chapter introduction to physics teacher guide

7/31/2019 Chapter Introduction to Physics Teacher Guide

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SMK Gombak Setia Physics Module Form 4Teachers Guide Chapter 1 : Introduction To Physics_________________________________________________________________________________________

CHAPTER 1 : INTRODUCTION TO PHYSICS

1.1 Understanding Physics

1

Mechanical Energy

PHYSICS

Study of the natural phenomena and the

ro erties of matter.

Solid

Liquid

Gas

Mechanical Energy

Heat Energy

Light Energy

Wave Energy

Electrical Energy

Nuclear Energy

Chemical Energy

Relationship

with

matter

Properties of

Ener

Relationship

with

energy

Properties of

Matter

formsstates

Matter Energy

Mechanics

Propertieso matter

Heat

Light

Wave

in the fields of

Electricity &Electromagnetism

Atomic Physics& Nuclear

Electronics


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1.2 PHYSICAL QUANTITIES

Base quantity

1 A physical quantity is ..

2 Examples of scientific instruments :

3 A base quantity is a physical quantity which cannot be defined in terms of other physical

quantities.

4 Study the following picture and list the physical quantities that can be measured.

5 List of 5 basic physical quantities and their units.

Base quantity Symbol S.I. Unit Symbol for S.I. Unit

Length

Mass

Time

CurrentTemperature

6 Two quantities that have also identified as basic quantity. There are :

i) ..unit .. ii) . unit ..

Standard Form

The list of physical quantities :

1. .

2. .

3. .

4. .

5. .

6. .

7. .

8. .

batteryattery

any quantity that can be measured by a scientific instrument.

stopwatch, metre rule balance,thermometer,ammeter

etc.

Height,

mass,

size,

age,

temperature,

current

Power,

Thermal energy

l meter m

m kilogram kg

t second s

I Amppere A

T Kelvin K

Light intensity candela Amount of substance mol

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1 Standard form = A x 10n , 1 < A < 10 and n = integer

2 Standard form is used to ...

3 Some physical quantities have extremely small magnitudes. Write the following quantities

in standard form :

a. Radius of the earth = 6 370 000 m =.

b. Mass of an electron = 0.000 000 000 000 000 000 000 000 000 000 911 kg =...

c. Size of a particle = 0.000 03 m =

b. Diameter of an atom = 0.000 000 072 m = ...

c. Wavelength of light = 0.000 000 55 m = ..

Prefixes

1. Prefixes are usually used to ...

2. It will be written

3. The list of prefixes :

Tera (T)

Giga (G)

Mega (M)

kilo (k)

mili (m)

micro ()

nano (n)

pico (p)

1012

109

106

103

100

10-3

10-6

10-9

10-12

Hekto (ha)

Deka (da)

desi (d)centi (s)

102

10110-1

10-2

Eg :

1 Tm = .

3.6 mA = .

How to change the unit ;

Eg :

1. Mega to nano

2. Tera to micro

3. piko to Mega

simplify the expression of very large and small numbers

6.37 x 106m

9.11 x 10-31 kg

3.0 x 10-4 m

7.2 x 10-8 m

5.5 x 10-7

represent a large physical quantity or extremely small quantity in S.Iunits.before the unit as a multiplying factor.

1 x 1012 m

3.6 x 10-3A

1.33 MA = 1.33 x 106A

= 1.33 x 10 6-(-9) nA

= 1.33 x 10 -15 nA

1.23 Tm to unit m unit

1.23 Tm = 1.23 x 10 12m

= 1.23 x 10 12 (-6)m

= 1.23 x 10 18m

5456 pA to MA unit

5456 pA = 5.456 x 10 3 + (-12) pA

= 5.456 x 10 -9pA

= 5.456 x 10 -9 (6)MA

= 5.456 x 10 -15 MA

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4. Some physical quantities have extremely large magnitudes. These extremely large and

small values can be written in standard form or using standard prefixes. Write the

quantities in standard prefixes:

a. Frequency of radio wave = 91 000 000 Hz = .

b. Diameter of the earth = 12 800 000 m =

c. Distance between the moon and the earth = 383 000 000 m =

d. Mass of the earth = 6 000 000 000 000 000 000 000 000 kg =

Derived quantities

1 A derived quantity is .

2 Determine the derived unit for the following derived quantities.

Derived

quantityFormula Derived unit

Name of

derived unit

area area = length x width m x m = m2

volume volume = length x width x height m x m x m = m3

densityvolume

massensityd = 3

3mkg

m

kg =

velocity time

ntdisplaceme

elocityv =1

sms

m =

momentum momentum = mass x velocity kg m s-1

Accelerationtime

velocityinchangeonaccelerati =

2

11-1

sm

ssms

sm

=

=

Force force = mass x acceleration kg m s-2 Newton (N)

pressure

area

forcepressure=

weight weight = mass x gravitational acceleration

work work = force x displacement

powertime

workpower=

kinetic energy2velocitymassK.E =

2

1

potential

energy P.E = mass x gravitational acceleration x height Kg ms-2

Joule (J)

kgm s-2 / m2 kg m-1 s-2 (Nm-2)

kg ms -2 Newton (N)

N m Joule (J)

J s -1 Watt (W)

Kg ms-2 Joule (J)

9.1 x 10 1MHz

12.8 Mm = 1.28 x 10 1 Mm

383 Mm = 3.83 x 10 2 Mm

6.0 x 10 12 Tm

a physical quantity which combines several basic quantities through

multiplication, division or both

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Derived

quantityFormula Derived unit

Name of

derived unit

charge charge = current x time Ampere second(As)

Coulomb (C)

voltagecharge

workvoltage = J C-1 Volt (v)

resistancecurrent

voltageresistance= v A-1 Ohm ()

Note that the physical quantities such as width, thickness, height, distance, displacement,

perimeter, radius and diameter are equivalent to length.

1.3 SCALAR AND VECTOR QUANTITIES

1 Scalar quantities are

Examples :

2 Vector quantities are...

Examples :

3 Study the following description of events carefully and then decide which events require

magnitude, direction or both to specify them.

Description of events Magnitude Direction1. The temperature in the room is 25 0C

2. The location of Ayer Hitam is 60 km to the north-

west of Johor Bahru

3. The power of the electric bulb is 80 W

4. A car is travelling at 80 km h-1 from Johor Bahru

to Kuala Lumpur

1.4 MEASUREMENTS

Using Appropriate Instruments to Measure

1 There are various types of.

2 We must know how to choose the appropriate instrument to ..

3 Examples of instrument and its measuring ability.

Measuring instrument Range of measurement Smallest scale division

Measuring tape

Quantity which has only magnitude or size

Mass, Length, Speed, volume

Quantity which has magnitude or size and direction.

Velocity, Force, Displacement, Acceleration

measuring instrument with different measuring capabilities.

measure a particular quantity.

Up to a few meters 0.1 cm

1 m 0.1 cm (0.01 m)

10 cm 0.01 cm

less than 2 cm (20 mm) 0.001 cm (0.01 mm)

is use to measure electric current5


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Meter rule

Vernier caliper

Micrometer screw gauge

4 Sample of measuring instruments :

4.1 Ammeter : ..

4.2 Measuring cylinder : ....................

4.3 Ruler :

wrong right wrong

10 11 12 13 14 15 Reading = cm

4.4 Vernier calliper

A venier calliper is used to measure :a. b. .

c. d. .

A vernier calliper gives readings to an accuracy of .... cm.

pointer mirrorpointer mirror

Pointers image is behind the pointer

incorret reading correct

reading

1 2 3

0 4

1 2 30 4

Pointers image can be seen

Right position of eye (eye are in a line perpendicular to the plane of

the scale)

wrong position of eye

wrong position of eye

water

cm 0 1 2 3 4SKALA

UTAMA0

5 10

inside jawsVernier scale

outside jaws

Main scale

is use to determine the volume of liquid.

is use to determine the length

small object depth of a hole

external diameter of a cylinder or pipe internal diameter of a pipe or tube

0.1 cm

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Length of vernier scale = cm

Vernier scale is divided into 10 divisions

Length of the divisions = . cm

The diagram below shows a vernier calliper with reading.

Vernier calliper reading = . cm

4.5 Micrometer screw gauge.

A micrometer screw gauge is used to measure :

a.

b. .

c.

Example :

0 5 10

0 1

0 1

0 5 10

Main scale in cm

Vernier scale

0 1 2 3 4 5 6 7 8 9 10

0 1 cm

Main scale = .

Vernier scale = ..

Final reading = ..

Find the division ofvernier scale which iscoincides with any part ofthe main scale

One complete turn of the thimble

(50 division) moves the spindle by

0.50 mm.

Division of thimble

= ..

= ..A accuracy of micrometer

screw gauge = ..

Sleeve scale :

Thimble scale : .

Total reading : ..

Sleeve scale :

Thimble scale : .

Total reading : ...

The differenct between the main scale and vernier scaleis = . cm

0.15

objects that are small in sizediameter of a wire

diameter of small spheres such as ball bearings

0.5 50

0.01 mm 4.5 mm0.01 mm 0.22 mm

4.62 mm

0.9

0.09

0.01 cm

0.2 cm

0.06 cm

0.26 cm

2.0 mm

0.22 mm

2.22 mm

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4.6 Some others measuring instruments :

..

. ..

Hands-on activity 1.1 on page 1 of the practical book to learn more about choosing

appropriate instruments.

Exercise: Vernier Callipers And Micrometer Screw Gauge

1. Write down the readings shown by the following

(a)

(b)

(c)

(d)

0 5 10

0 1

0 510

6 7

0 5 10

7 8

0 5 10

4 5A B

QP

Answer: 7.79 cm..

Answer: 4.27 cm..

Answer: 6.28 cm..

Answer: 0.02 cm..

Analogue stopwatch digital stopwatch thermometer miliammeter

Measuring tape measuring cylinder beaker

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2. (a) The following diagram shows the scale of a vernier calliper when the jaws are closed.

Zero error = 0.02 cm(b). The following diagram shows the scale of the same vernier calliper when there are

40 pieces of cardboard between the jaws.

3. Write down the readings shown by the following micrometer screw gauges.

(a) (b)

Answer: . Answer:..

(c) (d)

Answer: Answer:.

0 5 10

5 6

0 5 10

0 1

Reading shown = 5.64.cm

Corrected reading = 5.62..cm

35

400 5

3

0

0 5 10

3

5

20

250

15

200 5

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4. (a) Determine the readings of the following micrometer screw gauges.

Zero error = 0.02.. mm Zero error = 0.03.. mm

(b) Determine the readings of the following micrometer screw gauges.

5. Write down the readings shown by the following micrometer screw gauges.

(a) (b)

Answer: 6.88 mm Answer: ..12.32 mm(c) (d)

Answer:4.71 mm Answer: 9.17 mm

6. (a) Determine the readings of the following micrometer screw gauges.

Zero error = -0.02 mm Zero error = 0.03.. mm

0 0

45

5

0

0

5

0

0 0 5

15

20

Zero error = 0.03mm Reading shown = 6.67..mm

Corrected reading = 6.64..mm

35

400 5

3

0

0 5 10

3

5

20

250

0 0

45

5

0

0

15

200 5

10


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(b) Determine the readings of the following micrometer screw gauges.

Accuracy and consistency in measurements.

1. Accuracy :

2. Consistency :

3. Sensitivity :

..

.. ..

Hands-on activity 1.2 on page 2 of the practical book to determine the sensitivity of

some measuring instruments.

Errors in measurements

1. All measurements are values

2. In other word, it is a matter of

3. This is because

4. Two main types of errors:

4.1

target

target

The ability of an instrument to measure nearest to the actual value

The ability of an instrument to measure consistently with little or no relativedeviation among readings.The ability of an instrument to detect a small change in the quantity measured.

consistent but inaccurate consistent and accurate inaccurate and not consistent

Accuratebut not consistent inaccurate but consistent inaccurate but not consistent

5

0

0 0 5

15

20

Zero error = 0.03.mmReading shown = .6.67..mm

Corrected reading = 6.64..mm

of approximation only.

how close the measurement is to the actual value.

error exist in all measurements.

Systematic errors

a weakness of the instrument

the difference between reaction time of the brain and the action.

zero error is when the pointer is not at zero when not in use.

Range of the measuring instrument absolute error .

Reaction time of the brain.

Initial reading is not at the zero scale zero error

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where the pointer is not at zero when not in use

+0.03 cm- 0.04 cm

+ 0.02 mm - 0.03 mm


Occurs due to :

a)

b)

c)

Examples :

a)

b)

c)

Absolute error :

.

.

Example :

Parallax error :

Zero error : ...

Correct reading = observed reading zero error

Refer to the smallest reading that can be measured by an instrument.

If, the smallest reading = 0.1 cm

Then, Absolute error = 0.1 / 2 = 0.05 cm

It occurs because the position of the eye is not perpendicular to the scale of theinstrument.

wrong

right position of the eye (no error)wrong

Zero error =

0 1 cm

0 1 2 3 4 5 6 7 8 9 10 0 1 2 3 4 5 6 7 8 9 10

Zero error =

0 1 cm

Horizontalreference

Horizontalreference3 divisions above

horizontal reference2 divisions below

horizontal reference

Positive zero error Negative zero error

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4.2

Occurs due to

a)

b)

c)

Example :a) ..

b) ..

.....................................................................................................................

1.5 SCIENCETIFIC INVESTIGATION

Steps Explanation

1

Making

observation

2Drawing

inferences

A conclusion from an observation or phenomena using informationthat already exist.

3 Identifying andcontrolling

variables

Variables are factors or physical quantities which change in thecourse of a scientific investigation.There are three variables :

i. Manipulated variables physical quantity which change according to the aim of the

experiment.ii. Responding variables physicals

quantity which is the result of the changed by manipulatedvariable.

iii. Fixed variables physicals quantitieswhich are kept constant during the experiment.

4Formulating a

hypothesis

Zero error of screw meter gauge

Zero error = Zero error = -

Random error

carelessness in making the measurement.

parallex error , incorrect positioning of the eye when taking the readings.

sudden change of ambient factors such as temperature or air circulation.

Readings are close to the actual value but they are not consistent.

Can be minimized by consistently repeating the measurement at different places in

an identical manner.

Gather all available information about the object or phenomenon to be

studied.Using the five senses, sight, hearing, touch, taste and smell.

Statement of relationship between the manipulated variable and theresponding variable those we would expect.

Hypothesis can either be true or false.

i. Conduct an experiment includes the compilation andinterpretation of data.

ii. Making a conclusion regarding the validity of the hypothesis.

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5Conducting

experiments

Plan and report an experiment

Situation : A few children are playing on a different length of swing in a

playground. It is found that the time of oscillation for each swing is different.

Steps Example : refer to the situation above

1 InferenceThe period ofthe oscillation depends on the length of the pendulum.

2 Hypothesis When the length of the pendulum increases, the period of theoscillation increases.

3 Aim Investigate the relationship between length and period of a simple

pendulum.4 Variables Manipulated variable : the length of the pendulum.

Responding variable : PeriodFixed variable : the mass of the pendulum and the displacement.

5 List of

apparatus and

materials

Retort stand with clamp, 100 cm of thread, bob,meter rule, 2 blocks of clamp wood, protractor and

stopwatch.

6 Arrangement of

the apparatus

l

Retort standprotractor

l

bob

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7 Procedures

8 Tabulate the

data

9

10

11

Analyse the

data

Discussion

Conclusion

T / s

1.4

1.2

1.0

0.8

0.6

0.4

0.2

Graf of period, T vspendulums

length, l

1. Set up the apparatus as shown in the figure above.2. Measure the length of the pendulum,l = 60.0 cm by using a meter

rule.3. Give the pendulum bob a small displacement 300.Time of

10 oscillations is measured by using a stop watch.4. Repeat the timing for another 10 oscillations. Calculate the average

time.Period = t10oscillations10

5. Repeat steps 2, 3 and 4 using l = 50.0 cm, 40.0 cm, 30.0 cm and20.0 cm

1.581.58

1.501.50

1.311.31

1.191.19

0.990.99

15.815.8

15.015.0

13.113.1

11.911.9

9.99.9

15.715.7

15.015.0

13.113.1

11.911.9

9.99.9

15.815.8

15.015.0

13.113.1

11.911.9

9.99.9

60.060.0

50.050.0

40.040.0

30.030.0

20.020.0

Period/ sPeriod/ s

(T = t(T = t1010/10)/10)AverageAverage

2211

Length,Length,ll //cmcm

Time for 10 oscillations / s

10 20 30 40 50 60 l / cm

Precautions :1. Oscillation time is measured when the pendulum attained a steady

state.2. Time for 10 oscillations is repeated twice to increase accuracy.3. Discussion (refer to given questions)

The period increases when the length of the pendulum increases.Hypothesis accepted.

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Reinforcement Chapter 1

Part A :Objective Question

1. Which of the following is a base SIquantity?

A Weight B Energy

C Velocity D Mass

2. Which of the following is a derived

quantity?

A Length B Mass

C Temperature D Voltage

3. Which of the following is not a basic

unit?A Newton B kilogram

C ampere D second

4. Which of the following quantities

cannot be derived?

A Electric current B Power

C Momentum D Force

5. Which of the following quantities is not

derived from the basic physical quantity

of length?

A Electric charge B Density

C Velocity D Volume

6. Initial velocity u, final velocity v,time tand another physical quantity kisrelated by the equation v - u = kt.The unit forkisA m s-1 B m-1 s C

m s-2 D m2 s-2

7. Which of the following has the smallestmagnitude?

A megametre B centimetre

C kilometre D mikrometre

8. 4 328 000 000 mm in standard form is

A 4.328 x 10-9 m B 4.328 x 10-6 m

C 4.328 x 106 m D 4.328 x 109 m

9. Which of the following measurements

is the longest?

A 1.2 x 10-5

cm B 120 x 10-4

dmC 0.12 mm D 1.2 x 10-11 km

10. The diameter of a particle is 250m.What is its diameter in cm?

A 2.5 x 10-2 B 2.5 x 10-4

C 2.5 x 10-6 D 2.5 x 10-8

11. Which of the following prefixes is

arranged in ascending order?

A mili, senti, mikro, desi

B mikro, mili, senti, desi

C mili, mikro, desi, senti

D desi, mikro, mili, senti

12. Velocity, density, force and energy are

A basic quantities

B scalar quantities

C derived quantities

D vector quantities

13. Which of the following shows the

correct conversion of units?

A 24 mm3 =2.4 x 10-6 m3

B 300 mm

3

=3.0 x 10

-7

m

3

C 800 mm3=8.0 x 10-2 m3

D 1 000 mm3=1.0 x 10-4 m3

14. Which of the following measurements

is the shortest ?

A 3.45 x 103 m

B 3.45 x 104 cm

C 3.45 x 107 mm

D 3.45 x 1012m

15. The Hitz FM channel broadcasts radiowaves at a frequency of 92.8 MHz in

the north region. What is the frequency

of the radio wave in Hz?

A 9.28 x 104 B 9.28 x 105

C 9.28 x 107 D 9.28 x 1010

16. An object moves along a straight line

for time, t. The length of the line, s is

given by the equation2

2

1gts = . The SI

unit of g isA m2 s2 B m s-2

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C s-1 D s-2 m

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Part B : Structure Question

1. A car moves with an average speed of 75 km h-1 from town P to town Q in 2 hours as

shown in Figure 1. By using this information, you may calculate the distance between the

two towns.

P Q

Figure 1

(a) (i) Based on the statements given, state two basic quantities and their respective

SI units.

(ii) State a derived quantity and its SI unit.

(b) Convert the value 1 . m to standard form.

5 x 10-3

(c) Complete Table 1 by writing the value of each given prefix.

Table 1

(d) Power is defined as the rate of change of work done. Derive the unit for power in terms

of its basic units.

(e) Calculate the volume of a wooden block with dimension of 7 cm, 5 cm breadth and 12

cm height in m3 and convert its value in standard form.

Distance : m and time : s

Speed m s-1

= 0.2 x 103 m= 2.0 x 102m

10-9

10-6

106

109

Power =time

work=

time

ntdisplacemeForceUnit =

s

mkgms 2= kg m2s-3

Volume = (7 x 10-2) (5 x 10-2) (12 x 10-2)= 420 x 10-6

= 4.20 x 10-4 m3

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