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Prentice-Hall © 2002General Chemistry: Chapter 3Slide 1 of 37
Philip DuttonUniversity of Windsor, Canada
Prentice-Hall © 2002
Chapter 3: Chemical Compounds
General ChemistryPrinciples and Modern Applications
Petrucci • Harwood • Herring
8th Edition
Prentice-Hall © 2002General Chemistry: Chapter 3Slide 2 of 37
Contents
3-1 Molecular and Ionic Compounds
3-2 Molecular Mass
3-3 Composition
3-4 Oxidation States
3-5 Names and formulas Focus on Mass Spectrometry
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Molecular compounds
1 /inch 0.4 /cm
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Standard color scheme
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Some molecules
H2O2 CH3CH2Cl P4O10
CH3CH(OH)CH3 HCO2H
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Ionic compounds
Atoms of almost all elements can gain or lose electrons to form charged species called ions.
Compounds composed of ions are known as ionic compounds.
Metals tend to lose electrons to form positively charged ions called cations.
Non-metals tend to gain electrons to form negatively charged ions called anions.
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Sodium chloride
Extended array of Na+ and Cl- ions Simplest formula unit is NaCl
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Inorganic molecules
S8P4
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Molecular mass
HOO
H
H
HO
H
OH
OHHH
OH
Molecular formula C6H12O6
Empirical formula CH2O
Glucose
6 x 12.01 + 12 x 1.01 + 6 x 16.00
Molecular Mass: Use the naturally occurring mixture of isotopes,
= 180.18
Exact Mass: Use the most abundant isotopes,
6 x 12.000000 + 12 x 1.007825 + 6 x 15.994915= 180.06339
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Halothane C2HBrClF3
M(C2HBrClF3) = 2MC + MH + MBr + MCl + 3MF
= (2 12.01) + 1.01 + 79.90 + 35.45 + (3 19.00)
= 197.38 g/mol
Chemical Composition
Mole ratio nC/nhalothane
Mass ratio mC/mhalothane
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Example 3.4Calculating the Mass Percent Composition of a Compound
Calculate the molecular massM(C2HBrClF3
) = 197.38 g/mol
For one mole of compound, formulate the mass ratio and convert to percent:
%17.12%10038.197
)01.122(%
g
gC
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Example 3-4
%88.28%10038.197
)00.193(%
%96.17%10038.197
45.35%
%48.40%10038.197
90.79%
%51.0%10038.197
01.1%
%17.12%10038.197
)01.122(%
g
gF
g
gCl
g
gBr
g
gH
g
gC
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Empirical formula
1. Choose an arbitrary sample size (100g).
2. Convert masses to amounts in moles.
3. Write a formula.
4. Convert formula to small whole numbers.
5. Multiply all subscripts by a small whole number to make the subscripts integral.
5 Step approach:
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Determining the Empirical and Molecular Formulas of a Compound from Its Mass Percent Composition.
Dibutyl succinate is an insect repellent used against household ants and roaches. Its composition is 62.58% C, 9.63% H and 27.79% O. Its experimentally determined molecular mass is 230 u. What are the empirical and molecular formulas of dibutyl succinate?
Step 1: Determine the mass of each element in a 100g sample.
C 62.58 g H 9.63 g O 27.79 g
Dibutyl succinate is an insect repellent used against household ants and roaches. Its composition is 62.58% C, 9.63% H and 27.79% O. Its experimentally determined molecular mass is 230 u. What are the empirical and molecular formulas of dibutyl succinate?
Example 3-5
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Step 2: Convert masses to amounts in moles.
OmolOg
OmolOgn
HmolHg
HmolHgn
CmolCg
CmolCgn
O
H
C
737.1999.15
179.27
55.9008.1
163.9
210.5011.12
158.62
Step 3: Write a tentative formula.
Step 4: Convert to small whole numbers.
C5.21H9.55O1.74
C2.99H5.49O
Example 3-5
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Step 5: Convert to a small whole number ratio.
Multiply 2 to get C5.98H10.98O2
The empirical formula is C6H11O2
Step 6: Determine the molecular formula.
Empirical formula mass is 115 u.Molecular formula mass is 230 u.
The molecular formula is C12H22O4
Example 3-5
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Combustion analysis
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Oxidation States
Metals tend to lose electrons.
Na Na+ + e-
Non-metals tend to gain electrons.
Cl + e- Cl-
Reducing agents Oxidizing agents
We use the Oxidation State to keep track of the number of electrons that have been gained or lost by an element.
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Rules for Oxidation States
1. The oxidation state (OS) of an individual atom in a free element is 0.
2. The total of the OS in all atoms in: i. Neutral species is 0.ii. Ionic species is equal to the charge on the ion.
3. In their compounds, the alkali metals and the alkaline earths have OS of +1 and +2 respectively.
4. In compounds the OS of fluorine is always –1
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Rules for Oxidation States
6. In compounds, the OS of hydrogen is usually +1
7. In compounds, the OS of oxygen is usually –2.
8. In binary (two-element) compounds with metals:
i. Halogens have OS of –1,
ii. Group 16 have OS of –2 and
iii. Group 15 have OS of –3.
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Assigning Oxidation States.
What is the oxidation state of the underlined element in each of the following? a) P4; b) Al2O3; c) MnO4
-; d) NaH
a) P4 is an element. P OS = 0
b) Al2O3: O is –2. O3 is –6. Since (+6)/2=(+3), Al OS = +3.
c) MnO4-: net OS = -1, O4 is –8. Mn OS = +7.
d) NaH: net OS = 0, rule 3 beats rule 5, Na OS = +1 and H OS = -1.
Example 3-7
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Naming Compounds
Trivial names are used for common compounds.
A systematic method of naming compounds is known as a system of nomenclature.
Organic compounds
Inorganic compounds
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Inorganic Nomenclature
Binary Compounds of Metals and Nonmetals
NaCl = sodium chloride
name is unchanged
“ide” endingelectrically neutral
MgI2 = magnesium iodide
Al2O3 = aluminum oxide
Na2S = sodium sulfide
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Binary Compounds of Two Non-metals
Molecular compoundsusually write the positive OS element first.
HCl hydrogen chloride
mono 1 penta 5
di 2 hexa 6
tri 3 hepta 7
tetra 4 octa 8
Some pairs form more than one compound
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Binary Acids
Emphasize the fact that a molecule is an acid by altering the name.
HCl hydrogen chloride hydrochloric acid
HF hydrogen fluoride hydrofluoric acid
Acids produce H+ when dissolved in water.
They are compounds that ionize in water.
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Polyatomic Ions
Polyatomic ions are very common.
Table 3.3 gives a list of some of them. Here are a few:
ammonium ion NH4+ acetate ion C2H3O2
-
carbonate ion CO32- hydrogen carbonate HCO3
-
hypochlorite ClO- phosphate PO43-
chlorite ClO2- hydrogen phosphate HPO4
2-
chlorate ClO3- sulfate SO4
2-
perchlorate ClO4- hydrogensulfate HSO4
-
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Naming Organic Compounds
Organic compounds abound in nature
Fats, carbohydrates and proteins are foods.
Propane, gasoline, kerosene, oil.
Drugs and plastics
Carbon atoms form chains and rings and act as the framework of molecules.
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Visualizations of some hydrocarbons
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Visualizations of some hydrocarbons
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IsomersIsomers have the same molecular formula but have different
arrangements of atoms in space.
H
(c)
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Functional Groups – carboxylic acid
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Functional Groups - alcohol
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Chapter 3 Questions
3, 5, 12, 24, 35, 46, 53, 61, 57, 73, 95, 97