chapter 6 section 5 copyright © 2008 pearson education, inc. publishing as pearson addison-wesley

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Chapter Chapter 6 6 Section Section 5 5 Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

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Page 1: Chapter 6 Section 5 Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

Chapter Chapter 66Section Section 55

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

Page 2: Chapter 6 Section 5 Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

Solving Quadratic Equations by Factoring

Solve quadratic equations by factoring.Solve other equations by factoring.

11

22

6.56.56.56.5

Page 3: Chapter 6 Section 5 Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

Solving Quadratic Equations by Factoring.

A quadratic equation is an equation that can be written in the form

ax2 + bx + c = 0,

where a, b, and c are real numbers, with a ≠ 0.

Slide 6.5 - 3

The form ax2 + bx + c = 0 is the standard form of a quadratic equation. For example,

and are all quadratic equations, but only x2 + 5x +6 = 0 is in standard form.

2 0,5 6x x 22 5 3,x x 2 4x

Until now, we have factored expressions, including many quadratic expressions. In this section we see how we can use factored quadratic expressions to solve quadratic equations.

Page 4: Chapter 6 Section 5 Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

Objective 11

Solve quadratic equations byfactoring.

Slide 6.5 - 4

Page 5: Chapter 6 Section 5 Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

We use the zero-factor property to solve a quadratic equation by factoring.

If a and b are real numbers and if ab = 0, then a = 0 or b = 0.

That is, if the product of two numbers is 0, then at least one of the numbers must be 0. One number must, but both may be 0.

Solve quadratic equations by factoring.

Slide 6.5 - 5

Page 6: Chapter 6 Section 5 Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

EXAMPLE 1

Solve. Solution:

Using the Zero-Factor Property

Slide 6.5 - 6

2 3 5 7 0x x

2 4 0x x

2 3 0x

0x

32 33 0x 2 3

2 2

x

3

2x

75 77 0x 5 7

5 5

x

7

5x

5 7 0x

2 4 0x 42 44 0x

2 4

2 2

x

2x 0, 2

3 7,

2 5

or

or

Page 7: Chapter 6 Section 5 Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

Solve.

EXAMPLE 2

Solution:

Solving Quadratic Equations

Slide 6.5 - 7

2 2 8x x

2 30x x

4 0x

6 0x

4 44 0x 4x

2 22 0x 2x

2 0x

5 0x 6 66 0x

6x 5 55 0x

5,6

2 8 82 8x x 2 2 8 0x x

4 2 0x x 4,2

2 3 30030x xx x 2 30 0x x

6 5 0x x

5x

or

or

Page 8: Chapter 6 Section 5 Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

Solve quadratic equations by factoring. (cont’d)

Slide 6.5 - 8

In summary, follow these steps to solve quadratic equations by factoring.

Step 1: Write the equation in standard form— that is, with all terms on one side of the equals sign in descending power of the variable and 0 on the other side.

Step 2: Factor completely.

Step 3: Use the zero-factor property to set each factor with variable equal to 0, and solve the resulting equations.

Step 4: Check each solution in the original equation.

Page 9: Chapter 6 Section 5 Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

EXAMPLE 3

Solution:

Solving a Quadratic Equation with a Common Factor

Slide 6.5 - 9

Solve 3m2 − 9m = 30.

2 303 9 3 300m m

53 2 0m m

23 9 30 0m m

2 3 10 03 m m

2,5

2 0m 2 22 0m

2m

5 0m

5 55 0m

5m

A common error is to include the common factor 3 as a solution. Only factors containing variables lead to solutions.

Page 10: Chapter 6 Section 5 Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

EXAMPLE 4

Solution:

249 9 0x

7 3 7 3 0x x

2 3x x

3 3,

7 7

3 33 0x

Solving Quadratic Equations

Slide 6.5 - 10

Solve.

0,3

2 333x xx x 3 0x x

0x

3x

37 33 0x

3

7x

7 3

7 7

x

37 33 0x 7 3

7 7

x

3

7x

Page 11: Chapter 6 Section 5 Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

EXAMPLE 4

Solution:

Solving Quadratic Equations (cont’d)

Slide 6.5 - 11

Solve.

4 7 2x x

24 2 27 2x x 24 7 2 0x x

2 4 1 0x x

12,

4

2 22 0x 2x

2 0x

4 1

4 4

x

14 11 0x

1

4x

4 1 0x

Page 12: Chapter 6 Section 5 Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

Objective 22

Solve other equations by factoring.

Slide 6.5 - 12

Page 13: Chapter 6 Section 5 Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

EXAMPLE 5

Solve.

Solution:

32 50 0x x

Solving Equations with More than Two Variable Factors

Slide 6.5 - 13

22 25 0x x

2 5 5 0x x x

2 0x 2 0

2 2

x

0x 0, 5,5

5 55 0x 5x

5 55 0x 5x

Page 14: Chapter 6 Section 5 Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

EXAMPLE 5

Solve.

Solving Equations with More than Two Variable Factors (cont’d)

Slide 6.5 - 14

22 1 2 7 15 0x x x

2 1 2 3 5 0x x x

12 11 0x 2 1

2 2

x

1

2x

32 33 0x 2 3

2 2

x

3

2x

5 55 0x

1 35, ,

2 2

5x

Solution:

Page 15: Chapter 6 Section 5 Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

Solve.

EXAMPLE 6

21 2 1 1x x x

Solving an Equation Requiring Multiplication before Factoring

Slide 6.5 - 15

2 22 3 1 2 1x x x x 2 22 22 1 2 12 3 1 2 1x x x xx x x x

2 5 0x x 5 0x x

0x 5 55 0x 5x 0,5

Solution: