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CALENDAR

1. January 1, 1995 was a Sunday, what day of the week lies on January

1, 1999?

Ans:Monday

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Division Method

Answer with Explanation:

• 1995 being on ordinary year, it has 1 odd day.

• So, the first day of 1996 will be one day beyond Sunday.

• Therefore it will be Monday.

Calender sums, BU www.aptitudecoach.com

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2. On 8th Feb 1995 it was Wednesday. The day of the week of the week

on 8th Feb 1994 was

ans: Tuesday


Basic Formula:

Division Method


• 1994 being on ordinary year, it has 1 odd day.

• So, the day on 8th Feb 1994 is one day beyond the day on 8th Feb, 1994.

• But, 8th Feb 1995 was Wednesday.

• Therefore 8th Feb, 1994 was Tuesday.


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3. January 1, 1992 was Wednesday, what day of the week was on

January 1, 1993?

Ans:Friday


Basic Formula:

Division of 4


• 1992 being a leap year

• ∴ It has 2 odd days

• So, the first day of the year 1993 must be two days beyond Wednesday.

• ∴ it was Friday.


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4. May 6, 1993 was Thursday, What day of the week on May 6, 1992?

Ans:Tuesday


Basic Formula:

Division of 4


• 1992 being a leap year

• ∴ It has 2 odd days

• So, the day on May, 1993 is 2 days beyond the day on may 6, 1992.

• But, on may 6, 1993 it was Thursday

• So, on May 6, 1992 it was Tuesday


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5. Monday falls on 20th March, 1995. What was the day on 3rd

November, 1994?

Ans:Thursday


Basic Formula:

Addition


Counting the number of days after 3rd November, 1994, we have

Nov Dec Jan Feb March

27 + 31 + 31 + 28 + 20 = 137 days

= 19 weeks + 4 days

∴Number of odd days = 4

∴ The day on 3rd November, 1994 is (7-4) days beyond the day on 20 th March

1995.

So the day is Thursday.


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6. Today is Tuesday, after 62 days it will be

Ans:Monday


Basic Formula:

Addition


• Each day of the week is repeated after 7 days

• ∴After 63 days, it will be Tuesday

• ∴After 62 days, it will be Monday.


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7. Today is 1st April. The day of the week is Wednesday. This is a leap

years. The day of the week on this day after 3 years will be

ans:Saturday


Basic Formula:

Addition


• This being a leap year, none of the next 3 years is a leap year.

• So, the day of the week will be 3 days beyond Wednesday.

• ∴The day after 3 years will be Saturday.


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8. The year next to 1996 having the same calendar as that of 1996 is

Ans:2001


Basic Formula:

Divide by 4


Starting with 1996, we go on counting the number of odd days till thesum is divisible by 7

Year 1996 1997 1998 1999 2000 Total

Odd

days

2 1 1 1 2 7

7/7 = 0 odd day

∴

Calender for 2001 will be the same as that of 1995.


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9. How many days are there from 2nd January 1995 to 15th March 1995?

Ans73


Basic Formula:

Basic Addition


Jan Feb March

30 + 28 + 15 = 73 days.


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10.The first republic day of India was celebrated on 26 th January, 1950, it

was

Ans”Thursday


Basic Formula:

Division


Step 1 : 1950 / 7 = 4 remainder

Step 2 : 1950/4 = 487 ½

487 /7 = 69 4/7

= 4 remainder

Step 3 : 26/7 = 5 remainder

Step 4 : Month Code= 0

Ordinary year ⇒ :7

20544 −+++

= 11/7 = 1 4/7

∴ 4 odd day means Thursday


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11.What was the day of the week on 28th Feb 1995?

Ans: Tuesday


Basic Formula:

Ordinary leap year =7

2−+++ DC B A



Step 2 : 1995/4 = 498 3/4

498 /7 = 1 remainder




23010 −+++

= 2/7

∴ 2 odd day means Tuesday


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12. What will be the day of the week on 1st Jan 2001?

Ans: Sunday


Basic Formula:

Ordinary leap year =7

2−+++ DC B A



Step 2 : 2001/4 = 500 1/4

500 /7 = 3 remainder




20136 −+++

= 8/7 = 1 1/7

∴ 1 odd day means Monday.


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13.If the first day of the year 1991 was Tuesday, what day of the week

must have been on 1st January 1998?

Ans”Thursday


Basic Formula:

Addition


Total number of odd days from 1st Jan 1001 to 1 Jan 1998

Year 1991 1992 1993 1994 1995 1996 1997 Total

Odd

days

1 2 1 1 1 2 1 9

That is (9-7) =2 odd days

∴ the day is 2 days beyond the day on 1st Jan 1991

The required day must be Thursday.


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14.On what dates of April, 1994 did Sunday fall?

Ans: 3,10,17,24


Basic Formula:


First, we find the day on 1st April 1994

1600 years contain 0 odd day

300 years contain 1 odd day.

93 years = (23 leap years + 70 ordinary years)

= (46 + 70) odd days

= 4 odd days.

Number of days upto 1st April, 1994

Month Jan Feb March April Total

days 31 28 31 1 91 0 odd day

∴ Total number of odd days = (0+1+4+0) = 5 odd day

∴Day on 1st April 1994 is Friday

∴ Sunday was on 3rd, 10th, 17th and 24th.


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15.The calendar for 1990 is the same as for ?

Ans: 1996


Basic Formula:

Division


First we count the number of days for 1990 onwards to get 0 odd day

Year 199

0

1991 1992 1993 1994 1995 Total Odd

day

Odd

days

1 1 2 1 1 1 7 0

∴Calender for 1990 is the same as for the Year 1996.


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16.The day on 5th March of a year is the same day on what date of the

same year?

Answer : 5th November


Basic Formula:

Division


Since any date in March is the same day of the week as thecorresponding date in November of that year.

So, the same day falls on 5th November.


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