chapter 3 combustion
TRANSCRIPT
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CHAPTER 3
COMBUSTION
3.1 Introduction
In this chapter is dealing with the system undergoes the chemical changes
during a process, that is, system that involve chemical reaction known as
combustion.
In practical engines and power plants the source of heat is the chemical
energy of substances called fuels. This energy is released during the
chemical reaction of the fuel with oxygen.
The combustion process takes place in the combustion chamber after
initiation of combustion by an ignition device such as an electric spark. The
most convenient source of oxygen supply is from the atmosphere.
Internal combustion engines are run on liquid fuels which are group as
gasoline (petrol), diesel oil and gaseous fuels. here as the power plants run
mainly on kerosene and natural gas.
3.2 Basic Cheistr!
!toms " the smallest particle that take part in chemical reaction e.g. #, $, %,
&, ' etc.
olecules " a combination of atoms that hold together by strong inter
atomic forces $*, %*, '*etc.
+elative molecular mass " relative masses of the atoms which constitute themolecule e.g. $* *, %* -*, '* -*, # *, & -* etc.
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Table -. #hemical compositions of liquid and gases
Co"ound #oru$a Re$ati%e Mo$ecu$ar
Mass
ater/steam $*% (* x ) 0 ( x 1) 2#arbon monoxide #% ( x *) 0 ( x 1) *2
#arbon dioxide #%* ( x *) 0 (* x 1) 33
&ulphur dioxide &%* ( x -*) 0 (* x 1) 13
ethane #$3 ( x *) 0 (3 x ) 1
4thane #*$1 (* x *) 0 (1 x ) -5
6ropane #-$2 (- x *) 0 (2 x ) 33
n7utane #3$5 (3 x *) 0 (5 x ) 82
4thylene #*$3 (* x *) 0 (3 x ) *2
6ropylene #-$1 (- x *) 0 (1 x ) 3*
n6entane #8$* (8 x *) 0 (* x ) 9*7en:ene #1$1 (1 x *) 0 (1 x ) 92
Toluene #9$2 (9 x *) 0 (2 x ) ;*
n%ctane #2$2 (2 x *) 0 (2 x )
3
3.3 #ue$s
!ny materials that can be burned to release thermal energy are calledfuel.
ost familiar fuels are hydrocarbon fuels that consist primarily of
hydrogen and carbon such as coal, gasoline and natural gas.
#oal is a solid fuel contains varying amounts of oxygen, hydrogen,
nitrogen, sulfur, moisture and ash.
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#hemical analysis of fuel is called ultimate analysis analysis by
mass of important elements in the fuel.
>or solid fuels such as coal, proximate analysis that gives percentage
of inherent moisture, volatile matter, and combustible solid also can
be used.
3.& Co'ustions
! chemical reaction during which a fuel is oxidi:ed and a large
amount of energy is released is called combustion.
The oxidi:er most often used in combustion processes is air, for
obvious reasons " it is free and readily available. The composition of
dry air can be approximated to *? of %*and 9;? of '*by molenumbers.
The chemical reaction can be expressed by equation such as@
*$* 0 %* A *$*%
* volume $*0 volume %*A * volumes $*% (based on volume
analysis)
3kg $* 0 -*kg %* A -1kg $*% (based on mass analysis)
%r
kg $* 0 2kg %* A ;kg $*%
%r
*kmol $* 0 kmol %* A *kmol $*%
>or the air used in the combustion processB
******
9;*
*
9;* NOHNOH +++
&ince kmol of oxygen there are 9;/* kmol of nitrogen.
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ratioFAtricstoichiome
ratioFAtricstoichiomeratioFAactual
D/D
D/DD/D =
>or gaseous fuels the ratios are expressed by volume and for solid and liquid
fuels the ratios are expressed by mass.
6etrol engines have to meet various conditions of load and speed, and
operate over a wide range of mixture strengths@
ratioFAactual
ratioFAtricstoichiomestrengthMixture
D/D
D/DD =
The working values range between 25? (weak) and *5? (rich).
E*a"$e 3.1
%ne kmol of octane (#2$2) is burned with air that contains *5kmol of
oxygen. !ssuming the product contain only #%*, $*%, %*, and '*, determine
the mole number each gas in the products and the airfuel ratio for this
combustion process
So$ution+
#hemical equation for this combustion processB
******22 )91.-(*5 wNzOOyHxCONOHC +++++
Thus, from the equation
#@ x 2
$@ *y 2, y ; %@ *x 0 y 0 : 35, : 9.8
'*@ w 98.*
&ubstituting will give@
******22 *.988.9;2)91.-(*5 NOOHCONOHC +++++
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)(2)*(2
*;91.3*5/
+
==fuel
air
m
mFA
*3.*kg air/kg fuel
3., E*haust and #$ue -as Ana$!sis
The products of combustion are mainly gaseous
! sample is taken for analysis cooled down to a temperature which
below the saturation of the steam present. The dew point also can be
calculated as the water vapour condensed@
prod
prod
prodv
prodv Pn
nP
= ,,
>rom the dew point temperature, Tdpcan be obtained from the
steam table for 6v,prod.
&ince the products are gaseous, analysis by volume is usually used
E*a"$e 3.2
! sample of dry anthracite has the following composition by mass,
# ;5? B $ -? B % *.8? B ' ? B & 5.8? B ash -?
#alculate@
(i) the stoichiometric !/> ratio
(ii) the !/> ratio and the dry air and wet analysis of combustion by
mass or by volume, when *5? excess air is supplied
&olution
(i) 4ach constituent for complete combustionB
#arbon@
** COOC + *kg # 0 -*kg %*A 33kg #%*
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%xygen required 5.; x -*/* *.3kg/kg coal
#arbon dioxide produced 5.; x 33/* -.-kg #%*
$ydrogen@
OHOH ***.
* + *kg $*0 1kg %*A 2kg $*% kg $*0 2kg %*A ;kg $*%
%xygen required 5.5- x 2 5.*3kg/kg coal
&team produced 5.5- x ; 5.*9kg/kg coal
&ulphur@
** SOOS + -*kg & 0 -*kg %*A 13kg &%* kg & 0 kg %*A *kg &%*
%xygen required 5.558kg/kg coal
&ulphur dioxide produced * x 5.558 5.5kg/kg coal
#onstituent ass >raction %xygen +equired
(kg/kg coal)
6roduct ass
(kg/kg coal)
#arbon (#)
$ydrogen ($)
&ulphur (&)
%xygen (%)
'itrogen (')
!sh
5.;55
5.5-5
5.558
5.5*8
5.55
5.5-5
*.355
5.*35
5.558
5.5*8
-.-5 (#%*)
5.*9 ($*%)
5.5 (&%*)
5.5('*)
Total oxygen required per kg of coal *.1* kg
Thus, total air required per kg of coal *.1*/5.*-- .*38kg
here air is assumed to contain *-.-? %*by mass
&toichiometric airfuel ratio .*38
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(ii) >or air supply which is *5? in excess,
!ctual !/> ratio .* x .*38 -.3;3@
-.9 6ractical !nalysis of #ombustion 6roduct
In combustion process, it is necessary to analy:e the product of
combustion for study purposes or improvement on the system
any of equipment now are available on the market that provides a
quicker, more accurate, and continuous analysis.
(i) 'ondispersive infrared ('EI+)
The constituent gas is measured by its optical absorption in the infra
red spectrum.
(ii) =as #arbon Eioxide and %xygen +ecorders
! digital instrument that uses to indicate the quality of combustion
process in the boiler
(iii) =as analy:er
! digital instrument that measures the composition of gas products in
ppm or percentage.
-.2 Eissociation
It is found that during adiabatic combustion the maximum
temperature reached is lower than expected.
>or this case, the exothermic combustion process can be reversed if
the temperature is high enough. The reversed process is known as
endothermic.
4xample of the combustion process of carbon dioxide and hydrogen
as follows@
** ** COOCO + and OHOH *** ** +
To obtain relation for chemical equilibrium in terms of the properties
of the individual components, consider a mixture of four chemical
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componentsA " C and# which exist in equilibrium at a specified
T and 6. 'ow consider a reaction which occurs to an infinitesimal
extent during which differential amounts of reactants A and " are
converted to products # and E a t T remaining constant throughout
the process. FanGt $off equilibrium box as shown in >igure -.8 can be
used to study a reversible combustion process@
>igure -.8
a kmol ! 0 b kmol 7 H c kmol # 0 d kmol E
The process may proceed equally well in either direction and the
reversal of the process the heat and work transfers would be reversed
in direction
=
=
*
* lnlnP
P$n
P
Pm%$&
This can be applied to each of the compressors and expanders in the
system
a
AAA
P
P$
P
P$aAoninputwor'&
=
==
..
lnlnDDD
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(
"""
P
P$
P
P$("oninputwor'&
=
==
..
lnlnDDD
c
C
C
CP
P$
P
P$cConinputwor'&
=
==
.
. lnlnDDD
d#
#
#P
P$
P
P$d#oninputwor'&
=
==
lnlnDDD
Therefore the net work output of the system
#C"A &&&&& =
+=
+
+
= + dc(a
(
"
a
A
d
#
c
C
d
#
c
C
(
"
a
A PPP
PP$
P
P
P
P
P
P
P
P$&
lnlnlnlnlnln
&upposed that in second similar system in the same surroundings the
pressure in the equilibrium box is 6 then it will have a net work
output, as
+
= + dc(a
(
"
a
A
d
#
c
CP
PP
PP$&
.lnln
here #C"A PPPPP +++=
>or a combination of two system as shown in >igure -.1 below@
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>igure -.1
The net work output of the system ()(), thus according to the second
law of thermodynamics, . Therefore@
)PP
PP
PP
PP(
"
a
A
d
#
c
C
(
"
a
A
d
#
c
C =
=
)()(
)()(
here J is the thermal equilibrium or dissociation constant.
! standard thermodynamics equilibrium constant, JK, is defined in
dimensionless form by referring each partial pressure to a pressure of bar,
+
=(
"
a
A
d
#
c
C
P
P
P
P
P
P
P
P)
lnlnlnln
%r in general
i
i
i
PP)
= lnln where Li stoichiometric coefficient
These expressions can be applied in the combustion process such as
*** COOCO +
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ith molar proportions for #%, %*, and #%*of , 5.8, and . Thus,
=*
.
*
*
.
*
)(
)(lnln
OCO
CO
PP
PP)
>or the combustion of hydrogen,
OHOH ***.
* +
ith molar proportions , 5.8, and . Thus,
= *.**
*
.
*
)(
)(
OH
OH
PP
PP)
In the combustion of hydrocarbon fuels both of the above reactions may
occur simultaneously and another equilibrium constant can be defined by
dividing
*
.
**
*
.
*
)(
)(
OH
OH
PP
PP
by
*
.
*
*
.
*
)(
)(
OCO
CO
PP
PP
Thus,
=)(
)(
**
*
COH
COOH
PP
PP)
The value of JKcan be used to determine the reaction temperature from the
table.
E*a"$e 3.3
! combustible mixture of carbon monoxide and air which is 5? rich is
compressed to a pressure of 2.*2bar and a temperature of *2*M#. The
mixture is ignited and combustion occurs adiabatically at constant volume.
hen the maximum temperature is attained analysis shows 5.**2kmol of
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#% present for kmol of #% supplied. &how that the maximum temperature
reached is *1;8M#.
So$ution+
)91.-(*)91.-( **
***
** NCONOCO +++
**** 22.22.8.5 NCONOCO +++
!ctual !/> ratio stoichiometric !/> ratio x 55/5
stoichiometric !/> ratio/.
Thus, the actual reactants are
./)22.8.5( ** NOCO ++
ith dissociation there will be some break up of #%*giving #% and %*,
thus
***** )./22.(./)22.8.5( NcO(COaCONOCO +++=++
The question states that b 5.**2, therefore
***** 95;.*22.595;.388.5 NcOCOaCONOCO +++=++
#arbon @ a 0 5.**2 , a 5.99*
%xygen@ 0 (* x 5.388) *a 0 5.**2 0*c , c 5.51;
>or the reaction *** COOCO +
= *.
*
*
.
*
)(
)(
OCO
CO
PP
PP
)
!nd **
*P
n
aPCO = , *
*
Pn
(PCO = , *
**
Pn
cPO =
Therefore
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*
*
cP
Pn
(
a)
= ()
here 6* total pressure at the required temperature n* total amount of substance of products
n* a 0 b 0 c 0 .95; 5.99* 0 5.**2 0 5.51; 0 .95; *.992kmol
!t ignition
6 2.*2bar and T* *9- 0 *2* 888J
$n*P = and *** $n*P = and F constant
Therefore
***$n
$nPP =
here n 0 5.388 0 .95; -.13 and T* *9- 0 *1;8 *;12J
(assuming)
(ar$n$nPP 22.-2
)888(13.-)*;12(992.**2.2
*** ===
&ubstitute in (),
331.-22.-251;.5
922.*
**2.5
99*.5
*
* =
==cP
Pn
(
a)
Therefore, *-9.ln =) , 6* -2.22bar and from the table, the reaction
temperature is *;12J where the assumption made is correct.
3. Entha$"! o/ #oration and Entha$"! o/ Reaction
The molecules of a system possess various forms of energy, such as sensible
energy, latent energy, chemical energy and nuclear energy.
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6rocess which involves chemical reactions will involve changes in chemical
energy and must be considered in energy balance. In absence of nuclear
reactions, kinetic and potential energy changes, the energy balance is
chemstatesys +++ +=
The common practice to choose a reference state is at *8M# and atm. This is
known as the standard reference state, and the properties at this state are
denoted by a superscript NoO.
3..1 Entha$"! o/ Reaction hR
>or combustion processes, the h+is usually referred to as the enthalpy ofcombustion h hc, which represents the amount of heat released during a
steadyflow combustion process when kg (or kmol) of fuel is burnt
completely at a specified temperature and pressure. It is expressed as
rpc hhh =
here hpis the enthalpy of the products and hris the enthalpy of reactants.
It is evident that, hcis a usefull property for analy:ing the combustion
processes. $owever, it is impractical to list the value of hcfor all possible
fuel and fuel mixture. Therefore, a more practical approach would be to have
a fundamental property that would represent the chemical energy of an
element or compound at some reference state. The enthalpy of formation hf
is such a fundamental property which is the enthalpy of substance at a
specified state owing to its chemical composition.
!ll stable elements, such as %*, '*, $*, and # have a :ero value as their
enthalpy of formation at the standard reference state (*8M# and atm). That
is, 5=o
fh for all stable elements.
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%r in terms of enthalpy of combustiono
Ch , energy equation above can be
rewritten as
( ) ( )r
o
rp
o
p
o
c hhnhhnh&/ +=
E*a"$e 3.&
Eetermine the enthalpy of combustion of gaseous propane (#-$2) at *8M#
and atm. !ssume that water in the product is in liquid form.
So$ution+
The stoichiometric equation for this reactionB
*****2- 91.-3-)91.-( aNOHCONOaHC ++++
Thus, rpc hhh = or ( ( 2-** )()()( HCo
fOH
o
fCO
o
fr
o
frp
o
fpc nhnhnhhnhnh +==
Psing the enthalpy table, we get
'mol'-hc /5-5,**5,*)285,5-()2-5,*28(3)8*5,-;-(- =+=
3..3 #or c$osed s!stes
>or a chemically reacting closed system, the conservation of energy relation
can be expressed as
rp 00&/ =
7y definition,
Phu
=
%r Phhhuuu oo
f
oo
f +=+
Thus,
( ) ( )r
oo
frp
oo
fp PhhhnPhhhn&/ ++=
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>or solids and liquids, the 6Q terms are negligible and for gases which
behave as an ideal gas the 6Q terms can be replaced by +T.
E*a"$e 3.(
ethane gas is burnt with the stoichiometric amount of oxygen gas. The
water is the product in the gas phase. Eetermine the heat released or
observed if the reaction occurs at *8M# and atm.
So$ution+
The combustion equation is
OHCOOCH ***3 ** ++
The heat transfer is a steady flow combustion and 5. Thus,
( ) ( )r
oo
frp
oo
fp hhhnhhhn/ ++=
%r ( ) ( ) )5(*)285,93()2*5,*3(*)8*5,-;-( +== rofrpofp hnhn/
25*,-5 kR/kmol #$3
3.1 Adia'atic #$ae Te"erature
The chemical energy loss to surrounding or is used internally to raise the
temperature of the combustion products for the absence of kinetic and
potential energies. &ince no heat loss case, S5 the temperature of products
will reach a maximum which is called the adiabatic flame temperature of the
reaction.
>or steady flow combustion process, the adiabatic flame temperature is
determined from (S5 and 5)@
( ) ( )r
oo
frp
oo
fp hhhnhhhn +=+
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>or the case of no excess air, the adiabatic flame temperature is called the
theoretical adiabatic flame temperature for the fuel. It is the highest
temperature that can be achieved from the fuel used in the combustion.
3.11 Poer P$ant Thera$ E//icienc!
The overall thermal efficiency ois defined as
pliedenergyfuel
outputwor'o
supDD
D=
The fuel energy supplied can be considered either Sgr,6or Snet,6.
>or example, in a plant the boiler efficiency 7is obtained by the followingequation@
PnetPgr
"/or/
fluidtodtransferreHeat
,,
DD
DDD
=
3.12 Practica$ eterination o/ Ca$ori/ic 4a$ues
#alorific value is used to measure the total energy available in the fuels.
&ince, the types of fuel are can be in the forms of solid, liquid and gases.
Thus, the instruments used to determine the calorific value also depend on
the type of fuel. >or solid and liquid fuels are usually tested in a bomb
calorimeter and for gaseous fuels in a 7oysG calorimeter as described briefly
bellows@
(i) &olid and uelsIn a bomb calorimeter combustion occurs at constant volume and is a
nonflow process.
The bomb is a small stainless steel vessel in which a small mass of the
fuel is held in a crucible (see >igure -.*) as a pellet.
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>igure -.* 7omb #alorimeter
The pellet is estimated such that the temperature rise to be measured does
not exceed *-J. The pellet is ignited by fusing a piece of platinum or
nichrome wire which in contact with it.
The crucible carrying the pellet is located in the bomb, a small quantity
of distilled water is put into the bomb to absorb the vapors formed by
combustion and to ensure that the water vapors produced is condensed,
and the top bomb is screwed down.
!fter fifth minute the charge is fired and temperature readings are taken
every 5 seconds during this period. hen the temperature readings start
to fall, the frequency of readings is taking every minute.
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The temperature rise of the circulating water is measured, and the
condensate from the products of combustion is collected. The water flow
rate is measured and condensate is weighed. Thus, calorific value of fuel
can be obtained by
(Folume of fuel at .5-bar and 8V#) U calorific value (mass of water
circulated) U specific heat capacity of water U (temperature rise of water)
3.13 Air and #ue$)4a"or Mi*tures
The mixture supplied to an engine fitted with a carburetor is one air and fuel
vapor, and the quality of the mixture is controlled by the carburetor.
If the mixture is saturated with fuel vapor then the relative proportion of fuelto air can be determined from the knowledge of the temperaturepressure
relationship for the saturated fuel.
E*a"$e 3.,+
>or a stoichiometric mixture of ethyl alcohol of 5.5**kmol/kg and air
substance of 5.-5;kmol/kg, calculate the temperature above which there will
be no liquid fuel in the mixture. The pressure of the mixture is 5.-k6a.
So$utions+
'g'moln OHC /5**.51* = and 'g'molnAir /-5;.5=
'g'molnnn AirOHC$otal /--.51* =+=
'g'molPn
n
P mixture$otal
OHC
OHC /5**.51*
1* =
=
>rom the table of #*$1%@
T (o#) 5 5 *5 -5 35 85 15
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6 (k6a) .1* -.3 8.*2 5.3; 2.55 *1.15 31.;5
Thus,
C$ =
+= 28.*523.83;.5
23.89.1*5