ccna drag and drop questions

8/15/2019 Ccna Drag and Drop Questions

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ccna-drag-and-drop-questions

Question 1:

A dental firm is redesigning the network that connects its three locations. The administrator gave the networking team 192.168.164.0 to use for addressing the entire netwok. After subnetting

the address the team is read! to assign the addresses. The administrator "lans to configure i" subnet#$ero and use %&' v2 as the routing "rotocol. As a member of the networking team !ou

must address the network and at the same time conserver unused addresses for future growth. (ith those goals in mind drag the host addresses on the left to the correct router interface.

)nce of the routers is "artiall! configured. *ove !our mouse over a router to view its configuration. +ot all of the host addresses on the left are necessar!.

Answer:

Explanation:

&n short we should start calculating from the biggest network ,with 16 hosts- to the smallest one using the formula 2 n # 2 ,n is the number of bits we need to borrow-.Therefore

16 hosts / 2 # 2 ,we need to borrow bits # 23-

11 hosts / 24 # 2 ,borrow 4 bits # 28-

hosts / 2 # 2 ,borrow bits # 29-

5rom the available i" addresses we see that each of them has onl! one suitable solution ,the! are 192.168.164.14923192.168.164.16628 and 192.168.164.13829-

The smallest network is the 5loss 00 which onl! re7uires 2 hosts 22 # 2 ,need to borrow 2 bits #0-. There are 2 suitable answers 192.168.164.1890 and 192.168.164.1880 but notice

that 192.168.164.1880 is the network address so we can not use it ,because 188 4 43- # we have to choose 192.168.164.189 as the correct solution.

&n fact it is not the formal wa! to solve a :;* 7uestion so & recommend !ou to review !our


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Answer:

1- enable

2- configure terminal

- hostname

4- &nterface vlan 1

- no shutdown

6- i" address

3- i" default#gatewa!

Question 3:

The *issouri branch office router is connected through its s0 interface to the Alabama >ead7uarters router s1 interface. The Alabama router has two ;A+s. *issouri users obtain &nternet

access through the >ead7uarters router. The network interfaces in the to"olog! are addressed as follows Missouri e0 - 192.168.35.17/28? s0 - 192.168.35.33/28? Alaa!a e0 -

192.168.35."9/28 ? e1 - 192.168.35.65/28? s1 - 192.168.35.3"/28. The accounting server has the address of 192.168.35.66/28 . *atch the access list conditions on the left with the goals on the

right. ,+ot all o"tions on the left are used.-

Answer:

1- den! i" 192.168..16 0.0.0.1 host 192.168..66

2- den! i" 192.168.. 0.0.0.0 host 192.168..66


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- "ermit i" 192.168..0 0.0.0.2 host 192.168..66

Explanation:

1- The wildcard mask of the command @den! i" 192.168..16 0.0.0.1 host 192.16..66@ is 0.0.0.1 which is e7ual to network mask of 2.2.2.240 28. o the access list will den! all

traffic from network 192.168..1628 from accessing host 192.16..66 which is the &' address of accounting server.

2- The command @den! i" 192.168.. 0.0.0.0 host 192.168..66@ will den! host 192.168.. which is a user and belongs to interface e0 of Alabama router ,192.168..4928- from

accessing accounting server.

- ecause there is an im"licit @den! all@ command at the end of each access list so the command @"ermit i" 192.168..0 0.0.0.2 host 192.168..66@ will onl! let network 192.168..024

access accounting server whilst "revent traffic from other networks.

Question ":

A host with the address of 192.168.12.423 needs to be denied access to all hosts outside its own subnet. To accom"lish this com"lete the command in brackets #a$$ess-list 100 %en&

protocol address mask an&' b! dragging the a""ro"riate o"tions on the left to their correct "laceholders on the right.

Answer:

1- i"

2- 192.168.12.4

- 0.0.0.0

5ull command a$$ess-list 100 %en& ip 192.168.125.3" 0.0.0.0

Question 5:

Brag and dro" the network user a""lication to the a""ro"riate descri"tion of its "rimar! use ,not all o"tions are used-


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Answer:

1- web browser

2- instant message

- e#mail

4- database

- collaboration

Question 6:

This to"olog! contains routers and 1 switch.


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+ote ecause routes are not being added to the configurations !ou will not be able to "ing through the internetwork.

All devices have cable autosensing ca"abilities disabled.

All hosts are '


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Detail Explanation

(p%ate% )ro! real A exa! on an-09-2010

This to"olog! contains routers and 1 switch. int use the given host addresses and *ain router information-

To remove a device or connection drag it awa! from the to"olog!.

(se in)or!ation *at+ere% )ro! t+e Main router to $o!plete t+e $on)i*uration o) an& a%%itional routers. +o "asswords are re7uired to access the *ain router. The config terminal

command has been disabled for the >C router. The router does not re7uire an! configuration.


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ote: e$ause routes are not ein* a%%e% to t+e $on)i*urations &ou will not e ale to pin* t+rou*+ t+e internetwor.

All devices have cable autosensing ca"abilities disabled.

All hosts are '


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,>ost B and host F will be automaticall! added after "lacing two routers. ost erver

roup 2: >ub witch

)ne device in grou" 1 G )ne device in grou" 2 use strai*+t-t+rou*+ $ale

Two devices in the same grou" use $rosso,er $ale

5or eEam"le we use straight#through cable to connect switch to router switch to host hub to host hub to server... and we use crossover cable to connect switch to switch switch to hub router

to router host to host... -


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Assign a""ro"riate &' addresses for interfaces

5rom *ain router use s+ow runnin*-$on)i* command

(Notice that you may see different IP addresses in the real CCNA exam, the ones shown above are just used for demonstration)

5rom the out"ut we learned that the i" address of 5a00 interface of the *ain router is 192.168.12.13328. This address belongs to a subnetwork which has

n$re!ent: 16 ,28 2.2.2.240 or 1111 1111.1111 1111.1111 1111.1111 0000-

etwor a%%ress 192.168.12.136 ,because 136 16 11 and 136 / 133-

roa%$ast a%%ress: 192.168.12.191 ,because 191 136 G 16 # 1-

And we can "ick u" an i" address from the list that belongs to this subnetwork 192.168.152.190 and assign it to the 5a00 interface the router on the left

Hse the same method for interface erial00 with an i" address of 192.168.12.161

n$re!ent: 16

etwor a%%ress: 192.168.12.160 ,because 160 16 10 and 160 / 161-


# and we choose 192.168.152.17" for erial00 interface of the router on the right

nter)a$e ;a0/1 o) t+e router on t+e le)t

&' ,of the com"uter on the left- 192.168.12.12928

n$re!ent: 16



# we choose 192.168.152.1"2 from the list

nter)a$e ;a0/0 o) t+e router on t+e ri*+t

&' ,of the com"uter on the left- 192.168.12.2228

n$re!ent: 16



# we choose 192.168.152.238 from the list

;et=s have a look at the "icture below to summari$e


10/11

enale

=outer1?$on)i*ure ter!inal

=outer1$on)i*?inter)a$e )a0/0

=outer1$on)i*-i)?ip a%%ress 192.168.152.190 255.255.255.2"0

=outer1$on)i*-i)?no s+ut%own

=outer1$on)i*-i)?inter)a$e )a0/1

=outer1$on)i*-i)?ip a%%ress 192.168.152.1"2 255.255.255.2"0

=outer1$on)i*-i)?no s+ut%own

et "asswords ,configure on two routers-

G onsole passwor%:

=outer1$on)i*-i)?exit

=outer1$on)i*?line $onsole 0

=outer1$on)i*-line?passwor% $onsolepw

=outer1$on)i*-line?lo*in

=outer1$on)i*-line?exit

G @elnet passwor%:


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=outer1$on)i*?line ,t& 0 "

=outer1$on)i*-line?passwor% telnetpw

=outer1$on)i*-line?lo*in

=outer1$on)i*-line?exit

G 4ri,ile*e !o%e passwor%:

=outer1$on)i*?enale passwor% pri,pw

a,e t+e $on)i*uration:

=outer1$on)i*?exit

=outer1?$op& runnin*-$on)i* startup-$on)i*

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