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Chapter Seven (part 2)

Multiple Row Functions:

Objectives:-Multiple row

functions-Ordering-Grouping-Concept of JOIN

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Aggregate Functions:

MAX (DISTINCT | ALL) (value) MIN   (DISTINCT | ALL) (value) AVG (DISTINCT | ALL) (value) SUM (DISTINCT | ALL) (value) COUNT (DISTINCT | ALL) (value)* STDDEV (DISTINCT | ALL) (value) VARIANCE (DISTINCT | ALL) (value)

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Aggregate Functions:

List the highest GPA

SELECT MAX (GPA)FROM Student;

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Aggregate Functions:

List average, max, min, and total salary of cosc faculty

SELECT AVG(salary), MIN(salary), MAX(salary), SUM(salary)

FROM faculty WHERE dept = ‘COSC’;

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Aggregate Functions:

List average salary of cosc faculty:

SELECT AVG( NVL(salary,0)),COUNT(*)

FROM faculty WHERE dept = ‘COSC’;

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Practice:

Find Average, and sum of quoted price from order form. Also the number of orders.

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Practice:

Find the highest quoted price from order form. Order number must be in this range :2000 to 3000.

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Distinct:

SELECT DISTinct (dept)FROM Faculty;

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Practice:

How many customers have an order on March, 10 2001?

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Ordering ORDERING: (Default is Ascending ASC)

List students name in an alphabetic order 

SELECT nameFROM studentORDER BY name;

ORDER BY Name , GPA DESC;

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Ordering

List of the faculty salary for the next year with 5% increase order by new salary.

 SELECT name,

salary pay, salary+salary*0.05 AS

new_salaryFROM facultyORDER BY new_salary;

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Practice:

Find the list of customers: last name, first name, balance, credit line and birth date; order the data by birth date from older to younger and balance from lowest to highest.

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Grouping

SELECTFROM[WHERE][GROUP BY][ORDER BY]

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Grouping Average Salary of faculty members

by department

SELECT dept, AVG (Salary)FROM FacultyGROUP BY dept;

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Grouping

List number of courses taken by each student

SELECT ID, COUNT(*)FROM Student_CourseGROUP BY ID;

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Grouping by multiple attributes List total number of credits taken by

each studentSELECT ID, SUM(Cr)FROM Student_CourseGROUP BY ID;

SELECT ID, semester, SUM(Cr)FROM Student_CourseGROUP BY ID, semester;

SELECT dept, count(name)FROM facultyGROUP BY dept;

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Practice:

List of customer last names and first names for each customer state.

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Having

Condition on Group:

SELECTFROM[WHERE][GROUP BY][HAVING][ORDER BY]

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Having

List ID of students who have more than 20 credits and majoring in COSC.

SELECT ID

FROM Student_CourseWHERE Major = 'COSC' GROUP BY IDHAVING SUM(Cr) > 20 ;

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Having

SELECT dept, MAX(salary)FROM facultyGROUP BY deptHAVING MAX(salary)>50000;

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Having

SELECT dept, MAX(salary)FROM facultyGROUP BY deptHAVINGMAX(salary)>50000ORDER BY MAX(salary);

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Having

SELECT dept, AVG(MAX(salary)-MIN(salary))FROM facultyGROUP BY dept;

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Illegal Queries: SELECT name, count(*)

FROM department;

SELECT name, count(*) FROM department GROUP BY name; SELECT name, AVG(salary) FROM department WHERE AVG(salary) >5000;

SELECT name, AVG(salary) FROM department GROUP BY name HAVING AVG(salary) >5000;

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Practice:

List each SalesRepNumber with their total customer’s balance.

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Practice:

List each SalesRepNumber with their total customer’s balance, only for customers with balance of $1000 or more.

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Practice:

List each SalesRepNumber with their total customer’s balance, only if the total SalesRepNumber balance is less than $100,000, for customers with balance of $1000 or more.

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JOIN: Definition General Format:

SELECT col1,col2,….FROM table1, table2,…WHERE conditions;

 

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JOIN: List of student’s name with the grade

= 'A'  SELECT Name

FROM Student_Course, StudentWHERE Student.ID =

Student_Course.ID and Grade =‘A’;

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JOIN: Aliases:  FROM Student a, Student b WHERE a.ID > b.ID

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CARTESIAN PRODUCT:

Join condition is omitted Join condition is invalid All rows in table one are joined to all

rows in table two

SELECT *FROM Student, faculty;

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JOIN Equijoin:

SELECT NameFROM Student_Course, StudentWHERE Student.ID = Student_Course.ID ;

SELECT department.num_faculty,faculty.name

FROM department, facultyWHERE department.name=faculty.dept;

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Practice:

Find the list of customers: Last name, first name, balance and the city where their sales person lives.

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JOIN  Non-Equijoin:

Faculty (name, salary)Status (rank, low_salry, high_salary)

Get the name, salary and rank of faculty members

SELECT name, salary, rankFROM faculty, statusWHERE salary BETWEEN low_salary AND high_salary;

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JOIN Outer Join:List of students who did take courses.

SELECT nameFROM student, student_courseWHERE student.id =student_course.id (+); 

SELECT department.num_faculty, faculty.nameFROM department, facultyWHERE department.name=faculty.dept(+)

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Practice:

Find the list of customers: Last name, first name, who did not ordered some items in year 2004;

Assume there is a table called customer_order with attributes: c_number, o_number

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JOIN

Self Join

SELECT a.NameFROM Student a, Student bWHERE a.ID > b.ID AND

b.Name = ‘SMITH';

What is the output of this query

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JOIN Self Join List of Faculty member with salary

higher than salary of Mary and less than salary of John

  SELECT a.NameFROMFaculty a, Faculty b, Faculty cWHERE a.Salary > b.Salary AND

a.Salary < c.Salary ANDb.Name = 'MARY' ANDc.Name = ‘JOHN’;

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Practice:

Find the list of customers: Last name, first name, who are reside in the same city as Ms joy Smith