chemical reaction engineering
DESCRIPTION
Molar flow reactorsTRANSCRIPT
CHEE 321: Chemical Reaction Engineering
Module ∞: Fun Stuff we didn’t cover
and thinking about the exam
Dead zones (1) and “short-circuiting” (2) in CSTR or PFR
Topic 1: Not all Reactors are Ideal!
Velocity profiles (2) and (3) lead to deviations from ideal PFR behaviour
Computational Fluid Dynamics
• CFD simulations provide velocity profiles as function of reactor geometry, impeller design and fluid properties
• These profiles can be used to identify dead zones, choose the position of the inlet and outlet streams, and to examine characteristic mixing times
• For ideal behaviour, mixing times should be short compared to time scale of reaction kinetics
Characterization of Non‐Ideal Reactors
Why ?• To model non-ideal hydrodynamics (mixing and flow) behaviour• To understand how the non-ideality will impact reactor performance, i.e.
what would be the reactant conversion in these “real” reactors.
• Combine knowledge of Residence Time Distribution (RTD) and the already known concepts of ideal reactors to model the behavior of non-ideal reactors.
How ?
Fogler, Ch. 13
How to Measure RTDs ??
REACTORDetector
Tracer
Feed Effluent
Desirable Qualities of a Tracer• easily detectable• non-reactive• non-absorptive or adsorptive• physical properties similar to fluid
RTD Characteristics‐ Examples
Nearly plug-flow
Packed Bed Reactorwith channeling
Models are available that use the actual RTD to calculate the effectof non-ideal mixing on conversion, temperature, etc...
Complicating factors
• Many reactions occurring in parallel
• Polymer has a distribution of chain lengthsSpecialized modeling techniques are requiredDifficult to characterize product
• Viscosity increases by several orders of magnitude as monomers are converted to polymers
Heat and mass transfer effects become important
• Heterogeneous (multiphase) processes are often used
Topic 2: Polymer Reaction Engineering
Radical Polymerization Kinetic Balances
Transfer to Monomer Pn + M ⎯→ Dn + P1
Transfer to Solvent Pn + S ⎯→ Dn + P1
Propagation Pn + M ⎯→ Pn+1
Termination Pn + Pm ⎯→ Dn+m
Pn + Pm ⎯→ Dn + Dm
Initiation I ⎯→ 2 f P1
kd kp
kt,c
kt,d
montrk
soltrk
P1 Pn (n>1) ∑∞
=
=1n
ntot PP Dn ∑∞
=
=1n
ntot DD
Initiation +2·f·kd·[I] +2·f·kd·[I]
Propagation -kp·[M]·P1 -kp·[M]·(Pn-Pn-1)
Term. by Disprop. -ktd·Ptot·P1 -ktd·Ptot·Pn -ktd·(Ptot)2 +ktd·Ptot·Pn +ktd·(Ptot)2
Term. by Comb. -ktc·Ptot·P1 -ktc·Ptot·Pn -ktc·(Ptot)2 +½ktc mn
n
mmPP −
−
=∑
1
1+½·ktc·(Ptot)2
Tr. to Monomer + montrk ·[M]·(Ptot-P1) - mon
trk ·[M]·Pn + montrk ·[M]·Pn + mon
trk ·[M]·Ptot
Tr. to Solvent + soltrk ·[S] (Ptot-P1) - sol
trk ·[S]·Pn + soltrk ·[S]·Pn + sol
trk ·[S]·Ptot
Polymer Molecular Weight Distributions
Living polymerization - Mw/Mn = 1.1
Conventional free radical polymerization - Mw/Mn = 2.0
Two polymers - same number average molecular weight (= 100 units)
1 10 102 103 104
Polymer chain length
Wt f
ract
ion
of p
olym
er
What we did cover…Isothermal, Ideal Reactor (Single Reaction) Design
Mole Balance(Module-1,2)
In – Out + Con = AccFA,in-FA,out+(rA)V = dCA/dt
Rate Law(Module-1)
(rA) = kCAn
Design Algorithm(Module-2)
1. GMBE, 2. Rate Law3. Stoich 4.Combine
Analysis of Rate law(Module-5)
Kinetics: How to obtain k and rxn order
Multiple Reactions(Module-6)
Selectivity, Yield
Non-Isothermal Reactor Design
dT/dz = ?
Tin-Tout =?
Output
• Reactor Volume• Reaction Time
• Rate Constant
• Conversion• Product Composition
• Energy Balance• Heat Transfer Rate• Equilibrium Reactions• Multiple Steady State
(Module-3)• Temperature Profile• Heat Removal• Heating Requirement
Output
Summary ‐ Design Equations of Ideal Reactors
DifferentialEquation
AlgebraicEquation
IntegralEquation
Remarks
Vrdt
dNj
j )(=0( )
j
j
Nj
jN
dNt
r V′
= ∫Conc. changes with time but is uniform within the reactor. Reaction rate varies with time.
Batch(well‐mixed)
CSTR(well‐mixed at steady‐state)
0
( )j j
j
F FV
r−
=−
Conc. inside reactor is uniform. (rj) is constant. Exit conc = conc inside reactor.
PFR(steady‐state flow; well‐mixed radially)
jj r
dVdF
=
0( )
j
j
Fj
jF
dFV
r′
= ∫Concentration and hence reaction rates vary spatially (with length).
Design Equation in Terms of Conversion(limiting reactant A, single reaction)
IDEAL DIFFERENTIAL ALGEBRAIC INTEGRAL REACTOR FORM FORM FORM
0 ( )AA A
dXN r Vdt
= − 00
AXA
AA
dXt Nr V
′=
−∫
0 ( )AA A
dXF rdV
= − 00
AXA
AA
dXV Fr
′=
−∫
CSTR
PFR
0 ( )( )A A
A
F XVr
=−
BATCH
Basic idea: use plot of vs. X to calculate V
0
0
PFRXA
PFRA
FV dXr
=−∫
X
)(0
A
A
rF−
][])(
[ 0CSTR
A
ACSTR X
rFV ×−
=
Plug Flow Reactor (PFR)
Continuous Stirred Tank Reactor (CSTR)
)(0
A
A
rF−
XEvaluated at X=XCSTR
XPFR
XCSTR
)(0
A
A
rF−
General Algorithm for Solving Reactor Problems (Single Reaction, reversible or irreversible)
1. General Mole Balance Equation (GMBE)2. Rate Laws
• Write down rate law in terms of limiting reactant
3. Stoichiometry• relate concentration to volume and number of moles (for batch
reactors) or to volumetric flow rate and molar flow rate (for flow reactor)
• Relate volume or volumetric flow rate to conversion, pressure and temperature
4. Combine and Solve• Substitute rate law and stoichiometry in to the GMBE
See Fogler Figure 4.1
Stoichiometric Table for Flow Reactors
Reaction: b c dC D
a a aA B +⎯⎯→+ ←⎯⎯
Species Feed Flow Rate (mol/s)
Change within Reactor (mol/s)
Effluent Rate from Reactor (mol/s)
A 0AF 0( )A AF X− 0 (1 )A A AF F X= −
B 0 0B B AF Fθ= 0( )A A
b F Xa
− 0 ( )B A B AbF F Xa
θ= −
C 0 0C C AF Fθ= 0( )A A
c F Xa
0 ( )C A C AcF F Xa
θ= +
D 0 0D D AF Fθ= 0( )A A
d F Xa
0 ( )D A D AdF F Xa
θ= +
I (inert) 0 0I I AF Fθ= - 0I IF F=
Total 0TF 0A AF Xδ 0 0T T A AF F F Xδ= +
Batch reactor stoichiometric tables are similar
Define 0 0/i i AF Fθ =
(Limiting reagent A)
Calculating Concentration for Flow Reactors
From stoichiometry and mole balances, we have Fi = f(XA)
What value of v (flowrate) should we use?
Liquid phase reactions (incompressible) v = v0
Gas phase reactions (ideal gas)0
00 0
( )( )T
T
PF Tv vF P T
=
For isothermal and isobaric reactorswith no change in number of moles (i.e. δ=0)
v = v0
Concentration in Flow Reactors : ii
FCv
=
0 0T T A AF F F Xδ= +
General Form of Energy Balance
dtEdEFEFWQ
outi
n
iiini
n
ii
ˆ
11=−+− ∑∑
==
sW
Qnn EF
EFEF
,...
,,
22
11
nn EF
EFEF
,...
,,
22
11
dtEdHFHFWQ
outi
n
iiini
n
iis
ˆ
11=−+− ∑∑
==
Energy Balance Equation in terms of Enthalpy
[ ]0
0 01
ˆ] ( )
Tn
s A i pi A A Rxni T
dEQ W F C dT F X H Tdt
θ=
⎡ ⎤′− − − ⋅ ⋅ Δ =⎢ ⎥
⎢ ⎥⎣ ⎦∑ ∫
Energy Balance Equation in terms of Conversion
010
( ) ( ) ( ) ( )n
aRxn ref p ref A i pi
iA
UA T T H T C T T X C T TF
θ=
− ⎡ ⎤− Δ + Δ − ⋅ = −⎣ ⎦ ∑
Non‐isothermal CSTR Design at Steady State
Fogler 8.6: Figure 8-13 and Table 8-4 (p 525-526)
combine with design equation: 0 ( )( )A A
A
F XVr
=−
How can these be used?
1. Specify XA, find V and Thttp://www.engin.umich.edu/~cre/08chap/html/excd8-2.htmand class example
2. Specify T, find XA and Vhttp://www.engin.umich.edu/~cre/course/lectures/eight/second.htm
3. Specify V, find XA and TThe 3rd type of problem is the most challenging
PFR with Heat Exchange
1
1
( ) ( ) ( )n
a i A ii
n
i pii
U a T T r H TdTdV F C
ν=
=
⋅ ⋅ − − ⋅ − ⋅=
⋅
∑
∑
How do we solve non-isothermal PFR problems?
)( Aii r
dVdF
−=ν )(0 AA rdVdXF =−or ),( TXf=
),( TXg=
We need to solve the two differential equations simultaneously.Usually done numerically.
(Can’t be done in an exam.)
Multiple Reactions: don’t use Design Equations in terms of Conversion
'0 ( )
A
AA
dXF rdW
= −
IDEAL DIFFERENTIAL ALGEBRAIC INTEGRAL REACTOR FORM FORM FORM
0 ( )AA A
dXN r Vdt
= − 00
AX
AA
dXt Nr V
′=
−∫
0 ( )AA A
dXF rdV
= −0
0
AX
AA
dXV Fr
′=
−∫
CSTR0 ( )
( )A A
A
F XVr
=−
BATCH
PFR
PBR 0 '0
A
A
X
AdXW F
r′
=−∫
If you have multiple reactions:A + B C
andA + C D
then the consumption/generation rates of A, B, C and D are not simply coupled
Therefore, we need to write individual equations for all species in the system.
Write these in terms of molar quantities, not fractional conversions
Modification to the CRE Algorithm for Multiple Reactions
• Mole balance on every species (not in terms of conversion)
• Rate Law: Net Rate of reaction for each species, e.g., rA = Σ riΑ where subscript ‘i’ indicates the ith reaction
• Stoichiometry
– a) Liquid Phase, incompressible: CA=NA/V=FA/v0– b) Gas Phase use
• Combine – More difficult: set of algebraic or differential equations for A, B, …
Fogler, 6.4
Variable volumetric flowrate; ideal gas
Energy Balance with Multiple Reactions
Steady‐state PFR, Single Reaction
1
( ) ( ) ( ( ))a A rxnn
i pii
U a T T r H TdTdV F C
=
⋅ ⋅ − + − ⋅ −Δ=
⋅∑
Steady‐state PFR, Multiple Reaction (Nrxn)
,1
1
( ) ( ) ( ( ))rxnN
a ij rxn iji
n
i pii
U a T T r H TdTdV F C
=
=
⋅ ⋅ − + − ⋅ −Δ=
⋅
∑
∑
Fogler, 8.8.1
Rxn-i rate and heat of reaction specified in terms of reactant-j
See Example 8-10
Energy Balance with Multiple Reactions
Steady‐state CSTR, Single Reaction
Steady‐state CSTR, Multiple Reaction (Nrxn)
Fogler, 8.8.2
Rxn-i rate and heat of reaction specified in terms of reactant-j
See Example 8-11
[ ]0 0 01
( ) ( ) ( )n
a A Rxn A A i pii
UA T T F H T X F C T Tθ=
− − Δ ⋅ = −∑
[ ] 0 01
( ) ( ) ( ) ( )n
a Rxn A A i pii
UA T T H T r V F C T Tθ=
− + Δ ⋅ = −∑0 ( )( )A A
A
F XVr
=−
but
, 0 01 1
( ) ( ) ( )rxnN n
a ij Rxn ij A i pii i
UA T T V r H T F C T Tθ= =
⎡ ⎤− + Δ = −⎣ ⎦∑ ∑
Selectivity and YieldInstantaneous Global
U
DDU r
rS =U
DDU F
FS =~
A
DD r
rY−
=0 0
D DD
A A A A
F NYF F N N
= =− −
Selectivity
Yield
• What should be the criterion for designing the reactor ? • Is it necessary that reactor operates such that minimum amount of
undesired products are formed ?
Total Cost
Desired Reaction:
Undesired Reaction:
DA Dk⎯→⎯
2
U
U
k
k
A U
D U
⎯⎯→
⎯⎯→
Cos
t
Reactant Conversion
ReactorSystem
FA0FA
FD
FU
FD
FU
SEPARATOR
FA
and/or
Fogler 6.1
Multiple Reactions
• Algorithm for Reactor Design of Multiple Reactions– Mole Balance
– Net Rates of Reactions
– Stoichiometry
– Energy balances
• Analyses of Parallel and Series Reactions– Maximizing the reactor operation for single reactant systems
– Maximizing the reactor operation for two reactant systems
– Consideration of selectivity and yield
• Non‐elementary Reactions and Active Intermediate Species– Pseudo‐steady‐state hypothesis
– Rate‐determining (rate‐controlling) step
The final examFaculty: ENG Dept: CHEE
Course: CHEE321 Section: -
Offered Jointly With: N/A Total: 132
Date & Time: Dec 12 at 19:00 Location: Bartlett Gym - Main Floor
Datasheets YES Photocopies YES
Notebooks YES Calculator YES - Sticker (GOLD)
Math Tables YES Portable PC NO
Textbooks YES
Aids Allowed:
QUEEN’S UNIVERSITYFACULTY OF APPLIED SCIENCE
DEPARTMENT OF CHEMICAL ENGINEERINGCHEE 321
FINAL EXAMINATIONDECEMBER 2009
PROF. ROBIN HUTCHINSON
INSTRUCTIONS:• This examination is THREE HOURS in length. The exam consists of 4
questions for a total of 100 marks. Please answer all questions. • A gold sticker calculator is allowed. This is an open book/open notes exam. • Values of the gas constant, conversion factors for units, and common integrals
are found in the appendices of the course textbook.• Answer all questions in the answer booklets provided. Put your student number
on the front of all answer booklets. • GOOD LUCK!
**PLEASE NOTE**Proctors are unable to respond to queries about the interpretation of exam questions. Do your best to answer exam questions as written.
The candidate is urged to submit with the answer paper a clear statement of any assumptions made if doubt exists as to the interpretation of any question that requires a written answer.