ch5
TRANSCRIPT
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Chap 5
Quasi-One-Dimensional Flow
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5.1 Introduction
Good approximation for practicing gas dynamicists eq. nozzle flow 、 flow through wind tunnel & rocket engines
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5.2 Governing Equations• For a steady,quasi-1D flow The continuity equation :
222111 AuAu
s
dt
sdv
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The momentum equation :
s s
sdpdfdtvvsdv
)()(
2222221
21111 )( 2
1
AuApApdAuAp xA
A
Automatically balainced
X-dir
Y-dir
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The energy equation
s
dvfsdvpdq )(
s
dsvVedVet
)2
()]2
([22
consthuhuh 0
22
2
21
1 22
peh
total enthalpy is constant along the flow
Actually, the total enthalpy is constant along a streamline in any adiabatic steady flow
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PAuρ
P +dPA +dAu +duρ+dρ
dx
In differential forms
0)( uAdconstuA
)())(())(( 2
2
dAAduuddAAdpp
pdAAupA
0222 uAdudAudAuAdp
Dropping 2nd order terms
(1)
022 dAuuAdudAu (2)0)( uAd
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(1) - (2) = 0 uAduAdp
ududp
constuh 2
2
0)2
(2
uhd
0ududh
Euler’s equation
)()()()(
dudpdudp
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5.3 Area-Velocity Relation0)( uAd
uAAudAduudA
0 udud
ddPdP
0AdA
udud
uduM
uaduu
audud 2
2
2
2
∵ adiabatic & inviscid no dissipation mechanism∴
→ isentropic
uduM
AdA )1( 2
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Important information1. M→0 incompressible flow Au=const consistent with the familiar continuity eq for
incompressible flow2. 0 M≦ < 1 subsonic flow an increase in velocity (du , +) is associated with a
decrease in area (dA,- ) and vice versa.3. M>1 supersonic flow
an increase in velocity is associated with an increase in area , and vice versa
4. M=1 sonic flow →dA/A=0 a minimum or maximum in the area
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A subsonic flow is to be accelerated isentropically from subsonic to supersonic
Supersonic flow is to be decelercted isentropically from supersonic to subsonic
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Application of area-velocity relation
1.Rocket engines
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2.Ideal supersonic wind tunnel
Diffuser is to slow down the flow in the convergent duct to sonic flow at the second throat, and then futher slowed to low subsonic speeds in the divergent duct.(finally being exhausted to the atmosphere for a blow-down wind tunnel)
“chocking” “blocking”(When both nozzle with M=1)
Handout – Film Note by Donald Coles
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5.4 Isentropic Flow of a Calorically Perfect Gas through Variable-Area Duct
***** auuAAu
ua
AA *
0
0
*
*
Stagnation density (constant throughout an isentropic flow)
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11
22
2* )]
211(
12[1)(
r
r
MrrMA
A
11
20 )2
11( rMr
11
11
*0 )
21()
211(
rr rr
)3.(
211
21
)(2*
2
2
2*
chMMr
Mr
au
(1)
(2)
(3)
Area – Mach Number Relation
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There are two values of M which correspond to a given A/A* >1 , a subsonic & a supersonic value
Boundary conditions will determine the solution is subsonic or supersonic
)( *AAfM
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1. For a complete shock-free isentropic supersonic flow, the exit pressure ratio Pe /P0 must be precisely equal to Pb /P0
2. Pe /P0 、 Te /T0 & Pe /P0 = f(Ae /A*) and are continuously decreasing.
3. To start the nozzle flow, Pb must be lower than P0
4. For a supersonic wind tunnel, the test section conditions are determined by (Ae /A*) 、 P0 、 T0 gas property & Pb
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Pb=P0 at the beginning there is no ∴flow exists in the nozzle
Minutely reduce Pb , this small pressure difference will cause a small wind to blow through the duct at low subsonic speeds
Futher reduce Pb , sonic conditions are reached (Pb=Pe3)
Pe /P0 & A/At are the controlling factors for the local flow properties at any given section
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528.0)2
11( 1
0
*
rrr
pp
for r=1.4
tAtUtm
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Should use dash-line to indicate irreversible process
What happens when Pb is further reduced below Pe3 ?
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Note: quasi-1D consideration does not tell us much about how to design the contour of a nozzle – essentially for ensuring a shockfree supersonic nozzle
Method of characteristics
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Wave reflection from a free boundary
Waves incident on a solid (free) boundary reflect in like (opposite) manner , i.e, a compression wave as a compression (expansion wave ) and an expansion wave reflects as an expansion ( compression ) wave
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5.5 diffusers Assume that we want to
design a supersonic wind tunnel with a test section M=3Ae/A*=4.23P0/Pe=36.7
3 alternatives
(a) Exhaust the nozzle directly to the atmosphere
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(b) Exhaust the nozzle into a constent area duct which serves as the test section
atmPPP
PPP e
e
55.3)P10.33
1(36.7)(02
00
∴ the resvervair pressure required to drive the wind tunnel has markedly dropped from 36.7 to 3.55 atm
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(c) Add a divergent duct behind the normal the normal shock to even slow down the already subsonic flow to a lower velocity
3M
For
atmPPP
PP
PPP e
e
04.3117.11)
33.101)(7.36(
02
2
2
00
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∴ the reservoir pressure required to drive a supersonic wind tunnel (and hence the power required form the compressors) is considerably reduced by the creation of a normal shock and subsequent isentropic diffusion to M ~ 0 at the tunnel exit
Note:
3M 328.001
02 PP
04.3328.01
02
01 PP
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Diffuser - the mechanism to slow the flow with as small a
loss total pressure as possible
Consider the ideal supersonic wind funnel again
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If shock-free →P02/P01=1 no lose in total pressure →a perpetual motion machine!!← something is wrong(1) in real life , it hard to prevent oblique shock wave from occuring inside the duct(2) even without shocks , friction will cause a lose of P0
the design of a perfect isentropic diffuser is physically impossible∴
Replace the normal shock diffuser with an oblique shock diffuser provide greater pressure recovery
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Diffuser efficiency
)(
)PP(
01
02
0
d0
PP
actual
D (mostl common one)
If ηD=1→normal shock diffuser
for low supersonic test section Me, ηD>1
for hypersonic conditions ηD<1 (normal shock recovery is about the best to be expected)
Normal shock at Me
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Is very sensitive to
At2>At1(due to the entropy increase in the diffuser) proof: assume the sonic flow exists at both throats
*22
*2
*11
*1 aAaA tt
02
01*
2
*1
*2
*2
*1
*1
*2
*1
*2
*1
*2
*1
1
2 )(PP
PP
RTPRT
P
aa
AA
t
t
02
01
1
2
PP
AA
t
t 0102 PP always 12 tt AA
D2tA
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At2ηD=max is slightly larger than (P01/P02)At1
the fix- geometry diffuser will operate at an efficiency less than η∴ D,m to start properly
ηD is low it is because At2 is too large the flow pass though a series of ∴
oblique shock waves id still “very” supersonic a strong normal shock form before ∴exit of the diffuser defeats the purpose of are oblique ∴shock diffuser