calculus-9/21/2011

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Calculus-9/21/2011 Objectives: Solve complex algebraic problems using laws of logs and exponents. Use the definition of log and exponent to switch between log and exponent form in an algebraic equation. Agenda •Do Now Laws of Logarithms Practice HW: Log Properties Handout UPCOMING- Test Moved to MONDAY instead of Friday!! Take Out: Do Now Sheet, Pencil, Homework DO NOW: Exponent laws handout Do these on answers out on your green sheet under Wednesday (because guess what it is Wednesday)

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Calculus-9/21/2011. Take Out: Do Now Sheet, Pencil, Homework. DO NOW: Exponent laws handout Do these on answers out on your green sheet under Wednesday (because guess what it is Wednesday). Agenda Do Now Laws of Logarithms Practice HW: Log Properties Handout - PowerPoint PPT Presentation

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Page 1: Calculus-9/21/2011

Calculus-9/21/2011

Objectives: Solve complex algebraic problems using laws of logs and exponents. Use the definition of log and exponent to switch between log and exponent form in an algebraic equation.

Agenda•Do Now•Laws of Logarithms•Practice•HW: Log Properties Handout

UPCOMING- Test Moved to MONDAY instead of Friday!!

Take Out: Do Now Sheet, Pencil, Homework DO NOW:

Exponent laws handout

Do these on answers out on your green sheet under Wednesday (because guess what it is Wednesday)

Page 2: Calculus-9/21/2011

Exponents, Logs

Objectives: Solve complex algebraic problems using laws of logs and exponents. Use the definition of log and exponent to switch between log and exponent form in an algebraic equation.

Page 3: Calculus-9/21/2011

Exponents

Exponents are repeated multiplication:

n times

Example:

bbbbbn ...

822223

Objectives: Solve complex algebraic problems using laws of logs and

exponents. Use the definition of log and exponent to switch between log and exponent form in an algebraic

equation.

Page 4: Calculus-9/21/2011

Rules for Exponents

nn

bb 1

Rule Example

81

212 3

3

10 b 120

mnmn bb

mnmn bbb 633 222

933 22

mnm

n

bbb 43

4

3

222 12

21

Objectives: Solve complex algebraic problems using laws of logs and exponents. Use the definition of log and exponent to switch between log and exponent form in an algebraic equation.

Page 5: Calculus-9/21/2011

Practice

?1 8

?171

?0 33 23

42

2

3

192

)1)2

)3)4

)5

)6

)7Objectives: Solve complex algebraic problems

using laws of logs and exponents. Use the definition of log and exponent to switch between log and exponent form in an algebraic equation.

Page 6: Calculus-9/21/2011

Objectives: Solve complex algebraic problems using laws of logs and exponents. Use the definition of log and exponent to switch between log and exponent form in an algebraic equation.

More Exponent Rules

nba nn ba nvw ba vnwn ba

2

22

ba

ba

nv

nwn

v

w

ba

ba

Page 7: Calculus-9/21/2011

Objectives: Solve complex algebraic problems using laws of logs and exponents. Use the definition of log and exponent to switch between log and exponent form in an algebraic equation.

Practice

332aa1

92

?3

2

3

632ba

)1

)2

)3

)4

Page 8: Calculus-9/21/2011

Objectives: Solve complex algebraic problems using laws of logs and exponents. Use the definition of log and exponent to switch between log and exponent form in an algebraic equation.

Common Mistakes

Page 9: Calculus-9/21/2011

Objectives: Solve complex algebraic problems using laws of logs and exponents. Use the definition of log and exponent to switch between log and exponent form in an algebraic equation.

ROOTS Roots don’t count as a separate category, because they are

just like exponents. We’ll see why in a second.

baba

ba

ba

41682

2428

28

Page 10: Calculus-9/21/2011

Objectives: Solve complex algebraic problems using laws of logs and exponents. Use the definition of log and exponent to switch between log and exponent form in an algebraic equation.

Root – Exponent Connection

nn aa /1 288 33/1

nmm nmn aaa / 3/553 66

Page 11: Calculus-9/21/2011

Objectives: Solve complex algebraic problems using laws of logs and exponents. Use the definition of log and exponent to switch between log and exponent form in an algebraic equation.

Practice

21

16

3/12a2/1

2

4

3 42 gg

Page 12: Calculus-9/21/2011

Objectives: Solve complex algebraic problems using laws of logs and exponents. Use the definition of log and exponent to switch between log and exponent form in an algebraic equation.

Logs

I want you to be able to use logs to solve for a variable.

Things to Remember…If you have an exponential equation with a #

base use logs to solve.If you have an exponential equation with

base e use natural log (ln) to solve.

Page 13: Calculus-9/21/2011

Objectives: Solve complex algebraic problems using laws of logs and exponents. Use the definition of log and exponent to switch between log and exponent form in an algebraic equation.

Logs

Basic Definition of a log:

cab bca log

8log2 3

9log3 2

xgg 3log

3x

3gg x

Page 14: Calculus-9/21/2011

Objectives: Solve complex algebraic problems using laws of logs and exponents. Use the definition of log and exponent to switch between log and exponent form in an algebraic equation.

More Log Rules-Inverse Properties

baa log bb

a alog b

BASE a: BASE e:

xe ln x

xeln x

Page 15: Calculus-9/21/2011

Objectives: Solve complex algebraic problems using laws of logs and exponents. Use the definition of log and exponent to switch between log and exponent form in an algebraic equation.

How can we use this in an algebraic context? Whenever the variable you are looking for is in the

exponent, we need to use logs

43 xe4loglog 3

ex

e e 4lnln 3 xe4ln3 x

3/4lnx

Page 16: Calculus-9/21/2011

Objectives: Solve complex algebraic problems using laws of logs and exponents. Use the definition of log and exponent to switch between log and exponent form in an algebraic equation.

Example 2-using inverse property

100105 y

100log10log 105

10 y

100log5 10y 2

52

y

Page 17: Calculus-9/21/2011

Example 3- Using Change of Base Rule

1629 z

16log2log9 z

2log16log

2log2log9 z

9449

z

z

Objectives: Solve complex algebraic problems using laws of logs and

exponents. Use the definition of log and exponent to switch between log and

exponent form in an algebraic equation.

Page 18: Calculus-9/21/2011

Objectives: Solve complex algebraic problems using laws of logs and exponents. Use the definition of log and exponent to switch between log and exponent form in an algebraic equation.

Practice-Now you try either use change of base or inverse property to solve for x

1) e2x = 10

2) 54x + 1 = 15

3) 5 ex + 1 = 30

4) ex/5 + 4 = 7

5) 32x = 40

Page 19: Calculus-9/21/2011

Objectives: Solve complex algebraic problems using laws of logs and exponents. Use the definition of log and exponent to switch between log and exponent form in an algebraic equation.

Rules of Logarithms Since a logarithm is simply an exponent which is just

being written down on the line, we expect the logarithm laws to work the same as the rules for exponents, and luckily, they do

Exponents Logarithms

bm × bn = bm+n logb xy = logb x + logb y

bm ÷ bn = bm-n logb (x/y) = logb x − logb y

(bm)n = bmn logb (xn) = n logb x

b1 = b logb (b) = 1

b0 = 1 logb (1) = 0

Page 20: Calculus-9/21/2011

Objectives: Solve complex algebraic problems using laws of logs and exponents. Use the definition of log and exponent to switch between log and exponent form in an algebraic equation.

Example 1 3)3(log)1(log 22 xx

3)3)(1(log 2 xx

)3)(1(23 xx

348 2 xx540 2 xx

1,5 x

Apply product property

Change into exponential form to solve

Simplify

Reduce 1 side to zero to solve the quadraticFactor

Solutions!!

)1)(5(0 xx

Page 21: Calculus-9/21/2011

Objectives: Solve complex algebraic problems using laws of logs and exponents. Use the definition of log and exponent to switch between log and exponent form in an algebraic equation.

Example 2 8)9ln( 4 x

8)9ln(4 x

48)9ln(4 x

29log xe

2)9ln( x

92 xe

9389.7 x

389.16x

Page 22: Calculus-9/21/2011

Objectives: Solve complex algebraic problems using laws of logs and exponents. Use the definition of log and exponent to switch between log and exponent form in an algebraic equation.

Example 3 3)4(log)12(log 22 xx

34)12(log 2

xx

41223

xx

4128

xx

12328 xx

316 x

631

x

Product Property of Logs

Switch into exponential form

Simplify

Get rid of the fraction by multiplying (x-4)

Solve for x