c++ programming: program design including data …...control structures (cont'd.) c++...
TRANSCRIPT
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C++ Programming: Program
Design Including
Data Structures, Fifth Edition
Chapter 4: Control Structures I
(Selection)
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Objectives
In this chapter, you will:
• Learn about control structures
• Examine relational and logical operators
• Explore how to form and evaluate logical
(Boolean) expressions
• Discover how to use the selection control structures if, if...else, and switch
in a program
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Objectives (cont’d.)
• Learn how to avoid bugs by avoiding
partially understood concepts
• Learn to use the assert function to
terminate a program
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Control Structures
• A computer can proceed:
– In sequence
– Selectively (branch): making a choice
– Repetitively (iteratively): looping
• Some statements are executed only if
certain conditions are met
• A condition is met if it evaluates to true
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Control Structures (cont'd.)
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Relational Operators
• A condition is represented by a logical (Boolean) expression that can be true
or false
• Relational operators:
– Allow comparisons
– Require two operands (binary)
– Evaluate to true or false
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Relational Operators (cont'd.)
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Relational Operators and Simple
Data Types
• You can use the relational operators with
all three simple data types:
– 8 < 15 evaluates to true
– 6 != 6 evaluates to false
– 2.5 > 5.8 evaluates to false
– 5.9 <= 7.5 evaluates to true
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Comparing Characters
• Expression with relational operators
– Depends on machine’s collating sequence
– ASCII character set
• Logical (Boolean) expressions
– Expressions such as 4 < 6 and 'R' > 'T’
– Returns an integer value of 1 if the logical
expression evaluates to true
– Returns an integer value of 0 otherwise
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Relational Operators and thestring Type
• Relational operators can be applied to strings
• Strings are compared character by character, starting with the first character
• Comparison continues until either a mismatch is found or all characters are found equal
• If two strings of different lengths are compared and the comparison is equal to the last character of the shorter string
– The shorter string is less than the larger string
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Relational Operators and thestring Type (cont'd.)
• Suppose we have the following
declarations:
string str1 = "Hello";
string str2 = "Hi";
string str3 = "Air";
string str4 = "Bill";
string str4 = "Big";
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Relational Operators and thestring Type (cont'd.)
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Relational Operators and thestring Type (cont'd.)
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Logical (Boolean) Operators and
Logical Expressions
• Logical (Boolean) operators enable you to
combine logical expressions
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Logical (Boolean) Operators and
Logical Expressions (cont'd.)
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Logical (Boolean) Operators and
Logical Expressions (cont'd.)
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Logical (Boolean) Operators and
Logical Expressions (cont'd.)
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Order of Precedence
• Relational and logical operators are
evaluated from left to right
• The associativity is left to right
• Parentheses can override precedence
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Order of Precedence (cont'd.)
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Order of Precedence (cont'd.)
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Order of Precedence (cont'd.)
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Order of Precedence (cont'd.)
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int Data Type and Logical
(Boolean) Expressions
• Earlier versions of C++ did not provide
built-in data types that had Boolean values
• Logical expressions evaluate to either 1 or
0
– The value of a logical expression was stored in a variable of the data type int
• You can use the int data type to
manipulate logical (Boolean) expressions
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The bool Data Type and Logical
(Boolean) Expressions
• The data type bool has logical (Boolean)
values true and false
• bool, true, and false are reserved
words
• The identifier true has the value 1
• The identifier false has the value 0
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Selection: if and if...else
• One-Way Selection
• Two-Way Selection
• Compound (Block of) Statements
• Multiple Selections: Nested if
• Comparing if...else Statements with a
Series of if Statements
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One-Way Selection
• The syntax of one-way selection is:
• The statement is executed if the value of the expression is true
• The statement is bypassed if the value is false; program goes to the next
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• if is a reserved wordC++ Programming: Program Design Including Data Structures, Fifth Edition 26
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One-Way Selection (cont'd.)
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One-Way Selection (cont'd.)
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One-Way Selection (cont'd.)
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One-Way Selection (cont'd.)
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Two-Way Selection
• Two-way selection takes the form:
• If expression is true, statement1 is executed; otherwise, statement2 is executed– statement1 and statement2 are any C++
statements
• else is a reserved word
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Two-Way Selection (cont'd.)
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Two-Way Selection (cont'd.)
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Two-Way Selection (cont'd.)
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Compound (Block of)
Statements
• Compound statement (block of
statements):
• A compound statement is a single
statement
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Compound (Block of) Statements
(cont'd.)if (age > 18)
{
cout << "Eligible to vote." << endl;
cout << "No longer a minor." << endl;
}
else
{
cout << "Not eligible to vote." << endl;
cout << "Still a minor." << endl;
}
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Multiple Selections: Nested if
• Nesting: one control statement in
another
• An else is associated with the most
recent if that has not been paired with
an else
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Multiple Selections: Nested if(cont'd.)
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Multiple Selections: Nested if(cont'd.)
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Multiple Selections: Nested if
(cont'd.)
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Comparing if…else Statements
with a Series of if Statements
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Short-Circuit Evaluation
• Short-circuit evaluation: evaluation of a
logical expression stops as soon as the
value of the expression is known
• Example:
(age >= 21) || ( x == 5) //Line 1
(grade == 'A') && (x >= 7) //Line 2
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Comparing Floating-Point Numbers
for Equality: A Precaution
• Comparison of floating-point numbers for
equality may not behave as you would
expect
– Example:
• 1.0 == 3.0/7.0 + 2.0/7.0 + 2.0/7.0
evaluates to false
• Why? 3.0/7.0 + 2.0/7.0 + 2.0/7.0 =
0.99999999999999989
• Solution: use a tolerance value
– Example: fabs(x – y) < 0.000001
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Associativity of Relational
Operators: A Precaution
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Associativity of Relational
Operators: A Precaution (cont’d.)
• num = 5
• num = 20
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Avoiding Bugs by Avoiding Partially
Understood Concepts and
Techniques• Must use concepts and techniques
correctly;
– Otherwise solution will be either incorrect or
deficient
• If you do not understand a concept or
technique completely
– Don’t use it
– Save yourself an enormous amount of
debugging time
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Input Failure and the if
Statement• If input stream enters a fail state
– All subsequent input statements associated with that stream are ignored
– Program continues to execute
– May produce erroneous results
• Can use if statements to check status of input stream
• If stream enters the fail state, include instructions that stop program execution
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Confusion Between the Equality
(==) and Assignment (=) Operators
• C++ allows you to use any expression that can be evaluated to either true or false
as an expression in the if statement:if (x = 5)
cout << "The value is five." << endl;
• The appearance of = in place of ==
resembles a silent killer
– It is not a syntax error
– It is a logical error
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Conditional Operator (?:)
• Conditional operator (?:) takes three
arguments
– Ternary operator
• Syntax for using the conditional operator:expression1 ? expression2 : expression3
• If expression1 is true, the result of the
conditional expression is expression2
– Otherwise, the result is expression3
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Program Style and Form
(Revisited): Indentation
• If your program is properly indented
– Spot and fix errors quickly
– Show the natural grouping of statements
• Insert a blank line between statements that
are naturally separate
• Two commonly used styles for placing braces
– On a line by themselves
– Or left brace is placed after the expression, and
the right brace is on a line by itself
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Using Pseudocode to Develop,
Test, and Debug a Program
• Pseudocode, or just pseudo
– Informal mixture of C++ and ordinary
language
– Helps you quickly develop the correct
structure of the program and avoid making
common errors
• Use a wide range of values in a walk-
through to evaluate the program
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switch Structures
• switch structure: alternate to if-else
• switch (integral) expression is evaluated first
• Value of the expression determines which corresponding action is taken
• Expression is sometimes called the selector
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switch Structures (cont'd.)
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switch Structures (cont'd.)
• One or more statements may follow a case label
• Braces are not needed to turn multiple statements into a single compound statement
• The break statement may or may not appear after each statement
• switch, case, break, and default are reserved words
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switch Structures (cont'd.)
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Avoiding Bugs by Avoiding Partially
Understood Concepts and
Techniques: Revisited
• To output results correctly
– The switch structure must include a break
statement after each cout statement
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Terminating a Program with the assert Function
• Certain types of errors that are very
difficult to catch can occur in a program
– Example: division by zero can be difficult to
catch using any of the programming
techniques examined so far
• The predefined function, assert, is useful
in stopping program execution when
certain elusive errors occur
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The assert Function (cont'd.)
• Syntax:
expression is any logical expression
• If expression evaluates to true, the next statement executes
• If expression evaluates to false, the program terminates and indicates where in the program the error occurred
• To use assert, include cassert header file
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The assert Function (cont'd.)
• assert is useful for enforcing
programming constraints during program
development
• After developing and testing a program,
remove or disable assert statements
• The preprocessor directive #define
NDEBUG must be placed before the
directive #include <cassert> to
disable the assert statementC++ Programming: Program Design Including Data Structures, Fifth Edition 59
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Programming Example: Cable
Company Billing
• This programming example calculates a
customer’s bill for a local cable company
• There are two types of customers:
– Residential
– Business
• Two rates for calculating a cable bill:
– One for residential customers
– One for business customers
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Programming Example: Rates
• For residential customer:
– Bill processing fee: $4.50
– Basic service fee: $20.50
– Premium channel: $7.50 per channel
• For business customer:
– Bill processing fee: $15.00
– Basic service fee: $75.00 for first 10 connections/$5.00 for each additional one
– Premium channel cost: $50.00 per channel for any number of connections
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Programming Example:
Requirements
• Ask user for account number and
customer code
• Assume R or r stands for residential
customer and B or b stands for business
customer
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Programming Example: Input and
Output
• Input:
– Customer account number
– Customer code
– Number of premium channels
– For business customers, number of basic service connections
• Output:
– Customer’s account number
– Billing amount
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Programming Example: Program
Analysis
• Purpose: calculate and print billing amount
• Calculating billing amount requires:
– Customer for whom the billing amount is calculated (residential or business)
– Number of premium channels to which the customer subscribes
• For a business customer, you need:
– Number of basic service connections
– Number of premium channelsC++ Programming: Program Design Including Data Structures, Fifth Edition 64
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Programming Example: Program
Analysis (cont'd.)
• Data needed to calculate the bill, such as
bill processing fees and the cost of a
premium channel, are known quantities
• The program should print the billing
amount to two decimal places
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Programming Example: Algorithm
Design
• Set precision to two decimal places
• Prompt user for account number and customer type
• If customer type is R or r– Prompt user for number of premium channels
– Compute and print the bill
• If customer type is B or b– Prompt user for number of basic service
connections and number of premium channels
– Compute and print the bill
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Programming Example: Variables
and Named Constants
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Programming Example:
Formulas
Billing for residential customers:
amountDue = RES_BILL_PROC_FEES +
RES_BASIC_SERV_COST
+ numOfPremChannels *
RES_COST_PREM_CHANNEL;
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Programming Example: Formulas
(cont'd.)
Billing for business customers:
if (numOfBasicServConn <= 10)
amountDue = BUS_BILL_PROC_FEES +
BUS_BASIC_SERV_COST
+ numOfPremChannels *
BUS_COST_PREM_CHANNEL;
else
amountDue = BUS_BILL_PROC_FEES +
BUS_BASIC_SERV_COST
+ (numOfBasicServConn - 10)
* BUS_BASIC_CONN_COST
+ numOfPremChannels *
BUS_COST_PREM_CHANNEL;
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Programming Example: Main
Algorithm
1. Output floating-point numbers in fixed decimal with decimal point and trailing zeros
– Output floating-point numbers with two decimal places and set the precision to two decimal places
2. Prompt user to enter account number
3. Get customer account number
4. Prompt user to enter customer code
5. Get customer codeC++ Programming: Program Design Including Data Structures, Fifth Edition 70
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Programming Example: Main
Algorithm (cont'd.)
6. If the customer code is r or R,
– Prompt user to enter number of premium
channels
– Get the number of premium channels
– Calculate the billing amount
– Print account number and billing amount
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Programming Example: Main
Algorithm (cont'd.)
7. If customer code is b or B,
– Prompt user to enter number of basic service connections
– Get number of basic service connections
– Prompt user to enter number of premium channels
– Get number of premium channels
– Calculate billing amount
– Print account number and billing amount
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Programming Example: Main
Algorithm (cont'd.)
8. If customer code is other than r, R, b,
or B, output an error message
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Summary
• Control structures alter normal control flow
• Most common control structures are
selection and repetition
• Relational operators: ==, <, <=, >, >=, !=
• Logical expressions evaluate to 1 (true)
or 0 (false)
• Logical operators: ! (not), && (and), ||
(or)
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Summary (cont'd.)
• Two selection structures: one-way selection and two-way selection
• The expression in an if or if...elsestructure is usually a logical expression
• No stand-alone else statement in C++
– Every else has a related if
• A sequence of statements enclosed between braces, { and }, is called a compound statement or block of statements
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Summary (cont'd.)
• Using assignment in place of the equality
operator creates a semantic error
• switch structure handles multiway
selection
• break statement ends switch statement
• Use assert to terminate a program if
certain conditions are not met
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