ch 2 matter & atoms

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Ch 2 Matter & Atoms Natural Approach to Chemistry Lab Aids Condensed 2.1 Frames 2-28 2.2 Frames 29-62 2.3 Fr. 63-106

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Ch 2 Matter & Atoms. Natural Approach to Chemistry Lab Aids Condensed. 2.1 Frames 2-282.2 Frames 29-62 2.3 Fr. 63-106. 2.1 Matter & the Elements. Standards: SC.912.P.8.5 relate properties of atoms & their position in the periodic table to the arrangement of their electrons - PowerPoint PPT Presentation

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Page 1: Ch 2 Matter & Atoms

Ch 2 Matter & Atoms

Natural Approach to ChemistryLab Aids

Condensed

2.1 Frames 2-28 2.2 Frames 29-62 2.3 Fr. 63-106

Page 2: Ch 2 Matter & Atoms

2.1 Matter & the Elements

• Standards:• SC.912.P.8.5 relate properties of atoms & their

position in the periodic table to the arrangement of their electrons

• SC.912.P.8.9 apply the mole concept and the law of conservation of mass to calculate quantities of chemicals participating in reactions

Page 3: Ch 2 Matter & Atoms

The “stuff” that we are made of is called matter.

Chemistry tells us how one kind of matter can be changed into a completely different kind of matter.

What are things made of?

Page 4: Ch 2 Matter & Atoms

substance: a kind of matter that can’t be separated into other substances by physical means such as heating, cooling, filtering, drying, sorting, or dissolving.

Corn oil is a pure substance

Page 5: Ch 2 Matter & Atoms

mixture: matter that contains more than one substance.

Corn oil is a pure substance

Oil and vinegar dressing is a mixture of substances

Page 6: Ch 2 Matter & Atoms

Examples: MassDensityColor

Physical properties can be measured or seen through direct observations.

Physical properties

Page 7: Ch 2 Matter & Atoms

Physical changes include changes in shape, phase or temperature.

Page 8: Ch 2 Matter & Atoms
Page 9: Ch 2 Matter & Atoms

Chemical properties are observed when a substance changes into a different substance.

Iron RustChemical change

Page 10: Ch 2 Matter & Atoms

Signs that a

chemical change has occurred

Page 11: Ch 2 Matter & Atoms

Each element is a unique type of atom.

All oxygen atoms are identical.

An oxygen atom is different from a silicon atom or a potassium atom.

element: a substance that cannot be separated into simpler substances by chemical means.

Page 12: Ch 2 Matter & Atoms

1 grain of rice = 0.01 gram

1 hydrogen atom = 1.678 x 10–24 grams

= 0.000000000000000000000001678 grams

How small is an atom?

Page 13: Ch 2 Matter & Atoms

The periodic table

Page 14: Ch 2 Matter & Atoms
Page 15: Ch 2 Matter & Atoms

The periodic table organizes elements according to how they combine with other elements (based on their chemical properties).

Page 16: Ch 2 Matter & Atoms
Page 17: Ch 2 Matter & Atoms

HydrogenLightest elementAtomic number: 1

UraniumHeaviest naturally occurring elementAtomic number: 92

Increasing atomic number

Incr

easin

g at

omic

num

ber

Page 18: Ch 2 Matter & Atoms

Elements that belong to the same group (column) have similar chemical properties.

Page 19: Ch 2 Matter & Atoms

Reminder

1 atomic mass unit (amu) = 1.66 x 10-24 g

Page 20: Ch 2 Matter & Atoms

The atomic mass is the mass of:

1) a single atom in amu.

2) a mole of atoms in grams.

One single hydrogen atom weighs 1.01 amu.

One mole of hydrogen atoms weighs 1.01 g.

What does that mean?

Page 21: Ch 2 Matter & Atoms

The atomic mass is the mass of:

1) a single atom in amu.

2) a mole of atoms in grams.

One single carbon atom weighs 12.0 amu.

One mole of carbon atoms weighs 12.0 g.

What does that mean?

Page 22: Ch 2 Matter & Atoms

One mole contains 6.02 x 1023 atoms

Avogadro’s number

Page 23: Ch 2 Matter & Atoms

How many moles are in 100 g of sulfur (S)?

Page 24: Ch 2 Matter & Atoms

How many moles are in 100 g of sulfur (S)?

Asked: The number of molesGiven: The element is sulfur and there are 100 gRelationships: One mole of sulfur has a mass of 32.065 g

Page 25: Ch 2 Matter & Atoms

How many moles are in 100 g of sulfur (S)?

Asked: The number of molesGiven: The element is sulfur and there are 100 gRelationships: One mole of sulfur has a mass of 32.065 g

Solve:

Answer: 100 g of sulfur contains 3.12 moles of sulfur atoms.

110032.065

3.12mole Sg Sg S

moles S

Page 26: Ch 2 Matter & Atoms

How many grams of calcium (Ca) do you need to have 2.50 moles of calcium?

Asked: The number of gramsGiven: The element is calcium and there are 2.50 molesRelationships: One mole of calcium has a mass of 40.078 g

Page 27: Ch 2 Matter & Atoms

How many grams of calcium (Ca) do you need to have 2.50 moles of calcium?

Asked: The number of gramsGiven: The element is calcium and there are 2.50 molesRelationships: One mole of calcium has a mass of 40.078 g

Solve:

Answer: 2.50 moles of calcium has a mass of 100. g.

40.0782.501

100.2g Camoles Camole Ca

g Ca

Page 28: Ch 2 Matter & Atoms

Physical properties can be seen and measured

Chemical properties are observed when one substance is changed into another

Elements are organized in a periodic table This allows to convert

grams to moles and vice versa.

Page 29: Ch 2 Matter & Atoms

2.2 Molecules and Compounds

Sc.912.P.8.7 interpret formula representations of molecules and compounds in terms of composition and structure.Sc.912.P.8.9 mole concept and law of conservation of mass

Page 30: Ch 2 Matter & Atoms

One H2 moleculeOne O2 molecule

molecule: a group of atoms chemically bonded together.

Page 31: Ch 2 Matter & Atoms

molecule: a group of atoms chemically bonded together.

compound: a substance containing more than one element in which atoms of different elements are chemically bonded together.

One H2O moleculeOne H2 moleculeOne O2 molecule

Page 32: Ch 2 Matter & Atoms

What do all these have in common?

Page 33: Ch 2 Matter & Atoms

What do all these have in common?

They are made up of only 3 types of atoms: carbon, oxygen and hydrogen.

Page 34: Ch 2 Matter & Atoms

More than 200,000 words in the English language

Trillions of substances that make up the universe

The alphabet of chemistry

Page 35: Ch 2 Matter & Atoms

The chemical formula

Page 36: Ch 2 Matter & Atoms

The chemical formula

Page 37: Ch 2 Matter & Atoms

Write a chemical formula for a compound that has three hydrogen (H) atoms for each atom of nitrogen (N).

Page 38: Ch 2 Matter & Atoms

Write a chemical formula for a compound that has three hydrogen (H) atoms for each atom of nitrogen (N).

Asked: Chemical formulaGiven: 3 hydrogen (H) and 1 nitrogen (N)Relationships: The subscript tells the number of each element in the

compound.

Page 39: Ch 2 Matter & Atoms

Write a chemical formula for a compound that has three hydrogen (H) atoms for each atom of nitrogen (N).

Asked: Chemical formulaGiven: 3 hydrogen (H) and 1 nitrogen (N)Relationships: The subscript tells the number of each element in the

compound.Answer: NH3

Page 40: Ch 2 Matter & Atoms

The properties of a compound depend more on the exact structure of the molecule

than on the individual elements from which it is made.

Page 41: Ch 2 Matter & Atoms

F

U

N

E

RA

L

F U N E R A L F U NER A L

The arrangement of letters matters!

Page 42: Ch 2 Matter & Atoms

The arrangement of atoms matters!

Page 43: Ch 2 Matter & Atoms

Representation

There are many ways of representing the same thing.

Page 44: Ch 2 Matter & Atoms

Representation

Page 45: Ch 2 Matter & Atoms

Ionic compounds

Salt (NaCl) is not a molecule!

Page 46: Ch 2 Matter & Atoms

ionic compound: a compound such as a salt in which positive and negative ions attract each other to keep matter together.

ion: an atom or small molecule with an overall positive or negative chare as a result of an imbalance of protons and electrons.

Page 47: Ch 2 Matter & Atoms

Formula mass

The formula mass of water (H2O) is 18 g.

Page 48: Ch 2 Matter & Atoms

What is the mass of 1 mole of methane (CH4)?

Page 49: Ch 2 Matter & Atoms

What is the mass of 1 mole of methane (CH4)?

Asked: The mass of 1 mole of methane

Given: Methane (CH4) contains 1 carbon (C) and 4 hydrogen (H) atoms

Relationships: The formula mass is the sum of the atomic masses for each atom in the compound

Page 50: Ch 2 Matter & Atoms

What is the mass of 1 mole of methane (CH4)?

Asked: The mass of 1 mole of methane

Given: Methane (CH4) contains 1 carbon (C) and 4 hydrogen (H) atoms

Relationships: The formula mass is the sum of the atomic masses for each atom in the compound

Solve:

Answer: One mole of methane (CH4) has a mass of 16.04 g. 44 4 1.0079 12.0 16.0411 g CH

moH

eC

l

Page 51: Ch 2 Matter & Atoms

How many moles are in 100 grams of water (H2O)?

Page 52: Ch 2 Matter & Atoms

How many moles are in 100 grams of water (H2O)?

Asked: The moles in 100 g of water

Given: Water (H2O) contains 2 hydrogen (H) atoms and 1 oxygen (O)

atom.

Relationships: The formula mass is the sum of the atomic masses for each atom in the compound.

Page 53: Ch 2 Matter & Atoms

How many moles are in 100 grams of water (H2O)?

Asked: The moles in 100 g of water

Given: Water (H2O) contains 2 hydrogen (H) atoms and 1 oxygen (O)

atom.

Relationships: The formula mass is the sum of the atomic masses for each atom in the compound.

Solve:

Answer: 100 g of water (H2O) contains 5.55 moles.

2

5

2 2 1.0079 15.999 18.015

110018.01

55

. 5

gH O H Omole

molegg

moles

Page 54: Ch 2 Matter & Atoms

How many grams are in 2.300 moles of butane (C4H10)? Butane is used as a lighter fluid in disposal lighter.

Page 55: Ch 2 Matter & Atoms

How many grams are in 2.300 moles of butane (C4H10)? Butane is used as a lighter fluid in disposal lighter.

Asked: The mass in grams of 2.300 moles of butane

Given: 2.300 moles of C4H10

Relationships: The formula mass is the sum of the atomic masses for each atom in the compound.

Page 56: Ch 2 Matter & Atoms

How many grams are in 2.300 moles of butane (C4H10)? Butane is used as a lighter fluid in disposal lighter.

Asked: The mass in grams of 2.300 moles of butane

Given: 2.300 moles of C4H10

Relationships: The formula mass is the sum of the atomic masses for each atom in the compound.

Solve:

Answer: 133.7 g are in 2.300 moles of butane (C4H10).

4 1

2

4 10

00

4 1

4 10 4 12.011 10 1.0079 58.12

133.7

3

58.1232.300

1

gH O H Omole

g C Hgmo

gle mole C

C HH

Page 57: Ch 2 Matter & Atoms

How many oxygen atoms are in 200.0 g of glucose (C6H12O6)?

Asked: Number of oxygen atoms

Given: 200.0 g of C6H12O6

Relationships: Formula mass of glucose:

6 12 6

6 12.011 12 1.0079 6 15.9 19 80.159

C Og

m e

H

ol

Remember: Avogadro’s number indicates that one mole contains 6.02 x 1023 atoms

Page 58: Ch 2 Matter & Atoms

Solve: First we find how many moles are in 200.0 g of glucose:

6 12 66 12 6

6 16 12 6

2 6

1200.0

180.1.11

150

mole C molesH O Cg C H Og H

H OC O

Page 59: Ch 2 Matter & Atoms

Solve: First we find how many moles are in 200.0 g of glucose:

Next we find how many molecules are contained in 1.11 moles of glucose:

6 12 66 12 6 6 12 6

6 12 6

1200.0 1.110

180.15mole C H Og C H O moles C H O

g C H O

236 12

2

66 12 6

6 12 6

36 12 6

6.022 101.110

1

6.684 10

molecules C H Omoles C H

molecules

O

C

mole C

O

H O

H

Page 60: Ch 2 Matter & Atoms

Solve: First we find how many moles are in 200.0 g of glucose:

Next we find how many molecules are contained in 1.11 moles of glucose:

Then we find how many O atoms are contained in 6.684 x 1023 molecules of glucose:

6 12 66 12 6 6 12 6

6 12 6

1200.0 1.110

180.15mole C H Og C H O moles C H O

g C H O

236 12 6

6 12 66 12 6

236 12 6

6.022 101.110

1

6.684 10

molecules C H Omoles C H Omole C H O

molecules C H O

236 12 6

6 1 6

24

2

4.66.684 101

010 10O atomsmolecules C H Omolecule C H O

O atoms

Page 61: Ch 2 Matter & Atoms

Solve: First we find how many moles are in 200.0 g of glucose:

Next we find how many molecules are contained in 1.11 moles of glucose:

Then we find how many O atoms are contained in 6.684 x 1023 molecules of glucose:

Answer: There are 4.010 x 1024 atoms of O in 200.0 g of glucose (C6H12O6).

6 12 66 12 6 6 12 6

6 12 6

1200.0 1.110

180.15mole C H Og C H O moles C H O

g C H O

236 12 6

6 12 66 12 6

236 12 6

6.022 101.110

1

6.684 10

molecules C H Omoles C H Omole C H O

molecules C H O

236 12 6

6 1 6

24

2

4.66.684 101

010 10O atomsmolecules C H Omolecule C H O

O atoms

Page 62: Ch 2 Matter & Atoms

We can build compounds using atoms- The type of atom matters

- The arrangement of atoms also matters

We can calculate the formula mass of compounds:

Page 63: Ch 2 Matter & Atoms

2.3 Mixtures and Solutions

Sc.912.P.8.9 mole concept and law of conservation of massSc.912.P.12.12 explain how various factors such as concentration, temperature, and presence of a catalyst affect the rate of a chemical reaction

Page 64: Ch 2 Matter & Atoms

CHAPTER 2

Matter and Atoms

2.3 Mixtures and Solutions

Page 65: Ch 2 Matter & Atoms

A recipe calls for you to “mix until homogeneous.”

What does that mean?

Page 66: Ch 2 Matter & Atoms

A mixture that is uniform throughout.

Page 67: Ch 2 Matter & Atoms

A mixture that is uniform throughout. Different samples may have different compositions.

Page 68: Ch 2 Matter & Atoms
Page 69: Ch 2 Matter & Atoms

What happens when sugar is added to water?

Page 70: Ch 2 Matter & Atoms

What happens when sugar is added to water?

A solution is obtained.

Page 71: Ch 2 Matter & Atoms

Is orange juice a solution?

Hint: Are things dissolved in orange juice?

Page 72: Ch 2 Matter & Atoms

Is orange juice a solution?

It is partially a solution because some chemicals are dissolved in water, but some bits (like pulp) are not.

Page 73: Ch 2 Matter & Atoms

These four solutions contain the same solvent and solute.

Which one is the most concentrated solution?Which one is the most dilute solution?

Page 74: Ch 2 Matter & Atoms

concentration: the amount of each solute compared to the total solution.

Page 75: Ch 2 Matter & Atoms

• Can you dissolve salt in water?

VariablesAmount of saltAmount of water

Page 76: Ch 2 Matter & Atoms

• Can you dissolve salt in water?

• Can you continue adding more and more salt, and still get a solution?

Variables

Amount of saltAmount of water

Page 77: Ch 2 Matter & Atoms

• Can you dissolve salt in water?

• Can you continue adding more and more salt, and still get a solution?

• Can you dissolve more salt when you increase the temperature?

Variables

Amount of saltAmount of water

Amount of saltAmount of waterTemperature

Page 78: Ch 2 Matter & Atoms

solubility: the amount of a solute that will dissolve in a particular solvent at a particular temperature and pressure.

Solubility of common substances in water at 25oC

Page 79: Ch 2 Matter & Atoms

If the concentration of a sugar solution is 75 g/L, how much solution do you need if you want 10 g of sugar?

Page 80: Ch 2 Matter & Atoms

If the concentration of a sugar solution is 75 g/L, how much solution do you need if you want 10 g of sugar?

Asked: Volume of solution

Given: 10 g of solute and concentration of 75 g/L

Relationships:mass of soluteLiters of solution

concentration in g L

Page 81: Ch 2 Matter & Atoms

If the concentration of a sugar solution is 75 g/L, how much solution do you need if you want 10 g of sugar?

Asked: Volume of solution

Given: 10 g of solute and concentration of 75 g/L

Relationships:

Solve:

mass of soluteLiters of solutionconcentration in g L

10 0.1 1333375

g L org

LL

m

Page 82: Ch 2 Matter & Atoms

How much menthol do you need to make 10 kg of mouthwash if the concentration of menthol must be 0.05%?

Page 83: Ch 2 Matter & Atoms

How much menthol do you need to make 10 kg of mouthwash if the concentration of menthol must be 0.05%?

Asked: Mass of solute

Given: 10 kg of solution, solute concentration of 0.05%

Relationships: %100

concentration inmass of solute mass of solution

Page 84: Ch 2 Matter & Atoms

How much menthol do you need to make 10 kg of mouthwash if the concentration of menthol must be 0.05%?

Asked: Mass of solute

Given: 10 kg of solution, solute concentration of 0.05%

Relationships:

Solve:

%100

concentration inmass of solute mass of solution

0.05%10 0.00510

50

kg kg or g

Page 85: Ch 2 Matter & Atoms

molarity: the number of moles of solute per liter of solution.

( )( )

amount of solute moles molesmolarityvolume of solvent liters L

moles ML

Page 86: Ch 2 Matter & Atoms

If 10.0 g of citric acid (C6H8O7) is added to 500 mL of water, what is the molarity of the resulting solution?

Page 87: Ch 2 Matter & Atoms

Asked: The molarity of a solution

Given: The amount of solute (citric acid) and the volume of solution

Relationships:

moles solutemolarityvolume of solution L

If 10.0 g of citric acid (C6H8O7) is added to 500 mL of water, what is the molarity of the resulting solution?

Page 88: Ch 2 Matter & Atoms

Asked: The molarity of a solution

Given: The amount of solute (citric acid) and the volume of solution

Relationships:

Solve: Start by calculating the formula mass of C6H8O7:

moles solutemolarity

volume of solution L

6 12.011 8 1.0079 7 1 192.5. 12999 g mole

If 10.0 g of citric acid (C6H8O7) is added to 500 mL of water, what is the molarity of the resulting solution?

Page 89: Ch 2 Matter & Atoms

Asked: The molarity of a solution

Given: The amount of solute (citric acid) and the volume of solution

Relationships:

Solve: Start by calculating the formula mass of C6H8O7:

Next we calculate the number of moles in 10.0 g of C6H8O7:

moles solutemolarity

volume of solution L

6 12.011 8 1.0079 7 15.999 192.12 g mole

1# 10.0192.12

0.0521molemoles gg

moles

If 10.0 g of citric acid (C6H8O7) is added to 500 mL of water, what is the molarity of the resulting solution?

Page 90: Ch 2 Matter & Atoms

If 10.0 g of citric acid (C6H8O7) is added to 500 mL of water, what is the molarity of the resulting solution?

Asked: The molarity of a solution

Given: The amount of solute (citric acid) and the volume of solution

Relationships:

Solve: Start by calculating the formula mass of C6H8O7:

Next we calculate the number of moles in 10.0 g of C6H8O7:

Answer:

moles solutemolarity

volume of solution L

6 12.011 8 1.0079 7 15.999 192.12 g mole

1# 10.0 0.0521192.12molemoles g moles

g

0.05210.500

0.104molesmolarityL

M

Page 91: Ch 2 Matter & Atoms

Ascorbic acid = Vitamin C

Vitamin C acts as a food preservative by reacting with oxygen (O2)Ascorbic acid

C6H8O6

Page 92: Ch 2 Matter & Atoms
Page 93: Ch 2 Matter & Atoms

How much (volume) of a 1 M ascorbic acid solution will completely react with 0.02 moles of oxygen (O2)?

Page 94: Ch 2 Matter & Atoms

Asked: Volume of solution

Given: Concentration (1M) and balanced reaction

Relationships:

According to the balanced reaction we need 2 moles of ascorbic acid for every mole of O2.

moles solutemolarity

volume of solution L

How much (volume) of a 1 M ascorbic acid solution will completely react with 0.02 moles of oxygen (O2)?

Page 95: Ch 2 Matter & Atoms

Asked: Volume of solution

Given: Concentration (1M) and balanced reaction

Relationships:

According to the balanced reaction we need 2 moles of ascorbic acid for every mole of O2.

Solve: That means we need 0.04 moles of ascorbic acid:

0.04 0 41

0.04moles solute molesvolume L L ormolarit

LM

my

moles solutemolarity

volume of solution L

How much (volume) of a 1 M ascorbic acid solution will completely react with 0.02 moles of oxygen (O2)?

Page 96: Ch 2 Matter & Atoms

Asked: Volume of solution

Given: Concentration (1M) and balanced reaction

Relationships:

According to the balanced reaction we need 2 moles of ascorbic acid for every mole of O2.

Solve: That means we need 0.04 moles of ascorbic acid:

Answer: 40 mL of the solution contains 0.04 moles of ascorbic acid, which is enough to react with 0.02 moles of oxygen (O2).

0.04 0 41

0.04moles solute molesvolume L L ormolarit

LM

my

moles solutemolarity

volume of solution L

How much (volume) of a 1 M ascorbic acid solution will completely react with 0.02 moles of oxygen (O2)?

Page 97: Ch 2 Matter & Atoms

The air you breathe is a mixture!

Page 98: Ch 2 Matter & Atoms

Air takes up less space under high pressure.

Page 99: Ch 2 Matter & Atoms

Standard

Temperature and

Pressure

molar volume: the amount of space occupied by a mole of gas at STP. It is equal to 22.4 L.

0oC

1 atm

Page 100: Ch 2 Matter & Atoms

Partial pressures

The total pressure in a mixture of gases is the sum of

the partial pressures of each individual gas

in the mixture.

Page 101: Ch 2 Matter & Atoms

Gas A

Gas BGas C

Gas A Gas B

Gas CTotal pressure

=

+

+

Partial pressure of A

Partial pressure of C

Partial pressure of B

Partial pressures

Page 102: Ch 2 Matter & Atoms

If 1 L of helium (75%) and neon (25%) is at STP, what is the partial pressure of helium?

Page 103: Ch 2 Matter & Atoms

Asked: Partial pressure of helium

Given: 75% He and 25% Ne at STP conditionsStandard pressure is 101,325 Pa or 1 atm

Relationships: The total pressure is the sum of the partial pressures of each gas.

If 1 L of helium (75%) and neon (25%) is at STP, what is the partial pressure of helium?

Page 104: Ch 2 Matter & Atoms

Asked: Partial pressure of helium

Given: 75% He and 25% Ne at STP conditionsStandard pressure is 101,325 Pa or 1 atm

Relationships: The total pressure is the sum of the partial pressures of each gas.

Solve: 75,9940.75 101,30.75

250.75 1

Paor

Paatmatm

or

If 1 L of helium (75%) and neon (25%) is at STP, what is the partial pressure of helium?

Page 105: Ch 2 Matter & Atoms

Asked: Partial pressure of helium

Given: 75% He and 25% Ne at STP conditionsStandard pressure is 101,325 Pa or 1 atm

Relationships: The total pressure is the sum of the partial pressures of each gas.

Solve:

Answer: The partial pressure of helium is 75,994 Pa or 0.75 atm.

75,9940.75 101,30.75

250.75 1

Paor

Paatmatm

or

If 1 L of helium (75%) and neon (25%) is at STP, what is the partial pressure of helium?

Page 106: Ch 2 Matter & Atoms

STP conditions:

Standard

Temperature (0oC)

Pressure (1 atm)

Air is a mixture of gases. Based on Dalton’s law of partial pressures:

2 2...air N O ArP P P P

Concentration of a solution can be expressed in:mass per volumemass percentmolarity

moles of solutemolarity Mliters of solvent