caida inclinada

DISEÑO DE RAPIDAS (1)

DATOSCOTA A= 969.9 H= 1.5COTA B= 968.4

CANAL ENTRADA (1) CANAL SALIDA(2)b= 0.6 b= 0.6S= 0.003 S= 0.003n= 0.013 n= 0.014

Qd= 0.25 Qd= 0.12RAPIDA

Sr= 0.086 8.6 %n= 0.013

1.-CALCULO DEL TIRANTE NORMAL DE ENTRADA

n = rugosidad del materialR = radio hidráulicoA = área de la sección de canalS = pendiente del canal

Espejo de agua = bPerímetro mojado= b+2*y

Área Hidráulica= b*yRadio Hidráulico= (b*y)/(b+2*y)

ITERANDO

0.3373 m

0.2024

1.2746 m

0.1588 m

1.2353 m /s

0.4151 m

2.-CALCULO DEL ANCHO DE LA SECCION DE CONTROL

0.55 m0.5483

TIRANTE CRITICO

y1=

A1= m2

P1=

RHe=

Q=1n⋅R

23⋅A⋅S

12

V 1=QdA1

=

E1= y1+V12

2∗g=

B=√27∗Q28 (Emin )3∗g=

Yc=3√ Q2

B2∗g=

0.2762 m

VELOCIDAD CRITICA

1.6459 m/s

3.-LONGITUD DE ENTRADA DE LA RAPIDA

0.0604 m10 cm asumir longitud constructiva

4.- CALCULO DE LOS TIRANTES A LO LARGO DE LA RAPIDACalculo por el método tramos fijos

Longitud de la Rapida

alfa= 0.0858Longitud horizontal = 17.4419 Entonces= 17.5Tirante Normal Rapìd 0.1099 Calcular iterandoLR=longitud de la rapida

LR= 17.5062 redondear a entero18

planilla de calculo de los tirantes

Canal Rectangular

b 0.55 Delta Tirante 0.0333

s 0.086

n 0.013

Q 0.25

y (m) A (m2) P (m) Rh (m) V (m/s) V2/2g (m) E

0.2762 0.1519 1.1023 0.1378 1.646 0.1381 0.4142

0.2429 0.1336 1.0358 0.1290 1.871 0.1785 0.4214

0.2097 0.1153 0.9693 0.1190 2.168 0.2396 0.4492

0.1764 0.0970 0.9028 0.1075 2.577 0.3384 0.5148

0.1432 0.0787 0.8363 0.0941 3.175 0.5139 0.6570

Determinar y1 por tanteos

Yc=3√ Q2

B2∗g=

Vc=√ yc∗g=

LTe=b−B

2Tan(22.5 )=

f ( y2 )= y 2+ Q2

2∗g∗A22

+ ΔX∗Q2∗n2

2 ( P22A25

)23

C=So∗ΔX+ y1+Q2

2∗g∗A12

− ΔX∗Q2∗n2

2 ( P12A15

)23

SE=(V∗n

RH23 ) SFmedia=

SF e+SF s

2

0.1099 0.0604 0.7698 0.0785 4.136 0.8719 0.9818

ENTONCES0.1099

4.136

5.-CALCULO DEL BORDO LIBRE Y ALTURA TOTAL DE LA PARED

0.6908689

0.8008

0.5665812

0.80226

0.5993856

7.-CALCULO DE LA PROFUNDIDAD DE LA POZA

0.3142684 e= 0,35m

8.- LONGITUD DEL COLCHON DISCIPADORK=5

2.2834062

LP= 2,3m

y1

V1

6.-CALCULO DEL TIRANTE CONJUGADO (y2)

BL=0 .64+0.0371∗V∗√ y=h=BL+ y=

y2=− y12

+√ 2∗Q2

g∗y1∗B2+y12

4=

V 2=Qd

A2=

E2= y2+V22

2∗g=

e=1 ,15∗ y2− yn=

Lp=K ( y2− y1)=

Delt. E Sf Sf med So - Sm Delt. X Acum

…… 0.006433 …… …… …… 0.00

0.0071 0.009081 0.007757 -0.078243 -0.09 -0.09

0.0278 0.013577 0.011329 -0.074671 -0.37 -0.46

0.0656 0.021961 0.017769 -0.068231 -0.96 -1.43

0.1422 0.039785 0.030873 -0.055127 -2.58 -4.01

0.3248 0.085981 0.062883 -0.023117 -14.05 -18.05

DISEÑO DE RAPIDAS (2)DATOS

COTA A= 968.4 H= 2COTA B= 966.4



Sr= 0.0667 6.67 %n= 0.013





ITERANDO

0.3373 m

0.2024

1.2746 m

0.1588 m

1.2353 m /s

0.4151 m


0.55 m

0.5483 m

TIRANTE CRITICO

y1=

A1= m2

P1=

RHe=

Q=1n⋅R

23⋅A⋅S

12

V 1=QdA1

=

E1= y1+V12

2∗g=

B=√27∗Q28 (Emin )3∗g=

Yc=3√ Q2

B2∗g=

0.2762 m

VELOCIDAD CRITICA

1.6459 m/s


0.0604 mLte=10cm



alfa= 0.0666longitud horizontal = 29.9850 30.0000Tirante Normal Rapìd 0.1198 calcular iterandoLR=longitud de la rapida



Canal Rectangular


s 0.0667

n 0.013

Q 0.25


0.2762 0.1519 1.1023 0.1378 1.646 0.1381 0.4142

0.2449 0.1347 1.0398 0.1295 1.856 0.1756 0.4205

0.2136 0.1175 0.9772 0.1202 2.128 0.2308 0.4444

0.1823 0.1003 0.9147 0.1096 2.493 0.3167 0.4991

0.1511 0.0831 0.8521 0.0975 3.009 0.4614 0.6125

0.1198 0.0659 0.7896 0.0834 3.794 0.7337 0.8535


Yc=3√ Q2

B2∗g=

Vc=√ yc∗g=

LTe=b−B

2Tan (22.5 )=

f ( y2 )= y 2+ Q2

2∗g∗A22

+ ΔX∗Q2∗n2

2 ( P22A25

)23

C=So∗ΔX+ y1+Q2

2∗g∗A12

− ΔX∗Q2∗n2

2 ( P12A15

)23

SE=(V∗n

RH23 ) SFmedia=

SF e+SF s

2

ENTONCES0.1198

3.794


0.6887217

0.8085

0.5360833

0.8479008

0.5727263


0.2791958 e= 0,3 m

8.-LONGITUD DEL COLCHON DISCIPADORK=5

2.0814164

LP= 2,10m

y1

V1


BL=0 .64+0.0371∗V∗√ y=h=BL+ y=

y2=− y12

+√ 2∗Q2

g∗y1∗B2+y12

4=

V 2=Qd

A2=

E2= y2+V22

2∗g=

e=1 ,15∗ y2− yn=

Lp=K ( y2− y1)=


…… 0.006433 …… …… …… 0.00

0.0062 0.008883 0.007658 -0.059042 -0.11 -0.11

0.0239 0.012896 0.010890 -0.055810 -0.43 -0.53

0.0547 0.020012 0.016454 -0.050246 -1.09 -1.62

0.1134 0.034090 0.027051 -0.039649 -2.86 -4.48

0.2411 0.066718 0.050404 -0.016296 -14.79 -19.28

DISEÑO DE RAPIDAS (3 y 4)

DATOSCOTA A= 964.8 H= 2

Rápida 4COTA A= 966.5

COTA B= 962.8 COTA B= 964.5


Qd= 0.25 Qd= 0.25RAPIDASr 0.1 10n 0.013





ITERANDO

0.3373 m

0.2024

1.2746 m

0.1588 m

1.2353 m /s

0.4151 m


0.55 m (Redondeado)

0.5483 m

TIRANTE CRITICO

y1=

A1= m2

P1=

RHe=

Q=1n⋅R

23⋅A⋅S

12

V 1=QdA1

=

E1= y1+V12

2∗g=

B=√27∗Q28 (Emin )3∗g=

Yc=3√ Q2

B2∗g=

0.2762 m

VELOCIDAD CRITICA

1.6459 m/s


0.0604 m asumir longitud constructivaLte=10cm



alfa= 0.0997longitud horizontal = 20.0000 20.0000Tirante Normal Rapìd 0.1044 calcular iterandoLR=longitud de la rapida



Canal Rectangular


s 0.1

n 0.013

Q 0.25


0.2762 0.1519 1.1023 0.1378 1.646 0.1381 0.4142

0.2418 0.1330 1.0336 0.1287 1.880 0.1801 0.4219

0.2075 0.1141 0.9649 0.1183 2.191 0.2447 0.4521

0.1731 0.0952 0.8962 0.1062 2.626 0.3514 0.5245


Yc=3√ Q2

B2∗g=

Vc=√ yc∗g=

LTe=b−B

2Tan(22.5 )=

f ( y2 )= y 2+ Q2

2∗g∗A22

+ ΔX∗Q2∗n2

2 ( P22A25

)23

C=So∗ΔX+ y1+Q2

2∗g∗A12

− ΔX∗Q2∗n2

2 ( P12A15

)23

SE=(V∗n

RH23 ) SFmedia=

SF e+SF s

2

0.1388 0.0763 0.8275 0.0922 3.276 0.5470 0.6857

0.1044 0.0574 0.7588 0.0757 4.354 0.9662 1.0706

ENTONCES0.1044

4.354


0.6921916

0.7966

0.585137

0.7768189

0.6158937


0.3356075 e= 0.35


2.403685

LP= 2,5m

y1

V1

6.- CALCULO DEL TIRANTE CONJUGADO (y2)

BL=0 .64+0.0371∗V∗√ y=h=BL+ y=

y2=− y12

+√ 2∗Q2

g∗y1∗B2+y12

4=

V 2=Qd

A2=

E2= y2+V22

2∗g=

e=1 ,15∗ y2− yn=

Lp=K ( y2− y1)=


…… 0.006433 …… …… …… 0.00

0.0077 0.009193 0.007813 -0.092187 -0.08 -0.08

0.0302 0.013978 0.011586 -0.088414 -0.34 -0.43

0.0724 0.023160 0.018569 -0.081431 -0.89 -1.31

0.1612 0.043530 0.033345 -0.066655 -2.42 -3.73

0.3848 0.100090 0.071810 -0.028190 -13.65 -17.38

DISEÑO DE RAPIDAS Nº 1DATOS

H= 1.5



Sr= 0.086 8.6 %n= 0.013





ITERANDO

0.3373 m

0.2024

1.2746 m

0.1588 m

1.2353 m /s

0.4151 m


0.55 m0.5483

TIRANTE CRITICO

0.2762 m

y1=

A1= m2

P1=

RHe=

Q=1n⋅R

23⋅A⋅S

12

V 1=QdA1

=

E1= y1+V12

2∗g=

B=√27∗Q28 (Emin )3∗g=

Yc=3√ Q2

B2∗g=

VELOCIDAD CRITICA

1.6459 m/s


0.0604 m10 cm asumir longitud constructiva



alfa= 0.0858Longitud horizontal = 17.4419 Entonces= 17.5Tirante Normal Rapìd 0.1099 Calcular iterandoLR=longitud de la rapida

LR= 17.506218

planilla de calculo de los tirantes4.136

ENTONCES0.1099

4.1360


0.6909

0.8008


y1=

V1=


Yc=3√ Q2

B2∗g=

Vc=√ yc∗g=

LTe=b−B

2Tan(22.5 )=

f ( y2 )= y 2+ Q2

2∗g∗A22

+ ΔX∗Q2∗n2

2 ( P22A25

)23

C=So∗ΔX+ y1+Q2

2∗g∗A12

− ΔX∗Q2∗n2

2 ( P12A15

)23

SE=(V∗n

RH23 ) SFmedia=

SF e+SF s

2

BL=0 .64+0.0371∗V∗√ y=h=BL+ y=

y2=− y12

+√ 2∗Q2

g∗y1∗B2+y12

4=

0.5666

0.8023

0.5994


0.3143 e= 0,35m

8.- LONGITUD DEL COLCHON DISCIPADORK=5

2.2834

LP= 2,3m

y2=− y12

+√ 2∗Q2

g∗y1∗B2+y12

4=

V 2=Qd

A2=

E2= y2+V22

2∗g=

e=1 ,15∗ y2− yn=

Lp=K ( y2− y1)=

DISEÑO DE RAPIDAS Nº 2DATOS

H= 2



Sr= 0.0667 6.67 %n= 0.013





ITERANDO

0.3373 m

0.2024

1.2746 m

0.1588 m

1.2353 m /s

0.4151 m


0.55 m

0.5483 m

TIRANTE CRITICO

0.2762 m

y1=

A1= m2

P1=

RHe=

Q=1n⋅R

23⋅A⋅S

12

V 1=QdA1

=

E1= y1+V12

2∗g=

B=√27∗Q28 (Emin )3∗g=

Yc=3√ Q2

B2∗g=

VELOCIDAD CRITICA

1.6459 m/s


0.0604 mLte=10cm



alfa= 0.0666longitud horizontal = 29.9850 30.0000Tirante Normal Rapìd 0.1198 calcular iterandoLR=longitud de la rapida 3.794

LR= 30.051630


ENTONCES0.1198

3.794


0.6887

0.8085

0.5361


y1

V1


Yc=3√ Q2

B2∗g=

Vc=√ yc∗g=

LTe=b−B

2Tan (22.5 )=

f ( y2 )= y 2+ Q2

2∗g∗A22

+ ΔX∗Q2∗n2

2 ( P22A25

)23

C=So∗ΔX+ y1+Q2

2∗g∗A12

− ΔX∗Q2∗n2

2 ( P12A15

)23

SE=(V∗n

RH23 ) SFmedia=

SF e+SF s

2

BL=0 .64+0.0371∗V∗√ y=h=BL+ y=

y2=− y12

+√ 2∗Q2

g∗y1∗B2+y12

4=

0.8479

0.5727


0.2792 e= 0,3 m


2.0814

LP= 2,10m

y2=− y12

+√ 2∗Q2

g∗y1∗B2+y12

4=

V 2=Qd

A2=

E2= y2+V22

2∗g=

e=1 ,15∗ y2− yn=

Lp=K ( y2− y1)=

DISEÑO DE RAPIDAS (Nº3 y Nº4)DATOS

H= 2



Sr= 0.1 10 %n= 0.013





ITERANDO

0.3373 m

0.2024

1.2746 m

0.1588 m

1.2353 m /s

0.4151 m


0.55 m (Redondeado)

0.5483 m

TIRANTE CRITICO

0.2762 m

y1=

A1= m2

P1=

RHe=

Q=1n⋅R

23⋅A⋅S

12

V 1=QdA1

=

E1= y1+V12

2∗g=

B=√27∗Q28 (Emin )3∗g=

Yc=3√ Q2

B2∗g=

VELOCIDAD CRITICA

1.6459 m/s


0.0604 m asumir longitud constructivaLte=10cm



0.0997longitud horizontal = 20.0000 20.0000Tirante Normal Rapìd 0.1044 calcular iterandoLR=longitud de la rapida

LR= 20.0998 redondear a entero 4.35421


ENTONCES0.1044

4.354


0.6922

0.7966


y1=

V1=

6.- CALCULO DEL TIRANTE CONJUGADO (y2)

Yc=3√ Q2

B2∗g=

Vc=√ yc∗g=

LTe=b−B

2Tan(22.5 )=

f ( y2 )= y 2+ Q2

2∗g∗A22

+ ΔX∗Q2∗n2

2 ( P22A25

)23

C=So∗ΔX+ y1+Q2

2∗g∗A12

− ΔX∗Q2∗n2

2 ( P12A15

)23

SE=(V∗n

RH23 )

y2=− y12

+√ 2∗Q2

g∗y1∗B2+y12

4=

α=

h=BL+ y=

BL=0 .64+0.0371∗V∗√ y=

SFmedia=SF e+SF s

2

0.5851

0.7768

0.6159


0.3356 e= 0.35


2.4037

LP= 2,5m

y2=− y12

+√ 2∗Q2

g∗y1∗B2+y12

4=

V 2=Qd

A2=

E2= y2+V22

2∗g=

e=1 ,15∗ y2− yn=

Lp=K ( y2− y1)=

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