c h a p t e r 11 c h a p t e r 11 bjt frequency response

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C H A P T E R 11 BJT FREQUENCY RESPONSE

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  • Slide 1
  • C H A P T E R 11 C H A P T E R 11 BJT FREQUENCY RESPONSE
  • Slide 2
  • INTRODUCTION We will now investigate the frequency effects introduced by the larger capacitive elements of the network at low frequencies and the smaller capacitive elements of the active device at the high frequencies. Since the analysis will extend through a wide frequency range, the logarithmic scale will be defined and used throughout the analysis. The frequency response analyses of BJTs permit a coverage in the chapter.
  • Slide 3
  • LOGARITHMS The use of log scales can significantly expand the range of variation of a particular variable on a graph. Most graph paper available is of the semi log or double-log (log-log) variety.
  • Slide 4
  • LOGARITHMS Note that the vertical scale is a linear scale with equal divisions. The spacing between the lines of the log plot is shown on the graph.
  • Slide 5
  • LOGARITHMS The log of 2 to the base 10 is approximately 0.3. The distance from 1 (log10 1 = 0) to 2 is therefore 30% of the span and so on
  • Slide 6
  • LOGARITHMS It is important to note the resulting numerical value and the spacing, since plots will typically only have the tic marks indicated in Fig. 11.2 due to a lack of space. You must realize that the longer bars for this figure have the numerical values of 0.3, 3, and 30 associated with them, whereas the next shorter bars have values of 0.5, 5, and 50 and the shortest bars 0.7, 7, and 70.
  • Slide 7
  • LOGARITHMS The important point is that the results extracted at each level be correctly labeled by developing a familiarity with the spacing of Figs. 11.1 and 11.2.
  • Slide 8
  • DECIBELS The background surrounding the term decibel has its origin that power and audio levels are related on a logarithmic basis. That is, an increase in power level, say 4 to 16 W, does not result in an audio level increase by a factor of 16/4 = 4. It will increase by a factor of 2 as derived from the power of 4 in the following manner: (4) 2 =16. For a change of 4 to 64 W, the audio level will increase by a factor of 3 since (4) 3 =64. In logarithmic form, the relationship can be written as log 4 64 = 3.
  • Slide 9
  • DECIBELS The term bel was derived from the surname of Alexander Graham Bell. For standardization, the bel (B) was defined by the following equation to relate power levels P 1 and P 2 : It was found, however, that the bel was too large a unit of measurement for practical purposes, so the decibel (dB) was defined such that 10 decibels = 1 bel. Therefore,
  • Slide 10
  • DECIBELS The above equation indicates that the decibel rating is a measure of the difference in magnitude between two power levels. For a specified terminal (output) power (P 2 ) there must be a reference power level (P 1 ). The reference level is generally accepted to be 1 mW, although on occasion, the 6-mW standard of earlier years is applied. The resistance to be associated with the 1-mW power level is 600 chosen because it is the characteristic impedance of audio transmission lines.
  • Slide 11
  • DECIBELS There exists a second equation for decibels that is applied frequently. It can be best described through the system of Fig. 11.3. For V i equal to some value V 1, P 1 = V 2 1 /R i, where R i, is the input resistance of the system of Fig. 11.3. If V i should be increased (or decreased) to some other level, V 2, then P 2 = V 2 2 /R i. Figure 11.3 Configuration employed in the discussion
  • Slide 12
  • DECIBELS If we determine the resulting difference in decibels between the power levels, Figure 11.3 Configuration employed in the discussion
  • Slide 13
  • DECIBELS One of the advantages of the logarithmic relationship is the manner in which it can be applied to cascaded stages. For example, the magnitude of the overall voltage gain of a cascaded system is given by
  • Slide 14
  • DECIBELS In an effort to develop some association between dB levels and voltage gains, Table 11.2 was developed. First note that a gain of 2 results in a dB level of +6 dB while a drop to 1/2 results in a -6dB level. A change in Vo/Vi from 1 to 10, 10 to 100, or 100 to 1000 results in the same 20dB change in level. When V o = V i, V o /V i = 1 and the dB level is 0.
  • Slide 15
  • DECIBELS
  • Slide 16
  • DECIBELS
  • Slide 17
  • GENERAL FREQUENCY CONSIDERATIONS The frequency of the applied signal can have an effect on the response of a single-stage or multistage network. At low frequencies, we shall find that the coupling and bypass capacitors can no longer be replaced by the short- circuit approximation because of the increase in reactance of these elements. The frequency-dependent parameters of the small-signal equivalent circuits and the stray capacitive elements associated with the active device and the network will limit the high-frequency response of the system. An increase in the number of stages of a cascaded system will also limit both the high- and low-frequency responses.
  • Slide 18
  • GENERAL FREQUENCY CONSIDERATIONS The magnitudes of the gain response curves of an RC- coupled, direct-coupled, and transformer-coupled amplifier system are provided in Fig. 11.4. Note that the horizontal scale is a logarithmic scale to permit a plot extending from the low- to the high- frequency regions.
  • Slide 19
  • GENERAL FREQUENCY CONSIDERATIONS For the RC-coupled amplifier, the drop at low frequencies is due to the increasing reactance of C C, C s, or C E,
  • Slide 20
  • GENERAL FREQUENCY CONSIDERATIONS while its upper frequency limit is determined by either the parasitic capacitive elements of the network and frequency dependence of the gain of the active device.
  • Slide 21
  • GENERAL FREQUENCY CONSIDERATIONS Let us say that the drop in gain for the transformer-coupled system is simply due to the shorting effect (across the input terminals of the transformer) of the magnetizing inductive reactance at low frequencies (X L =2fL). The gain must obviously be zero at f= 0 since at this point there is no longer a changing flux established through the core to induce a secondary or output voltage.
  • Slide 22
  • GENERAL FREQUENCY CONSIDERATIONS As indicated in Fig. 11.4, the high- frequency response is controlled primarily by the stray capacitance between the turns of the primary and secondary windings. For the direct-coupled amplifier, there are no coupling or bypass capacitors to cause a drop in gain at low frequencies. As the figure indicates, it is a flat response to the upper cutoff frequency, which is determined by either the parasitic capacitances of the circuit or the frequency dependence of the gain of the active device.
  • Slide 23
  • GENERAL FREQUENCY CONSIDERATIONS For each system of Fig. 11.4, there is a band of frequencies in which the magnitude of the gain is either equal or relatively close to the mid-band value. To fix the frequency boundaries of relatively high gain, 0.707A vmid was chosen to be the gain at the cutoff levels. The corresponding frequencies f 1 and f 2 are generally called the corner, cutoff, band, break, or half-power frequencies. The multiplier 0.707 was chosen because at this level the output power is half the mid-band power output, that is, at mid-frequencies,
  • Slide 24
  • GENERAL FREQUENCY CONSIDERATIONS and at the half-power frequencies, The bandwidth (or pass-band) of each system is determined by f 1 and f 2, that is, and
  • Slide 25
  • GENERAL FREQUENCY CONSIDERATIONS In Fig. 11.5, the gain at each frequency is divided by the mid-band value. Obviously, the mid-band value is then one as indicated. At the half-power frequencies the resulting level is 0.707=1/2. A decibel plot can now be obtained by applying :
  • Slide 26
  • GENERAL FREQUENCY CONSIDERATIONS At mid-band frequencies, 20 log 10 (1) = 0dB, and at the cutoff frequencies, 20 log 10 (1/2)= -3 dB. Both values are clearly indicated in the resulting decibel plot of Fig. 11.6. The smaller the fraction ratio, the more negative the decibel level.
  • Slide 27
  • GENERAL FREQUENCY CONSIDERATIONS It should be understood that most amplifiers introduce a 180 phase shift between input and output signals. This fact must now be expanded to indicate that this is the case only in the mid-band region. At low frequencies, there is a phase shift such that V o lags V i by an increased angle. At high frequencies, the phase shift will drop below 180. Figure 11.7 is a standard phase plot for an RC-coupled amplifier.
  • Slide 28
  • LOW-FREQUENCY ANALYSISBODE PLOT In the low-frequency region of the single-stage BJT amplifier, the R-C combinations formed by the network capacitors C C, C E, and Cs and the network resistive parameters that determine the cutoff frequencies. In fact, an R-C network similar to Fig. 11.8 can be established for each capacitive element and the frequency at which the output voltage drops to 0.707 of its maximum value determined. Once the cutoff frequencies due to each capacitor are determined, they can be compared to establish which will determine the low-cutoff frequency for the system.
  • Slide 29
  • LOW-FREQUENCY ANALYSISBODE PLOT At very high frequencies, and the short-circuit equivalent can be substituted for the capacitor as shown in Fig. 11.9. The result is that Vo Vi at high frequencies. and the open-circuit approximation can be applied as shown in Fig. 11.10, with the result that Vo = 0 V. At f = 0 Hz,
  • Slide 30
  • LOW-FREQUENCY ANALYSISBODE PLOT Between the two extremes, the ratio A v =V o /V i will vary as shown in Fig. 11.11. As the frequency increases, the capacitive reactance decreases and more of the input voltage appears across the output terminals. The output and input voltages are related by the voltage-divider rule in the following manner: with the magnitude of Vo determined by
  • Slide 31
  • LOW-FREQUENCY ANALYSISBODE PLOT For the special case where X C =R, the level of which is indicated on Fig. 11.11.
  • Slide 32
  • LOW-FREQUENCY ANALYSISBODE PLOT In other words, at the frequency of which X C =R, the output will be 70.7% of the input for the network of Fig. 11.8. The frequency at which this occurs is determined from
  • Slide 33
  • LOW-FREQUENCY ANALYSISBODE PLOT In Fig. 11.6, we recognize that there is a 3-dB drop in gain from the mid band level when f = f 1. In a moment, we will find that an RC network will determine the low-frequency cutoff frequency for a BJT transistor and f 1 will be determined by
  • Slide 34
  • LOW-FREQUENCY ANALYSISBODE PLOT
  • Slide 35
  • For frequencies where f f 1 or (f 1 /f) 2 1, the equation above can be approximated by
  • Slide 36
  • LOW-FREQUENCY ANALYSISBODE PLOT In the same figure, a straight line is also drawn for the condition of 0 dB for f f 1.
  • Slide 37
  • LOW-FREQUENCY ANALYSISBODE PLOT A change in frequency by a factor of 2, equivalent to 1 octave, results in a 6-dB change in the ratio as noted by the change in gain from f 1 /2 to f 1. For a 10:1 change in frequency, equivalent to 1 decade, there is a 20- dB change in the ratio as demonstrated between the frequencies of f 1 /10 and f 1.
  • Slide 38
  • LOW-FREQUENCY ANALYSISBODE PLOT A fairly accurate plot of the frequency response as indicated in the same figure. The piecewise linear plot of the asymptotes and associated breakpoints is called a Bode plot of the magnitude versus frequency.
  • Slide 39
  • LOW-FREQUENCY ANALYSISBODE PLOT The phase angle of is determined from
  • Slide 40
  • LOW-FREQUENCY ANALYSISBODE PLOT EXAMPLE 11.8 For the network of Fig. 11.13: (a) Determine the break frequency. (b) Sketch the asymptotes and locate the 3-dB point. (c) Sketch the frequency response curve.
  • Slide 41
  • LOW-FREQUENCY RESPONSE BJT AMPLIFIER LOW-FREQUENCY RESPONSE BJT AMPLIFIER For the network of Fig. 11.16, the capacitors C s, C C, and C E will determine the low- frequency response. We will now examine the impact of each independently in the order listed. When we analyze the effects of Cs we must assume that the analysis of the reactance of C E and C C becomes too unwieldy, that is, that the magnitude of the reactance of C E and C C permits employing a short-circuit equivalent in comparison to the magnitude of the other series impedances.
  • Slide 42
  • LOW-FREQUENCY RESPONSE BJT AMPLIFIER LOW-FREQUENCY RESPONSE BJT AMPLIFIER The general form of the R-C configuration is established by the network of Fig. 11.17. The total resistance is now Rs + Ri, and the cutoff frequency is At mid or high frequencies, the reactance of the capacitor will be sufficiently small to permit a short- circuit approximation for the element. The voltage Vi will then be related to Vs by
  • Slide 43
  • LOW-FREQUENCY RESPONSE BJT AMPLIFIER LOW-FREQUENCY RESPONSE BJT AMPLIFIER The ac equivalent network for the input section of BJT amplifier will appear as shown in Fig. 11.18. The value of R i for is determined by The voltage Vi applied to the input of the active device can be calculated using the voltage-divider rule:
  • Slide 44
  • LOW-FREQUENCY RESPONSE BJT AMPLIFIER LOW-FREQUENCY RESPONSE BJT AMPLIFIER Since the coupling capacitor is connected between the output of the active device and the applied load, the R- C configuration that determines the low cutoff frequency due to C C appears in Fig. 11.19. The cutoff frequency due to C C is determined by The ac equivalent network for the output section with Vi = 0 V appears in Fig. 11.20. The resulting value for Ro is then simply
  • Slide 45
  • LOW-FREQUENCY RESPONSE BJT AMPLIFIER LOW-FREQUENCY RESPONSE BJT AMPLIFIER To determine f LE, the network seen by C E must be determined as shown in Fig. 11.21. Once the level of R e is established, the cutoff frequency due to C E can be determined using the following equation: where Rs = Rs // R 1 // R 2. The loaded voltage-divider BJT bias configuration, the ac equivalent as seen by C E appears in Fig. 11.22. The value of Re is therefore determined by
  • Slide 46
  • LOW-FREQUENCY RESPONSE BJT AMPLIFIER LOW-FREQUENCY RESPONSE BJT AMPLIFIER The effect of C E on the gain is best described in a quantitative manner by recalling that the gain for the configuration of Fig. 11.23 is given by
  • Slide 47
  • LOW-FREQUENCY RESPONSE BJT AMPLIFIER LOW-FREQUENCY RESPONSE BJT AMPLIFIER EXAMPLE 11.9 (a) Determine the lower cutoff frequency for the network of Fig. 11.16 using the following parameters: (b) Sketch the frequency response using a Bode plot.
  • Slide 48
  • LOW-FREQUENCY RESPONSE BJT AMPLIFIER LOW-FREQUENCY RESPONSE BJT AMPLIFIER
  • Slide 49
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  • Slide 52
  • Miller Effect Capacitance In the high-frequency region, the capacitive elements of importance are the inter-electrode (between terminals) capacitances internal to the active device C be, C ce, C bc , and the wiring capacitance between leads of the network C Mi, C Mo. For inverting amplifiers (phase shift of 180 between input and output resulting in a negative value for A v ), the input and output capacitance is increased by a capacitance level sensitive to the interelectrode capacitance between the input and output terminals of the device C bc and the gain of the amplifier. In Fig. 11.39, this feedback capacitance is defined by C f. Figure 11.39 Network employed in the derivation of an equation for the Miller input capacitance.
  • Slide 53
  • Miller Effect Capacitance Figure 11.39 Network employed in the derivation of an equation for the Miller input capacitance.
  • Slide 54
  • Miller Effect Capacitance Figure 11.39 Network employed in the derivation of an equation for the Miller input capacitance. Establishing the equivalent network of Fig. 11.40. The result is an equivalent input impedance to the amplifier of Fig. 11.39 that includes the same R i that we have dealt with in previous chapters, with the addition of a feedback capacitor magnified by the gain of the amplifier.
  • Slide 55
  • Miller Effect Capacitance Figure 11.39 Network employed in the derivation of an equation for the Miller input capacitance.
  • Slide 56
  • Miller Effect Capacitance Figure 11.39 Network employed in the derivation of an equation for the Miller input capacitance. This shows us that: For any inverting amplifier, the input capacitance will be increased by a Miller effect capacitance C M sensitive to the gain of the amplifier and the inter-electrode capacitance connected between the input and output terminals of the active device.
  • Slide 57
  • Miller Effect Capacitance The Miller effect will also increase the level of output capacitance, which must also be considered when the high- frequency cutoff is determined. In Fig. 11.41, the parameters of importance to determine the output Miller effect are in place. Applying Kirchhoffs current law will result in
  • Slide 58
  • Miller Effect Capacitance
  • Slide 59
  • Slide 60
  • High-frequency Response BJT Amplifier Network Parameters In the high-frequency region, the RC network of concern has the configuration appearing in Fig. 11.42. At increasing frequencies, the reactance X C will decrease in magnitude, resulting in a shorting effect across the output and a decrease in gain. The derivation leading to the corner frequency for this RC configuration follows along similar lines to that encountered for the low-frequency region. The most significant difference is in the general form of Av appearing below:
  • Slide 61
  • High-frequency Response BJT Amplifier Which results in a magnitude plot such as shown in Fig. 11.43 that drops off at 6 dB/octave with increasing frequency
  • Slide 62
  • High-frequency Response BJT Amplifier In Fig. 11.44, the various parasitic capacitances (C be, C bc, C ce ) of the transistor have been included with the wiring capacitances (C wi, C Wo ) introduced during construction. The high-frequency equivalent model for the network of Fig. 11.44 appears in Fig. 11.45. Figure 11.44 Network of Fig. 11.16 with the capacitors that affect the high-frequency response.
  • Slide 63
  • High-frequency Response BJT Amplifier The capacitance C i includes the input wiring capacitance C wi, the transition capacitance C be, and the Miller capacitance C Mi. The capacitance C o includes the output wiring capacitance C wo, the parasitic capacitance C ce, and the output Miller capacitance C Mo.
  • Slide 64
  • High-frequency Response BJT Amplifier Determining the Thvenin equivalent circuit for the input and output networks of Fig. 11.45 will result in the configurations of Fig. 11.46. Figure 11.46 Thvenin circuits for the input and output networks of the network of Fig. 11.45.
  • Slide 65
  • High-frequency Response BJT Amplifier Figure 11.46 Thvenin circuits for the input and output networks of the network of Fig. 11.45. For the input network, the 3-dB frequency is defined by
  • Slide 66
  • High-frequency Response BJT Amplifier Figure 11.46 Thvenin circuits for the input and output networks of the network of Fig. 11.45. At very high frequencies, the effect of C i is to reduce the total impedance of the parallel combination of R 1, R 2, R i, and C i in Fig. 11.45. The result is a reduced level of voltage across C i, a reduction in I b, and a gain for the system.
  • Slide 67
  • High-frequency Response BJT Amplifier Figure 11.46 Thvenin circuits for the input and output networks of the network of Fig. 11.45.
  • Slide 68
  • High-frequency Response BJT Amplifier Figure 11.46 Thvenin circuits for the input and output networks of the network of Fig. 11.45. At very high frequencies, the capacitive reactance of C o will decrease and consequently reduce the total impedance of the output parallel branches of Fig. 11.45. The net result is that V o will also decline toward zero as the reactance X C becomes smaller.
  • Slide 69
  • High-frequency Response BJT Amplifier The frequencies f Hi and f Ho will each define a 6-dB/octave asymptote such as depicted in Fig. 11.43. If the parasitic capacitors were the only elements to determine the high cutoff frequency, the lowest frequency would be the determining factor. However, the decrease in h fe (or ) with frequency must also be considered as to whether its break frequency is lower than f Hi or f Ho.
  • Slide 70
  • h fe (or ) Variation High-frequency Response BJT Amplifier The variation of h fe (or ) with frequency will approach, with some degree of accuracy, the following relationship:
  • Slide 71
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