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  • Slide 1
  • Chapter 10 Chemical Bonding II
  • Slide 2
  • Taste The taste of a food depends on the interaction between the food molecules and taste cells on your tongue The main factors that affect this interaction are the shape of the molecule and charge distribution within the molecule The food molecule must fit snugly into the active site of specialized proteins on the surface of taste cells When this happens, changes in the protein structure cause a nerve signal to transmit
  • Slide 3
  • Sugar & Artificial Sweeteners Sugar molecules fit into the active site of taste cell receptors called Tlr3 receptor proteins When the sugar molecule (the key) enters the active site (the lock), the different subunits of the T1r3 protein split apart This split causes ion channels in the cell membrane to open, resulting in nerve signal transmission Artificial sweeteners also fit into the Tlr3 receptor, sometimes binding to it even stronger than sugar making them sweeter than sugar
  • Slide 4
  • Structure Determines Properties! Properties of molecular substances depend on the structure of the molecule The structure includes many factors, such as: the skeletal arrangement of the atoms the kind of bonding between the atoms ionic, polar covalent, or covalent the shape of the molecule Bonding theory should allow you to predict the shapes of molecules
  • Slide 5
  • Molecular Geometry Molecules are 3-dimensional objects We often describe the shape of a molecule with terms that relate to geometric figures These geometric figures have characteristic corners that indicate the positions of the surrounding atoms around a central atom in the center of the geometric figure The geometric figures also have characteristic angles that we call bond angles
  • Slide 6
  • Lewis Theory Predicts Electron Groups Lewis theory predicts there are regions of electrons in an atom Some regions result from placing shared pairs of valence electrons between bonding nuclei Other regions result from placing unshared valence electrons on a single nuclei
  • Slide 7
  • Using Lewis Theory to Predict Molecular Shapes Lewis theory says that these regions of electron groups should repel each other because they are regions of negative charge This idea can then be extended to predict the shapes of molecules the position of atoms surrounding a central atom will be determined by where the bonding electron groups are the positions of the electron groups will be determined by trying to minimize repulsions between them
  • Slide 8
  • VSEPR Theory Electron groups around the central atom will be most stable when they are as far apart as possible we call this valence shell electron pair repulsion theory because electrons are negatively charged, they should be most stable when they are separated as much as possible The resulting geometric arrangement will allow us to predict the shapes and bond angles in the molecule
  • Slide 9
  • Slide 10
  • Electron Groups The Lewis structure predicts the number of valence electron pairs around the central atom(s) Each lone pair of electrons constitutes one electron group on a central atom Each bond constitutes one electron group on a central atom regardless of whether it is single, double, or triple ONO there are three electron groups on N three lone pair one single bond one double bond
  • Slide 11
  • Electron Group Geometry There are five basic arrangements of electron groups around a central atom based on a maximum of six bonding electron groups though there may be more than six on very large atoms, it is very rare Each of these five basic arrangements results in five different basic electron geometries in order for the molecular shape and bond angles to be a perfect geometric figure, all the electron groups must be bonds and all the bonds must be equivalent For molecules that exhibit resonance, it doesnt matter which resonance form you use the electron geometry will be the same Tro: Chemistry: A Molecular Approach, 2/e
  • Slide 12
  • Linear When there are two electron groups around the central atom, they will occupy positions on opposite sides of the central atom This results in the electron groups taking a linear geometry The bond angle is 180
  • Slide 13
  • Trigonal Planar When there are three electron groups around the central atom, they will occupy positions in the shape of a triangle around the central atom This results in the electron groups taking a trigonal planar geometry The bond angle is 120
  • Slide 14
  • Tetrahedral When there are four electron groups around the central atom, they will occupy positions in the shape of a tetrahedron around the central atom This results in the electron groups taking a tetrahedral geometry The bond angle is 109.5
  • Slide 15
  • Trigonal Bipyramidal 5 electron groups around a central atom occupy positions in the shape of two tetrahedra base-to-base with the central atom in the center of the shared bases The positions above and below the central atom are called the axial positions The positions in the same base plane as the central atom are called the equatorial positions The bond angle between equatorial positions is 120 The bond angle between axial and equatorial positions is 90
  • Slide 16
  • Octahedral When there are six electron groups around the central atom, they will occupy positions in the shape of two square-base pyramids that are base-to-base with the central atom in the center of the shared bases This results in the electron groups taking an octahedral geometry it is called octahedral because the geometric figure has eight sides All positions are equivalent The bond angle is 90
  • Slide 17
  • Molecular Geometry The actual geometry of the molecule may be different from the electron geometry When the electron groups are attached to atoms of different size, or when the bonding to one atom is different than the bonding to another, this will affect the molecular geometry around the central atom Lone pairs also affect the molecular geometry they occupy space on the central atom, but are not seen as points on the molecular geometry
  • Slide 18
  • Not Quite Perfect Geometry Because the bonds and atom sizes are not identical in formaldehyde, the observed angles are slightly different from ideal
  • Slide 19
  • The Effect of Lone Pairs Lone pair groups occupy more space on the central atom because their electron density is exclusively on the central atom rather than shared like bonding electron groups Relative sizes of repulsive force interactions is Lone Pair Lone Pair > Lone Pair Bonding Pair > Bonding Pair Bonding Pair This affects the bond angles, making the bonding pair bonding pair angles smaller than expected
  • Slide 20
  • Effect of Lone Pairs The bonding electrons are shared by two atoms, so some of the negative charge is removed from the central atom The nonbonding electrons are localized on the central atom, so area of negative charge takes more space
  • Slide 21
  • Bond Angle Distortion from Lone Pairs
  • Slide 22
  • Slide 23
  • Bent Molecular Geometry: Derivative of Trigonal Planar Electron Geometry When there are three electron groups around the central atom, and one of them is a lone pair, the resulting shape of the molecule is called a trigonal planar bent shape The bond angle is less than 120 because the lone pair takes up more space
  • Slide 24
  • Pyramidal Geometry: A Derivative of Tetrahedral Electron Geometry When there are four electron groups around the central atom, and one is a lone pair, the result is called a pyramidal shape because it is a triangular-base pyramid with the central atom at the apex Bond angle is less than 109.5
  • Slide 25
  • Bent Tetrahedral Molecular Geometry: A Derivative of Tetrahedral Electron Geometry When there are four electron groups around the central atom, and two are lone pairs, the result is called a tetrahedral bent shape it is planar it looks similar to the trigonal planarbent shape, except the angles are smaller the bond angle is less than 109.5 Tro: Chemistry: A Molecular Approach, 2/e
  • Slide 26
  • Derivatives of the Trigonal Bipyramidal Electron Geometry When there are five electron groups around the central atom, and some are lone pairs, they will occupy the equatorial positions because there is more room Seesaw Shape - five electron groups around the central atom, and one is a lone pair ( aka distorted tetrahedron) T-shaped 5 electron groups around the central atom, and two are lone pairs Linear shape 5 electron groups around the central atom, and three are lone pairs The bond angles between equatorial positions are less than 120 The bond angles between axial and equatorial positions are less than 90 linear = 180 axialtoaxial
  • Slide 27
  • Replacing Atoms with Lone Pairs in the Trigonal Bipyramid System
  • Slide 28
  • Seesaw Shape
  • Slide 29
  • TShape
  • Slide 30
  • Slide 31
  • Linear Shape
  • Slide 32
  • Derivatives of the Octahedral Geometry When there are six electron groups around the central atom, and some are lone pairs, each even number lone pair will take a position opposite the previous lone pair Square Pyramid Shape 6 electron groups around the central atom, and one is a lone pair, the result is called a the bond angles between axial and equatorial positions is less than 90 Square Planar Shape 6 electron groups around the central atom, and two are lone pairs, the result is called a the bond angles between equatorial positions is 90
  • Slide 33
  • Square Pyramidal Shape
  • Slide 34
  • Square Planar Shape
  • Slide 35
  • Slide 36
  • Predicting the Shapes Around Central Atoms 1.Draw the Lewis structure 2.Determine the number of electron groups around the central atom 3.Classify each electron group as bonding or lone pair, and count each type remember, multiple bonds count as one group 4. Use Table 10.1 to determine the shape and bond angles
  • Slide 37
  • Example 10.2: Predict the geometry and bond angles of PCl 3 1.Draw the Lewis structure a)26 valence electrons 2. Determine the Number of electron groups around central atom a)four electron groups around P
  • Slide 38
  • Example 10.2: Predict the geometry and bond angles of PCl 3 3.Classify the electron groups a)three bonding groups b)one lone pair 4.Use Table 10.1 to determine the shape and bond angles a)four electron groups around P = tetrahedral electron geometry b)three bonding + one lone pair = trigonal pyramidal molecular geometry c)trigonal pyramidal = bond angles less than 109.5
  • Slide 39
  • Practice Predict the molecular geometry and bond angles in SiF 5
  • Slide 40
  • Practice Predict the molecular geometry and bond angles in SiF 5 Si = 4e F 5 = 5(7e ) = 35e () = 1e total = 40e 5 electron groups on Si 5 bonding groups 0 lone pairs Shape = trigonal bipyramid Bond angles F eq SiF eq = 120 F eq SiF ax = 90 Si least electronegative Si is central atom
  • Slide 41
  • Practice Predict the molecular geometry and bond angles in ClO 2 F
  • Slide 42
  • Cl = 7e O 2 = 2(6e ) = 12e F = 7e Total = 26e 4 electron groups on Cl 3 bonding groups 1 lone pair Shape = trigonal pyramidal Bond angles OClO < 109.5 OClF < 109.5 Cl least electronegative Cl is central atom
  • Slide 43
  • Representing 3-Dimensional Shapes on a 2-Dimensional Surface One of the problems with drawing molecules is trying to show their dimensionality By convention, the central atom is put in the plane of the paper Put as many other atoms as possible in the same plane and indicate with a straight line For atoms in front of the plane, use a solid wedge For atoms behind the plane, use a hashed wedge
  • Slide 44
  • Slide 45
  • SF 6 S F F F FF F
  • Slide 46
  • Multiple Central Atoms Many molecules have larger structures with many interior atoms We can think of them as having multiple central atoms When this occurs, we describe the shape around each central atom in sequence shape around left C is tetrahedral shape around center C is trigonal planar shape around right O is tetrahedral-bent
  • Slide 47
  • Describing the Geometry of Methanol
  • Slide 48
  • Describing the Geometry of Glycine
  • Slide 49
  • Practice Predict the molecular geometries in H 3 BO 3
  • Slide 50
  • 3 electron groups on B B has 3 bonding groups 0 pone pairs 4 electron groups on O O has 2 bonding groups 2 lone pairs Practice Predict the molecular geometries in H 3 BO 3 B = 3e O 3 = 3(6e ) = 18e H 3 = 3(1e ) = 3e Total = 24e Shape on B = trigonal planar B least electronegative B Is Central Atom oxyacid, so H attached to O Shape on O = tetrahedral bent
  • Slide 51
  • Polarity of Molecules For a molecule to be polar it must 1.have polar bonds electronegativity difference - theory bond dipole moments - measured 2.have an unsymmetrical shape vector addition Polarity affects the intermolecular forces of attraction therefore boiling points and solubilities like dissolves like Nonbonding pairs affect molecular polarity, strong pull in its direction
  • Slide 52
  • Molecule Polarity The HCl bond is polar. The bonding electrons are pulled toward the Cl end of the molecule. The net result is a polar molecule.
  • Slide 53
  • Vector Addition
  • Slide 54
  • Slide 55
  • Molecule Polarity The OC bond is polar. The bonding electrons are pulled equally toward both O ends of the molecule. The net result is a nonpolar molecule.
  • Slide 56
  • Molecule Polarity The HO bond is polar. Both sets of bonding electrons are pulled toward the O end of the molecule. The net result is a polar molecule.
  • Slide 57
  • Predicting Polarity of Molecules 1.Draw the Lewis structure and determine the molecular geometry 2.Determine whether the bonds in the molecule are polar a)if there are not polar bonds, the molecule is nonpolar 3.Determine whether the polar bonds add together to give a net dipole moment
  • Slide 58
  • Example 10.5: Predict whether NH 3 is a polar molecule 1.Draw the Lewis structure and determine the molecular geometry a)eight valence electrons b)three bonding + one lone pair = trigonal pyramidal molecular geometry
  • Slide 59
  • Example 10.5: Predict whether NH 3 is a polar molecule 2.Determine if the bonds are polar a)electronegativity difference b)if the bonds are not polar, we can stop here and declare the molecule will be nonpolar EN N = 3.0 EN H = 2.1 3.0 2.1 = 0.9 therefore the bonds are polar covalent
  • Slide 60
  • Example 10.5: Predict whether NH 3 is a polar molecule 3)Determine whether the polar bonds add together to give a net dipole moment a)vector addition b)generally, asymmetric shapes result in uncompensated polarities and a net dipole moment The HN bond is polar. All the sets of bonding electrons are pulled toward the N end of the molecule. The net result is a polar molecule.
  • Slide 61
  • Practice Decide whether the following molecules are polar EN O = 3.5 N = 3.0 Cl = 3.0 S = 2.5
  • Slide 62
  • Practice Decide whether the following molecules Are polar polar nonpolar 1. polar bonds, N-O 2. asymmetrical shape 1. polar bonds, all S-O 2. symmetrical shape Trigonal Bent Trigonal Planar 2.5
  • Slide 63
  • Molecular Polarity Affects Solubility in Water Polar molecules are attracted to other polar molecules Because water is a polar molecule, other polar molecules dissolve well in water and ionic compounds as well Some molecules have both polar and nonpolar parts
  • Slide 64
  • Problems with Lewis Theory Lewis theory generally predicts trends in properties, but does not give good numerical predictions e.g. bond strength and bond length Lewis theory gives good first approximations of the bond angles in molecules, but usually cannot be used to get the actual angle Lewis theory cannot write one correct structure for many molecules where resonance is important Lewis theory often does not predict the correct magnetic behavior of molecules e.g. O 2 is paramagnetic, though the Lewis structure predicts it is diamagnetic
  • Slide 65
  • Valence Bond Theory Linus Pauling and others applied the principles of quantum mechanics to molecules They reasoned that bonds between atoms would occur when the orbitals on those atoms interacted to make a bond The kind of interaction depends on whether the orbitals align along the axis between the nuclei, or outside the axis
  • Slide 66
  • Orbital Interaction As two atoms approached, the half-filled valence atomic orbitals on each atom would interact to form molecular orbitals molecular orbtials are regions of high probability of finding the shared electrons in the molecule The molecular orbitals would be more stable than the separate atomic orbitals because they would contain paired electrons shared by both atoms the potential energy is lowered when the molecular orbitals contain a total of two paired electrons compared to separate one electron atomic orbitals
  • Slide 67
  • Orbital Diagram for the Formation of H 2 S + H 1s1s HS bond H 1s1s S 3s3s3p3p HS bond Predicts bond angle = 90 Actual bond angle = 92
  • Slide 68
  • Valence Bond Theory Hybridization One of the issues that arises is that the number of partially filled or empty atomic orbitals did not predict the number of bonds or orientation of bonds C = 2s 2 2p x 1 2p y 1 2p z 0 would predict two or three bonds that are 90 apart, rather than four bonds that are 109.5 apart To adjust for these inconsistencies, it was postulated that the valence atomic orbitals could hybridize before bonding took place one hybridization of C is to mix all the 2s and 2p orbitals to get four orbitals that point at the corners of a tetrahedron
  • Slide 69
  • Unhybridized C Orbitals Predict the Wrong Bonding & Geometry
  • Slide 70
  • Valence Bond Theory Main Concepts 1.The valence electrons of the atoms in a molecule reside in quantum-mechanical atomic orbitals. The orbitals can be the standard s, p, d, and f orbitals, or they may be hybrid combinations of these. 2.A chemical bond results when these atomic orbitals interact and there is a total of two electrons in the new molecular orbital a)the electrons must be spin paired 3.The shape of the molecule is determined by the geometry of the interacting orbitals
  • Slide 71
  • Hybridization Some atoms hybridize their orbitals to maximize bonding more bonds = more full orbitals = more stability Hybridizing is mixing different types of orbitals in the valence shell to make a new set of degenerate orbitals sp, sp 2, sp 3, sp 3 d, sp 3 d 2 Same type of atom can have different types of hybridization C = sp, sp 2, sp 3
  • Slide 72
  • Hybrid Orbitals The number of standard atomic orbitals combined = the number of hybrid orbitals formed combining a 2s with a 2p gives two 2sp hybrid orbitals H cannot hybridize!! its valence shell only has one orbital The number and type of standard atomic orbitals combined determines the shape of the hybrid orbitals The particular kind of hybridization that occurs is the one that yields the lowest overall energy for the molecule
  • Slide 73
  • Carbon Hybridizations Unhybridized 2s2s 2p2p sp hybridized 2sp sp 2 hybridized 2p2p sp 3 hybridized 2p2p 2sp 2 2sp 3
  • Slide 74
  • sp 3 Hybridization Atom with four electron groups around it tetrahedral geometry 109.5 angles between hybrid orbitals Atom uses hybrid orbitals for all bonds and lone pairs
  • Slide 75
  • Slide 76
  • Orbital Diagram of the sp 3 Hybridization of C
  • Slide 77
  • sp 3 Hybridized Atoms Orbital Diagrams Unhybridized atom 2s2s 2p2p sp 3 hybridized atom 2sp 3 C 2s2s 2p2p 2sp 3 N Place electrons into hybrid and unhybridized valence orbitals as if all the orbitals have equal energy Lone pairs generally occupy hybrid orbitals
  • Slide 78
  • Practice Draw the orbital diagram for the sp 3 hybridization of each atom Unhybridized atom 3s3s 3p3p Cl 2s2s 2p2p O sp 3 hybridized atom 3sp 3 2sp 3
  • Slide 79
  • Bonding with Valence Bond Theory According to valence bond theory, bonding takes place between atoms when their atomic or hybrid orbitals interact overlap To interact, the orbitals must either be aligned along the axis between the atoms, or The orbitals must be parallel to each other and perpendicular to the interatomic axis
  • Slide 80
  • Methane Formation with sp 3 C
  • Slide 81
  • Ammonia Formation with sp 3 N
  • Slide 82
  • Types of Bonds A sigma ( ) bond results when the interacting atomic orbitals point along the axis connecting the two bonding nuclei either standard atomic orbitals or hybrids stos, ptop, hybridtohybrid, stohybrid, etc. A pi ( ) bond results when the bonding atomic orbitals are parallel to each other and perpendicular to the axis connecting the two bonding nuclei between unhybridized parallel p orbitals The interaction between parallel orbitals is not as strong as between orbitals that point at each other; therefore bonds are stronger than bonds
  • Slide 83
  • Slide 84
  • Orbital Diagrams of Bonding Overlap between a hybrid orbital on one atom with a hybrid or nonhybridized orbital on another atom results in a bond Overlap between unhybridized p orbitals on bonded atoms results in a bond
  • Slide 85
  • CH 3 NH 2 Orbital Diagram sp 3 C sp 3 N 1s H
  • Slide 86
  • Formaldehyde, CH 2 O Orbital Diagram sp 2 C sp 2 O 1s H p Cp O
  • Slide 87
  • sp 2 Atom with three electron groups around it trigonal planar system C = trigonal planar N = trigonal bent O = linear 120 bond angles flat Atom uses hybrid orbitals for bonds and lone pairs, uses nonhybridized p orbital for bond
  • Slide 88
  • Slide 89
  • sp 2 Hybridized Atoms Orbital Diagrams Unhybridized atom 2s2s 2p2p sp 2 hybridized atom 2sp 2 2p2p C 3 1 2s2s 2p2p 2sp 2 2p2p N 2 1
  • Slide 90
  • Practice Draw the orbital diagram for the sp 2 hybridization of each atom. How many and bonds would you expect each to form? Unhybridized atom 2s2s 2p2p B 3 0 2s2s 2p2p O 1 1 sp 2 hybridized atom 2sp 2 2p2p 2p2p
  • Slide 91
  • Hybrid orbitals overlap to form a bond. Unhybridized p orbitals overlap to form a bond.
  • Slide 92
  • CH 2 NH Orbital Diagram sp 2 C sp 2 N 1s H p Cp N CN H HH
  • Slide 93
  • Bond Rotation Orbitals form the bond point along the internuclear axis rotation around that bond does not require breaking the interaction between the orbitals Orbitals that form the bond interact above and below the internuclear axis rotation around the axis requires the breaking of the interaction between the orbitals
  • Slide 94
  • Slide 95
  • Slide 96
  • sp Atom with two electron groups linear shape 180 bond angle Atom uses hybrid orbitals for bonds or lone pairs, uses nonhybridized p orbitals for bonds
  • Slide 97
  • Slide 98
  • Slide 99
  • sp Hybridized Atoms Orbital Diagrams Unhybridized atom 2s2s 2p2p sp hybridized atom 2sp 2p2p C22C22 2s2s 2p2p 2sp 2p2p N12N12
  • Slide 100
  • HCN Orbital Diagram sp C sp N 1s H s p Cp N 22
  • Slide 101
  • sp 3 d Atom with five electron groups around it trigonal bipyramid electron geometry Seesaw, TShape, Linear 120 & 90 bond angles Use empty d orbitals from valence shell d orbitals can be used to make bonds
  • Slide 102
  • Slide 103
  • sp 3 d Hybridized Atoms Orbital Diagrams Unhybridized atom 3s3s 3p3p sp 3 d hybridized atom 3sp 3 d S 3s3s 3p3p 3sp 3 d P 3d3d 3d3d (non-hybridizing d orbitals not shown)
  • Slide 104
  • SOF 4 Orbital Diagram sp 3 d S sp 2 O 2p F d Sp O 2p F
  • Slide 105
  • sp 3 d 2 Atom with six electron groups around it octahedral electron geometry Square Pyramid, Square Planar 90 bond angles Use empty d orbitals from valence shell to form hybrid d orbitals can be used to make bonds
  • Slide 106
  • Slide 107
  • sp 3 d 2 Hybridized Atoms Orbital Diagrams Unhybridized atom sp 3 d 2 hybridized atom S 3s3s 3p3p 3sp 3 d 2 3d3d I 5s5s 5p5p 5d5d 5sp 3 d 2 (non-hybridizing d orbitals not shown)
  • Slide 108
  • Slide 109
  • Predicting Hybridization and Bonding Scheme 1.Start by drawing the Lewis structure 2.Use VSEPR Theory to predict the electron group geometry around each central atom 3.Use Table 10.3 to select the hybridization scheme that matches the electron group geometry 4.Sketch the atomic and hybrid orbitals on the atoms in the molecule, showing overlap of the appropriate orbitals 5.Label the bonds as or
  • Slide 110
  • Example 10.7: Predict the hybridization and bonding scheme for CH 3 CHO Draw the Lewis structure Predict the electron group geometry around inside atoms C1 = 4 electron areas C1= tetrahedral C2 = 3 electron areas C2 = trigonal planar
  • Slide 111
  • Example 10.7: Predict the hybridization and bonding scheme for CH 3 CHO Determine the hybridization of the interior atoms C1 = tetrahedral C1 = sp 3 C2 = trigonal planar C2 = sp 2 Sketch the molecule and orbitals
  • Slide 112
  • Label the bonds Example 10.7: Predict the hybridization and bonding scheme for CH 3 CHO
  • Slide 113
  • Practice Predict the hybridization of all the atoms in H 3 BO 3 H = cant hybridize B = 3 electron groups = sp 2 O = 4 electron groups = sp 3
  • Slide 114
  • Practice Predict the hybridization and bonding scheme of all the atoms in NClO N = 3 electron groups = sp 2 O = 3 electron groups = sp 2 Cl = 4 electron groups = sp 3 ONCl Nsp 2 Clp Osp 2 Nsp 2 OpNp
  • Slide 115
  • Problems with Valence Bond Theory VB theory predicts many properties better than Lewis theory bonding schemes, bond strengths, bond lengths, bond rigidity However, there are still many properties of molecules it doesnt predict perfectly magnetic behavior of O 2 In addition, VB theory presumes the electrons are localized in orbitals on the atoms in the molecule it doesnt account for delocalization
  • Slide 116
  • Molecular Orbital Theory In MO theory, we apply Schrdingers wave equation to the molecule to calculate a set of molecular orbitals in practice, the equation solution is estimated we start with good guesses from our experience as to what the orbital should look like then test and tweak the estimate until the energy of the orbital is minimized In this treatment, the electrons belong to the whole molecule so the orbitals belong to the whole molecule delocalization
  • Slide 117
  • LCAO The simplest guess starts with the atomic orbitals of the atoms adding together to make molecular orbitals this is called the Linear Combination of Atomic Orbitals method weighted sum Because the orbitals are wave functions, the waves can combine either constructively or destructively
  • Slide 118
  • Molecular Orbitals When the wave functions combine constructively, the resulting molecular orbital has less energy than the original atomic orbitals it is called a Bonding Molecular Orbital , most of the electron density between the nuclei When the wave functions combine destructively, the resulting molecular orbital has more energy than the original atomic orbitals it is called an Antibonding Molecular Orbital *, * most of the electron density outside the nuclei nodes between nuclei
  • Slide 119
  • Interaction of 1s Orbitals
  • Slide 120
  • Molecular Orbital Theory Electrons in bonding MOs are stabilizing lower energy than the atomic orbitals Electrons in antibonding MOs are destabilizing higher in energy than atomic orbitals electron density located outside the internuclear axis electrons in antibonding orbitals cancel stability gained by electrons in bonding orbitals
  • Slide 121
  • Energy Comparisons of Atomic Orbitals to Molecular Orbitals
  • Slide 122
  • MO and Properties Bond Order = difference between number of electrons in bonding and antibonding orbitals only need to consider valence electrons may be a fraction higher bond order = stronger and shorter bonds if bond order = 0, then bond is unstable compared to individual atoms and no bond will form A substance will be paramagnetic if its MO diagram has unpaired electrons if all electrons paired it is diamagnetic
  • Slide 123
  • 1s1s1s1s ** Hydrogen Atomic Orbital Hydrogen Atomic Orbital Dihydrogen, H 2 Molecular Orbitals Because more electrons are in bonding orbitals than are in antibonding orbitals, net bonding interaction
  • Slide 124
  • H2H2 * Antibonding MO LUMO bonding MO HOMO
  • Slide 125
  • 1s1s1s1s ** Helium Atomic Orbital Helium Atomic Orbital Dihelium, He 2 Molecular Orbitals Because there are as many electrons in antibonding orbitals as in bonding orbitals, there is no net bonding interaction BO = (2-2) = 0
  • Slide 126
  • 1s1s1s1s Lithium Atomic Orbitals Lithium Atomic Orbitals Dilithium, Li 2 Molecular Orbitals Because more electrons are in bonding orbitals than are in antibonding orbitals, there is a net bonding interaction 2s2s2s2s Any fill energy level will generate filled bonding and antibonding MOs; therefore only need to consider valence shell BO = (4-2) = 1
  • Slide 127
  • bonding MO HOMO * Antibonding MO LUMO Li 2
  • Slide 128
  • Interaction of p Orbitals
  • Slide 129
  • Slide 130
  • Slide 131
  • O2O2 Dioxygen is paramagnetic Paramagnetic material has unpaired electrons Neither Lewis theory nor valence bond theory predict this result
  • Slide 132
  • O 2 as Described by Lewis and VB Theory
  • Slide 133
  • Oxygen Atomic Orbitals Oxygen Atomic Orbitals 2s2s2s2s 2p2p2p2p Because more electrons are in bonding orbitals than are in antibonding orbitals, there is a net bonding interaction Because there are unpaired electrons in the antibonding orbitals, O 2 is predicted to be paramagnetic O 2 MOs BO = (8 be 4 abe) BO = 2
  • Slide 134
  • N has 5 valence electrons 2 N = 10e () = 1e total = 11e Example 10.10: Draw a molecular orbital diagram of N 2 ion and predict its bond order and magnetic properties Write a MO diagram for N 2 using N 2 as a base Count the number of valence electrons and assign these to the MOs following the aufbau principle, Pauli principle & Hunds rule 2s2s 2s2s 2p2p 2p2p 2p2p 2p2p
  • Slide 135
  • Example 10.10: Draw a molecular orbital diagram of N 2 ion and predict its bond order and magnetic properties Calculate the bond order by taking the number of bonding electrons and subtracting the number of antibonding electrons, then dividing by 2 Determine whether the ion is paramagnetic or diamagnetic 2s2s 2s2s 2p2p 2p2p 2p2p 2p2p BO = (8 be 3 abe) BO = 2.5 Because this is lower than the bond order in N 2, the bond should be weaker Because there are unpaired electrons, this ion is paramagnetic
  • Slide 136
  • Practice Draw a molecular orbital diagram of C 2 + and predict its bond order and magnetic properties
  • Slide 137
  • 2s2s 2s2s 2p2p 2p2p 2p2p 2p2p BO = (5 be 2 abe) BO = 1.5 Because there are unpaired electrons, this ion is paramagnetic Practice Draw a molecular orbital diagram of C 2 + and predict its bond order and magnetic properties C has 4 valence electrons 2 C = 8e (+) = 1e total = 7e
  • Slide 138
  • Heteronuclear Diatomic Molecules & Ions If the combining atomic orbitals are identical and equal energy the contribution of each atomic orbital to the molecular orbital is equal If the combining atomic orbitals are different types and energies the atomic orbital closest in energy to the molecular orbital contributes more to the molecular orbital
  • Slide 139
  • Heteronuclear Diatomic Molecules & Ions The more electronegative an atom is, the lower in energy are its orbitals Lower energy atomic orbitals contribute more to the bonding MOs Higher energy atomic orbitals contribute more to the antibonding MOs Nonbonding MOs remain localized on the atom donating its atomic orbitals
  • Slide 140
  • NO a free radical 2s Bonding MO shows more electron density near O because it is mostly Os 2s atomic orbital BO = (6 be 1 abe) BO = 2.5
  • Slide 141
  • HF
  • Slide 142
  • Polyatomic Molecules When many atoms are combined together, the atomic orbitals of all the atoms are combined to make a set of molecular orbitals, which are delocalized over the entire molecule Gives results that better match real molecule properties than either Lewis or valence bond theories
  • Slide 143
  • Ozone, O 3 MO Theory: Delocalized bonding orbital of O 3