2 +1.07 +0.9 -1.626 -7.5 -7.5 -21,5

2.8 0 1.13 0.17 2.526 5.874 0 14

2 1 1 1 1 1 0.85 0.85

5.6 0 1.13 0.17 2.526 5.874 0 11.9

5.6 5.6 6.73 6.9 9.426 15.3 15.3 27.2

0 0 0 0 0 0 1.1 1.1

1.6 1.6 1.6 1.6 1.6 1.6 1.6 1.6

0.1982 0.1982 0.1982 0.1982 0.1982 0.1982 0.509 0.509

1.427 1.427 1.651 1.685 2.185 3.35 7.033 13.09

Ta v c biu p lc t ch ng sau cng thm vo mt biu p lc do ti trng ca t nm trn mi dc khi ,bn trong lng th trt.Tung i ca biu p lc gia tng ny c xc nh: H .tg k a 12,5.tg 240 4 ' = S0= =1,083 (m) 1 + tg k 1 + tg 240H .m0 a S0' (1 + m0 ) + b 12,5.2 4 1, 083(1 + 2) + 2 = S0= =6,584 (m) 1 + m0 1+ 2 1 = 2 = (q tc + itc .h)(ar ak ).S0 (1, 6 + 1,81.2,8)(0,333 0,1982).1, 083 =0,269 (T/m 2 ) H 3, 6171 tc (q tc + 1tc .h + 2 .S0' )(ar ak ).S0 ' ='

H (1, 6 + 0,86.2,8 + 1, 75.1, 083)(0,333 0,1982).1, 083 = 3, 6171

' 2 =

=0,346 (T/m 2 ) tc (q tc + 1tc .h + 2 .S0' )(ar ak ).S0

t (1, 6 + 0,86.2,8 + 1, 75.1, 083)(0,333 0,1982).6,584 = 14

= 0,374(T/m 2 ) 3 =tc (q tc + 1tc .h + 2 .( S0' + S0 ))(ar ak ).S0

t ((1, 6 + 0,86.2,8 + 1, 75.(1, 083 + 6,584))(0,333 0,1982).6,584 = 14

= 1,105(T/m 2 ) 2.3.2. p lc t b ng p lc t b ng c tnh theo cng thc:


9

BTL cng trnh bn I

B mn CTGTTP&CTT

pi = (q0 + i .hi ).pi + 2.ci .tg (450 + / 2)

Bng 2-4: Xc nh p lc t b ng ca t i p p Stt Cao h i . i hi h i . i Ci q0 3 2 2 2 2 trnh (m) (t/m ) (t/m ) (t/m ) (T/m ) (T/m ) (T/m 2 ) 1 -7,5 0 1 0 0 0 0 5,045 0 2 -9,5 2 1 2 2 0 0 5,045 10,09 2 -9,5 0 0,85 0 2 1,1 0 1,965 7,014 3 -21,5 12 0,85 10,2 12,2 1,1 0 1,965 27,057 Biu p lc tc dng ln cng trnh bn do chn cn trc, do khi t p sau bn,v do ti trng ca mi t bn trn lng th gim ti c th hin trong hnh sau

p lc t Hnh 2.3. Biu p lc t

p lc chn cn trc

p lc tng

\

CHNG 3 : XC NH CHIU SU H C TNH TON,NI LC CA C3.1. TNH CHIU SU H CSinh vin: Nguyn Th Quang_CTT K4710

BTL cng trnh bn I

B mn CTGTTP&CTT

Chiu su h c c xc nh bng phng php gii. Cc qu trnh tnh ton phng php ny c th hin trong hnh . T a gic dy v ng khp kn a gic dy, ta s tm c chiu su h c: t p =t min + t Trong : t min : su chn c theo tnh ton gii,tnh t y bn n giao im pha gia ng khp kn vi a gic dy, t min =11(m) t : gia s chn su ca tng mt ddamr bo cho tng ngm hon ton v c xc nh theo cng thc:t =' Ep

2[(q0 + i .hi ). p + c4. tg (450 + 4 / 2) a (q0 + i .hi ) + c4. tg (450 4 / 2)]' Ep

t ='

2.( p a )

E p : hp lc ca p lc b ng xc nh theo a gic lc trong tnh ton gii: a = 12.7186 (T/m 2 ) p = 21.9739 (T/m 2 ) E p = 46.5679 t =2.526 (m) Vy chiu su h c tnh ton l: t p =t min + t =11+2.526=13.526 (m) Tng chiu di c l: t=H+ t p =12,5+13.526=26.026 (m). Chn chiu di c l t= 26 m'

3.2. KIM TRA IU KIN QUAY CA TNG QUANH IM GN NEOTa kim tra theo cng thc: nc .n.md .M q m .M g . kn

Trong :n c ,n,m d ,m,k n :tra trong tiu chun 22TCN 207-92 Sinh vin: Nguyn Th Quang_CTT K4711

BTL cng trnh bn I

B mn CTGTTP&CTT

n c = 1, n=1.25 , k n =1.15 , m d =0.95 , m=1.15 T biu tng hp tc dng ln tng c,ta chia nh thnh cc phn mi phn coi nh mt lc tp trung (P 1 ,P 2 P n ) t ti tm ca biu hp lc.khong cch t cc lc ny n im neo l (h 1 ,h 2 h n )M g = pi .hii =1 n

M g : mmen ca cc lc b ng v lc ch ng pha trn thanh neo, gi cho tng khi b quay quanh im gn thanh neo. M g =1,0463.0,3231+1,2375.1,1379+0,7677.2,132+2,224.12,2383+3,2451.13,2162+ 4,2662.14,2+5,2874.15,2161+6,3085.16,1868+7,3296.17,1849+8,3508.19,1824+ 9,3719.20,1815+10,393.21,1808+10,8513.20,63=1235,92(T.m) M q : m men ca cc lc ch ng lm quay tng mt quanh im gn thanh neo M q =2,8737.11,098+5,8959.10,1829+3,1520.9,2666+3,4143.8,3539+3,2093.7,3839+3,0 042.6,3317+2,7992.5,3946+2,5939.4,3326+3,2127.3,5638+5,9513.2,8029+6,7028.1,719 1+2,0601.0,577=259,56 (T.m) Ta c: VT= nc .n.md .M q =1.1,25.0,95.259,56=308,2275 (T.m) VP=m 1,15 .M g = .1235,92 =1235,92 (T.m) kn 1,15

Do : VT = 308,2275 (T.m) < VP=1235,92 (T.m) Nh vy chiu su tnh ton t p ca tng c khng xoay quanh im neo.

3.3. NI LC CA C-Gi tr mmen nhp trrong mt cu kin tng mt c xc nh theo cng thc M tt = ( M max .mc + M k )(b + ) . Trong : = 30T , y max =2,1078m M max = . y max =30.2,1078=63,234 m c =0,75 , b+ =1 , M k =0. M tt =63,234.0,75=47,4265 (T.m)

CHNG 4. TNH TON H THNG THANH NEO CA TNG C4.1. CHN TIT DIN THANH NEO


12

BTL cng trnh bn I

B mn CTGTTP&CTT

Tr s thnh phn ni lc trong thanh neo v cc cu kin lin kt thanh neo c xc inh theo cng thc: Rtt = ma.Ra.la Trong : ma = 1,5 vi tng v bn khng cng trc thanh neo Ra = 26,3006 lc ngang thanh neo xc nh trn a gic dy. la l bc thanh neo dc tuyn bn: 0,8 m vy lc ko 1 thanh neo l: Rtt = 1,5.0,8.26,3006= 31,56 (T) - Tit din thanh neo c xc inh theo cng thc:F= Rtt mb .[ k ] 31,56.103 = 14, 61(cm 2 ) 0,8.2700

Trong : mb = 0,8 l h s lm vic Fa = d=

4.Fa 4.14, 61 = = 4,314(cm) . Ta chn ng knh thanh neo l

d = 5(cm)

4.2. TNH TON CHIU CAO BN (hC )CA BN NEOChiu cao ca bn neo c chn phi tha mn 2 yu cu sau: Theo yu ca trng thi gii hn II tc l ln S phi nh hn ln cho php S n :S= Tn ,b + Ea , n hbn .bbn .Cv S n =8(cm) hb = Tn ,b + Ea , n S n .lb .Cv

Theo yu cu ca trng thi gii hn I m bo n nh ca khi t:nc (Tn ,b + Ea ,n ) m.md . .En ,n kn

Trong : n c =1; k n =1,15; m=1,15; m d =0,95 T n ,b :lc cng ca thanh neo theo phng ngang truyn sang bn: T n ,b =R tt -T Vi: R tt =31,56(T) T: lc ma st ca thanh neo vi t ct: T = f . .h.d .L / 2 = .h.d .L / 4 Sinh vin: Nguyn Th Quang_CTT K4713

BTL cng trnh bn I

B mn CTGTTP&CTT

f=0,5; d=0,05(m); =1,81(t/m 3 ); h=2,8 m; An ton sai s khng ln ly = dn =0,86(t/m 3 ); T=0,86.2,8.0,05.28/4=0,8428 (T) T n ,b =31,56-0,8428=30,7172(T) - Ea,n, En,n tnh ton vi MNCTK; - Ea tng p lc ch ng tc dng ln bn neo trng hp nguy him nht khi ti trng phn b q=1,6 (T/m 2 ) cch bn neo mt khong l2 = t1.cotg, c = 0 vi t ct; Ea ,n = (q + 0,5. .t1 ).a , nl .t1 .ln + (q + .t1 + 0,5. .hbn ).hbn a ,n 2 .ln = (1,6+0,5.1,81.5).0,333.5.0,8+(1,6+1,81.5+0,5.1,81.3).3.0,333.0,8= 18,84(T) Trong :t1 =5 m :khong cch t nh bn neo n mt bn

t bn = 8m :khong cch t y bn neo n mt bn hbn =3 m : chiu cao ca bn neo =1,81(t/m 3 )

a ,n1 = a ,n 2 = cat = 0,333

l n =0,8 m

: khong cch gia cc thanh neo

En,n l p lc b ng ca t nh nht tc dng vo bn neo En, n = .tbn 2 . p .ln / 2 = 1,81.8 2 .3.0,4/2=69,504(T)

Vi p =tg 2 (45 0 +30 0 /2)=3 Tnh ton th dn ta c tbn = 8m ,hbn = 3m tha mn hb/t21/3 v hp l.tc - Tnh p lc b ng: p = ( .hi ).p (T/m 2 )i

q i = i .hi =1,81.1,05+0,86.3,95=5,2975 (T/m 2 )tc - Tnh p lc ch ng: a = (qi + i .hi ).a (T/m 2 ) q i =q 0 + i .hi =1,6+1,81.1,05+0,86.3,95=6,8975(T/m 2 ) Bng4.1 :Tnh ton p lc ch ng qi i hi ci i ai Stt Cao qi + i .hi 2 3 2 trnh (T/m ) (t/m ) (m) (T/m ) () 1 0 6,8975 0,86 0 0 6,8975 30 0,333 2 -3 6,8975 0,86 3 0 9,4775 30 0,333

ai (T/m 2 ) 2,297 3,156


14

BTL cng trnh bn I

B mn CTGTTP&CTT

Bng4.2: Tnh ton p lc b ng i hi Stt Cao qi = i .hi 2 3 trnh (T/m ) (t/m ) (m) 1 0 5,2975 0,86 0 2 -3 5,2975 0,86 3

ci

(T/m ) 0 02

qi + i .hi

5,2975 7,8775

i () 30 30

pi

pi

3 3

(T/m 2 ) 15,8925 23,6325

Hnh 4.1.Biu p lc t tng hp tc dng ln bn neo

4.3. TNH CHIU DI THANH NEOChiu di L max ca thanh neo c tnh t gi thit hai mt trt ch ng sau c v b ng trc bn neo cao trnh mt bn nh hnh v:Lmax = t / .tg 600 + h1 .tg 300 + h2 .tg 330 + h3 .tg 35.50 = 29, 691( m)

Do thanh neo ta neo xin gc: = 7 0 nn chiu di thc ca thanh neo l:Lneo = Lmax / cos7 0 = 29, 691/ cos70 = 29,91(m) Chn: Lneo = 30(m)


15

BTL cng trnh bn I

B mn CTGTTP&CTT

Hnh 4.2: S xc nh chiu di thanh neo

CHNG 5. TNH TON N NH CNG TRNH5.1. KIM TRA IU KIN TRT PHNG:- TrT phng c neo ca c c xc nh n c khi t gia c v bn neo. iu kin n nh l:

i =1

n 1

Wi + Ei + Hw m.(Ep + Wn)

Trong : Hw hp lc ca p lc sng, Hw = 0. Ea, Ep lc ch ng tc ng ln bn neo v lc b ng tc ng ln c; Ep =214,516 (T); Ea =18,84 (T); m - h s, ly bng 1,2;


16

BTL cng trnh bn I

B mn CTGTTP&CTT

Wi lc gy trt trong phn t th i c b rng l bi nm trong lng th ch ng ca t do trng lng bn thn Gi. lc dnh t Ci ; gc ma st trong i ca chnh nguyn t gy ra.i i i Wi = tg - sin 2 + sin .cos .tg ( i i) i i i i

G

C .b

i = 45 - i/2 : gc trt.

Wn lc gi do lng th b ng ca bn gi neo, xc nh theo cng thc sau:n n n Wn = tg - sin 2 + sin .cos .tg ( n n) i n n n

G

C .b

n = 45 + n/2 : gc trt.

Ta c: G1 = G11+ G12+ G13+ G14 = 7,2.0,85 +11,875.0,895+52,4.0.86+46.1,81 G1 =145,07 (T). G2 = G21+ G22 =9,1.0,85+4,34.0,895 = 11,62 (T). G3 = G31+ G32 = 10,9.0,85+3,35.0,895 = 11,57 (T).W1 = w2 = 145, 07 = .103,5(T ) tg (35,50 + 190 ) 11, 62 = 7,55(T ). tg (330 + 240 ) 11,57 = 7,51(T ). tg (330 + 240 )

w3 =

Gn = 26.0,85 = 22,1 (T). Wn = Gn . cos = 22,1.cos600 = 11,05(T).

W + Ei =1 i

n 1

a

= 103,5 + 7,55 + 7,51 + 18,84 = 137, 4(T )

m.( E p + Wn ) = 1, 2(214,516 + 18,84) = 280, 027(T )

Vy iu kin trt phng c tha mn

5.2. KIM TRA IU KIN TRT SU:Sinh vin: Nguyn Th Quang_CTT K4717

BTL cng trnh bn I

B mn CTGTTP&CTT

- V a cht cng trnh khng tn ti nhng lp t yu xen k cng nh cc lp , nn ta kim tra n nh trt cung trn. Ta kim tra theo cng thc sau y: nc.n.md.Mtr m .Mg kn

- Cng trnh ch n nh khi v ch khi: K=Mg M tr k n .n c .n.md =1.1875 m

- Kim tra n nh vi mt trt i qua chn c, Xc nh tm trt theo phng php sau: + Cc phn t c b rng bi = 0,1.Ri , ct t c ng knh OiM i qua trng tm k hiu l ct t th 0. + Cc ct khc bn tri k hiu l -1, -2, -3,,-m, cch ng thng ng OiM tng ng bng b, -2b,, cc ct khc bn phi k hiu l +1, +2, +3, , +m, cch ng thng ng OiM tng ng bng b, 2b,nbi n = sin i = R m

n s th t ct t ; m s lp t chia mi bn ; - Xt cc t s:q 1, 6 = = 0,15 .H 0,85.12,5 t 13,526 = = 1, 08 H 12,5

Do ta c th ly: x = ( 0,31 0,41 ) v y = ( 0,35 0,53 ); ta tm Oi(xi.H; yi.H); 5.2.1. Kim tra n nh vi tm O1 Vi tm O1 :

x1 = 0,32.12,5 = 4 m Y1 = 0,38.12,5 = 4,75 m


18

BTL cng trnh bn I

B mn CTGTTP&CTT

Hnh 5.1. Kim tra iu kin trt su vi tm 01 Bng 5.1. Tnh n nh tm 01 (R = 31.538m)Stt 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 Tng Stt ct t -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9 10 sin i -0.76 -0.67 -0.57 -0.48 -0.38 -0.29 -0.19 -0.1 0 0.1 0.19 0.29 0.38 0.48 0.57 0.67 0.76 0.86 0.95 cos i 0.65 0.75 0.82 0.88 0.92 0.96 0.98 1 1 1 0.98 0.96 0.92 0.88 0.82 0.75 0.65 0.52 0.31 tg 0.344 0.344 0.344 0.344 0.344 0.344 0.344 0.344 0.344 0.344 0.344 0.344 0.344 0.344 0.344 0.344 0.344 0.344 0.445 gi 6.834 14.705 20.74 25.458 29.079 31.79 33.643 34.74 35.088 31.892 73.447 71.492 68.823 65.176 60.569 54.577 46.748 36.106 17.338 Cil 1.1 1.1 1.1 1.1 1.1 1.1 1.1 1.1 1.1 1.1 1.1 1.1 1.1 1.1 1.1 1.1 1.1 1.1 0 R 31.538 31.538 31.538 31.538 31.538 31.538 31.538 31.538 31.538 31.538 31.538 31.538 31.538 31.538 31.538 31.538 31.538 31.538 31.538 li 4.72 4.02 3.65 3.41 3.24 3.13 3.06 3.01 3.01 2.76 3.04 3.13 3.24 3.41 3.65 4 4.6 5.77 8.92 Mtr -164 -308.9 -373.5 -382.2 -348.5 -285.7 -201.6 -104.1 0 95.55 440.1 642.6 824.8 978.4 1091 1146 1122 974.7 520 5667 Mg 211.9 258.4 311.3 361.1 404.3 439.1 464.6 479.7 485 440.3 887.8 851.9 803.2 740 665.9 580.3 488.4 402.8 75.24 9351


19

BTL cng trnh bn I

B mn CTGTTP&CTT

5.2.2. Kim tra n nh vi tm 02: Vi tm 02

x2 = 0,36.12,5 = 4,25 m; Y2 = 0,42.12,5 = 5,25 m;

Hnh 5.2. Kim tra n nh vi tm 02 Bng 5.2. Tnh n nh tm 02 ( R = 31.82 m)Stt ct Stt t 1 -8 2 -7 3 -6 4 -5 5 -4 6 -3 7 -2 8 -1 9 0 10 1 11 2 12 3 13 4 14 5 15 6 16 7 17 8 18 9 19 10 Tng sin -0.75 -0.66 -0.57 -0.47 -0.38 -0.28 -0.19 -0.09 0 0.09 0.19 0.28 0.38 0.47 0.57 0.66 0.75 0.85 0.94 cos 0.66 0.75 0.82 0.88 0.93 0.96 0.98 1 1 1 0.98 0.96 0.93 0.88 0.82 0.75 0.66 0.53 0.33 tg 0.344 0.344 0.344 0.344 0.344 0.344 0.344 0.344 0.344 0.344 0.344 0.344 0.344 0.344 0.344 0.344 0.344 0.344 0.445 gi 7.1485 14.85 20.851 25.526 29.138 31.824 33.694 34.791 35.148 34.791 73.302 71.441 68.755 65.142 60.467 54.466 46.672 36.081 16.243 Cil 1.1 1.1 1.1 1.1 1.1 1.1 1.1 1.1 1.1 1.1 1.1 1.1 1.1 1.1 1.1 1.1 1.1 1.1 0 R 31.82 31.82 31.82 31.82 31.82 31.82 31.82 31.82 31.82 31.82 31.82 31.82 31.82 31.82 31.82 31.82 31.82 31.82 31.82 li 8.55 4.01 3.65 3.41 3.24 3.14 3.06 3.01 3.01 3.02 3.06 3.13 3.25 3.4 3.05 4.01 4.95 6.75 9.11 Mtr -171.5 -311.9 -375.5 -382.6 -349.5 -286.6 -202.6 -104.1 0 104.1 440.8 643.3 824.8 976.3 1089 1144 1120 974.7 487.4 5620 Mg 350.7 262.3 315.8 365.8 408.8 443.8 469.1 484.6 490 484.7 894.8 859.7 810.7 748.1 652.3 588.1 508.8 445.1 76.54 9660


20

BTL cng trnh bn I

B mn CTGTTP&CTT

5.2.3. Kim tra n nh vi tm O3 (R=31.856m) Vi tm 03

x2 = 0,38.12,5 = 4,75 m; Y2 = 0,44.12,5 = 5,5 m;

Bng 5.3. Tnh n nh tm 03 (R=31.856m)Stt ct t -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9 10 sin -0.753 -0.659 -0.565 -0.471 -0.377 -0.283 -0.188 -0.094 0 0.094 0.188 0.283 0.377 0.471 0.565 0.659 0.753 0.848 0.942 cos 0.65802 0.75214 0.82509 0.88213 0.92621 0.95912 0.98217 0.99557 1 0.99557 0.98217 0.95912 0.92621 0.88213 0.82509 0.75214 0.65802 0.53 0.33561 tg 0.344 0.344 0.344 0.344 0.344 0.344 0.344 0.344 0.344 0.344 0.344 0.344 0.344 0.344 0.344 0.344 0.344 0.344 0.344

STT 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 tng

gi 7.3185 14.9685 20.961 25.6445 29.24 31.9175 33.7875 34.034 35.241 37.74 73.3615 71.3215 68.5845 64.904 60.1355 54.0155 46.0595 35.477 15.7351

Cil 1.1 1.1 1.1 1.1 1.1 1.1 1.1 1.1 1.1 1.1 1.1 1.1 1.1 1.1 1.1 1.1 1.1 1.1 0

R 31.856 31.856 31.856 31.856 31.856 31.856 31.856 31.856 31.856 31.856 31.856 31.856 31.856 31.856 31.856 31.856 31.856 31.856 31.856

li 5.918 3.996 3.639 3.409 3.245 3.128 3.055 3.02 3 3.273 3.065 3.135 3.257 3.424 3.669 4.033 4.652 5.87 8.63

Mtr -175.553 -314.235 -377.269 -384.775 -351.164 -287.744 -202.351 -101.914 0 113.0111 439.3567 642.981 823.6801 973.831 1082.357 1133.953 1104.855 958.3717 472.1829 5549.575

Mg 260.1491 263.4016 317.0401 367.3577 410.4923 445.0784 470.7091 477.1346 491.312 526.4324 896.997 859.4787 810.2546 747.398 672.2965 586.5364 495.1437 411.7426 57.87039 9566.825


21

BTL cng trnh bn I

B mn CTGTTP&CTT

Hnh 5.3. Kim tra n nh vi tm 03 T bng tnh ton ta c: + Tm 01 : R =31,538 m Mg = 9351 (Tm); Mtr = 5620(T.m); k = 1,65 > 1,1875 cng trnh n nh trt su. + Tm 02 : R = 31,82 m; Mg = 9660 (Tm); Mtr = 5583 (T.m); k = 1,72 > 1,1875 cng trnh n nh trt su. + Tm 03: R=31,856m Mg= 9566,825 (T.m); : Mtr=5549,575(T.m); k = 1.723 > 1,1875 cng trnh n nh trt su


22

BTL cng trnh bn I

B mn CTGTTP&CTT

TI LIU THAM KHO1. Gio trnh v ti liu 1.1. V MINH TUN . Thit k cng trnh bn cng. Nh xut bn Xy Dng . H ni, 2010. 1.2. PHM VN GIP, NGUYN HU U, NGUYN NGC HU . Cng trnh bn cng. . Nh xut bn Xy Dng . H Ni, 1998. 1.3. PHNG VN THNH, DNG VN PHC.Quy hoch cng. H ni, 1984. 1.4. The overseas coastal area development institute of Japan.Technical standards and commentaries for port and harbour facilities in Japan. Japan ports and harbour Associatiation-Tokyo. Japan, 2002. 2. Tiu chun, quy trnh, quy phm. 2.1. TCVN 4253 1986. Nn v cc cng trnh thu cng. Nh xut bn xy dng. H ni, 1986. 2.1. 22TCN 207 92. Tiu chun thit k Cng trnh bn cng bin. H ni, 1992. 2.3. 22TCN 222 95. Tiu chun thit k Ti trng tc ng (do sng v do tu). H ni, 1995.


23

BTL cng trnh bn I

B mn CTGTTP&CTT

MC LCTrang Chng 1.Cc thng s c bn ca bn ._________________________ 2 1.1. Cao trnh mt bn._________________________________________ 2 1.2. Cao trnh y bn._________________________________________ 2 1.3. Chiu di bn.____________________________________________ 2 1.4. La chon kt cu bn.______________________________________ 2 1.4.1. Phn tch cc yu t nh hng n vic la chn kt cu bn.______ 2 1.4.2. M t kt cu bn.________________________________________ 2 Chng 2. Ti trng tc dng ln cng trnh.____________________ 3 2.1. Ti trng v tc ng do tu.________________________________ 3 2.1.1. S liu tnh ton._________________________________________ 3 2.1.2. Ti trng neo tu._________________________________________ 4 2.1.3 Ti trng do va tu._______________________________________ 5 2.1.4 Ti trng do ta tu. ______________________________________ 5 2.1.5 Ti trng tc dng do lc ko ca dy.________________________ 6 2.2. Ti trng do thit b, hng ho trn mt bn.____________________ 7 2.3. p lc t.______________________________________________ 8 2.3.1. p lc t ch ng.______________________________________ 8 2.3.2. p lc t b ng ______________________________________ 10 Chng 3. Xc nh chiu su h c tnh ton, ni lc ca c.______ 11 3.1. Tnh chiu su h c.______________________________________ 11 3.2. Kim tra iu kin quay ca tng quanh im gn neo.__________ 12 3.3. Ni lc ca c.__________________________________________ 12 Chng 4. Tnh ton h thng thanh neo ca tng c.____________ 13 4.1. Chn tit din thanh neo.__________________________________ 13 4.2. Tnh ton chiu cao bn hc ca bn neo._______________________ 13 4.3. Tnh chiu di thanh neo.__________________________________ 15 Chng 5. Tnh ton n nh cng trnh._______________________ 16 5.1. Kim tra iu kin trt phng._____________________________ 16 5.2. Kim tra iu kin trt su ._______________________________ 18


24

btl ctb1_ nguyen the quang

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