chapter 14 acids and bases table of contents · acids 1. aqueous solutions of acids have a sour...
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Table of Contents
Chapter 14 Acids and Bases
Section 1 Properties of Acids and Bases
Section 2 Acid-Base Theories
Section 3 Acid-Base Reactions
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Lesson Starter
• The solutions in the beakers are different because
they have a different pH.
• One beaker contains a basic solution and the other
beaker contains an acidic solution
Chapter 14 Section 1 Properties of Acids and
Bases
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Objectives
• List five general properties of aqueous acids and
bases.
• Name common binary acids and oxyacids, given
their chemical formulas.
• List five acids commonly used in industry and the
laboratory, and give two properties of each.
• Define acid and base according to Arrhenius’s theory
of ionization.
• Explain the differences between strong and weak
acids and bases.
Chapter 14 Section 1 Properties of Acids and
Bases
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Acids
1. Aqueous solutions of acids have a sour taste.
2. Acids change the color of acid-base indicators.
3. Some acids react with active metals and release
hydrogen gas, H2.
Ba(s) + H2SO4(aq) BaSO4(s) + H2(g)
Chapter 14 Section 1 Properties of Acids and
Bases
4. Acids react with bases to produce salts and water.
5. Acids conduct electric current.
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Visual Concepts
Properties of Acids
Chapter 14
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Acids, continued Acid Nomenclature
• A binary acid is an acid that contains only two
different elements: hydrogen and one of the more
electronegative elements.
• HF, HCl, HBr, and HI
• Binary Acid Nomenclature
1. The name of a binary acid begins with the prefix
hydro-.
2. The root of the name of the second element
follows this prefix.
3. The name then ends with the suffix -ic.
Chapter 14 Section 1 Properties of Acids and
Bases
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Acids, continued Acid Nomenclature, continued
Chapter 14 Section 1 Properties of Acids and
Bases
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Acids, continued Acid Nomenclature, continued
• An oxyacid is an acid that is a compound of
hydrogen, oxygen, and a third element, usually a
nonmetal.
• HNO3, H2SO4
• The names of oxyacids follow a pattern.
• The names of their anions are based on the names of
the acids.
Chapter 14 Section 1 Properties of Acids and
Bases
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Acids, continued Acid Nomenclature, continued
Chapter 14 Section 1 Properties of Acids and
Bases
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Some Common Industrial Acids
• Sulfuric Acid • Sulfuric acid is the most commonly produced industrial
chemical in the world.
• Nitric Acid
• Phosphoric Acid
• Hydrochloric Acid
• Concentrated solutions of hydrochloric acid are commonly
referred to as muriatic acid.
• Acetic Acid
• Pure acetic acid is a clear, colorless, and pungent-smelling
liquid known as glacial acetic acid.
Chapter 14 Section 1 Properties of Acids and
Bases
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Bases
1. Aqueous solutions of bases taste bitter.
2. Bases change the color of acid-base indicators.
3. Dilute aqueous solutions of bases feel slippery.
4. Bases react with acids to produce salts and water.
5. Bases conduct electric current.
Chapter 14 Section 1 Properties of Acids and
Bases
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Visual Concepts
Properties of Bases
Chapter 14
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Arrhenius Acids and Bases
• An Arrhenius acid is a chemical compound that
increases the concentration of hydrogen ions, H+, in
aqueous solution.
• An Arrhenius base is a substance that increases the
concentration of hydroxide ions, OH−, in aqueous
solution.
Chapter 14 Section 1 Properties of Acids and
Bases
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Arrhenius Acids and Bases, continued Aqueous Solutions of Acids
• Arrhenius acids are molecular compounds with
ionizable hydrogen atoms.
• Their water solutions are known as aqueous acids.
• All aqueous acids are electrolytes.
Chapter 14 Section 1 Properties of Acids and
Bases
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Arrhenius Acids and Bases, continued Aqueous Solutions of Acids, continued
• Common Aqueous Acids
Chapter 14 Section 1 Properties of Acids and
Bases
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Arrhenius Acids and Bases, continued Strength of Acids
• A strong acid is one that ionizes completely in
aqueous solution.
• a strong acid is a strong electrolyte
• HClO4, HCl, HNO3
• A weak acid releases few hydrogen ions in aqueous
solution.
• hydronium ions, anions, and dissolved acid
molecules in aqueous solution
• HCN
• Organic acids (—COOH), such as acetic acid
Chapter 14 Section 1 Properties of Acids and
Bases
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Arrhenius Acids and Bases, continued Aqueous Solutions of Bases
• Most bases are ionic compounds containing metal
cations and the hydroxide anion, OH−.
• dissociate in water
s aq + aq2H O –NaOH( ) Na ( ) OH ( )
aq + l aq + aq–
3 2 4NH ( ) H O( ) NH ( ) OH ( )
Chapter 14 Section 1 Properties of Acids and
Bases
• Ammonia, NH3, is molecular
• Ammonia produces hydroxide ions when it reacts
with water molecules.
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Arrhenius Acids and Bases, continued Strength of Bases
• The strength of a base depends on the extent to
which the base dissociates.
• Strong bases are strong electrolytes
Chapter 14 Section 1 Properties of Acids and
Bases
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Relationship of [H3O+] to [OH–]
Chapter 14 Section 1 Properties of Acids and
Bases
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Lesson Starter
• List three terms that describe the person in the
photo.
• The person has been described in many different
ways, but he or she is still the same person.
• Acids and bases also can be described differently
based on the circumstances.
Chapter 14 Section 2 Acid-Base Theories
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Objectives
• Define and recognize Brønsted-Lowry acids and
bases.
• Define a Lewis acid and a Lewis base.
• Name compounds that are acids under the Lewis
definition but are not acids under the Brønsted-Lowry
definition.
Chapter 14 Section 2 Acid-Base Theories
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Brønsted-Lowry Acids and Bases
• A Brønsted-Lowry acid is a molecule or ion that is a
proton donor.
• Hydrogen chloride acts as a Brønsted-Lowry acid
when it reacts with ammonia.
+ –
3 4HCl NH NH Cl
l + aq aq + aq–
2 3 4H O( ) NH ( ) NH ( ) OH ( )
Chapter 14 Section 2 Acid-Base Theories
• Water can act as a Brønsted-Lowry acid.
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Brønsted-Lowry Acids and Bases, continued
• A Brønsted-Lowry base is a molecule or ion that is
a proton acceptor.
• Ammonia accepts a proton from the hydrochloric
acid. It acts as a Brønsted-Lowry base.
+ –
3 4HCl NH NH Cl
Chapter 14 Section 2 Acid-Base Theories
• The OH− ion produced in solution by Arrhenius
hydroxide bases (NaOH) is the Brønsted-Lowry
base.
• The OH− ion can accept a proton
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Brønsted-Lowry Acids and Bases, continued
• In a Brønsted-Lowry acid-base reaction, protons
are transferred from one reactant (the acid) to
another (the base).
+ –
3 4HCl NH NH Cl
Chapter 14 Section 2 Acid-Base Theories
acid base
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Monoprotic and Polyprotic Acids
• A monoprotic acid is an acid that can donate only
one proton (hydrogen ion) per molecule.
• HClO4, HCl, HNO3
• only one ionization step
g + l) aq + aq–
2 3HCl( ) H O( H O ( ) Cl ( )
Chapter 14 Section 2 Acid-Base Theories
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Monoprotic and Diprotic Acids
Chapter 14 Section 2 Acid-Base Theories
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Monoprotic and Polyprotic Acids, continued
• A polyprotic acid is an acid that can donate more
than one proton per molecule.
• H2SO4, H3PO4
• Multiple ionization steps
l + l aq + aq–
2 4 2 3 4H SO ( ) H O( ) H O ( ) HSO ( )
aq + l aq + l– 2–
4 2 3 4HSO ( ) H O( ) H O ( ) SO ( )
– 2–
4 4HSO and SO
Chapter 14 Section 2 Acid-Base Theories
(1)
(2)
• Sulfuric acid solutions contain H3O+,
ions
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Monoprotic and Polyprotic Acids, continued
• A diprotic acid is the type of polyprotic acid that can
donate two protons per molecule
• H2SO4
• A triprotic acid is the type of polyprotic acid that can
donate three protons per molecule.
• H3PO4
Chapter 14 Section 2 Acid-Base Theories
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Lewis Acids and Bases
• A Lewis acid is an atom, ion, or molecule that
accepts an electron pair to form a covalent bond.
• The Lewis definition is the broadest of the three
acid definitions.
• A bare proton (hydrogen ion) is a Lewis acid
aq + aq aq aq3 3 4H ( ) :NH ( ) [H—NH ] ( ) or [NH ] ( )
Chapter 14 Section 2 Acid-Base Theories
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Lewis Acids and Bases, continued
• The formula for a Lewis acid need not include
hydrogen.
• The silver ion can be a Lewis acid
aq + aq aq 3 3 3 3 2Ag ( ) 2 :NH ( ) [H N— Ag —NH ] ( ) or [Ag(NH ) ]
aq aq aq– –
3 4BF ( ) F ( ) BF ( )
Chapter 14 Section 2 Acid-Base Theories
• Any compound in which the central atom has three
valence electrons and forms three covalent bonds
can react as a Lewis acid.
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•A Lewis base is an atom, ion, or molecule that donates
an electron pair to form a covalent bond.
•Look for a negative charge on the molecule or ion
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Lewis Acids and Bases, continued Acid Base Definitions
Chapter 14 Section 2 Acid-Base Theories
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Lesson Starter
• What is the meaning of the word neutralization.
• How is the word used in everyday life?
• How is it likely to apply to acids and bases?
Chapter 14 Section 3 Acid-Base Reactions
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Objectives
• Describe a conjugate acid, a conjugate base, and an
amphoteric compound.
• Explain the process of neutralization.
• Define acid rain, give examples of compounds that
can cause acid rain, and describe effects of acid rain.
Chapter 14 Section 3 Acid-Base Reactions
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Conjugate Acids and Bases
• The species that remains after a Brønsted-Lowry
acid has given up a proton is the conjugate base of
that acid.
aq + l aq + aq–
2 3HF( ) H O( ) F ( ) H O ( )
Chapter 14 Section 3 Acid-Base Reactions
acid conjugate
base
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Conjugate Acids and Bases, continued
• Brønsted-Lowry acid-base reactions involve two
acid-base pairs, known a conjugate acid-base pairs.
aq + l aq + aq–
2 3HF( ) H O( ) F ( ) H O ( )
Chapter 14 Section 3 Acid-Base Reactions
acid1 base2 base1 acid2
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Neutralization Reactions
Chapter 14 Section 3 Acid-Base Reactions
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Conjugate Acids and Bases, continued Strength of Conjugate Acids and Bases
• The stronger an acid is, the weaker its conjugate
base • The stronger a base is, the weaker its conjugate acid
g + l aq + aq–
2 3HCl( ) H O( ) H O ( ) Cl ( )
Chapter 14 Section 3 Acid-Base Reactions
strong acid base acid weak base
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Conjugate Acids and Bases, continued Strength of Conjugate Acids and Bases, continued
• Proton transfer reactions favor the production of the
weaker acid and the weaker base.
aq + l aq + aq–
4 2 3 4HClO ( ) H O( ) H O ( ) ClO ( )
aq + l aq + aq–
3 2 3 3CH COOH( ) H O( ) H O ( ) CH COO ( )
Chapter 14 Section 3 Acid-Base Reactions
stronger acid stronger base weaker acid weaker base
• The reaction to the right is more favorable
weaker acid weaker base stronger acid stronger base
• The reaction to the left is more favorable
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Relative Strengths of Acids and Bases
Chapter 14 Section 3 Acid-Base Reactions
Relative Strengths of Acids and Bases
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Amphoteric Compounds
• Any species that can react as either an acid or a
base is described as amphoteric.
• example: water
• water can act as a base
aq + l aq + aq–
2 4 2 3 4H SO ( ) H O( ) H O ( ) HSO ( )
g + l aq aq–
3 2 4NH ( ) H O( ) NH ( ) OH ( )
Chapter 14 Section 3 Acid-Base Reactions
acid1 base2 acid2 base1
• water can act as an acid
base1 acid2 acid1 base2
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Amphoteric Compounds, continued –OH in a Molecule
• The covalently bonded OH group in an acid is
referred to as a hydroxyl group.
• Molecular compounds containing —OH groups can
be acidic or amphoteric.
• The behavior of a compound is affected by the
number of oxygen atoms bonded to the atom
connected to the —OH group.
Chapter 14 Section 3 Acid-Base Reactions
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Oxyacids of Chlorine
Chapter 14 Section 3 Acid-Base Reactions
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Neutralization Reactions Strong Acid-Strong Base Neutralization
• In aqueous solutions, neutralization is the reaction
of hydronium ions and hydroxide ions to form water
molecules.
• A salt is an ionic compound composed of a cation
from a base and an anion from an acid.
2aq + aq aq lHCl( ) NaOH( ) NaCl( ) H O( )
Chapter 14 Section 3 Acid-Base Reactions
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Acid Rain
• NO, NO2, CO2, SO2, and SO3 gases from industrial
processes can dissolve in atmospheric water to
produce acidic solutions.
g + l aq3 2 2 4SO ( ) H O( ) H SO ( )
Chapter 14 Section 3 Acid-Base Reactions
• example:
• Very acidic rain is known as acid rain.
• Acid rain can erode statues and affect ecosystems.
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Visual Concepts
Acid Precipitation
Chapter 14
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Objectives
• Describe the self-ionization of water.
• Define pH, and give the pH of a neutral solution at
25°C.
• Explain and use the pH scale.
• Given [H3O+] or [OH−], find pH.
• Given pH, find [H3O+] or [OH−].
Chapter 15 Section 1 Aqueous Solutions and
the Concept of pH
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Hydronium Ions and Hydroxide Ions
Self-Ionization of Water
• In the self-ionization of water, two water molecules
produce a hydronium ion and a hydroxide ion by
transfer of a proton.
l + l aq + aq–
2 2 3H O( ) H O( ) H O ( ) OH ( )
Chapter 15 Section 1 Aqueous Solutions and
the Concept of pH
• In water at 25°C, [H3O+] = 1.0 ×10−7 M and [OH−] =
1.0 × 10−7 M.
• The ionization constant of water, Kw, is expressed by
the following equation.
Kw = [H3O+][OH−]
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Hydronium Ions and Hydroxide Ions, continued
Self-Ionization of Water, continued
• At 25°C,
Kw = [H3O+][OH−] = (1.0 × 10−7)(1.0 × 10−7) = 1.0 × 10−14
• Kw increases as temperature increases
Chapter 15 Section 1 Aqueous Solutions and
the Concept of pH
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Hydronium Ions and Hydroxide Ions, continued
Neutral, Acidic, and Basic Solutions
• Solutions in which [H3O+] = [OH−] is neutral.
• Solutions in which the [H3O+] > [OH−] are acidic.
• [H3O+] > 1.0 × 10−7 M
• Solutions in which the [OH−] > [H3O+] are basic.
• [OH−] > 1.0 × 10−7 M
Chapter 15 Section 1 Aqueous Solutions and
the Concept of pH
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Hydronium Ions and Hydroxide Ions, continued
Calculating [H3O+] and [OH–]
• Strong acids and bases are considered completely
ionized or dissociated in weak aqueous solutions.
s aq + aq2H O –NaOH( ) Na ( ) OH ( )
-14 -14
-12
3 – -2
1.0 10 1.0 10[H O ] 1.0 10 M
[OH ] 1.0 10
Chapter 15 Section 1 Aqueous Solutions and
the Concept of pH
1 mol 1 mol 1 mol
• 1.0 × 10−2 M NaOH solution has an [OH−] of 1.0 × 10−2 M
• The [H3O+] of this solution is calculated using Kw.
Kw = [H3O+][OH−] = 1.0 × 10−14
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Hydronium Ions and Hydroxide Ions, continued
Calculating [H3O+] and [OH–]
• If the [H3O+] of a solution is known, the [OH−] can be
calculated using Kw.
[HCl] = 2.0 × 10−4 M
[H3O+] = 2.0 × 10−4 M
Kw = [H3O+][OH−] = 1.0 × 10−14
-14 -14
– -10
-4
3
1.0 10 1.0 10[OH ] 5.0 10 M
[H O ] 2.0 10
Chapter 15 Section 1 Aqueous Solutions and
the Concept of pH
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Some Strong Acids and Some Weak Acids
Chapter 15 Section 1 Aqueous Solutions and
the Concept of pH
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Concentrations and Kw
Chapter 15 Section 1 Aqueous Solutions and
the Concept of pH
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Hydronium Ions and Hydroxide Ions,
continued Calculating [H3O
+] and [OH–]
Sample Problem A
A 1.0 10–4 M solution of HNO3 has been prepared for a
laboratory experiment.
a. Calculate the [H3O+] of this solution.
b. Calculate the [OH–].
Chapter 15 Section 1 Aqueous Solutions and
the Concept of pH
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Sample Problem A Solution Given: Concentration of the solution = 1.0 × 10−4 M HNO3
Unknown: a. [H3O+]
b. [OH−]
Solution:
• HNO3 is a strong acid
l + l aq + aq–
3 2 3 3HNO ( ) H O( ) H O ( ) NO ( )
3
3
mol HNOmolarity of HNO
1 L solution
Chapter 15 Section 1 Aqueous Solutions and
the Concept of pH
a. 1 mol 1 mol 1 mol 1 mol
Hydronium Ions and Hydroxide Ions,
continued Calculating [H3O
+] and [OH–], continued
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Sample Problem A Solution, continued
3 3 33
3
mol HNO 1 mol H O mol H Omolarity of H O
L solution 1 mol HNO L solution
–14–
3
1.0 10[OH ]
[H O ]
Chapter 15 Section 1 Aqueous Solutions and
the Concept of pH
a.
b. [H3O+][OH−] = 1.0 × 10−14
Hydronium Ions and Hydroxide Ions,
continued Calculating [H3O
+] and [OH–], continued
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Sample Problem A Solution, continued
–4
3 3
3
–4–3 4
3
1.0 10 mol HNO 1 mol H O
1 L solution 1 mol HNO
1.0 10 mol H O
1 L solution1.0 10 M H O
Hydronium Ions and Hydroxide Ions,
continued Calculating [H3O
+] and [OH–], continued
-10
–14 –14–
-4
3
1.0 10 1.0 10[OH ]
[H O ] 1.0 101.0 10 M
Chapter 15 Section 1 Aqueous Solutions and
the Concept of pH
a.
b.
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The pH Scale
• The pH of a solution is defined as the negative of the
common logarithm of the hydronium ion concentration,
[H3O+].
pH = −log [H3O+]
• example: a neutral solution has a [H3O+] = 1×10−7
• The logarithm of 1×10−7 is −7.0.
pH = −log [H3O+] = −log(1 × 10−7) = −(−7.0) = 7.0
Chapter 15 Section 1 Aqueous Solutions and
the Concept of pH
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pH Values as Specified [H3O+]
Chapter 15 Section 1 Aqueous Solutions and
the Concept of pH
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The pH Scale
• The pOH of a solution is defined as the negative of the
common logarithm of the hydroxide ion concentration,
[OH−].
pOH = −log [OH–]
• example: a neutral solution has a [OH–] = 1×10−7
• The pH = 7.0.
• The negative logarithm of Kw at 25°C is 14.0.
pH + pOH = 14.0
Chapter 15 Section 1 Aqueous Solutions and
the Concept of pH
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Visual Concepts
pOH
Chapter 15
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The pH Scale
Chapter 15 Section 1 Aqueous Solutions and
the Concept of pH
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Approximate pH Range of Common Materials
Chapter 15 Section 1 Aqueous Solutions and
the Concept of pH
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[H3O+], [OH–], pH and pOH of Solutions
Chapter 15 Section 1 Aqueous Solutions and
the Concept of pH
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Visual Concepts
Comparing pH and pOH
Chapter 15
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Calculations Involving pH
• There must be as many significant figures to the right
of the decimal as there are in the number whose
logarithm was found.
• example: [H3O+] = 1 × 10−7
one significant figure
pH = 7.0
Chapter 15 Section 1 Aqueous Solutions and
the Concept of pH
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Using Logarithms in pH Calculations
Chapter 15 Section 1 Aqueous Solutions and
the Concept of pH
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Calculations Involving pH, continued
Calculating pH from [H3O+], continued
Sample Problem B
What is the pH of a 1.0 10–3 M NaOH solution?
Chapter 15 Section 1 Aqueous Solutions and
the Concept of pH
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–14 –14-11
3 – -3
1.0 10 1.0 10[H O ] 1.0 10 M
[OH ] 1.0 10
Chapter 15 Section 1 Aqueous Solutions and
the Concept of pH
Sample Problem B Solution
Given: Identity and concentration of solution = 1.0 × 10−3 M NaOH
Unknown: pH of solution
Solution: concentration of base → concentration of OH−
→ concentration of H3O+ → pH
[H3O+][OH−] = 1.0 × 10−14
pH = −log [H3O+] = −log(1.0 × 10−11) = 11.00
Calculations Involving pH, continued
Calculating pH from [H3O+], continued
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• pH = −log [H3O+]
• log [H3O+] = −pH
• [H3O+] = antilog (−pH)
• [H3O+] = 10−pH
• The simplest cases are those in which pH values are
integers.
Chapter 15 Section 1 Aqueous Solutions and
the Concept of pH
Calculations Involving pH, continued
Calculating pH from [H3O+], continued
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Calculations Involving pH, continued
Calculating [H3O+] and [OH–] from pH, continued
Sample Problem D
Determine the hydronium ion concentration of an
aqueous solution that has a pH of 4.0.
Chapter 15 Section 1 Aqueous Solutions and
the Concept of pH
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Calculations Involving pH, continued
Calculating [H3O+] and [OH–] from pH, continued
Sample Problem D Solution
Given: pH = 4.0
Unknown: [H3O+]
Solution:
[H3O+] = 10−pH
[H3O+] = 1 × 10−4 M
Chapter 15 Section 1 Aqueous Solutions and
the Concept of pH
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Calculations Involving pH, continued
pH Calculations and the Strength of Acids and Bases
• The pH of solutions of weak acids and weak bases
must be measured experimentally.
• The [H3O+] and [OH−] can then be calculated from the
measured pH values.
Chapter 15 Section 1 Aqueous Solutions and
the Concept of pH
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pH of Strong and Weak Acids and Bases
Chapter 15 Section 1 Aqueous Solutions and
the Concept of pH
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pH Values of Some Common Materials
Chapter 15 Section 1 Aqueous Solutions and
the Concept of pH
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Objectives
• Describe how an acid-base indicator functions.
• Explain how to carry out an acid-base titration.
• Calculate the molarity of a solution from titration
data.
Chapter 15 Section 2 Determining pH and
Titrations
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Indicators and pH Meters
• Acid-base indicators are compounds whose colors
are sensitive to pH.
• Indicators change colors because they are either
weak acids or weak bases.
– In + InH H
Chapter 15 Section 2 Determining pH and
Titrations
• HIn and In− are different colors.
• In acidic solutions, most of the indicator is HIn
• In basic solutions, most of the indicator is In–
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Indicators and pH Meters
• The pH range over which an indicator changes color
is called its transition interval.
• Indicators that change color at pH lower than 7 are
stronger acids than the other types of indicators.
• They tend to ionize more than the others.
• Indicators that undergo transition in the higher pH
range are weaker acids.
Chapter 15 Section 2 Determining pH and
Titrations
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Indicators and pH Meters
• A pH meter determines the pH of a solution by
measuring the voltage between the two electrodes
that are placed in the solution.
• The voltage changes as the hydronium ion
concentration in the solution changes.
• Measures pH more precisely than indicators
Chapter 15 Section 2 Determining pH and
Titrations
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Color Ranges of Indicators
Chapter 15 Section 2 Determining pH and
Titrations
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Chapter 15 Section 2 Determining pH and
Titrations
Color Ranges of Indicators
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Chapter 15 Section 2 Determining pH and
Titrations
Color Ranges of Indicators
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Titration
• Neutralization occurs when hydronium ions and
hydroxide ions are supplied in equal numbers by
reactants.
H3O+(aq) + OH−(aq) 2H2O(l)
Chapter 15 Section 2 Determining pH and
Titrations
• Titration is the controlled addition and measurement
of the amount of a solution of known concentration
required to react completely with a measured amount
of a solution of unknown concentration.
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Titration, continued
Equivalence Point
• The point at which the two solutions used in a titration
are present in chemically equivalent amounts is the
equivalence point.
• The point in a titration at which an indicator changes
color is called the end point of the indicator.
Chapter 15 Section 2 Determining pH and
Titrations
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Titration, continued
Equivalence Point, continued
• Indicators that undergo transition at about pH 7 are
used to determine the equivalence point of strong-
acid/strong base titrations.
• The neutralization of strong acids with strong bases
produces a salt solution with a pH of 7.
Chapter 15 Section 2 Determining pH and
Titrations
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Titration, continued
Equivalence Point, continued
• Indicators that change color at pH lower than 7 are
used to determine the equivalence point of strong-
acid/weak-base titrations.
• The equivalence point of a strong-acid/weak-base
titration is acidic.
Chapter 15 Section 2 Determining pH and
Titrations
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Titration, continued
Equivalence Point, continued
• Indicators that change color at pH higher than 7 are
used to determine the equivalence point of weak-
acid/strong-base titrations.
• The equivalence point of a weak-acid/strong-base
titration is basic.
Chapter 15 Section 2 Determining pH and
Titrations
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Titration Curve
for a Strong Acid
and a Strong
Base
Chapter 15 Section 2 Determining pH and
Titrations
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Titration Curve
for a Weak Acid
and a Strong
Base
Chapter 15 Section 2 Determining pH and
Titrations
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Molarity and Titration
• The solution that contains the precisely known
concentration of a solute is known as a standard
solution.
• A primary standard is a highly purified solid
compound used to check the concentration of the
known solution in a titration
• The standard solution can be used to determine the
molarity of another solution by titration.
Chapter 15 Section 2 Determining pH and
Titrations
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Performing a Titration, Part 1
Chapter 15 Section 2 Determining pH and
Titrations
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Performing a Titration, Part 1
Chapter 15 Section 2 Determining pH and
Titrations
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Performing a Titration, Part 1
Chapter 15 Section 2 Determining pH and
Titrations
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Performing a Titration, Part 2
Chapter 15 Section 2 Determining pH and
Titrations
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Performing a Titration, Part 2
Chapter 15 Section 2 Determining pH and
Titrations
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Performing a Titration, Part 2
Chapter 15 Section 2 Determining pH and
Titrations
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Molarity and Titration, continued
• To determine the molarity of an acidic solution, 10 mL
HCl, by titration
1. Titrate acid with a standard base solution
20.00 mL of 5.0 × 10−3 M NaOH was titrated
2. Write the balanced neutralization reaction
equation.
HCl(aq) + NaOH(aq) NaCl(aq) + H2O(l)
Chapter 15 Section 2 Determining pH and
Titrations
1 mol 1 mol 1 mol 1 mol
3. Determine the chemically equivalent amounts
of HCl and NaOH.
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Molarity and Titration, continued
4. Calculate the number of moles of NaOH used in
the titration.
• 20.0 mL of 5.0 × 10−3 M NaOH is needed to reach the
end point
-3-45.0 10 mol NaOH 1 L
20 mL 1.0 10 mol NaOH used1 L 1000 mL
-4-21.0 10 mol HCl 1000 mL
1.0 10 M HCl10.0 mL 1 L
Chapter 15 Section 2 Determining pH and
Titrations
5. amount of HCl = mol NaOH = 1.0 × 10−4 mol
6. Calculate the molarity of the HCl solution
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Molarity and Titration, continued
1. Start with the balanced equation for the
neutralization reaction, and determine the
chemically equivalent amounts of the acid and
base.
2. Determine the moles of acid (or base) from the
known solution used during the titration.
3. Determine the moles of solute of the unknown
solution used during the titration.
4. Determine the molarity of the unknown solution.
Chapter 15 Section 2 Determining pH and
Titrations
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Molarity and Titration, continued
Sample Problem F
In a titration, 27.4 mL of 0.0154 M Ba(OH)2 is added to
a 20.0 mL sample of HCl solution of unknown
concentration until the equivalence point is reached.
What is the molarity of the acid solution?
Chapter 15 Section 2 Determining pH and
Titrations
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Molarity and Titration, continued
Ba(OH)2 + 2HCl BaCl2 + 2H2O
1 mol 2 mol 1 mol 2 mol
Chapter 15 Section 2 Determining pH and
Titrations
Sample Problem F Solution
Given: volume and concentration of known solution
= 27.4 mL of 0.0154 M Ba(OH)2
Unknown: molarity of acid solution
Solution:
1. balanced neutralization equation
chemically equivalent amounts
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Molarity and Titration, continued
Sample Problem F Solution, continued
2. volume of known basic solution used (mL)
amount of base used (mol)
2
2 2
mol Ba(OH) 1 LmL of Ba(OH) solution mol Ba(OH)
1 L 1000 mL
2
2
2 mol HClmol of Ba(OH) in known solution mol HCl
mol Ba(OH)
Chapter 15 Section 2 Determining pH and
Titrations
3. mole ratio, moles of base used
moles of acid used from unknown solution
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Molarity and Titration, continued
Sample Problem F Solution, continued
4. volume of unknown, moles of solute in unknown
molarity of unknown
amount of solute in unknown solution (mol) 1000 mL
volume of unknown solution (mL) 1 L
molarity of unknown solution
Chapter 15 Section 2 Determining pH and
Titrations
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Molarity and Titration, continued
Sample Problem F Solution, continued
1. 1 mol Ba(OH)2 for every 2 mol HCl.
22
-4
2
0.0154 mol Ba(OH)24.7 mL of Ba(OH) solution
1 L
1 L4.22 10 mol Ba(OH)
1000 mL
–4
2
2
–4
2 mol HCl4.22 10 mol of Ba(OH)
1 mol Ba(OH)
8.44 10 mol HCl
Chapter 15 Section 2 Determining pH and
Titrations
2.
3.
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Molarity and Titration, continued
Sample Problem F Solution, continued
-2-48.44 10 mol HCl 1000 mL
20.0 m4.22 10
L 1M l
LHC
Chapter 15 Section 2 Determining pH and
Titrations
4.