chapter 5 circular motion; gravitation more of f=ma

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Chapter 5 Circular Motion; Gravitation More of F=ma

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Gravity Near the Earth’s Surface; Geophysical Applications Satellites and “Weightlessness” Kepler’s Laws and Newton’s Synthesis Types of Forces in Nature Preview of Chapter 5 (continued)

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Page 1: Chapter 5 Circular Motion; Gravitation More of  F=ma

Chapter 5

Circular Motion; Gravitation

More of F=ma

Page 2: Chapter 5 Circular Motion; Gravitation More of  F=ma

Preview of Chapter 5

•Kinematics of Uniform Circular Motion

•Dynamics of Uniform Circular Motion

•Highway Curves, Banked and Unbanked

•Non-uniform Circular Motion

•Centrifugation

•Newton’s Law of Universal Gravitation

This is really an extension of chapter 4, so we treat them as a single topic: F=ma

Page 3: Chapter 5 Circular Motion; Gravitation More of  F=ma

•Gravity Near the Earth’s Surface; Geophysical Applications

•Satellites and “Weightlessness”

•Kepler’s Laws and Newton’s Synthesis

•Types of Forces in Nature

Preview of Chapter 5 (continued)

Page 4: Chapter 5 Circular Motion; Gravitation More of  F=ma

5-1 Kinematics of Uniform Circular MotionUniform circular motion: motion in a circle of constant radius at constant speed

Instantaneous velocity is always tangent to circle.

Page 5: Chapter 5 Circular Motion; Gravitation More of  F=ma

5-1 Kinematics of Uniform Circular MotionLooking at the change in velocity in the limit that the time interval becomes infinitesimally small, we see that

(5-1)

Page 6: Chapter 5 Circular Motion; Gravitation More of  F=ma

5-1 Kinematics of Uniform Circular MotionThis acceleration is called the centripetal, or radial, acceleration, and it points towards the center of the circle.

Page 7: Chapter 5 Circular Motion; Gravitation More of  F=ma

5-2 Dynamics of Uniform Circular Motion

For an object to be in uniform circular motion, there must be a net force acting on it.

We already know the acceleration, so can immediately write the force:

(5-1)

Page 8: Chapter 5 Circular Motion; Gravitation More of  F=ma

5-2 Dynamics of Uniform Circular MotionWe can see that the force must be inward by thinking about a ball on a string:

Page 9: Chapter 5 Circular Motion; Gravitation More of  F=ma

5-2 Dynamics of Uniform Circular MotionThere is no centrifugal force pointing outward; what happens is that the natural tendency of the object to move in a straight line must be overcome.

If the centripetal force vanishes, the object flies off tangent to the circle.

Page 10: Chapter 5 Circular Motion; Gravitation More of  F=ma

Solve some problems

• Centrifuge• Labquest 2 on the bike wheel

Page 11: Chapter 5 Circular Motion; Gravitation More of  F=ma

End of material for Term 1!

• Wow, we’ve done a lot.• You are now in the elite group of humans

who can ‘do’ physics– Understand language– Solve problems – Make sense of physics and math

Page 12: Chapter 5 Circular Motion; Gravitation More of  F=ma

Review final exam

• Average 89%• Median 92%

• If you scored lower than you want to score, come see me.

Page 13: Chapter 5 Circular Motion; Gravitation More of  F=ma

Starting Term 2• What changes?

– I go a little faster– The material is a little harder– You are a lot smarter in physics– We are a little smaller

• What is the same?– How we learn– The tests, the labs, the demos– This lab is available for help or exploration

Page 14: Chapter 5 Circular Motion; Gravitation More of  F=ma

http://www.youtube.com/watch?v=sSUNllgMCqY

Analyze this rotational motion?

Page 15: Chapter 5 Circular Motion; Gravitation More of  F=ma

Solving UCM problems so far• Chapter 5 are dynamics problems!

a. Identify the bodyb. FBDc. F=ma in each dimensiond. ac = v2/R is the only new part

• Language that’s new– Centripital acceleration = “radial”– Period T– Frequency f– v = 2rf

Page 16: Chapter 5 Circular Motion; Gravitation More of  F=ma

5-3 Highway Curves, Banked and UnbankedWhen a car goes around a curve, there must be a net force towards the center of the circle of which the curve is an arc. If the road is flat, that force is supplied by friction.

Demo the air puck on a string

Page 17: Chapter 5 Circular Motion; Gravitation More of  F=ma

5-3 Highway Curves, Banked and Unbanked

If the frictional force is insufficient, the car will tend to move more nearly in a straight line, as the skid marks show.

Page 18: Chapter 5 Circular Motion; Gravitation More of  F=ma

5-3 Highway Curves, Banked and Unbanked

As long as the tires do not slip, the friction is static. If the tires do start to slip, the friction is kinetic, which is bad: why?

• The kinetic frictional force is smaller than the static.

• Which way does static friction always point?

• Which way does kinetic friction always point?

Opposite to incipient slideToward the center, as we’ve seen

Opposite the actual slide, not toward center

Page 19: Chapter 5 Circular Motion; Gravitation More of  F=ma

Flat turn, with friction

• Car mass M, travels around flat curve of radius R, with coefficient of friction .

• What is the maxium speed to avoid slipping?

Page 20: Chapter 5 Circular Motion; Gravitation More of  F=ma

Banked turn, no friction

Banking the curve can help keep cars from skidding. In fact, for every banked curve, there is one speed where the inertia to go straight pushes the car up the curve and this equals the force of gravity to go down.

Set up and solve this problem: find that speed V for car mass M, curve bank of

Coordinate system: line it up with ac

Page 21: Chapter 5 Circular Motion; Gravitation More of  F=ma

diagrams

Fx = max

Fy = may

Page 22: Chapter 5 Circular Motion; Gravitation More of  F=ma

Classics in 5 up to section 5.31. Banked turn no friction: relate v, r, m, and

2. Flat turn with friction: relate v, r, m, and

3. Ball spinning horizonatal on a string, no gravity: relate f (or v), m, and FTension

4. Ferris wheel ride: relate f (or v), m, and FNormal

Page 23: Chapter 5 Circular Motion; Gravitation More of  F=ma

Practice problems

• Car over a hill of radius R, speed v, what g does the passenger feel?

• Turning plate with weight slipping off. What needed for given v?

• Ball in bowl, what angle will it rise to at given v?

• Greek waiter water trick: how fast must it go to keep water from spilling?

Page 24: Chapter 5 Circular Motion; Gravitation More of  F=ma

5-4 Nonuniform Circular Motion

If an object is moving in a circular path but at varying speeds, it must have a tangential component to its acceleration as well as the radial one.

Page 25: Chapter 5 Circular Motion; Gravitation More of  F=ma

5-4 Nonuniform Circular Motion

This concept can be used for an object moving along any curved path, as a small segment of the path will be approximately circular.

Page 26: Chapter 5 Circular Motion; Gravitation More of  F=ma

5-5 Centrifugation

A centrifuge works by spinning very fast. This means there must be a very large centripetal force. The object at A would go in a straight line but for this force; as it is, it winds up at B.

Practice: what is g of our lab centrifuge?

Page 27: Chapter 5 Circular Motion; Gravitation More of  F=ma

5-6 Newton’s Law of Universal GravitationIf the force of gravity is being exerted on objects on Earth, what is the origin of that force?

Newton’s realization was that the force must come from the Earth.

He further realized that this force must be what keeps the Moon in its orbit.

Page 28: Chapter 5 Circular Motion; Gravitation More of  F=ma

5-6 Newton’s Law of Universal GravitationThe gravitational force on you is one-half of a Third Law pair: the Earth exerts a downward force on you, and you exert an upward force on the Earth.

When there is such a disparity in masses, the reaction force is undetectable, but for bodies more equal in mass it can be significant.

Page 29: Chapter 5 Circular Motion; Gravitation More of  F=ma

5-6 Newton’s Law of Universal Gravitation

Therefore, the gravitational force must be proportional to both masses.

By observing planetary orbits, Newton also concluded that the gravitational force must decrease as the inverse of the square of the distance between the masses.

In its final form, the Law of Universal Gravitation reads:

where

(5-4)

Page 30: Chapter 5 Circular Motion; Gravitation More of  F=ma

How simple was 1/r2?

The Moon rotates in UCM, and has aR=2.72x10-3 m/s2

Which is 1/3600 g

From the center of Earth, the Moon is 60x the distance to the surface of Earth.

rM = 60 rE

So Newton reasoned that FG is proportional to 1/r2

Page 31: Chapter 5 Circular Motion; Gravitation More of  F=ma

5-6 Newton’s Law of Universal GravitationThe magnitude of the

gravitational constant G can be measured in the

laboratory.

This is the Cavendish experiment.

Page 32: Chapter 5 Circular Motion; Gravitation More of  F=ma

Demo with gravity

• Hold ball in air 1.0 m from a person of mass M.

• Drop ball and measure displacement to the side (x-direction).

• Find if the result follows F=GMm/r2

• What kinematic equations will solve for distance in x?

• Have constant a in both dimensions, so use Table 3-1• FG is so weak it will not be seen See example problem.

Page 33: Chapter 5 Circular Motion; Gravitation More of  F=ma

5-7 Gravity Near the Earth’s Surface; Geophysical Applications

Now we can relate the gravitational constant to the local acceleration of gravity. We know that, on the surface of the Earth:

Solving for g gives:

Now, knowing g and the radius of the Earth, the mass of the Earth can be calculated:

(5-5)

Page 34: Chapter 5 Circular Motion; Gravitation More of  F=ma

5-7 Gravity Near the Earth’s Surface; Geophysical Applications

The acceleration due to gravity varies over the Earth’s surface due to altitude, local geology, and the shape of the Earth, which is not quite spherical.

Why is North pole high and equator low?

Page 35: Chapter 5 Circular Motion; Gravitation More of  F=ma

UCM with only one force: gravity

Page 36: Chapter 5 Circular Motion; Gravitation More of  F=ma

Dec 1: 5-8 Satellites and “Weightlessness”

Satellites are routinely put into orbit around the Earth. The tangential speed must be high enough so that the satellite does not return to Earth, but not so high that it escapes Earth’s gravity altogether.

We can calculate!!F=ma still is true:

GMm/r2 = mv2 /r

…so, find v…..

Page 37: Chapter 5 Circular Motion; Gravitation More of  F=ma

5-8 Satellites and “Weightlessness”

The satellite is kept in orbit by its speed – it is continually falling, but the Earth curves from underneath it.

What is g on the ISS? It is 385km above earth.

Page 38: Chapter 5 Circular Motion; Gravitation More of  F=ma

5-8 Satellites and “Weightlessness”Objects in orbit are said to experience weightlessness. They do have a gravitational force acting on them, though!

The satellite and all its contents are in free fall, so there is no normal force. This is what leads to the experience of weightlessness.

Page 39: Chapter 5 Circular Motion; Gravitation More of  F=ma

More properly, this effect is called apparent weightlessness, because the gravitational force still exists. It can be experienced on Earth as well, but only briefly:

Page 40: Chapter 5 Circular Motion; Gravitation More of  F=ma

Why are things weightless on the ISS?

• What is g at sea level?• What is g at minnesota? (300m)

• What is g at top of Everest? (8.9km) 0.28% less

• What is g at ISS elevation? (300km)

• What holds the moon with the earth? (384,000 km)

• Note: gravity works over long distances…• So: there is in fact FG on the ISS!!!• http://www.youtube.com/embed/doN4t5NK

W-k is a tour of the ISS (25 min)

Page 41: Chapter 5 Circular Motion; Gravitation More of  F=ma
Page 42: Chapter 5 Circular Motion; Gravitation More of  F=ma

5-9 Kepler’s Laws and Newton's Synthesis

Kepler’s laws describe planetary motion.

1. The orbit of each planet is an ellipse, with the Sun at one focus.

Page 43: Chapter 5 Circular Motion; Gravitation More of  F=ma

5-9 Kepler’s Laws and Newton's Synthesis

2. An imaginary line drawn from each planet to the Sun sweeps out equal areas in equal times.

Page 44: Chapter 5 Circular Motion; Gravitation More of  F=ma

5-9 Kepler’s Laws and Newton's SynthesisThe ratio of the square of a planet’s orbital period is proportional to the cube of its mean distance from the Sun.

Page 45: Chapter 5 Circular Motion; Gravitation More of  F=ma

5-9 Kepler’s Laws and Newton's SynthesisKepler’s laws can be derived from Newton’s laws. Irregularities in planetary motion led to the discovery of Neptune, and irregularities in stellar motion have led to the discovery of many planets outside our Solar System.

Page 46: Chapter 5 Circular Motion; Gravitation More of  F=ma

5-10 Types of Forces in Nature

Modern physics now recognizes four fundamental forces:

1. Gravity

2. Electromagnetism

3. Weak nuclear force (responsible for some types of radioactive decay)

4. Strong nuclear force (binds protons and neutrons together in the nucleus)

Page 47: Chapter 5 Circular Motion; Gravitation More of  F=ma

5-10 Types of Forces in Nature

So, what about friction, the normal force, tension, and so on?

Except for gravity, the forces we experience every day are due to electromagnetic forces acting at the atomic level.

Page 48: Chapter 5 Circular Motion; Gravitation More of  F=ma

• Newton’s law of universal gravitation:

•Satellites are able to stay in Earth orbit because of their large tangential speed.

Summary of Chapter 5

Look at ISS video

Page 49: Chapter 5 Circular Motion; Gravitation More of  F=ma

Classics up to section 5.31. Banked turn no friction: relate v, r, m, and

2. Flat turn with friction: relate v, r, m, and

3. Ball spinning horizonatal on a string: relate f (or v), m, and FTension

4. Ferris wheel ride: relate f (or v), m, and FNormal

Continued on next page……….

Page 50: Chapter 5 Circular Motion; Gravitation More of  F=ma

Cont: Classics for 5-4 to 5-85. Centrifuge: find ag for given r and v (or

rpm)6. Gravity force between any two objects with

known masses.7. Calculate ag for a planet of mass M and

radius R, or for an object above the planet at altitude H.

8. Satellite velocity necessary to stay in orbit at given altitude H above a planet of mass M

Page 51: Chapter 5 Circular Motion; Gravitation More of  F=ma

lab : ping pong cannon1. Show prediction of the muzzle velocity using F=ma as we did in class.

Use brief words to describe steps, and show the fishbone with all units and numbers.

2. Show Loggerpro measurement of muzzle velocity, including both x vs. t and v vs. t Loggerpro graphs, labeled.

3. For muzzle velocity, compare predicted with actual and explain any differences using the physics you know.

4. For v vs. t graph, describe the change in velocity5. Explain possible reasons for this v vs. t behavior using what you know

about gasses and physics.6. Due Tuesday 15 Dec at beginning of class.7. Analysis: Type 1-2 page of report plus graphs. You can show

equations as handwritten.This is the data and analysis sections from a report

Page 52: Chapter 5 Circular Motion; Gravitation More of  F=ma

practice

• An asteroid has mass of 100,000 metric tons, and also has a small 25kg rock in stable circular orbit around it. The rock is 4.0km from the asteroid’s center. 1. What is the period of the rock’s orbit?2. What is the force of the pull between the

rock and the asteroid?3. At what new altitude would the rock have a

period of exactly 1 day?