chapter 7.time-varying fields and maxwell’s equationsoptics.hanyang.ac.kr/~shsong/chapter...
TRANSCRIPT
Chapter 7. Time-Varying Fields and
Maxwell’s Equations
Electrostatic & Time Varying Fields• Electrostatic fields
• In the electrostatic model, electric field and magnetic fields are not related each other.
0, 0,
1
E DB H = J
D E
H B
Faraday’s law• A major advance in EM theory was made by M. Faraday in 1831
who discovered experimentally that a current was induced in a conducting loop when the magnetic flux linking the loop changed.
electromotive force (emf): VdVdt
Faraday’s law• Fundamental postulate for electromagnetic induction is
• The electric field intensity in a region of time-varying magnetic flux density is therefore non conservative and cannot be expressed as the negative gradient of a scalar potential.
dVdt t
BE
• The negative sign is an assertion that the induced emf will cause a current to flow in the closed loop in such a direction as to oppose the change in the linking magnetic flux Lentz’s law
t
BE
C C S
dV V dl dl ddt t
BE E s
7-2.3. A moving conductor in a static magnetic field
• Charge separation by magnetic force
• To an observer moving with the conductor, there is no apparent motion and the magnetic force can be interpreted as an inducted electric field acting along the conductor and producing a voltage.
• Around a circuit, motional emf or flux cutting emf
m q F u B
2
21 1V dl u B
21 CV dl u B
A moving conductor in a static magnetic field
• Example 7-2
(a) Open voltage V0 ?(b) Electric power in R(c) Mechanical power required to move the sliding bar
1
0 1 2 0 022
020 0
( )
( )
u B a a a
W
x z yC
e
a V V V dl u B dl uB h
uB hV uB hb I P I RR R R
1
022 22
0 00
( ) ,
F u F F
F B a F F
F a
m mechanical force to counteract the magnetic force
N
W
M M M
mag x M mag
M x M
e M
c P
I dl IB h
u B h u B huB hI PR R R
P P
A moving conductor in a static magnetic field
• Example 7-3. Faraday disk generator
4
0 0320 0
0
=
V2
z rC
b
V dl r B dr
B bB rdr
u B a a a
Magnetic force & electric force
0B q F v B '0E qF E
q F E u B
2 20 01 / / 1 / L L v c v c
When a charge q0 moves parallel to the current on a wire, the magnetic force on q0 is equivalent to the electric force on q0.
At the rest frame on wire At the moving frame on charge
I
I
'E
To observer moving with q0 under E and B fields, there is no apparent motion.But, the force on q0 can be interpreted as caused by an electric field, E’.
7-2.4. A moving circuit in a time-varying magnetic field
E E u B
u
To observer moving with q0 under E and B fields, there is no apparent motion.But, the force on q0 can be interpreted as caused by an electric field, E’.
Now, consider a conducting circuit with contour C and surface S moves with a velocity u under static E and B fields.
'' ECdl V E
Bd Vdt
Changing in magnetic flux due to the circuit movement produces an emf, V:
On the other hand, the moving circuit experiences an emf, V’, due to E’:
Is it true that 'B EV V
E E u B
VC S C
dl d dlt
BE s u B
time variationat rest
motional emf
E E E u Bby replacing with = - ,u
BE s From the Faraday's law of ,
C Sdl d
t
' ??B EV V
B sB S
d dV ddt dt' E E C
V dl
S S C
d d d dldt t
BB s s u B
Note that
Therefore, we need to prove that
• Time-rate of change of magnetic flux through the contour
2 1
2 1
2 10
2 10
1lim
1lim
H.O.T.,
H.O.T.
S S St
S S S St
d d d t t d t ddt dt t
tt t t t
ttd d d d d
dt t t
B s B s B s
BB B
BB s s B s B s
u
• In going from C1 to C2, the circuit covers a region bounded by S1, S2, and S3
'
E BdV V Vdt
• Therefore, the emf induced in the moving circuit C is equivalent to the emf induced by the change in magnetic flux
E = C
emf V dl
: same form as not in motion.
2 1 3
2 1
2 1 3
3 2 1
0
B B s B s B s
s u B s B s u B
BB s s u B
V S S S
S S C
S S C
d d d d
d dl t d d t dl
td d d dldt t
' ??B EV V
A moving circuit in a time-varying magnetic field
• Example 7.3– Determine the open-circuit voltage of the Faraday disk generator
2
0 00 0
20
2
2
b t
S
B
bd B rdrd B t
B bdVdt
B s
4
' 0320 0
0
=
2
E z rC
b
V dl r B dr
B bB rdr
u B a a a
'E C S CV dl d dl
t BE s u B
'B EV V
Compare!
(Example 7-4) Find the induced emf in the rotating loop under
(a) when the loop is at rest with an angle .
(b) When the loop rotates with an angular velocity ω about the x-axis
0
0
sin sin
cos cos , : the area of the lo
cos
op
y o n
a
d B t hw B hw t
dV B S t S hwdt
B s a a
0 0 0
0 0
1t sin sin scos in 22
1 sin 2 cos 22
cosn
B
t t S B S t B S t B S t
d dV B S t B S tdt dt
t
B a
1 3
0 02 4
0 0
[( ) ( sin )] [( ) ( sin )]2 2
2( sin sin ) sin sin ( = t)2
a n y x n y xC
w wV dl a a B t a dx a a B t a dx
w B t t h B S t
u B
2 2' 0 0(cos sin ) cos 2E a aV V V B S t t B S t
Compare!
'E C S CV dl d dl
t BE s u B
B sB S
d dV ddt dt
( ) siny ot B tB a
'B EV V
7-3. How Maxwell fixed Ampere’s law?
• We now have the following collection of two curl eqns. and two divergence eqns.
• Charge conservation law the equation of continuity
• The set of four equations is now consistent with the equation of continuity?
, =
, =0t
BE H J
D B
t
J
does
Takin
not
g the dive
vanish in
r
a time-varying situation and this equation is, i
gence of = ,0 0 from the vector null
n general, not true
ident y
.
it
J
H JH J H
Maxwell’s equations• A term ∂ρv /∂t must be added to the equation.
• The additional term ∂D/∂t means that a time-varying electric field will give rise to a magnetic field, even in the absence of a free current flow (J=0).
• ∂D/∂t is called displacement current (density).
0
t
t t
D
DH J
H J J D
0 0 0EBt
J
Maxwell’s equations• Maxwell’s equations
• These four equations, together with the equation of continuity and Lorentz’s force equation form the foundation of electromagnetic theory. These equations can be used to explain and predict all macroscopic electromagnetic phenomena.
• The four Maxwell’s equations are not all independent– The two divergence equations can be derived from the two curl
equations by making use of the equation of continuity
=
=0
t
t
BE
DH J
DB
t
J
( )F q E B
Continuity equation
Lorentz’s force
Maxwell’s equations• Integral form & differential form of Maxwell’s equations
Differential form Integral form Significance
Faraday’s law
Ampere’s law
Gauss’s law
No isolated magnetic charge
t
BE
= t
DH J
D
=0 B
C S
B ddl dSt dt
E
C Sdl I d
t
DH s
Cd Q D s
0S
d B s
Maxwell’s equations• Example 7-5
– Verify that the displacement current = conduction current in the wire.
1 1 0
1
0
cos
: uniform between the plates
sin
CC
C
di C C V tdt
ACd
Ed
VD E td
01 0cos cosD CA
Vi d t A C V t it d
D s
0 sinC V t
: conduction current in the connecting wireCi
Maxwell’s equations• Example 7-5
– Determine the magnetic field intensity at a distance r from the wire
1 2,Two typical open surfaces with rim may be chosen: (a) a planar disk surface b a curved surface
CS S
1
1 01 0
2
2
,
2 cos cos2
2
CC S
C Vdl rH d i C V t H tr
SS displacement current
rH
D
H J s 1For the surface S = 0
Since the surface passes through the dielectric medium,no conducting current flows through
1 0 cos2
D CAi d i
tC VH t
r
D s
7-5. Electromagnetic Boundary Conditions
1 2t tE E
2 1 2
1 2
1 2 1 1 2 2
0
0
0
n n s
n n n n
n ss V
s
dS d whe
D D
B B
B
H
d
H
n h
S
D a D D
0 0C S
Bdl dS when ht
E
; 0 0C S S
dl J d d when ht t
D DH s s 2 1 2 1 2 n s t t sna H H J H H J
Electromagnetic Boundary Conditions
1 2t tE E
1 2n n sD D
1 2t t snH H J
1 2n nB B
Both static and time-varying electromagnetic fields satisfy the same boundary conditions:
The tangential component of an E field is continuous across an interface.
The tangential component of an H field is discontinuous across an interfacewhere a surface current exists.
The normal component of an B field is continuous across an interface.
The normal component of an D field is discontinuous across an interfacewhere a surface charge exists.
Boundary conditions at an interface between two lossless linear media
Between two lossless media () with = 0, and S = 0, Js = 0
1 11 2
2 2
1 11 2
2 2
1 2 1 1 2 2
1 2 1 1 2 2
tt t
t
tt t
t
n n n n
n n n n
DE ED
BH HB
D D E E
B B H H
BD E H,
In a perfect conductor ( infinite, for example, supercondiuctors),
Medium 1(dielectric)Medium2
(perfect metal)
1 2
1 2t
1 2n
1 2n
0 0 0 0
0 0
t t
t s
n s
n
E EH J HD DB B
Boundary conditions at an interface between dielectric and perfect conductor
2 2 2 20 , 0E D H B
Boundary conditions• Table
7-4. Potential functions• Vector potential
• Electric field for the time-varying case.
T B A
0
V/m
t t
t
t
V
V
AE A E
AE
AE
0 B
Due to charge distribution
Due to time-varying current J
Wave equation for vector potential A
2
22
22
2
22
2
From , ,
or
Vt
t
Vt t
Vt t
Vt t
t
AH B A D E
DH J
AA J
AA A
A
J A
A
J
A
J
A
(Lorenz condition, or gauge)0
Non-homogeneous wave equation for vector potential A1traveling wave with a velocity of
(# Show that the Lorentz condition is consistent with the equation of continuity. Prob. P.7-12)
Wave equations for scalar potential V
22
2
2
A
A A
From ,v
v
v
v
AE V and Et
Vt
VVt t
VVt
ρε
ρερ μεε
ρμεε
for scalar potential V
0Vt
A
The Lorentz condition uncouples the wave equations for A and for V.
The wave equations reduce to Poisson’s equations in static cases.
Gauge freedom• Electric & magnetic field
• Gauge transformation
Gauge invarianceE & B fields are unchanged if we take any function (x,t) on simultaneously A and V via:
If , B remains unchanged.
Thus, if is further changed to , also remains same.
A AA AE
E
V Vt t t t
V V Vt
, =Vt
AE B A
A A
V Vt
0
A Vt
22
2 0 t
The Lorentz condition can be converted to a wave equation.
7-6. Solution of wave equations• The mathematical form of waves
x
t = t0t = 0
x = upt0up
f (x, t =0)
2 2
2 2 2
1 0 : wave equation,p
pf x t f fx u t
f x u t
Wave equation• Simple wave
– http://navercast.naver.com/science/physics/1376
, cos cos
2 22 , , p
x ty x t A A kx tT
f k uT k
Solution of wave equations from potentials
First consider a point charge at time t, (t)v’, located at a origin. Except at the origin, V(R) satisfies the following homogeneous equation ( = 0):
2 22
22
2 2
2 2
2 2
1Since for spherical symmetry , ,
1 0
1Introducing a new varible, , ,
10 , or ,
Thus, we can write
p pp
VV R V R V RR R
V VRR R R t
V R t U R tR
U U RU R t U t U R u t uR t u
in a form of ,p
RV R t V tu
22
2
vVV
tρμεε
: Nonhomogeneous wave equation for scalar electric potential
t'd
R
Solution of wave equations
Now consider a charge distribution over a volume V’ .
,t RV’
d
R
R
,p
RV R t V tu
/
/4
pp
t R uV t R u
R
The potential at R for a point charge is,
4
t
tV R
R
t
'd
R
, /1, V4
, /, Wb/m
4
p
V
p
V
R t R uV R t d
RR t R u
R t dR
J
A
The potentials at a distance R from the source at time t depend on the values of and J at an earlier time (t- R/u) Retarded in time
Time-varying charges and currents generate retarded scalar potential, retarded vector potential.
Source free wave equations Maxwell’s equations in source-free non-conducting media (ε, μ, σ=0).
• Homogeneous wave equation for E & H.
, = , 0, =0tt
H EE H E H
=t
EH
2
2
22
2 2
22
2 2
t
In an entirely similar wa
1 0
1y, 0
p
p
t
u t
u t
EE
HH
EE H
2 2 E E E
Consider a RLC circuit
Phasor method (exponential representation)
00 0
0
cos Re Re
Re Re
j j t j ts
j j t j ts
V t V t V e e V e
i t I e e I e
Review –The use of Phasors
01 , cos
diL Ri idt V t i t I tdt C
If we use phasors in the RLC circuit, Re , Re
1
1( ) Re /
j t j tss
s s
i ts
Idi j I e idt edt j
R j L I VC
i t V R j L eC
00
0
js
js
V V e
I I e
(Scalar) phasors that contain amplitude and phase information
but are independent of time t.
Time-harmonic Maxwell’s & wave equations
• Vector phasors.
• Time-harmonic (cos t) Maxwell’s equations in terms of vector phasors
, , , Re
, , ,
,
Re
,
, ,
j t
j t
x y z t e
x y z
x y
x e
z
zt y
E
H
E
H
0j
j
E
E HHH J E
=0
=
t
t
DBE
BDH J
Time-harmonic Maxwell’s & wave equations
Time-harmonic wave equations (nonhomogeneous Helmholtz’s equations)
2 2
22
2
22
22
22 2
( , )( , )( , )
( )( ) ( )
2
( ) ( )
(
wave nu
) ( )
mber
=
A A A JJ A
p
V R k V R
R
R tV R tV R tt
RV R j
R
V R
u
tk
k
Time-harmonic retarded potential• Phasor form of retarded scalar potential
• Phasor form of retarded vector potential.
•
1 V4
jkR
V
R eV R d
R
Wb/m4
jkR
V
R eR d
R
JA
cosj t kx j t kx
t kx
e e e
2 2
When 2 1
1 ... 12
, static expressions(Eq. 3-39 & Eq. 5-22)
jkR
RkR
k Re jkR
V R R
A
Time-harmonic retarded potential• Example: Find the magnetic field intensity H and the value of β when = 90
9, 5cos 10 V/myz t t z E a
9
0
10 (1/s)
5
1
j zyz e
zj
E a
EH
0
0 0
1
0 5 0
1 5 5 ( )
x y z
j z
j z j zx x x x
zj x y z
e
e e H zj z
a a a
H
a a a
2
20
0 0 0
10
0
9
0
1 1z 5
33 10 rad/m
5 0.0398
, 5 0.0398 cos 10 10
j zy x y
j z j zx x
j zx x
H ej j z
c
z e e
z t e t z
E H a a
H a a
H a a
The EM Waves in lossy media• If a medium is conducting (σ≠0), a current J=σE will flow
• When an external time-varying electric field is applied to material bodies, small displacements of bound charges result, giving rise to a volume density of polarization. This polarization vector will vary with the same frequency as that of the applied field.
• As the frequency increases, the inertia of the charged particles tends to prevent the particle displacements from keeping in phase with the field changes, leading to a frictional damping mechanism that causes power loss.
• This phenomenon of out of phase polarization can be characterized by a complex electric susceptibility and hence a complex permittivity.
• Loss tangent, δc
complex permitti
,
vity
c
c
j j j
j
j
j
H E E E=t
DH J
The EM Waves in lossy media• Loss tangent, δc
• Good conductor if
• Good insulator if
• Moist ground : loss tangent ~ 1.8104@1kHz, 1.810-3 @10GHz
tan , : loss anglec c
J
c
E
H E Ec
c
j jj
j
>>1
<<1
= jt j
EH J E
The electromagnetic spectrum• Spectrum of electromagnetic waves