ch04 position analysis
TRANSCRIPT
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POSITION ANALYSIS
Chapter 4
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Introduction
Dynamics
Kinematics
Position Velocity Acceleration
Kinetics
Newton’s Second Law
Work & Energy
Impulse & Momentum
Stresses
Design
Graphical
Analytical
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Coordinate Systems
Global or Absolute
Attached to Earth
Local
Attached to a link at some point of interest
LNCS (local nonrotatingcoordinate system)
LRCS (local rotating coordinate system)
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Position and Displacement
22
XYA RRR
X
Y
R
R1tan
Coordinate
Transformation sincos yxX RRR
cossin yxY RRR
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Displacement
The straight-line distance between the initial and final
position of a point which has moved in the reference
frameABBA RRR
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Translation, Rotation and Complex
Motion
Translation
All points on the body have the
same displacement
BBAA RR ''
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Translation, Rotation and Complex
Motion
Rotation
Different points in the body
undergo different
displacements and thus there is
a displacement difference
between any two points chosen
Euler’s theorem
BAABBB RRR ''
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Translation, Rotation and Complex
Motion
Complex Motion
Is the sum of the translation and
rotation
Chasles’Theorem
'"'" BBBBBB RRR
'"'" ABAAAB RRR
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Graphical Position Analysis
For any one-DOF, such a fourbar, only one
parameter is needed to completely define the
positions of all the links. The parameter usually
chosen is the angle of the input link.
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Graphical Position Analysis
Construction of the graphical solution
The a, b, c, d and the angle θ2 of the input link are
given.
1. The ground link (1) and the input link (2) are
drawn to a convenient scale such that they
intersect at the origin O2 of the global XY
coordinate system with link 2 placed at the input
angle θ2.
2. Link 1 is drawn along the X axis for
convenience.
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Graphical Position Analysis
Construction of the graphical solution
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Graphical Position Analysis
Construction of the graphical solution
3. The compass is set to the scaled length of link
3, and an arc of that radius swung about the end
of link 2 (point A).
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Graphical Position Analysis
Construction of the graphical solution
4. Set the compass to the scaled length of link 4, and a second arc swung about the end of link 1 (point O4). These two arcs will have two intersections at B and B’ that define the two solution to the position problem for a fourbarlinkage which can be assembled in two configurations, called circuits, labeled open and crossed.
5. The angles of links 3 and 4 can be measured with a protractor.
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Graphical Position Analysis
Construction of the graphical solution
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Algebraic Position Analysis
Algebraic Algorithm
Coordinates of point A
Coordinates of point B
2cosaAx
2sinaAy
222
yyxx ABABb
222
yx BdBc
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Algebraic Position Analysis
Algebraic Algorithm
Coordinates of point B
dA
BAS
dA
BA
dA
dcbaB
x
yy
x
yy
x
x
2
2
2
2
2
2222
02
2
2
c
dA
BASB
x
yy
y
P
PRQQBy
2
42
1
2
2
dA
AP
x
y
dA
SdAQ
x
y
2
22cSdR
dA
dcbaS
x
2
2222
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Algebraic Position Analysis
Algebraic Algorithm
Link angles for the
given position
xx
yy
AB
AB1
3 tan
dB
B
x
y1
4 tan
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Algebraic Position Analysis
Vector Loop
Links are represented as position vectors
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Algebraic Position Analysis
Complex Numbers as Vector
Unit vectors
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Algebraic Position Analysis
Complex Numbers as Vector
Complex number notation
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Algebraic Position Analysis
Complex Numbers as Vector
Complex number notation
Euler identity
sincos je j
jj
jed
de
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Algebraic Position Analysis
Vector Loop Equation
for a Fourbar Linkage
Position vector
Complex number
notation
01432 RRRR
01432 jjjj
decebeae
0Independent
variableTo be
determine
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Algebraic Position Analysis
Vector Loop Equation for a
Fourbar Linkage
Euler equivalents and separate
into two scalar equations
24
23
,,,,
,,,,
dcbaf
dcbaf
0sincossincossincossincos 11443322 jdjcjbja
Real part: 0coscoscos 432 dcba
0sinsinsin 432 cbaImaginary part:
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Algebraic Position Analysis
Solve simultaneously
Square and add
dcab 423 coscoscos
423 sinsinsin cab
242
2
423
2
3
22 coscossinsincossin dcacab
242
2
42
2 coscossinsin dcacab
424242
2222 coscossinsin2cos2cos2 accdaddcab
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Algebraic Position Analysis
To simplify, constants are define in terms of the
constant link length,
Substituting the identity,
Freudenstein’s equation
a
dK 1
424232241 sinsincoscoscoscos KKK
c
dK 2
ac
dcbaK
2
2222
3
424242 sinsincoscoscos
4232241 coscoscos KKK
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Algebraic Position Analysis
Using half angle identities,
Simplified form
2tan1
2tan2
sin42
4
4
2tan1
2tan1
cos42
42
4
02
tan2
tan 442
CBA
3221
2
32212
cos1
sin2
coscos
KKKC
B
KKKA
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Algebraic Position Analysis
The solution,
If the solution is complex conjugate, the link lengths
chosen are not capable of connection
The solution will usually be real and unequal
Crossed (+)
Open (-)
A
ACBB
2
4
2tan
2
4
A
ACBB
2
4arctan2
2
4 2,1
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Algebraic Position Analysis
Solution for θ3
Square and add
dbac 324 coscoscos
324 sinsinsin bac
323252431 sinsincoscoscoscos KKK
b
dK 4
ab
badcK
2
2222
5
02
tan2
tan 332
FED
5241
2
52412
cos1
sin2
coscos
KKKF
E
KKKD
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Algebraic Position Analysis
The solution,
If the solution is complex conjugate, the link lengths
chosen are not capable of connection
The solution will usually be real and unequal
Crossed (+)
Open (-)
D
DFEE
2
4arctan2
2
3 2,1
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Algebraic Position Analysis
Fourbar Slider-Crank
Linkage
Position vector
Complex number
notation
01432 RRRR
01432 jjjj
decebeae
0Independent
variableTo be
determine
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Algebraic Position Analysis
Vector Loop Equation for a
Fourbar Linkage
Euler equivalents and separate
into two scalar equations
0sincossincossincossincos 11443322 jdjcjbja
Real part: 0coscoscos 432 dcba
0sinsinsin 432 cbaImaginary part:
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Algebraic Position Analysis
The solution,
32
23
coscos
sinarcsin
1
bad
b
ca
b
ca 23
sinarcsin
2
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Algebraic Position Analysis
Inverted Slider-Crank (p193-p194)
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Algebraic Position Analysis
Geared Fivebar Linkage
Position vector
Complex number notation
015432 RRRRR
015432 jjjjj
fedecebeae
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Algebraic Position Analysis
Geared Fivebar Linkage
Using the relationship
between the two geared
links;
Complex number notation
25
012432
jjjjjfedecebeae
ratiogear ,
angle phase ,
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Algebraic Position Analysis
Geared Fivebar Linkage
Solution (pag. 196)
D
DFEE
2
4arctan2
2
4 2,1
22
22
2
22222
22
22
sinsin2
coscos2
cos2
sinsin2
coscos2
ad
fad
affdcbaC
adcB
fadcA
CAF
BE
ACD
2
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Algebraic Position Analysis
Geared Fivebar Linkage
Solution (pag. 196)
L
LNMM
2
4arctan2
2
3 2,1
22
22
2
22222
22
22
sinsin2
coscos2
cos2
sinsin2
coscos2
ad
fad
affdcbaK
dabH
fdabG
KGN
HM
GKL
2
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Algebraic Position Analysis
Sixbar Linkage
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Algebraic Position Analysis
Sixbar Linkage