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    Chapter 1 Physical Quantities and Units

    1.1 Introduction

    Definition of physics derives from Greek word means nature.

    Each theory in physics involves:

    (a) Concept of physical quantities.

    (b) Assumption obtain mathematical model.(c) Relationship between physical concepts.

    (d) Procedures to relate mathematical models to actual measurements from experiments.

    (e) Experimental proofs to devise explanation to nature phenomena.

    1.2 Physical quantities dan SI units

    A physical quantity is a quantity that can be measured. Physical quantity consist of a

    numerical magnitude and a unit.

    Physical quantities can be divided into two categories:

    1. basic quantities and

    2. derived quantities.

    (a) Basic quantity

    Quantity that cannot be derived from other quantities. This quantity is important because it

    - can be easily produced

    - does not change its magnitude

    - is internationally accepted

    In the interest of simplicity, seven basics quantities, consistent with a full description of the

    physical world, have been chosen.

    SI units

    The unit of a physical quantity is the standard size used to compare different magnitudes

    of the same physical quantity.

    Basic quantity SI base unit SymbolDimension (base

    quantity symbol)

    Length (l) Metre m L

    Mass (m) Kilogram kg M

    Time (t) Second s T

    Electric current (I) Ampere A A

    Thermodynamic temperature (T) Kelvin K q

    Quantity of matter (n) Mole Mol NLight intensity Candela cd I

    (b) Derived quantity

    Quantity that derived from basic quantities through multiplication and division.

    For example,

    Derived quantity Formula Derived unit

    Area length x length m2

    Volume length x length x length m3

    Density kg m-3

    Velocity m s-1

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    Acceleration m s-2

    Prefixes

    For very large or very small numbers, we can use standard prefixes with the base units.

    Prefix tera giga mega kilo deci centi mili micro nano pico

    Factor 102 109 106 103 10-1 10-2 10-3 10-6 10-9 10-12

    Symbol T G M k d c m n P

    1.2 Dimensions and Physical Quantities

    The dimension of a physical quantity is the relation between the physical quantity and the base

    quantities.

    The symbol for dimensions is [ ]

    Example [v] the dimension of velocity , this means that the base quantities in the velocity.

    Example 1

    Write the dimensions for the following physical quantity

    (a) Acceleration(pecutan),a

    [a],the dimension for the acceleration

    [a] =LT-2

    (b) Density

    [] =ML-3

    (c) Force

    [F]=M LT-2

    Use of dimensions

    To check the homogeneity of physical equations

    Concept of homogeneous

    The dimensions on both sides of an equation are the same.

    Those equations which are not homogeneous are definitely wrong.

    However, the homogeneous equation could be wrong due to the incomplete or has extra terms.

    The validity of a physical equation can only be confirmed experimentally.

    In experiment, graphs have to be drawn then. A straight line graph shows the correct equation and

    the non linear graph is not the correct equation.

    Deriving a physical equation

    An equation can be derived to relate a physical quantity to the variables that the quantity depends

    on.

    Example

    Determine the homogeneous of the equation.

    v2 =u2 +2as

    Left Right[v]2 [u]2 +2[a][s]

    L2 T-2 L2 T-2 + L2 T-2

    L2 T-2 L2 T-2

    =

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    homogenous

    Example

    (a)Diberi persamaan yang berikut tentang aliran cecair dalam sebatang paip mendatar

    (a)

    (b)

    (c)

    Dimana W,X,Y berdimensi sama dengan dimensi tekanan, A,B,C mewakili pemalar tak berdimensi

    g mewakili pecutan graviti

    T mewakili tegangan permukaan cecair (dimensinya MT-2)

    rmewakili ketumpatan cecair

    v mewakili halaju cecair

    p mewakili perubahan tekanan

    Tentukan kehomogenan persamaan di atas.

    (b) Dibawah ialah bacaan-bacaan bagip dan v :

    p (Nm-2) 2.0 103 2.0 103 2.0 103 2.0 103 2.0 103

    v (m s-2) 1.0 1.4 1.6 1.9 2.1

    Dengan menggunakan bacaan-bacaan ini,

    (i) cari persamaan yang betul

    (ii) cari pemalar bagi persamaan yang betul itu dengan menggunakan maklumat berkenaan

    [p = 1.0 103 kg m-3, T = 7.4 10-2 N m-1]

    Example 3

    Use the dimension analysis to obtain an expression which shows how the momentum p depends onthe force; F, mass; m and the length, l.

    1.3 Scalar and Vectors

    > A scalar quantity is a physical quantity which has only magnitude. For example, mass, speed (laju),

    density, pressure, .

    > A vector quantity is a physical quantity which has magnitude and direction. For example, force,

    momentum, velocity (halaju), acceleration .

    Graphical representation of vectors

    A vector can be represented by a straight arrow,

    The length of the arrow represents the magnitude of the vector.

    The vector points in the direction of the arrow.

    Basic principle of vectors

    Two vectors P and Q are equal if:

    a) Magnitude of P = magnitude of Q (b) Direction of P = direction of Q

    When a vector P is multiplied by a scalar k, the product is k P and the direction remains the same as

    P.

    The vector -P has same magnitude with P but comes in the opposite direction.

    Sum of vectors

    Method 1: Parallelogram of vectors

    It two vectors and are represented in magnitude and direction by the adjacent sides OA andOB of a parallelogram OABC, then OC represents their resultant(paduan).

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    Method 2: Triangle of vectors

    Use a suitable scale to draw the first vector.

    From the end of first vector, draw a line to represent the second vector.

    Complete the triangle. The line from the beginning of the first vector to the end of the second vector

    represents the sum in magnitude and direction.

    Example 4

    A kite flies in still air is 4.0 ms-1. Find the magnitude and direction of the resultant velocity of the kite

    when the air flows across perpendicularly(serenjang) is 2.5 ms -1. If the distance of the kite is 30 m,

    what is the time taken for the kite to fly? Calculate the height of the kite from the ground.

    Vector 1- direction (yes)

    2- magnitude (c2=a2+b2)

    c= 4.7m s-1

    Principles of vectors

    Relative velocity

    Let us look at two cases: VA = 10 ms-1 VB = 3 ms

    -1.

    Case oneThe velocity ofA relative to B = (VA VB)

    = (10- 3) ms

    = 7 ms -1 (in forward direction).

    Case two

    The velocity ofB relative to A = (VB VA)

    = (3 10) ms

    = -7 ms -1 (in backwards direction).

    We observe that(VB VA) and (VA VB) are same magnitude but different direction.

    Method 3 : Mathematical Method

    Resolving(leraian) vector

    A vector R can be considered as the two vectors. R refers to the resultant vectors. There are twomutually perpendicular component Rx and Ry

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    Example 5

    The figure shows 3 forces F1, F2 and F3 acting on a point O. Calculate the resultant force and the

    direction of resultant.

    F1 F2 F3

    magnitude 3N 5N 4N

    Direction

    degree 0 150 240

    Resolving X-axis

    F1x=+3N

    Y-axis

    F1y = 0

    X-axis

    F2x=-4.3N

    Y-axis

    F2y =2.5N

    1.4 Errors (Uncertainty)

    > There are two main types of errors: systematic error and random error.

    > Systematic error

    Characteristics of systematic error in the measurement of a particular physical quantity:

    -Its magnitude is constant.

    -It causes the measured value to be always greater or always less than the true value.

    Corrected reading = direct reading systematic error

    Sources of systematic error:

    - Zero error of instrument.

    - Incorrectly calibrated scale of instrument.

    - Personal error of observer, for example reaction time of observer.

    - Error due to certain assumption of physical conditions of surrounding

    for example, g = 9.81 ms-2

    Systematic error cannot be reduced or eliminated by taking repeated readings using the same method,

    instrument and by the same observer.

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    > Random error

    Characteristics of random error:

    - Its magnitude is not constant.

    - It causes the measured value to be sometimes greater and sometimes less than the true value.

    Corrected reading = direct reading random error

    The main source of random error is the observer.

    The surroundings and the instruments used are also sources of random errors.

    Example of random error:

    - Parallax error due to incorrect position of the eye when taking reading

    Parallax error can be reduced by having the line of sight perpendicular to the scale reading.

    - Error due to the inability to read an instrument beyond some fraction of the smallest division

    Reading are recorded to a precision of half the smallest division of the scale.

    Random errors can be reduced by taking several readings and calculating the mean.

    1.4.1 The uncertainty of the instrument is shown in the table below

    InstrumentsUncertainty

    (Absolute/actual)Example of readings

    Millimeter rule 0.1 cm (50.1 0.1)cmVernier caliper 0.01 cm (3.23 0.01)cm

    Micrometer screw

    gauge0.01 mm (2.63 0.01)mm

    Stopwatch (analogue) 0.1 s (1.4 0. 1 )s

    Thermometer 0.5 C (28.0 0.5)C

    Ammeter (0 3A) 0.05 A (1.70 0.05)A

    Voltmeter (0 5V) 0.05 V (0.65 0.05)V

    Primary data and secondary data Primary data are raw data or readings taken in an experiment. Primary data obtained using the same

    instrument have to be recorded to the same degree of precision i.e to the same number of decimal

    places.

    Secondary data are derived from primary data. Secondary data have to be recorded to the correct

    number of significant figures. The number of significant figures for secondary data may be the same

    (or one more than) the least number of significant figures in the primary data. Measurement play a

    crucial role in physics, but can never be perfectly precise.

    It is important to specify the uncertainty or error of a measurement either by stating it directly using

    the notation, and / or by keeping only correct number of significant figures.

    Example: 51.2 0.1

    Processing significant figures

    Addition and subtraction

    When two or more measured values are added or subtracted, the final calculated value must have the

    same number of decimal places as that measured value which has the least number , of decimal

    places.

    Example

    1. a = 1.35 cm + 1.325 cm

    = 2.675 cm

    = 2.68 cm

    2. b = 3.2 cm 0.3545 cm

    = 2.8465 cm

    = 2.8 cm

    3. c =

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    = 1.142 cm

    = 1.14 cm

    Multiplication and division

    When two or more measured values are multiplied and/or divided, the final calculated value must

    have as many significant figures as that measured value which has the least number of significant

    figures.

    Example

    1. Volume of a wooden block = 9.5 cm x 2.36 cm x 0.515 cm

    = 11.5463 cm3

    = 12 cm3

    2. If the time for 50 oscillations of a simple pendulum is 43.7 s, then the period of oscillation = 43.7

    50 = 0.874 s

    3. The gradient of a graph

    Note: Sometimes the final answer may be obtained only after performing several intermediate

    calculations. In this case, results produced in intermediate calculations need not be rounded off.

    Round only the final answer.

    1.4.2 Analysing error/uncertainty of a mean value

    - specifically error analysing is refer to error that cause by repetition and a combining

    measurement to produce a derive quantity.

    - Meaning that if we want to measure a volume of cube, of course we cannot just used a single

    measurement then we will get the answer. First we have to measure the length with the ruler together

    with the width and the height. The we need to feed in the formula length x width x height to get the

    volume.

    - While doing the measurement and caculating the answer actually we have continually increasing

    the error.

    - It is a good idea to mention the uncertainty for every measurement and calculation.

    - In this subtopic we deal with the repetition reading or data. Its known that if we have more thanone reading so the true value is the mean of the reading.

    - Mean value for a is

    - Mean value of uncertainty of a, should be caculated this way

    1. Calculated the deviation of every data given:

    2. Find the sum of deviation

    3. find the mean of deviation

    Its known that the mean deviataion is equally the same as the uncertainty of the mean value(true

    value).

    Or

    Working example:

    Diameter ,d of a wire was measured several time to reduce the uncertainty and the reading is given in

    the table below. Find the true value(mean value) and the uncertainty of the diameter.

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    d/mm 1.55 1.52 1.54 1.53 1.54 1.53

    1.4.3 Analysing error/uncertainty combining measurement or equation.1. Actual Value

    - is in the scale reading (pointer reading) of an instrument.(single reading)

    Or

    - is in the mean value.(of the repetition reading)

    2. Fractional and percentage error,

    (a) The fractional error of R :

    (b) The percentage error of R :

    3. Consequential Uncertianties/Error- to state the error of a derive quantitiesGiven

    R1 DR1 = Data Absolute Data Error = 51.2 0.1

    R2 DR2 = Data Absolute Data Error = 30.1 0.1

    (a) Addition

    W = R1 + R2 = 51.2 + 30.3 = 81.3

    DW = DR1 + DR2 = 0.1 + 0.1 = 0.2

    So W DW = 81.3 0.2

    (b) Subtraction

    S = R1 R2 = 51.2 30.3 = 21.1

    DS = DR1 + DR2 = 0.1 + 0.1 = 0.2

    So S DS = 21.1 0.2

    (c) Product

    P = R1 R2 = 51.2 30.3 =1541.12

    From

    P DP = 1541.12 7.71

    (d) Quotient

    From

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    Q DQ = 1.70 0.01

    Working example:

    Find v and the uncertainty in v

    and a =(1.830.01)m, b=(1.65 0.01) m, d=(0.001060.00003)m ,

    q = (4.28 0.05) s and T = (3.7 0.1) x 103 s.

    solution

    First calculate the percentage uncertainties in each of the 4 terms:

    (a b) = (0.180.02)m 11%

    d = (0.001 06 0.000 03) m 3%

    q = (4.28 0.05) s . 1.2%

    T = (3.70.1) x 103 s 3%

    The uncertainty in (a b) is now very large, although the readings themselves have been taken

    carefully. This is always the effect when subtracting two nearly equal numbers.The percentage uncertainty in d2 will be twice the percentage uncertainty in d;

    The percentage uncertainty in will be half the percentage uncertainty in T because a square root

    is a power of .

    This gives:

    Uncertainty percentage in v = 11% + 2(3%) + 1.2% + (3%) = 19.7% 20%

    This gives v = (7.8 1.6) x 10-11 m3 s-1, a rather uncertain result which would be better expressed as:

    v = (8 2) x 10-11

    m3

    s-1

    the rules for uncertainties therefore :

    addition and subtraction ADD absolute uncertainties

    multiplication and division ADD percentage uncertainties

    powers Multiply the percentage uncertainty by the power

    Note : There are some circumstances where the uncertainty in the final value is best found by

    working the problem through twice , once with the readings as taken and once with the limiting

    values which will give the maximum result. Equations containing trigonometrical ratios, or

    exponentials, or equations in which some of the terms appear both on the top and the bottom of the

    expression, such as

    are best dealt with this way.

    Example 5

    The diameter of a cone is (98 1)mm and the height is (224 1 )mm. What is:

    (a) The absolute error of the diameter.

    (b) The percentage error of the diameter.

    (c) The volume of the cone. Give your answer to the correct number of significant number.

    Example 6

    Discuss the ways of minimizing systematic and random errors

    Example 7

    The period of a spring is determined by measuring the time for 10 oscillations using a stopwatch.

    State a source of:(a) Systematic error

    (b) Random error

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    1.4.4. Method to find uncertainty/error from a graph

    Figure 1

    where n is the number of points plotted.

    1. The usual quantities that are deduced from a straight line graph are

    (a) the gradient of the graph m, and the intercept on the y-axis or the x-axis

    (b) the intercepts on the axes.

    First calculate the coordinates of the centroid using the formula

    where n is the number of sets of readings.

    2. The straight line graph that is drawn must pass through the centroid Figure . The best line is thestraight line which has the plotted points closest to it. This line will give the best gradient together

    with c.

    3. Two other straight lines, one with the maximum gradient and another with the least gradient

    , are then drawn. For a straight line graph where the intercept is not the origin , the three lines

    drawn must all pass through the centroid. Here also we can find and

    4. To find the uncertainty for the gradient and intercept used this equation

    and

    Working Example

    Table 1.7 shows the data collected in an experiment to determine the acceleration due to gravity

    using a simple pendulum. The time t for 50 oscillations of the pendulum is measured for different

    lengths l of the pendulum. The period T is calculated using

    from the theory of the simple pendulum, the period T is related to the length l, and the acceleration

    due to gravity g by the equation

    Hence, the acceleration due to gravity,

    A straight line graph would be obtained if a graph of against is plotted.

    Note the various important characteristics when tabulating the data as shown in Table

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    Table 1

    (a) Name or symbol of each quantity and its unit are stated in the heading of each column. Example:

    Length and cm, and T(s). The uncertainty for the primary data, such as length and t time for 50

    oscillations, is also written. Example: (l 0.05) cm and (t 0.1)s.

    (b) All primary data, such as length and time, should be recorded to reflect the precision of theinstrument used.

    For example, the length of the pendulum l is measured using a metre rule. hence it should be

    recorded to two decimal places of a cm, that is 10.00 cm, and not 10 cm or 10.0 cm.

    The time for 50 oscillations t is recorded to 0.1 s, that is 32.0 s and not 32 s.

    The average value of t is also calculated to 0.1 s. The average value of 31.9 s and 32.0 s is recorded

    as 32.0 s and not 31.95 s.

    (c) The secondary data such as T and T2, are calculated from the primary data. Secondary data should

    be calculated to the same number of significant figures as I hat in the least accurate measurement. For

    example, T and T2, are calculated to three significant figures, the same number of significant figures

    as the readings of t.

    (d) For a straight line graph, there should be at least six point plotted. If the graph is a curve, thenmore points should be plotted, especially near the maximum and minimum points.

    Table 2

    Note that the graph is plotted with the assumption that the origin (0, 0) is a point.

    The x-coordinate of the centroid =

    =

    = 45.0cm

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    The y-coordinate of the centroid =

    =

    = 1.80s2

    from the equation

    Hence a graph of T 2 against l is a straight line, passing through the origin, and gradient,

    From the graph,

    gradient of best line,

    Maximum gradient,

    Minimum gradient,

    Absolute uncertainty in the gradient,

    Fractional uncertainty in the gradient

    percentage uncertainty in gradient

    Acceleration due to gravity,

    Hence the percentage uncertainty in g is the sum of the percentage error in m only because 4p2

    is aconstant.

    Therefore percentage uncertainty in gravity,Dg = S uncertainty percentage = 1.88% according to

    above equation

    Hence acceleration due to gravity,

    Written in percentage uncertainty

    g = (9.8701.88%) m s2

    also can be write in absolute uncertainty

    g = (9.9 0.2) m s2 Since there is error in the second significant figure, the value of g is given to two

    significant figures.

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