chemistry 256 workshop #7 exercise spring 2016 prof. loyd

1
Chemistry 256 Workshop #7 Exercise Spring 2016 Prof. Loyd Bastin 1. The IR spectra below belong to 5-phenyl-1-pentyne and 6-phenyl-2-hexyne. Which is which? Explain your reasoning. 2. Compound C is asymmetric, has molecular formula C 5 H 10 O, and contains two methyl groups and a 3° functional group. It has a broad infrared absorption band in the 3200–3550 cm -1 region and no IR absorption bands between 1690–1750 cm -1 and 3000–3100 cm -1 . (a) Propose a structure for C. (b) Is your suggested structure capable of stereoisomerism? If so, can you determine from the data provided which stereoisomer Compound C represents? 3. An optically active compound D has the molecular formula C 6 H 10 and shows a sharp peak at 3300 cm -1 in its IR spectrum. On reaction with excess H 2 over catalytic Pt D yields E (C 6 H 14 ). Compound E is optically inactive and cannot be resolved. Propose structures for D and E.

Upload: others

Post on 02-Nov-2021

3 views

Category:

Documents


0 download

TRANSCRIPT

Page 1: Chemistry 256 Workshop #7 Exercise Spring 2016 Prof. Loyd

Chemistry 256 Workshop #7 Exercise Spring 2016 Prof. Loyd Bastin

1. The IR spectra below belong to 5-phenyl-1-pentyne and 6-phenyl-2-hexyne. Which is which? Explain your reasoning.

2. Compound C is asymmetric, has molecular formula C5H10O, and contains two methyl groups

and a 3° functional group. It has a broad infrared absorption band in the 3200–3550 cm-1 region and no IR absorption bands between 1690–1750 cm-1and 3000–3100 cm-1. (a) Propose a structure for C. (b) Is your suggested structure capable of stereoisomerism? If so, can you determine from the data provided which stereoisomer Compound C represents?

3. An optically active compound D has the molecular formula C6H10 and shows a sharp peak at

3300 cm-1 in its IR spectrum. On reaction with excess H2 over catalytic Pt D yields E (C6H14). Compound E is optically inactive and cannot be resolved. Propose structures for D and E.