business math chapter 3
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CHAPTER 3 : SYSTEM OF EQUATION
3.1 LINEAR EQUATIONS
3.2 QUADRATIC EQUATIONS
3.3 SYSTEM OF EQUATIONS
3.4 INEQUALITIES
3.1 LINEAR EQUATION
An equation is simply a statement that 2 quantities are the same.
E.g.
A statement can be true or false is said to be a conditional (or open) equation as it is true for some values of the variable & not true for others.
For example: 2x + 3 = 7 is true for x = 2 but is false for x = 8 or other values.
Any number that makes the equation true is called a solution or root of the equation.
RHSLHS
Equation =
Think of an equation as a pair of perfectly balanced old – fashioned scales
RHSLHS
954
Introduction
3.1 LINEAR EQUATION
A statement such as is called an identity as it is true for all real numbers x.
While solving equation, there may be no solution, one solution or there may be more than one solution.
For example:
112222 xx
Equation Solution Comment
x + 9 = 12 x = 3 Only one solution
x2 = 81 x = 9 or – 9 Two solutions
x = 5 + x No solution No solution
x2 – 16 = (x – 4)(x + 4) All values of x Equation is true for all values of x.
Introduction
3.1 LINEAR EQUATION
To solve an equation, we find the values of the unknown that satisfy it.
How: Isolate the unknown / variable & solve its value. A linear equation is an equation that can be written in
the form;
where a & b are real numbers. Linear equations have only one root/ solution.
0 bax 0 bax
Solving Linear equation with 1 variable
15
31233
123
x
x
x
9
31233
123
x
x
x
43
12
3
3
123
x
x
x
36
1233
3
123
x
x
x
Add 3 to both sides Subtract 3 from both sides
Multiply both sides by 3 Divide both sides by 3
Perform the same
operation on both
sides
Always check in the
original equation
3.1 LINEAR EQUATIONSolving Linear equation with 1 variable
Example 1 .8637 equation the Solve xxx
874 x
154 x
4
15x
837 xx
8637 xxx Parentheses removed
x – terms combined
Both sides divided by 4
7 added to both sides
3x added to both sides
Step Working
PRACTICE 1
4
37532 e)
242137 d)
643.05.1 c)
43 b)
3546 a)
equation. given the Solve 2.
VV
pp
xx
nn
LL
5
2
1
32d)
5
36
510
3
2c)
124
3
2b)
1035 a)
:equation following the Solve 1.
x
x
xx
xx
x
A quadratic equation contains terms of the first and second degree of unknown is given by;
where a, b, c are real numbers and a ≠ 0. A quadratic equation that contains terms of the 2nd
degree only of the unknown is called a pure quadratic equation, can be expressed as ;
A value of the unknown that will satisfy the equation is called a solution or a root of the equation.
02 cbxax 02 cbxax
02 cax 02 cax
3.2 QUADRATIC EQUATIONIntroduction
Standard form
Standard form
3.2 QUADRATIC EQUATIONSolving quadratic equation
All quadratic equations have two roots . In pure quadratic equation , the roots are equal but of
opposite sign. It can solve by extraction of the root.There are two methods of solving complete quadratic
equation; By factorization By using quadratic formula
219.45
89
5
89
895
0895 c)
416
16
016 b)
39
9 a)
:equation the Solve
2
2
2
2
2
2
R
R
R
R
x
x
x
x
x
3552 e)
6
361
36
36
036 d)
2
2
2
x
ix
x
x
x
x
Where Where
i 1
Example 2
The expression is written as the product of two factors.
If the product of 2 factors is zero, then one of those factors must be zero. Thus if then either
Only be used if the quadratic expression can be factorized completely.
cbxax 2
0mn.0 or 0 nm
3.2 QUADRATIC EQUATIONSolving quadratic equation - Factorization
34
0304
034
012 c)
5
2
0250
025
025 b)
6
060
06
06 a)
:equationquadratic the Solve
2
2
2
xx
xorx
xx
xx
x
xorx
xx
xx
x
xorx
xx
xx
x
x
4
-3
= 4x
= -3x
= xx2
(x-3)
(x+4)
-12
Example 3
32
0302
032
06
61 f)
71
0701
071
076 e)
34
0304
034
0127 d)
:equationquadratic the Solve
2
2
2
xx
xorx
xx
xx
x x
xx
xorx
xx
xx
xx
xorx
xx
xxx
x
4
3
= 4x
= 3x
= 7xx2
(x+3)
(x+4)
12
Example 3
PRACTICE 2
1642 e)
035116 d)
0253c)
8103 b)
0145 a)
:equationquadratic the Solve
2
2
2
2
xx
xx
xx
xx
xx
For any quadratic equation ax2 + bx + c = 0, the solutions for x can be found by using the quadratic formula:
The quantity b2 – 4ac is called discriminant of the quadratic equation that characterize the solution of the quadratic equations: If b2 – 4ac = 0 one real solution If b2 – 4ac > 0 2 real and unequal solutions If b2 – 4ac < 0 no real but 2 imaginary solutions
(complex number)
a
acbbx
2
42 a
acbbx
2
42
3.2 QUADRATIC EQUATIONSolving quadratic equation – Quadratic Formula
formulaquadratic the usingby 0582 equation the Solve 1. 2 kk
4
1048
22
52488
2
4
2
2
a
acbbk
5495.44
10482
k
5495.04
10481
k
Step 1
Step 2
Step 3
Identify a, b & c, by comparing with ax2 + bx + c = 0.
a = 2, b = 8, c = -5
Substitute into the formula:
The solutions are: b2 - 4ac > 0,2 real & unequal
roots
b2 - 4ac > 0,2 real & unequal
roots
Example 4
Example 4formulaquadratic the usingby 09124equation the Solve 2. 2 pp
8
012
42
9441212
2
4
2
2
a
acbbp
2
3
8
12p
Step 1
Step 2
Step 3
Identify a, b & c, by comparing with ax2 + bx + c = 0.
a = 4, b = -12, c = 9
Substitute into the formula:
The solution is: b2 - 4ac = 0,1 real root
b2 - 4ac = 0,1 real root
Example 4formulaquadratic the usingby 0453 equation the Solve 3. 2 kk
6
235
6
2315
6
235
32
43455
2
4
2
2
i
a
acbbk
808306
2352
.i.
i
k
8.083.06
2351
i
ik
Step 1
Step 2
Step 3
Identify a, b & c, by comparing with ax2 + bx + c = 0.
a = 3, b = -5, c = 4
Substitute into the formula:
The solutions are:
b2 - 4ac < 0,no real, 2
imaginary roots
b2 - 4ac < 0,no real, 2
imaginary roots
PRACTICE 3
sss
RR
xx
xx
xx
219 e)
25
3 d)
0373 c)
42499 b)
087 a)
:formulaquadratic using
by below equationquadratic the Solve
2
2
2
2
A system of equations contains 2 or more equations. Each equation contains 1 or more variables.
A solution of the system is any pair of values (x , y)
that satisfies the both equations.2 methods that are usually used:
Substitution method
Elimination method
222
111
cybxa
cybxa
222
111
cybxa
cybxa
Where a & b are
coefficients of x & y, c is a constant.
Where a & b are coefficients of x & y,
c is a constant.
3.3 SYSTEMS OF EQUATIONIntroduction
Step for solving by substitution: Pick 1 of the equation & solve for 1 of the
variables in terms of the remaining variables. Substitute the result in the remaining
equations. If 1 equation in 1 variable results, solve the
equation. Otherwise, repeat Step 1 – 3 again. Find the values of the remaining variables by
back – substitution. Check the solution found.
3.3 SYSTEMS OF EQUATIONSubstitution Method
2332
163
equations of system following the Solve
Eqyx
Eqyx
1
99
33612
33362
y
y
yy
yy
yx 36 From Eq 1, make x as subject:
Substitute x in Eq 2 :
Solve for y :
Substitute y in Eq 1, to solve for x: 3136 x
Solution:
Step 1
Step 2
Step 3
Step 4
Step 5 Check the solution : Eq 1, 3 – 3(-1) = 6
Eq 2, 2(3) + 3(-1) = 3
Example 5 a
Example 5 b
2143
182
equations of system following the Solve
Eqxy
Eqyx
yx 28 From Eq 1, make x as subject:
Substitute x in Eq 2 :
Solve for y :
Substitute y in Eq 1, to solve for x: 2328 x
Solution:
Step 1
Step 2
Step 3
Step 4
Step 5 Check the solution :
Eq 1; 2 + 2(3) = 8
Eq 2; 3(3) – 4(2) = 1
The solution is the intersection
point (2,3)
The solution is the intersection
point (2,3)
3
3311
18323
12843
y
y
yy
yy
Example 5 c
252
1824
equations of system following the Solve
Eqyx
Eqyx
xy 25 From Eq 2, make y as subject:
Substitute y in Eq 1 :
Solution:
Step 1
Step 2
Step 3 The result is a false statement.
Therefore the system is inconsistent. It means that there is no solutions for this system of equations
The lines are parallel & no intersection
The lines are parallel & no intersection
810
84104
82524
xx
xx
21236
142
equations of system following the Solve
Eqyx
Eqyx
1212
126126
122436
xx
xx
xy 24 From Eq 1, make y as subject:
Substitute y in Eq 2 :
Solution:
Step 1
Step 2
Step 3 The result is a true statement.
Therefore the system is dependent. It means that there is no unique solutions can be determined.
The lines is coincide, the systems has
infinitely many solution
The lines is coincide, the systems has
infinitely many solution
Example 5 d
Step for solving by elimination: Write x’s, y’s & numbers in the same order in both
equations. Compare x’s & y’s in the 2 equations & decide which
unknown is easier to eliminate. Make sure the number of this unknown is the same in both equations.
Eliminate the equal terms by adding or subtracting the 2 equations
Solve the resulting equation & substitute in the simpler original equation in order to find the value of the other unknown.
Check the solution found.
Elimination Method
3.3 SYSTEMS OF EQUATION
21923
1467
equations of system following the Solve
Eqyx
Eqxy
2
5829
7618821
y
y
yy
54
20
2764
x
x
Rearrange the eq:
To eliminate x, Eq1 multiply by 3, Eq 2 multiply by 4
Substitute y in Eq 1, to solve for x:
21923
1674
Eqyx
Eqyx
476812
3182112
Eqyx
Eqyx
Eq 3 – Eq 4, solve for y :
Multiply by a constants to
get same coefficient of x
Multiply by a constants to
get same coefficient of x
Solution:
Step 1
Step 2
Step 3
Step 4
Step 5Check the solution :
Example 6 a
223
1423
equations of system following the Solve
Eqyx
Eqyx
11
2
211
6492
y
y
yy
11
16
22611
211
23
x
x
x
To eliminate x, Eq2 multiply by 3;
Substitute y in Eq 2, to solve for x:
3693
1423
Eqyx
Eqyx
Eq 1 – Eq 3, solve for y :
Solution:
Step 1
Step 2
Step 3
Step 4Check the solution :
Example 6 b
PRACTICE 4
2
4)4
3610
425 3)
5186
362 2)
526
52 1)
A.
usingby system following the Solve
22
yx
yx
LK
LK
nm
nm
yx
yx
method onSubstituti
83
22)4
1236
42 3)
462
1269 2)
16
522 1)
B.
2
xy
xxy
SR
SR
nm
nm
yx
yx
method nEliminatio
An inequality is a statement involving 2 expressions separated by any of the inequality symbols below.
3.4 INEQUALITYIntroduction
Inequality Meaning
a > b a is greater than b
a < b a is less than b
a ≥ b a is greater than or equal to b
a ≤ b a is less than or equal to b
A real number is a solution of an inequality involving a variable if a true statement is obtained when the variable is replaced by the number.
The set of all real numbers satisfy the inequality is called the solution set.
3.4 INEQUALITYInequality, Interval Notation & Line Graph Inequalit
yNotation
Interval Notation
Graph
a ≤ x ≤ b [ a, b ]
a < x ≤ b ( a, b ]
a ≤ x < b [ a, b )
a < x < b ( a, b )
x ≥ b [ b, ∞ )
x > b ( b, ∞ )
x ≤ a ( -∞, a ]
x < a ( -∞, a )
a b
3.4 INEQUALITYProperties of Inequality
PropertiesLet a, b & c be any real
number
Example
If a < b and b < c, then a < c If 2 < 3 & 3 < 8 so 2 < 8
If a < b, then a ± c < b ± c 5 < 7, 5 + 3 < 7 + 3, 8 < 10
5 < 7, 5 - 3 < 7 - 3, 2 < 4
If a < b, c > 0 then ac < bc 5 < 7, 5(2) < 7(2), 10 < 14
If a < b, c < 0 then ac > bc 5 < 7, 5(-2) > 7(-2), -10 > -14
If a < b, c > 0 then a/c < b/c 5 < 7, 5/2 < 7/2, 2.5 < 3.5
If a < b, c < 0 then a/c > b/c 5 < 7, 5/(-2) > 7/(-2), -2.5 > -3.5Similar properties hold if < between a and b is replaced
by ≥ , > , or ≤ .
3
12
5
46 d)21273c)
17
17
10743
9254 b)74103 a)
:esinequaliti following the of each Solve
xxxx
x
x
xx
xxxx
Divide by –ve no , reverse
sign
Divide by –ve no , reverse
sign
Example 7
1,0,1,2or23Therefore
23
6339
423and2311
42311 a)
:esinequaliti following the of each Solve
xx
xx
xx
xx
x
Solution set
Solution set
. is thereTherefore5
17
6175
1372and72310
1372310 b)
solution no
x
xx
xxxx
xxx
Example 8
Impossible to have x that satisfies both inequalities
Impossible to have x that satisfies both inequalities
PRACTICE 5
7521b)
715123a)
:inequality the Solve .3
.41
satisfying of values of range the Determine .2
.513 for set solution the find integer, an is If .1
x
x xx
xx
xx
2400425006
that given dollars) (in profit maximum the Find 5.
5.275.1255
that given dollars) (in cost minimum the Find 4.
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