chapter 10 key management; other public key cryptosystems

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Chapter 10 Key Management; Other Public Key Cryptosystems

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Chapter 10 Key Management; Other Public Key Cryptosystems. Key Management. public-key encryption helps address key distribution problems have two aspects of this: distribution of public keys use of public-key encryption to distribute secret keys. Distribution of Public Keys. - PowerPoint PPT Presentation

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Page 1: Chapter 10 Key Management;  Other Public Key Cryptosystems

Chapter 10 Key Management;

Other Public Key Cryptosystems

Page 2: Chapter 10 Key Management;  Other Public Key Cryptosystems

Key Management

• public-key encryption helps address key distribution problems

• have two aspects of this:– distribution of public keys– use of public-key encryption to distribute

secret keys

Page 3: Chapter 10 Key Management;  Other Public Key Cryptosystems

Distribution of Public Keys

• can be considered as using one of:– Public announcement of public keys– Publicly available directory– Public-key authority– Public-key certificates

Page 4: Chapter 10 Key Management;  Other Public Key Cryptosystems

Public Announcement

• users distribute public keys to recipients or broadcast to community at large– eg. append PGP keys to email messages or

post to news groups or email list• major weakness is forgery

– anyone can create a key claiming to be someone else and broadcast it

– until forgery is discovered can masquerade as claimed user

Page 5: Chapter 10 Key Management;  Other Public Key Cryptosystems
Page 6: Chapter 10 Key Management;  Other Public Key Cryptosystems

Publicly Available Directory

• can obtain greater security by registering keys with a public directory

• directory must be trusted with properties:– contains {name, public-key} entries– participants register securely with directory– participants can replace key at any time– directory is periodically published– directory can be accessed electronically

• still vulnerable to tampering or forgery

Page 7: Chapter 10 Key Management;  Other Public Key Cryptosystems

Public-Key Authority

• improve security by tightening control over distribution of keys from directory

• has properties of directory• and requires users to know public key for

the directory• then users interact with directory to obtain

any desired public key securely– does require real-time access to directory

when keys are needed

Page 8: Chapter 10 Key Management;  Other Public Key Cryptosystems
Page 9: Chapter 10 Key Management;  Other Public Key Cryptosystems

Public-Key Authority

Page 10: Chapter 10 Key Management;  Other Public Key Cryptosystems

Public-Key Certificates

• certificates allow key exchange without real-time access to public-key authority

• a certificate binds identity to public key – usually with other info such as period of

validity, rights of use etc• with all contents signed by a trusted

Public-Key or Certificate Authority (CA)• can be verified by anyone who knows the

public-key authorities public-key

Page 11: Chapter 10 Key Management;  Other Public Key Cryptosystems

Public-Key Certificates

Page 12: Chapter 10 Key Management;  Other Public Key Cryptosystems

Public-Key Distribution of Secret Keys

• use previous methods to obtain public-key• can use for secrecy or authentication• but public-key algorithms are slow• so usually want to use private-key

encryption to protect message contents• hence need a session key• have several alternatives for negotiating a

suitable session

Page 13: Chapter 10 Key Management;  Other Public Key Cryptosystems

Simple Secret Key Distribution

• proposed by Merkle in 1979– A generates a new temporary public key pair– A sends B the public key and their identity– B generates a session key K sends it to A

encrypted using the supplied public key– A decrypts the session key and both use

• problem is that an opponent can intercept and impersonate both halves of protocol

Page 14: Chapter 10 Key Management;  Other Public Key Cryptosystems

Simple Secret Key Distribution

Page 15: Chapter 10 Key Management;  Other Public Key Cryptosystems

Public-Key Distribution of Secret Keys

• if have securely exchanged public-keys:

Page 16: Chapter 10 Key Management;  Other Public Key Cryptosystems

Diffie-Hellman Key Exchange

• first public-key type scheme proposed • by Diffie & Hellman in 1976 along with the

exposition of public key concepts– note: now know that James Ellis (UK CESG)

secretly proposed the concept in 1970 • is a practical method for public exchange

of a secret key• used in a number of commercial products

Page 17: Chapter 10 Key Management;  Other Public Key Cryptosystems

Diffie-Hellman Key Exchange• a public-key distribution scheme

– cannot be used to exchange an arbitrary message – rather it can establish a common key – known only to the two participants

• value of key depends on the participants (and their private and public key information)

• based on exponentiation in a finite (Galois) field (modulo a prime or a polynomial) - easy

• security relies on the difficulty of computing discrete logarithms (similar to factoring) – hard

Page 18: Chapter 10 Key Management;  Other Public Key Cryptosystems
Page 19: Chapter 10 Key Management;  Other Public Key Cryptosystems
Page 20: Chapter 10 Key Management;  Other Public Key Cryptosystems

Diffie-Hellman Example • users Alice & Bob who wish to swap keys:• agree on prime q=353 and α=3• select random secret keys:

– A chooses xA=97, B chooses xB=233• compute public keys:

– yA=397 mod 353 = 40 (Alice)– yB=3233 mod 353 = 248 (Bob)

• compute shared session key as:KAB= yB

xA mod 353 = 24897 = 160 (Alice)

KAB= yAxB mod 353 = 40233 = 160 (Bob)

Page 21: Chapter 10 Key Management;  Other Public Key Cryptosystems

ElGamal Public Key Cryptosystem • security relies on the difficulty of computing discrete

logarithms (similar to factoring) – hard• User Alice wants to send a message m to Bob• Bob: q - prime number - a primitive root of q X - private key = X mod q – public key• Alice:

– Downloads (, q, )– Chooses a secret random integer k– Encryption: r k mod q; t km mod q– Send (r, t)=(k, km) to Alice

• Bob:– Decryption: t/rX = m

Page 22: Chapter 10 Key Management;  Other Public Key Cryptosystems

Elliptic Curve Cryptography• majority of public-key crypto (RSA, D-H) use

either integer or polynomial arithmetic with very large numbers/polynomials

• imposes a significant load in storing and processing keys and messages

• an alternative is to use elliptic curves• offers same security with smaller bit sizes• Certain conventional systems with a 4096-bit

key size can be replaced by 313-bit elliptic curve system.

Page 23: Chapter 10 Key Management;  Other Public Key Cryptosystems

Elliptic Curves Over Real Number• an elliptic curve is defined by an equation in two

variables x & y, with coefficients• consider a cubic elliptic curve E(a, b) of

– y2 = x3 + ax + b – 4a3 + 27b2 0 to form a group– where x,y,a,b are all real numbers– O: the point at infinity (or be called as zero point)

• have addition operation for elliptic curve– geometrically sum of P+Q is reflection of the line L

through P and Q intersecting E– If P=Q then L is the tangent line of P

Page 24: Chapter 10 Key Management;  Other Public Key Cryptosystems
Page 25: Chapter 10 Key Management;  Other Public Key Cryptosystems
Page 26: Chapter 10 Key Management;  Other Public Key Cryptosystems

Elliptic Curves Over Real Number

• O: point at infinity (or be called as zero point)• O: additive identity

– O = -O – P+O=P

• P=(x, y), -P=(x, -y); P+(-P)=O• P=(x, 0), 2P=O, 3P=P, 4P=O, …• P+Q+R=O P, Q, R are collinear• Associative: (P+Q)+R=P+(Q+R)• Commutative: P+Q=Q+P

Page 27: Chapter 10 Key Management;  Other Public Key Cryptosystems

Elliptic Curves Over Real Number

E(a, b)= y2 = x3 + ax + b P1=(x1, y1), P2=(x2, y2), P1+P2=P3=(x3, y3) x3=m2-x1-x2

y3=m(x1-x3)-y1

if P1P2 then m=(y2-y1)/(x2-x1) if P1=P2 then m=(3x1

2+ a)/2y1

If m= then P3=O

Page 28: Chapter 10 Key Management;  Other Public Key Cryptosystems

Finite Elliptic Curves

• Elliptic curve cryptography uses curves whose variables & coefficients are finite

• have two families commonly used:– prime curves Ep(a,b) defined over Zp

• use integers modulo a prime• best in software

– binary curves E2m(a,b) defined over GF(2n)• use polynomials with binary coefficients• best in hardware

Page 29: Chapter 10 Key Management;  Other Public Key Cryptosystems

Elliptic Curves over Zp

prime curves Ep(a,b) defined over Zp – y2 mod p = (x3 + ax + b) mod p – a,b: nonnegative integer and less than p– (4a3 + 27b2) mod p 0 to form a group– P(x, y): x and y are nonnegative integers and

less than p– (x, y) Ep(a,b) (x, -y) Ep(a,b)

Page 30: Chapter 10 Key Management;  Other Public Key Cryptosystems

Elliptic Curves over Zp

prime curves Ep(a,b): y2 = (x3 + ax + b) – For each x (0x<p), calculate (x3 + ax + b) mod p– if (x3 + ax + b) is a square mod p then there are two

square roots: y and –y. i.e. (x, y)Ep&(x, -y)Ep

Ex: E23(1,1): y2 = (x3 + x + 1) mod 23

The number of points NEp is bounded by

For large p, N is approximately equal to p+1 points.

ppNpp 2121

Page 31: Chapter 10 Key Management;  Other Public Key Cryptosystems
Page 32: Chapter 10 Key Management;  Other Public Key Cryptosystems
Page 33: Chapter 10 Key Management;  Other Public Key Cryptosystems

Elliptic Curves Over Zp

Ep(a, b): y2 = x3 + ax + b (mod p), p5 is prime

P1=(x1, y1), P2=(x2, y2), P1+P2=P3=(x3, y3)

x3=(m2-x1-x2 ) mod p y3=(m(x1-x3)-y1) mod p if P1P2 then m=((y2-y1)/(x2-x1)) mod p if P1=P2 then m=((3x1

2+ a)/2y1) mod p

If m= then P3=O

Page 34: Chapter 10 Key Management;  Other Public Key Cryptosystems

Elliptic Curves Over Zp

E23(1, 1): y2 = x3 + x + 1 (mod 23)P1=(3, 10), P2=(9, 7),P1+P2=(m2-x1-x2 , m(x1-x3)-y1)=(17, 20) m=(y2-y1)/(x2-x1)=7-10/9-3=-1/2=11

P1=(3, 10), P2=(3, 10),P1+P2=(m2-x1-x2 , m(x1-x3)-y1)=(7, 12) m=(3x1

2+ a)/2y1=(3*32 + 1)/2*10=1/4=6

Page 35: Chapter 10 Key Management;  Other Public Key Cryptosystems

Elliptic Curve Cryptography• ECC addition is analog of modulo multiply• ECC multiplication is analog of modulo

exponentiation

Page 36: Chapter 10 Key Management;  Other Public Key Cryptosystems

Elliptic Curve Cryptography• ECC

– given k, P, find Q=kP EASY– given Q, P, find k HARD– known as the elliptic curve logarithm problem

• RSA– Given two primes p, q, find N=p*q EASY– Given N, find p, q HARD– known as factoring problem

• Diffle-Hellman– Given p, k, find q=pk EASY– Given q, p find k HARD– known as discrete logarithm problem

Page 37: Chapter 10 Key Management;  Other Public Key Cryptosystems

ECC Diffie-Hellman

• can do key exchange analogous to D-H• users select a suitable curve Ep(a,b)

• select a base point (Generator) G=(x1,y1) with large order n s.t. nG=O

• A & B select private keys nA<n, nB<n

• compute public keys: PA=nA×G, PB=nB×G

• compute shared key: K=nA×PB, K=nB×PA

– same since K=nA×nB×G

Page 38: Chapter 10 Key Management;  Other Public Key Cryptosystems
Page 39: Chapter 10 Key Management;  Other Public Key Cryptosystems

ECC Diffie-Hellman

E211(0, -4): y2 = x3 - 4 (mod 211)G=(2, 2) 240G=O nA=121, nB=203

compute public keys: PA=nA×G=(115, 48)

PB=nB×G=(130, 203)

compute shared key: K=nA×PB =(161, 69)

K=nB×PA =(161, 69)

Page 40: Chapter 10 Key Management;  Other Public Key Cryptosystems

ECC Encryption/Decryption• several alternatives, will consider simplest• must first encode any message M as a point on the

elliptic curve Pm

• select suitable curve & point G as in D-H• each user chooses private key nA<n

• and computes public key PA=nA*G

• to encrypt Pm : Cm={kG, Pm+k*Pb}, k random

• to decrypt Cm : Pm+kPb–nB(kG) = Pm+k(nBG)–nB(kG) = Pm

Page 41: Chapter 10 Key Management;  Other Public Key Cryptosystems

ElGamal using ECC Encryption/Decryption

E11(1, 6): y2 = x3 + x + 6 (mod 11) G=(2, 7)M=(10, 9)

nA=7,PA=nA*G=(7,2)

to encrypt M : k=3 Cm={kG,M+k*PA}={(8,3), (10,2)}

To decrypt Cm : M+kPA–nA(kG)=(10,2)–(3,5)=(10,2)+(3,6)=(10,9)

Page 42: Chapter 10 Key Management;  Other Public Key Cryptosystems

Menezes-Vanstone ECC Encryption/Decryption

• M =(m1, m2)• select suitable curve & point G as in D-H• each user chooses private key nA<n• and computes public key PA=nA*G• to encrypt M : Cm={kG, c1, c2}, k random kPA=(x, y)=k*nA*G c1 =x*m1 mod p c2 =y*m2 mod p• to decrypt Cm :

kG*nA =(x, y) (x-1, y-1)(c1*x-1, c2*y-1)= (m1, m2) = M

Page 43: Chapter 10 Key Management;  Other Public Key Cryptosystems

Menezes-Vanstone ECC Encryption/Decryption

E11(1, 6): y2 = x3 + x + 6 (mod 11); G=(2, 7); M=(9, 1)

nA=7,PA=nA*G=(7,2)to encrypt M : k=6 Cm={kG, c1, c2}= {(7, 9), 6, 3} kG=6(2, 7)=(7, 9) kPA=6(7, 2)=(8, 3) c1 =x*m1 mod p = 8*9 mod 11=6 c2 =y*m2 mod p = 3*1 mod 11=3to decrypt Cm : kG*nA =7(7,9)=(8,3) (x-1,y-1)=(7,4) (c1*x-1, c2*y-1)=(6*7, 4*3)=(9, 1)

Page 44: Chapter 10 Key Management;  Other Public Key Cryptosystems

ECC Security

• relies on elliptic curve logarithm problem• fastest method is “Pollard rho method”• compared to factoring, can use much

smaller key sizes than with RSA etc• for equivalent key lengths computations

are roughly equivalent• hence for similar security ECC offers

significant computational advantages

Page 45: Chapter 10 Key Management;  Other Public Key Cryptosystems