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Narayana CO Schools 1 Class: SZ1-A(Revision) JEE-MAIN MODEL Date: 02-01-21 Time: 3hrs RTM-04 Max. Marks: 300 Jee-Main_Model SZ1-A Physics Initial Key Dt. 02-01-2021 Q.No. 01 02 03 04 05 06 07 08 09 10 Ans. 1 3 3 1 4 2 4 2 4 1 Q.No. 11 12 13 14 15 16 17 18 19 20 Ans. 3 2 1 2 1 3 2 2 1 1 Q.No. 21 22 23 24 25 Ans. 6.00 10.55 to 10.60 34.28 to 34.30 10.00 40.00 SZ1-A Chemistry Initial Key Dt. 02-01-2021 Q.No. 26 27 28 29 30 31 32 33 34 35 Ans. 3 3 4 1 4 4 2 1 4 1 Q.No. 36 37 38 39 40 41 42 43 44 45 Ans. 4 1 3 4 1 3 1 1 3 2 Q.No. 46 47 48 49 50 Ans. 6.46 21.37 1.20 to 1.25 124.50 -0.90 SZ1-A Mathematics Initial Key Dt. 02-01-2021 Q.No. 51 52 53 54 55 56 57 58 59 60 Ans. 3 2 4 1 3 4 3 4 1 4 Q.No. 61 62 63 64 65 66 67 68 69 70 Ans. 2 2 1 4 4 1 2 2 4 4 Q.No. 71 72 73 74 75 Ans. 0.00 3.00 0.00 1.00 1.00

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  • Narayana CO Schools

    1

    Class: SZ1-A(Revision) JEE-MAIN MODEL Date: 02-01-21

    Time: 3hrs RTM-04 Max. Marks: 300

    Jee-Main_Model

    SZ1-A Physics Initial Key Dt. 02-01-2021

    Q.No. 01 02 03 04 05 06 07 08 09 10

    Ans. 1 3 3 1 4 2 4 2 4 1

    Q.No. 11 12 13 14 15 16 17 18 19 20

    Ans. 3 2 1 2 1 3 2 2 1 1

    Q.No. 21 22 23 24 25

    Ans. 6.00 10.55 to 10.60

    34.28 to 34.30

    10.00 40.00

    SZ1-A Chemistry Initial Key Dt. 02-01-2021

    Q.No. 26 27 28 29 30 31 32 33 34 35

    Ans. 3 3 4 1 4 4 2 1 4 1

    Q.No. 36 37 38 39 40 41 42 43 44 45

    Ans. 4 1 3 4 1 3 1 1 3 2

    Q.No. 46 47 48 49 50

    Ans. 6.46 21.37 1.20 to

    1.25 124.50 -0.90

    SZ1-A Mathematics Initial Key Dt. 02-01-2021

    Q.No. 51 52 53 54 55 56 57 58 59 60

    Ans. 3 2 4 1 3 4 3 4 1 4

    Q.No. 61 62 63 64 65 66 67 68 69 70

    Ans. 2 2 1 4 4 1 2 2 4 4

    Q.No. 71 72 73 74 75

    Ans. 0.00 3.00 0.00 1.00 1.00

  • SZ1-A_JEE-MAIN_RTM-04_Key&Solutions_Exam.Dt.02-01-21

    Narayana CO Schools

    2

    01. 1 2p p p= +

    Powers added up individual powers will be 2D

    02. Increases

    03. Power of the lenses does not depend on its size

    04. The ciliary muscles do not contract and the eye is least strained

    05. size of object directly depends

    08. 0 10 , 5f cm Fe cm= =

    0 0 0

    1 1 1

    v u f− =

    0

    1 11 1

    0.5v= − = −

    Object distance of eyepiece ( )1x cm= +

    1 1 1

    30 1 5x+ =

    +

    6x =

    1 6x+ =

    5x cm=

    13.

  • SZ1-A_JEE-MAIN_RTM-04_Key&Solutions_Exam.Dt.02-01-21

    Narayana CO Schools

    3

    14.

    15.

  • SZ1-A_JEE-MAIN_RTM-04_Key&Solutions_Exam.Dt.02-01-21

    Narayana CO Schools

    4

    16.

    19.

  • SZ1-A_JEE-MAIN_RTM-04_Key&Solutions_Exam.Dt.02-01-21

    Narayana CO Schools

    5

    23.

    25.

  • SZ1-A_JEE-MAIN_RTM-04_Key&Solutions_Exam.Dt.02-01-21

    Narayana CO Schools

    6

    30.

    31. q and w represents path function

    32.

    42.

    43.

  • SZ1-A_JEE-MAIN_RTM-04_Key&Solutions_Exam.Dt.02-01-21

    Narayana CO Schools

    7

    44.

    45.

    46.

    47.

  • SZ1-A_JEE-MAIN_RTM-04_Key&Solutions_Exam.Dt.02-01-21

    Narayana CO Schools

    8

    48.

    49.

    50.

  • SZ1-A_JEE-MAIN_RTM-04_Key&Solutions_Exam.Dt.02-01-21

    Narayana CO Schools

    9

    51. System has unique solution if det. of coefficinet 0=

    1 1 1

    2 1 1 0 0

    3 2

    52. AX B=

    2 3 6 4

    5 7 14 , , 1

    3 2 4 0

    x

    A X y B

    z

    = − = = −

    now 0A = .

    The equations either have no solution or an infinite number of

    solutions to decide about this we proceed to find ( ).adj A B

    0 0 0

    22 26 58

    11 13 29

    adjA

    = − − − −

    ( )

    0

    . 114 0

    57

    adj A B

    = − −

    no solution

    53. AX B=

    1 1 1 6

    0 1 2 8

    0 3 6 24

    A B

    =

    2 2 1R R R⎯⎯→ −

    3 3 1R R R⎯⎯→ −

    1 1 1 6

    0 1 2 8

    0 0 0 0

    = =

    Rank A = rank [A][B] = 2

    System has infinitely many solution.

    System is equivalent to 6, 2 8x y z y z+ + = + =

    8 2 , 2z y x= = − = − +

  • SZ1-A_JEE-MAIN_RTM-04_Key&Solutions_Exam.Dt.02-01-21

    Narayana CO Schools

    10

    54. 0A =

    Now

    4 6 2 4 6 2

    6 9 3 6 9 3

    2 3 1 2 3 1

    T

    adj A

    − −

    = − − = − − − −

    ( )

    2

    2

    2 2

    4 6 2 1 4 6 2

    6 9 3 6 9 3 0

    2 3 1 2 3

    adj A B

    − − +

    = − − = − + − = − − +

    Since system is consistent

    22 6 4 0 1,2 − + = =

    55. Augumented martrix

    1 1 1 5 1 1 1 5

    1 2 0 1 1 5

    1 2 3 9 0 0 3 9

    A B

    = = − − − −

    2 2 1

    3 3 1

    R R R

    R R R

    ⎯⎯→ −

    ⎯⎯→ −

    Rank A = Rank [AB] if 3

    The system has unique solution if 3

    If 3, 9 = = , rank A = rank [AB] = 2 < no. of unknowns

    The system has infinitely many solution if 3, 9 = =

    If 3, 9 = , rank A = 2, rank [AB] = 3 no solution

    56. System has non-trival solution 0

    a b c

    b c a

    c a b

    =

    3 3 3 3 0a b c abc + + − =

    ( )( )( )2 2 0a b c c bw aw c bw aw + + + + + + =

    Since , ,a b c are positive 0a b c+ + , either 2 0aw bw c+ + = or

    4 2 0aw bw c+ + =

    Hence roots of the equation 2 0at bt c+ + = are 2,w w

    57.

    1 1 1

    1 1 1 0

    1 1 1

    a

    b

    c

    − =

  • SZ1-A_JEE-MAIN_RTM-04_Key&Solutions_Exam.Dt.02-01-21

    Narayana CO Schools

    11

    ab bc ca abc + + =

    ( )1

    2 2 2 3

    3

    ab bc caa b c

    + +

    ( )1

    3 3abc

    ( )min 27abc =

    59. The system has infinite solutions if

    1 0

    0 1 0 1,1

    0 1

    a

    a a

    a

    = = −

    For 1a = we have the system 0, 0, 0x y y z z x+ = + = + = which have

    only one solution 0x y z= = =

    1a = −

    60. Non-trival solution if

    1 1

    1 1 0

    1 1

    − − =

    ( )2 1 0 − =

    0,1, 1 = −

    61. 1 2A A A I− = + +

    3 2I A A A= + +

    33 6 19

    35 4 30

    30 13 22

    A

    − −

    = − −

    3 26 11A A A I− + =

    multiplying both the sides by 1A−

    1 2 6 11A A A I− = − +

    6, 11 = − =

    5+ =

    62. ( ) ( )( ) ( ) 1 1T

    TTBB I A I A I A I A− −

    = − + + −

    ( ) ( )( )1 TI A I A I A−

    = − + +

  • SZ1-A_JEE-MAIN_RTM-04_Key&Solutions_Exam.Dt.02-01-21

    Narayana CO Schools

    12

    ( ) ( )( ) ( )1

    1 TI A I A I A I A

    −− = − + − −

    A is skew-symmetric TA A= −

    ( ) ( ) ( ) ( )11 TI A I A I A I A−−

    − − + −

    ( ) ( )( )( )1 1

    I A I A I A I A− −

    = − − + +

    .TBB I I I = =

    63. ( ) ( )1

    *A I A I A−

    = + −

    ( ) ( )1

    ** * *A I A I A−

    = + −

    ( ) ( ) ( ) ( ) ( )1 1 1

    * 2I A I A I A I A I A I A I− − −

    + = + + + + − = + ( )1

    2 I A−

    = +

    ( ) ( )1 1

    *2

    I A I A−

    + = +

    ( ) ( ) ( ) ( ) ( )1 1 1

    * 2I A I A I A I A I A I A A− − −

    − = + + − + − = +

    ( ) ( )11

    ** 22

    A I A I A A A−

    = + + =

    64. A has rank 3 0A

    ( )

    1

    1 0

    1

    b c

    y a b c y b c

    b y c

    + + + +

    +

    ( )

    1

    0 0 0

    0 0

    b c

    y a b c y

    y

    + + + ( )2 0y y a b c + + +

    65. matrix A has all integer entries

    cofactor of each entry is integer

    adjoine A has integers entries

    ( ) ( )11

    A adj A adj AA

    − = =

    66. T TPP I P P= =

    TQ PAP=

    T T T TP Q P PAP AP = =

  • SZ1-A_JEE-MAIN_RTM-04_Key&Solutions_Exam.Dt.02-01-21

    Narayana CO Schools

    13

    2005 2004 2004 2 2003 ...T T T TP Q P P Q Q P AP Q P A P Q P= = =

    ( ) ( )2004 2004 2005T TA P QP A P PA A= = =

    21 2 1

    ...0 1 0 1

    nn

    A A

    = =

    20051 2005

    0 1A

    =

    20051 2005

    0 1

    TP Q P

    =

    67. TA A I=

    2 2 2 1a b c + + =

    0ab bc ca+ + =

    Since , , 0a b c

    0ab bc ca+ +

    3 3 3a b c + + is exists

    ( )( )3 3 3 2 2 2 4a b c a b c a b c ab bc ca+ + = + + + + − − − =

    68. characteristic equation of A is

    0A I− =

    3 26 11 6 0 − + − =

    A satisfies characteristic equation 3 26 11 6 0A A A I− + − =

    1 26 6 11A A A I− = − +

    6, 11C d= − =

    69. 3 3ij

    P a

    =

    2i jij ijb a+=

    3 3ij

    Q b

    =

    11 12 13

    21 22 23

    31 32 33

    , 2

    a a a

    P a a a P

    a a a

    = =

  • SZ1-A_JEE-MAIN_RTM-04_Key&Solutions_Exam.Dt.02-01-21

    Narayana CO Schools

    14

    11 12 13 11 12 13

    21 22 23 21 22 23

    31 32 33 31 32 33

    4 8 16

    8 16 32

    16 32 64

    b b b a a a

    Q b b b a a a

    c c c a a a

    = =

    Determinant of

    11 12 13 11 12 13

    21 22 33 21 22 23

    31 32 33 31 32 33

    4 8 16

    8 16 32 4 8 16 2 2 2

    16 32 64 4 4 4

    a a a a a a

    Q a a a a a a

    a a a a a a

    = =

    11 12 13

    2 3 4 1 2 1 13

    21 22 23

    31 32 33

    4 8 16 2 4 2 2 2 2 2 2 2

    a a a

    a a a

    a a a

    = = =

    70. 2TP P I= +

    2 TP P I= +

    2 2P P I I= + +

    4 3P P I= +

    3 3P I= −

    PX X= −

    71. 3 3 2 2,P Q P Q Q P= =

    P Q

    Subtracting 3 2 3 2P P Q Q Q P− = −

    ( ) ( )2 2 0P P Q Q P Q− + − =

    ( )( )2 2 0P Q P Q+ − =

    If ( )2 2 0P Q P Q+ − =

    If 2 2 0P Q+ , then 2 2P Q+ is invertible

    0P Q − =

    Controduction

    Hence 2 2 0P Q+ =

    72. for no solution

    1 8 4

    3 3 1

    k k

    k k k

    +=

    + −

  • SZ1-A_JEE-MAIN_RTM-04_Key&Solutions_Exam.Dt.02-01-21

    Narayana CO Schools

    15

    2 4 3 8k k k+ + =

    2 4 3 0, 1,3k k k− + = =

    If 8 4 1

    1 false1 3 2

    k

    = +

    If 8 4 3

    3 true6 9 1

    k

    = =−

    3k =