component redundancy versus system redundancy in different stochastic orderings

16
IEEE TRANSACTIONS ON RELIABILITY, VOL. 63, NO. 2, JUNE 2014 567 Component Redundancy Versus System Redundancy in Different Stochastic Orderings Nil Kamal Hazra and Asok K. Nanda Abstract—Stochastic orders are useful to compare the lifetimes of two systems. We discuss both active redundancy as well as standby redundancy. We show that redundancy at the component level is superior to that at the system level with respect to different stochastic orders, for different types of systems. Index Terms—Coherent system, -out-of- system, reliability, stochastic orders. ACRONYMS AND ABBREVIATIONS st usual stochastic sp stochastic precedence hr hazard rate rhr reversed hazard rate lr likelihood ratio up shifted hazard rate down shifted hazard rate up shifted reversed hazard rate up shifted likelihood ratio down shifted likelihood ratio NOTATION underlying nonnegative random variable probability density function of random variable cumulative distribution function of random variable survival (reliability) function of random variable hazard rate function of random variable reversed hazard rate function of random variable lifetime of a coherent system Manuscript received September 05, 2012; revised August 25, 2013; accepted December 05, 2013. Date of publication April 17, 2014; date of current ver- sion May 29, 2014.The work of N. K. Hazra was supported by the Council of Scientic and Industrial Research, New Delhi under Grant 09/921(0060)2011- EMR-I. Associate Editor: C. Smidts. The authors are with the Department of Mathematics and Statistics, IISER Kolkata, Mohanpur 741252, India (e-mail: [email protected]; [email protected], [email protected]). Color versions of one or more of the gures in this paper are available online at http://ieeexplore.ieee.org. Digital Object Identier 10.1109/TR.2014.2315917 reliability function of a coherent system having lifetime lifetime of a -out-of- system coherent system with active redundancy at the component level coherent system with active redundancy at the system level -out-of- system with active redundancy at the component level -out-of- system with active redundancy at the system level -out-of- system with standby redundancy at the component level -out-of- system with standby redundancy at the system level state of at time state of at time state of at time state of at time state of at time state of at time empirical reliability function for component redundancy empirical reliability function for system redundancy Generalized Pareto distribution with reliability function given by , . NOMENCLATURE rst derivative of with respect to 0018-9529 © 2014 IEEE. Personal use is permitted, but republication/redistribution requires IEEE permission. See http://www.ieee.org/publications_standards/publications/rights/index.html for more information.

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Page 1: Component Redundancy Versus System Redundancy in Different Stochastic Orderings

IEEE TRANSACTIONS ON RELIABILITY, VOL. 63, NO. 2, JUNE 2014 567

Component Redundancy Versus System Redundancyin Different Stochastic Orderings

Nil Kamal Hazra and Asok K. Nanda

Abstract—Stochastic orders are useful to compare the lifetimesof two systems. We discuss both active redundancy as well asstandby redundancy. We show that redundancy at the componentlevel is superior to that at the system level with respect to differentstochastic orders, for different types of systems.

Index Terms—Coherent system, -out-of- system, reliability,stochastic orders.

ACRONYMS AND ABBREVIATIONS

st usual stochastic

sp stochastic precedence

hr hazard rate

rhr reversed hazard rate

lr likelihood ratio

up shifted hazard rate

down shifted hazard rate

up shifted reversed hazard rate

up shifted likelihood ratio

down shifted likelihood ratio

NOTATION

underlying nonnegative random variable

probability density function of randomvariable

cumulative distribution function of randomvariable

survival (reliability) function of randomvariable

hazard rate function of random variable

reversed hazard rate function of randomvariable

lifetime of a coherent system

Manuscript received September 05, 2012; revised August 25, 2013; acceptedDecember 05, 2013. Date of publication April 17, 2014; date of current ver-sion May 29, 2014.The work of N. K. Hazra was supported by the Council ofScientific and Industrial Research, New Delhi under Grant 09/921(0060)2011-EMR-I. Associate Editor: C. Smidts.The authors are with the Department of Mathematics and Statistics, IISER

Kolkata, Mohanpur 741252, India (e-mail: [email protected];[email protected], [email protected]).Color versions of one or more of the figures in this paper are available online

at http://ieeexplore.ieee.org.Digital Object Identifier 10.1109/TR.2014.2315917

reliability function of a coherent systemhaving lifetime

lifetime of a -out-of- system

coherent system with active redundancy atthe component level

coherent system with active redundancy atthe system level

-out-of- system with active redundancy atthe component level

-out-of- system with active redundancy atthe system level

-out-of- system with standby redundancyat the component level

-out-of- system with standby redundancyat the system level

state of at time

state of at time

state of at time

state of at time

state of at time

state of at time

empirical reliability function for componentredundancy

empirical reliability function for systemredundancy

Generalized Pareto distributionwith reliability function given by

,.

NOMENCLATURE

first derivative of with respect to

0018-9529 © 2014 IEEE. Personal use is permitted, but republication/redistribution requires IEEE permission.See http://www.ieee.org/publications_standards/publications/rights/index.html for more information.

Page 2: Component Redundancy Versus System Redundancy in Different Stochastic Orderings

568 IEEE TRANSACTIONS ON RELIABILITY, VOL. 63, NO. 2, JUNE 2014

second derivative of with respect to

and have the same sign

and have the same distribution

iid statistically independent and identicallydistributed

I. INTRODUCTION

W E can enhance the life of a system by incorporatingspares (or redundants) into the system. Then, the real

problem is where to allocate spares into the system so that thelifetime of the system is maximized. Design engineers generallybelieve that redundancy at the component level is more effec-tive than redundancy at the system level. Redundancy is mostlyof two types: active redundancy (or parallel redundancy), andstandby redundancy. In active redundancy, the original compo-nent and the redundant component work together so that the lifeof the system is the maximum of the lives of the original com-ponent and the redundant component. In standby redundancy,the redundant component starts to function only when the orig-inal component fails. Thus, system life is the sum of the livesof the original component and the redundant component. In thispaper, we discuss both active redundancy as well as standby re-dundancy. Both types of redundancies are extensively studied inthe literature; see, for example, Liang and Chen [29], Li and Hu[27], Misra et al. ([22], [23]), Li et al. [28], and the referencesthere-in. In the case of active redundancy, Barlow and Proschan[5], Boland and El-Neweihi [1], Singh and Singh [19], Guptaand Nanda [3], Misra et al. [2], Brito et al. [14], Nanda andHazra [11], and many other researchers have shown that com-ponent redundancy is superior to system redundancy in differentstochastic orders. On the other hand, very few results have beendeveloped for standby redundancy. The significant work in thisdirection is obtained in Boland and El-Neweihi [1].Suppose we have two different systems, and we want to

compare their reliabilities. Then, the key question is how todetermine that one system is more reliable than the other.Stochastic orders are an effective solution to this problembecause once the distribution functions of two lifetime randomvariables are known, stochastic orders use the complete infor-mation available regarding the underlying random variablesthrough its distribution, whereas the other kind of comparison(say, in terms of means and variances) does not utilize thecomplete information as available with the distributions. So itis quite natural that stochastic orders will give a better methodof comparison than using means or variances. In literature,many different types of stochastic orders have been defined.Each stochastic order has its own importance for comparison.For example, usual stochastic order compares two reliabilityfunctions, hazard rate order compares two failure rate functions,reversed hazard rate order compares two reversed failure ratefunctions, whereas likelihood ratio order is used as a sufficientcondition for the above mentioned orders to hold. For modelingin terms of failure rate, one may refer to Finkelstein [21]. Thefollowing well known definitions may be obtained in Shakedand Shanthikumar [8].

Definition 1: Let and be two absolutely continuousrandom variables with respective supports and

, where and may be positive infinity, andand may be negative infinity.1. is said to be smaller than in likelihood ratio (lr) order,denoted as , if

for all measurable sets and such that , wheremeans that for all and , we have

. This can equivalently be written as

2. is said to be smaller than in hazard rate (hr) order,denoted as , if

which can equivalently be written as for all.

3. is said to be smaller than in reversed hazard rate (rhr)order, denoted as , if

which can equivalently be written as for all.

4. is said to be smaller than in the usual stochastic (st)order, denoted as , if

.Many applications of convolution operation are found in dif-

ferent areas of mathematics and engineering. It is of interest toknow whether different stochastic orders are preserved underconvolution. It is well known that the likelihood ratio orderis closed under convolution of independent random variablesif the random variables under consideration have log-concavedensity functions. Shanthikumar and Yao [20] have introducedshifted likelihood ratio order which is preserved under convolu-tion without log-concavity condition. Later, Lillo et al. [4] havedefined some other shifted stochastic orders. These orders arefrequently used to study different stochastic inequalities. Manyproperties of these orders are studied by different authors, viz.Nakai [26], Belzunce et al. [13], Lillo et al. [4], Hu and Zhu[9], and the references there-in. Below we give the formal def-initions of shifted stochastic orders (cf. Lillo et al. [4], Shakedand Shanthikumar [8], and Hu and Zhu [9]).Definition 2: Let and be two random variables as de-

fined above in Definition 1.1. is said to be smaller than in up shifted likelihood ratio(lr ) order, denoted as , if , for all

. This can equivalently be written as

for all .

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HAZRA AND NANDA: COMPONENT REDUNDANCY VERSUS SYSTEM REDUNDANCY IN DIFFERENT STOCHASTIC ORDERINGS 569

2. is said to be smaller than in down shifted likelihoodratio (lr ) order, denoted as , if

, for all , or equivalently, if

for all .3. is said to be smaller than in up shifted hazard rate(hr ) order, denoted as , if , forall , which can equivalently be written as

for all .4. is said to be smaller than in down shifted hazard rate(hr ) order, denoted as , if, for all , or equivalently, if

for all .5. is said to be smaller than in up shifted reversed hazardrate (rhr ) order, denoted as , if, for all , or equivalently, if

for all .In the following diagrams, we present a chain of implica-

tions of the stochastic orders (cf. Shaked and Shanthikumar [8],and Lillo et al. [4]). The first (resp. second) diagram showsthat the up (resp. down) shifted likelihood ratio order is themost strongest order, whereas the usual stochastic order is theweakest one, and other orders lie between these two orders.There is no relation between up and down shifted orders.

Like stochastic orders, stochastic precedence order is also a veryuseful tool to compare the lifetimes of two systems. To knowmore details about stochastic precedence order, see Singh andMisra [18], Boland and Singh and Cukic [24], and Romera andValdés and Zequeira [25]. Usual stochastic order does not al-ways imply stochastic precedence order. If the two random vari-ables are statistically dependent, then there is no implication be-tween usual stochastic order and stochastic precedence order.Definition 3: Let and be two absolutely continuous

random variables. Then, is said to be greater than in sto-chastic precedence (sp) order, denoted as , if

Design engineers always like to design systems which sat-isfy two basic requirements. First, each of the system’s compo-nents should have some contribution to run the system. Second,if we replace a failed component by good one, then the systemlife must increase. On the basis of these two fundamental con-siderations, design engineers created a term to specify such asystem, which is coherent system. Another well known systemis the -out-of- : system, which is a special type of coherentsystem. If there is no ambiguity, then we simply write it as a-out-of- system. Two extreme cases of the -out-of- systemare the -out-of- system, known as a series system, and the1-out-of- system, known as a parallel system. For definitionsof coherent systems and -out-of- systems, one may refer toBarlow and Proschan [5], and Samaniego [17].Let us consider a coherent system formed by components. Further, let be the state vector of , where

if the th component is working, and if it isnot working, at time . Without any loss of generality, we writein place of , for mathematical simplicity, when there is no

ambiguity. Then, the state of at time , is defined as

if the system is functioningif the system is failed,

and its reliability function is defined as the probability that it isworking at time . Thus,

If the components are statistically independent, then the systemreliability can bewritten as a function of component reliabilities,and hence

where , , and .We write in place of whenever components arestatistically identical. In contrast to the dichotomous statesystem as defined above, a multistate system is also possible;see, for instance, El-Neweihi et al. [15], and Zaitseva andLevashenko [16]. Further, let be the randomvariables representing the lifetimes of spares. Clearly,

represents the life of a coherentsystem with active (resp. standby) redundancy at the com-ponent level, whereas (resp. )represents that of a coherent system with active (resp. standby)redundancy at the system level.It is natural that the components and the spares may not be

identical. By matching spares, we mean that the distributionof the lifetime of a spare is identical with that of the corre-sponding original component; and if the spare and its corre-sponding original component do not have the same distribution,they are called non-matching spares. It is to be mentioned herethat most of the results discussed in this paper can be general-ized to any random variable with obvious modification.The rest of the paper is organized as follows. In Section II,

we discuss active redundancy. In Section II.A, all the results areproved for matching spares of iid components and iid spares.Weprove that, under some sufficient conditions, redundancy at the

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570 IEEE TRANSACTIONS ON RELIABILITY, VOL. 63, NO. 2, JUNE 2014

component level is superior to that at the system level with re-spect to the up shifted hazard rate, the up shifted reversed hazardrate, and the up shifted likelihood ratio orders, for any coherentsystem. In Section II.B, we talk about matching spares of notnecessarily iid components and spares. We prove that compo-nent redundancy is more reliable than system redundancy in upshifted hazard rate order, for series system. In Section II.C, wediscuss non-matching spares of iid components and iid spares.We give sufficient conditions under which component redun-dancy offers better reliability than system redundancy with re-spect to the up shifted reversed hazard rate order, for any co-herent system. In Section II.D, we discuss non-matching sparesof not necessarily iid components and iid spares. We prove thatredundancy at the component level is better than redundancy atthe system level with respect to the stochastic precedence order,for -out-of- systems. We also show that, under some suffi-cient conditions, this principle holds in the hazard and the re-versed hazard rate orders, for 2-out-of-2 systems. In Section III,we discuss standby redundancy. We show that component re-dundancy is more reliable than system redundancy in stochasticprecedence order, for -out-of- systems. In Section IV, wediscuss some simulation results. The work is summarized inSection V.Throughout the manuscript, when we write a function to be

increasing it means that the function may be constant in someparts of the domain and strictly increasing in other parts. Similarconvention is followed for a decreasing function.

II. ACTIVE REDUNDANCY

In this section, we discuss active redundancy. We show thatredundancy at the component level is more reliable than that atthe system level with respect to different stochastic orderings.

A. Matching Spares of IID Components and IID Spares

Gupta and Nanda [3] proved that, for a coherent system, com-ponent redundancy offers better reliability than system redun-dancy in reversed hazard rate order. In Theorem 1, we extentthis result for up shifted reversed hazard rate order. Below wegive two lemmas to be used in proving the theorem. The firstlemma is analogous to Theorem 6.19 of Lillo et al. [4]. Theproof is omitted.Lemma 1: Let and be two absolutely continuous random

variables with interval supports. If or have log-concavedistribution functions, and if , then .Lemma 2: Let be the reliability function of a coherent

system of iid components. Further, let components have log-concave distribution functions. If isincreasing in , then the lifetime of the coherent system has alog-concave distribution function.

Proof: Let the reliability function, and the probability den-sity function of a component having lifetime be , and

, respectively. Note that the reversed hazard rate of thecoherent system is given by .Again, we know that the lifetime of a system has a log-con-cave distribution function iff its reversed hazard rate function isdecreasing. Therefore, to prove the result, it suffices to show

that is decreasing in . Wesee that

Because is increasing in , it follows thatis decreasing in . Also,

from the hypothesis, we have is decreasingin . Hence, the result follows.Theorem 1 below shows that, under some sufficient condi-

tions, holds.Theorem 1: Let be iid component lifetimes,

and be those of iid spares, all having log-con-cave distribution functions. Further, let and be statisti-cally independent, and . Supposethat either or both of (a) or (b), and (c) hold.(a) for all .(b) is increasing in

.(c) is increasing in .

Then, .Proof: Because the conditions (a) and (c) hold, by The-

orem 3.2 of Gupta and Nanda [3] we have. If (b) holds, then also

(see, Theorem 3.2 of Misra et al. [2]). Further,has a log-concave distribution function because of Lemma 2.Hence, from Lemma 1, it follows that

.Remark 1: Note that condition (a) holds for a series system

where each component is a -out-of- subsystem, and at leastone subsystem consists of a single component (see, Remark 3.2of Gupta and Nanda [3]), whereas conditions (b) and (c) aresatisfied for any -out-of- system (see Corollary 3.2 of Misraet al. [2], and Corollary 2.1 of Nanda et al. [7]). Thus, the aboveresult is valid for -out-of- systems.The following counterexample shows that the log-concavity

condition given in Theorem 1 cannot be relaxed.Counterexample 1: Let , and be iid random

variables with cumulative distribution function given by

for

forfor ,

which is not log-concave. Note that, for ,

and

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HAZRA AND NANDA: COMPONENT REDUNDANCY VERSUS SYSTEM REDUNDANCY IN DIFFERENT STOCHASTIC ORDERINGS 571

Fig. 1. Plot of against (Counterexample 1).

Writing , weget

From Fig. 1, it is clear that is not monotone. Hence,.

That component redundancy for a coherent system is superiorto system redundancy in hazard rate order is shown by Bolandand El-Neweihi [1]. In the following theorem, we generalize thisresult for the up shifted hazard rate order. Below we give twolemmas to be used in proving the upcoming theorem. The firstlemma is taken from Lillo et al. [4].Lemma 3: Let and be two absolutely continuous random

variables with interval supports. If or have log-concavesurvival functions, and if , then .Lemma 4: Let be the reliability function of a coherent

system of iid components. Further, let components have log-concave survival functions. If is decreasing in ,then the lifetime of the coherent system has a log-concave sur-vival function.

Proof: Let the reliability function of a componenthaving lifetime be . Write for

. Because is positive and decreasingin , it follows that is increasing and concave in . Fur-ther, write , so that ,which is increasing and concave in . Now, differentiating

twice with respect to , we get

The inequality follows because is increasing and concaveas shown above, and is concave by the hypothesis. Thus,

is log-concave in .

In the following theorem, we prove that, under some suffi-cient conditions, .Theorem 2: Let be iid component lifetimes,

and be those of iid spares, all having log-con-cave survival functions. Further, let and be statisticallyindependent, and . Suppose that (a)or (b) or both, and (c) hold.(a) for all .(b) is increasing in

.(c) is decreasing in .

Then .Proof: Because the conditions (a) and (c) hold, by The-

orem 2 of Boland and El-Neweihi [1], we have. If (b) holds, then also

(see, Theorem 3.2 of Misra et al. [2]). Further, has alog-concave survival function because of Lemma 4. Hence, theresult follows from Lemma 3.Remark 2: In Remark 1, it is mentioned that condition (a)

holds for some special type of series system. The conditions (b)and (c) hold for any -out-of- system (see, Corollary 3.2 ofMisra et al. [2], and Barlow and Proschan [5, p. 109], respec-tively). Thus, the above result is valid for -out-of- systems.That Theorem 2 does not hold without the log-concavity con-

dition is verified by the following counterexample.Counterexample 2: Let , and be iid random

variables with survival functions given by, which is not log-concave. Now, we have

and

Writing , we get

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572 IEEE TRANSACTIONS ON RELIABILITY, VOL. 63, NO. 2, JUNE 2014

Fig. 2. Plot of against (Counterexample 2).

Fig. 3. Plot of against (Counterexample 3).

From Fig. 2, see that is not monotone in . Thus,.

The next counterexample shows that a result similar to The-orem 2 does not hold for down shifted hazard rate order even ifcomponents have log-convex survival functions.Counterexample 3: Let , and be iid random

variables with survival functions given by, which is log-convex. We see that

and

Writing , weget

Fig. 3 shows that is not monotone in . Hence,.

It is well known that the likelihood ratio order is stronger thanboth hazard and reversed hazard rate orders. Again, up shiftedlikelihood ratio order implies likelihood ratio order. Misra et al.[2] proved that for a coherent system, component redundancy ismore reliable than system redundancy in likelihood ratio orderunder certain conditions. In the following theorem we show thatthis principle holds for up shifted likelihood ratio order. Beforegoing to the details of the next theorem, we give two lemmas.The first lemma is taken from Lillo et al. [4]. The proof of thesecond lemma, although done by us, comes from an idea due toBelzunce et al. ([12], Theorem 6.4).Lemma 5: Let and be two absolutely continuous random

variables with interval supports. If or or both have log-concave densities, and if , then .Lemma 6: Let be the reliability function of a coherent

system of iid components. Further, let components have log-concave densities. If there exists a point such that

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HAZRA AND NANDA: COMPONENT REDUNDANCY VERSUS SYSTEM REDUNDANCY IN DIFFERENT STOCHASTIC ORDERINGS 573

(a) is decreasing and positive for all ,and

(b) is decreasing and negative for all,

then the lifetime of the coherent system has log-concave density.Proof: Let the reliability function, the probability density

function, the hazard rate function, and the reversed hazard ratefunction of a component having lifetime be , ,

, and , respectively. Note that the lifetime of the co-herent system has log-concave density iff

or equivalently,

Now, we see that

(1)

(2)

Because is concave, it implies that

(3)

Again, is increasing in , and is decreasing inbecause is concave in (see Lemma 5.8 of Barlowand Proschan [5], and Proposition 1(e) of Sengupta and Nanda[6]). Let us consider the following two cases.

Case I: Let . Because condition (a) holds, it fol-lows that is increasing and posi-tive for all . Therefore,

(4)

Hence, from (3) and (4), we get that

Thus, the result follows from (1).Case II: Let . Then,

is increasingand negative for all because condition (b) holds. Therefore,

(5)Hence, from (3) and (5), we have that

Thus, the result follows from (2).Theorem 3 below shows that, under some sufficient condi-

tions, .Theorem 3: Let be iid component lifetimes,

and be those of iid spares, all having log-con-cave densities. Further, let and be statistically indepen-dent, and . Suppose three conditionshold.(a) is increasing in

, and for some point ,(b) is decreasing and positive for all ,

and(c) is decreasing and negative for all

.Then .

Proof: Becauseis increasing in , by Theorem 3.2 of Misra et al. [2] we have

. Again, has a log-con-cave density because of Lemma 6. Hence, from Lemma 5, itfollows that .Remark 3: It is to be noted that all the conditions (a), (b),

and (c) given in Theorem 3 are satisfied by a -out-of- system(cf. Corollary 3.2 of Misra et al. [2], and proof of Corollary 6.6of Belzunce et al. [12]).In the following counterexample, we show that Theorem 3

does not hold without the log-concavity condition.Counterexample 4: Let , and be iid

random variables with probability density, which is not log-concave. Note

that, for ,

and

Writing , wehave

From Fig. 4, it is clear that is not monotone in .Hence, .One may wonder whether a result analogous to Theorem 3

holds for down shifted likelihood ratio order. We answer thisquestion in negative through the following counterexample.Counterexample 5: Let , and be iid random

variables with survival functions given by. Clearly, , 2, have log-convex

densities. Note that, for ,

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574 IEEE TRANSACTIONS ON RELIABILITY, VOL. 63, NO. 2, JUNE 2014

Fig. 4. Plot of against (Counterexample 4).

and

Writing we get,see the equation at the bottom of the page. From Fig. 5, it isclear that is not monotone in . Hence,

.

B. Matching Spares of Not Necessarily IID Components andIID Spares

Boland and El-Neweihi [1] have shown that, in the case ofa series system, component redundancy is better than systemredundancy in hazard rate order. In the next theorem, we gener-alize this result for up shifted hazard rate order. Below we givea well known lemma without proof to be used in proving thenext theorem.Lemma 7: If the components of a series system have sta-

tistically independent lifetimes with log-concave survival func-tions, then the system lifetime will have a log-concave survivalfunction.Theorem 4: Let be statistically independent

component lifetimes, and be those of statisticallyindependent spares, all having log-concave survival functions.Further, let and be statistically independent, and

. Then .Proof: Note that, for each ,

has a log-concave survival function (cf. Theorem 4.1(a)of Nanda and Shaked [10]). Then, from Lemma 7, it fol-lows that has a log-concave survival function.

Further, we have(cf. Theorem 1 of Boland and El-Neweihi [1]). Therefore,

which follows fromLemma 3.Remark 4: From Counterexample 2, it is clear that the

log-concavity condition given in Theorem 4 cannot be relaxed,whereas Counterexample 3 shows that a result similar toTheorem 4 does not hold for down shifted hazard rate order.

C. Non-Matching Spares of IID Components and IID Spares

Gupta and Nanda [3] proved that, for 2-componentnon-matching spares of iid components and iid spares, compo-nent redundancy is more reliable than system redundancy inreversed hazard rate order. Later, Misra et al. [2] generalize thisresult for a coherent system. We know that up shifted reversedhazard rate order is stronger than reversed hazard rate order.Thus, a natural question raises, which is whether the resultholds for up shifted reversed hazard rate order. We answer thisquestion in affirmative in the following theorem. But beforestating the next theorem, we give a lemma which is taken fromSengupta and Nanda [6] to be used in proving the next theorem.Lemma 8: Let be the reliability function of a coherent

system of iid components. Further, let components have log-concave distribution functions. If is decreasing in, then the lifetime of the coherent system has a log-concavedistribution function.Theorem 5: Let be iid component lifetimes,

and be those of iid spares, all having log-con-cave distribution functions. Further, let and be statisti-cally independent, . Suppose that conditions (a)or (b), and (c) hold.(a) is decreasing in ,

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HAZRA AND NANDA: COMPONENT REDUNDANCY VERSUS SYSTEM REDUNDANCY IN DIFFERENT STOCHASTIC ORDERINGS 575

Fig. 5. Plot of against (Counterexample 5).

(b) is increasing in ,(c) for any fixed , is

decreasing in .Then .

Proof: Because, for any ,is decreasing in , by Theorem 3.1

of Misra et al. [2], we have .Again, both and have log-concave distributionfunctions because of Lemma 8 (or Lemma 2). Consequently,

has a log-concave distribution function (seeTheorem of Sengupta and Nanda [6]). Therefore, fromLemma 1, it folows that .Remark 5: Note that, for any -out-of- system, all the con-

ditions (a), (b), and (c) of Theorem 5 are validated (cf. Barlowand Proschan [5] on p.109, Corollary 2.1 of Nanda et al. [7],and Corollary 3.1 of Misra et al. [2]).Remark 6: From Counterexample 1, it is seen that the log-

concavity condition given in Theorem 5 cannot be removed.

D. Non-Matching Spares of Not Necessarily IID Componentsand IID Spares

We are well aware that redundancy at the component levelis always superior to that at the system level in usual stochasticorder, for coherent systems (cf. Barlow and Proschan [5, p. 23]).In Theorem 6, we show that the same principle holds in sto-chastic precedence order, for -out-of- systems.Theorem 6: Let be component lifetimes, and

be those of spares. Further, let and ,, be statistically independent. Then

and

Proof: Let , andbe the state vectors of , and ,

respectively. We show that

(6)

is never possible. To see this result, note that (6) holds iff

Or equivalently, one of the following three systems of equationsholds.

Or equivalently, one of the following three systems of inequal-ities is satisfied.

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576 IEEE TRANSACTIONS ON RELIABILITY, VOL. 63, NO. 2, JUNE 2014

where for all . It is easy to seethat none of the above three systems has any solution. Thus,

(7)

One may wonder whetheris also zero. Below we

show that this is not the case always. Note that the inequality

holds iff

or equivalently,

or equivalently, the following system of inequalities is satisfied.

where for all . One can easilyverify that the above system has a solution except for .Thus,

(8)

and for ,

(9)

Therefore, on using (7), (8), and (9), we have

where the equality holds for . Hence, the result follows.In Example 1 of Boland and El-Neweihi [1], it is mentioned

that in the case of nonmatching spares, the above result may nothold for hazard rate order. This result motivates us to investigatewhether the result holds under some conditions. In the followingtheorem, we show that, for a 2-out-of-2 system, this result holdsunder certain conditions.Theorem 7: Let , and be the lifetimes of the compo-

nents; and let , and be the lifetimes of the respective spares.

Further, let and be statistically independent, , 2.Suppose that one of the following conditions holds.(a) and ,(b) and .Then .

Proof: We prove the result under (a). The result under (b)follows similarly. We see that

and

Writing , we get theequation at the bottom of the page. Differentiating withrespect to , and performing some algebraic calculations, we get

To prove , it suffices to show that

(10)

and

(11)

Note that

(12)

and from condition (a), we have

(13)

and

(14)

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HAZRA AND NANDA: COMPONENT REDUNDANCY VERSUS SYSTEM REDUNDANCY IN DIFFERENT STOCHASTIC ORDERINGS 577

Fig. 6. Plot of against (Counterexample 6).

Therefore, on using (12), (13), and (14), we get

which proves (10). Further, one can verify that

(15)

Because , and , we have

(16)

and

(17)

Therefore, on using (15), (16), and (17), we get

which proves (11). So, for all . Thus,.

As a consequence of Theorem 7, we have the following corol-lary which is given in Boland and El-Neweihi [1].Corollary 1: If , and , then

.The following example illustrates the result given in Theorem

7.Example 1: Let , and be statistically inde-

pendent random variables having distributions respectively, , ,

and , , where , and . Notethat , and . Thus, from Theorem 7, itfollows that .The following counterexample shows that conditions

and given in Theorem 7 cannot bedropped.

Counterexample 6: Let , and be statisticallyindependent random variables with hazard rates , re-spectively. It is clear that , and . Notethat

Writing , we get

which is not monotone as Fig. 6 shows. Thus,.

In the case of 2-component non-matching spares of iid com-ponents and iid spares, Gupta and Nanda [3] proved that com-ponent redundancy is more reliable than system redundancy inreversed hazard rate order. Then a natural question arises, whichis whether this result holds for not necessarily iid componentsand spares. Below, we cite a counterexample which answers thisquestion in negative.Counterexample 7: Let , and be statistically

independent random variables with survival functions given by; ;and ,

respectively. Note that

and

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578 IEEE TRANSACTIONS ON RELIABILITY, VOL. 63, NO. 2, JUNE 2014

Fig. 7. Plot of against (Counterexample 7).

Writing , we get

From Fig. 7, it is seen that is not monotone in .Hence, .Counterexample 7 motivates us to find some sufficient con-

ditions under which component redundancy offers better relia-bility than system redundancy in reversed hazard rate order. Inthe following theorem, we prove a result for 2-component non-matching spares of not necessarily iid components and spares.Theorem 8: Let , and be the lifetimes of the compo-

nents; and let , and be the lifetimes of the respective spares.Further, let and be statistically independent, , 2.Suppose that one of the following conditions holds.(a) and .(b) and .Then .

Proof: We prove the result under (a), and it follows simi-larly under (b). We see that

and

Writing , we get theequation at the bottom of the page. Differentiating the aboveexpression with respect to , an extensive algebra shows that

To prove , it suffices to show that

(18)

and

(19)

Note that

(20)

Because , and , it gives

(21)

and

(22)

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HAZRA AND NANDA: COMPONENT REDUNDANCY VERSUS SYSTEM REDUNDANCY IN DIFFERENT STOCHASTIC ORDERINGS 579

Fig. 8. Plot of against (Counterexample 8).

Therefore, on using (20), (21), and (22), we have

which proves (18). Further,

(23)

Because , we get

(24)

Further, implies

(25)

Therefore, on using (23), (24), and (25), we get

which proves (19). Hence, for all . Thus,.

The following corollary proved by Gupta and Nanda [3] di-rectly follows from Theorem 8.Corollary 2: If , and , then

.The illustration of Theorem 8 is revealed through the fol-

lowing example.Example 2: Let , and be statistically inde-

pendent random variables having distributions respectively, , ,

and , , where , and . Notethat , and . Thus,

follows from Theorem 8.

The following counterexample shows that the conditionsand given in Theorem 8 cannot be

relaxed.Counterexample 8: Let , and be statistically in-

dependent random variables with cumulative distribution func-tions given by

for

forfor ,

for

forfor ,

and

It is easy to verify that , and .Note that, for , we have, by writing

,

Fig. 8 shows that is not monotone. Thus,.

III. STANDBY REDUNDANCY

In the case of standby redundancy, Boland and El-Neweihi[1] showed that component redundancy is more reliable thansystem redundancy in the usual stochastic order for series sys-tems, whereas the reverse principle holds for parallel systems.Below in Theorem 9 we prove that component redundancy

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580 IEEE TRANSACTIONS ON RELIABILITY, VOL. 63, NO. 2, JUNE 2014

offers better reliability than system redundancy in stochasticprecedence order, for -out-of- systems.Theorem 9: Let be component lifetimes, and

be those of spares. Further, let and ,, be statistically independent. Then

and

Proof: Let , andbe the state vectors of , and ,

respectively. We show that

(26)

is never possible. To see this result, note that (26) holds iff

and

Or equivalently, one of the following two systems of equationsholds.

Or equivalently, one of the following two systems of inequalitiesis satisfied.

where , and for all. It is easy to see that the above two sys-

tems do not have any solutions. Thus,

(27)

One may think that isalso zero. Below we show that this is not the case always. Notethat the inequality

holds iff

or equivalently,

or equivalently, the following system holds, for all, and , .

One can easily verify that the above system has a solution exceptfor . Thus,

(28)

and for ,

(29)

Therefore, on using (27), (28), and (29), we have

where the equality holds for . Hence, the result follows.

IV. DATA ANALYSIS

The result in Theorem 7 is described through simulationby analyzing a data set as detailed below. Similar kinds ofdata analysis could be done for the other results as well. Wedraw samples for , and , each of size 500,000,respectively from , ,

, and . We call thesamples , and , for ,respectively. Note that the conditions given in (a) of The-orem 7 are satisfied by the concerned random variables.Now, we calculate the lifetimes of the systems wherecomponent redundancy, and system redundancy are used;the lives being denoted by , and , respectively. Thus,we have , and

, for each . Then, wesort and together, and corresponding empirical reliabilityfunctions and are calculated. Further, by plotting

against , we get an increasing curve,which is shown in Fig. 9. The small deviation in the mono-tonicity, as one can see in the depicted figure, occurs only dueto sampling fluctuation.

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HAZRA AND NANDA: COMPONENT REDUNDANCY VERSUS SYSTEM REDUNDANCY IN DIFFERENT STOCHASTIC ORDERINGS 581

Fig. 9. Plot of against (Data Analysis).

V. CONCLUSION

In this paper, we consider the problem of active redundancyas well as standby redundancy allocation at component levelversus system level. We mainly concentrate our discussionon active redundancy. We give sufficient conditions underwhich active redundancy at the component level is superiorto that at the system level with respect to the hazard rate, thereversed hazard rate, the up shifted hazard rate, the up shiftedreversed hazard rate, and the up shifted likelihood ratio orders,for different types of systems. We also show that this principleholds in stochastic precedence order, for -out-of- systems.In addition to this, we show that standby redundancy at thecomponent level is more reliable than that at the system levelwith respect to the stochastic precedence order, for -out-of-systems. We also verify the results through data analysis. Eachstochastic order has its individual importance; for example,usual stochastic order compares two reliability functions,whereas hazard rate order compares the failure rates of twosystems. The usefulness of redundancy is seen in day-to-daylife. The electric inverter is one such example. To see moreimportant use of redundancy let us think of the shadowlesslamp used in the operation table where the redundancy is soimportant that the censoring and switching device is installedto instantaneously activate the redundant component or systemused. This case illustrates the usefulness of the redundancy inpractical life problems. As a result, our observations may behelpful to different groups of people, say for example to designengineers and reliability analysts to decide on the effective useof redundancy depending on the underlying situation.

ACKNOWLEDGMENT

The authors are thankful to the Associate Editor and anony-mous Reviewers for their valuable constructive commentswhich lead to an improved version of the manuscript. Theauthors are also thankful to Dr. S. Mazumder of IISER Kolkatafor some stimulating discussion.

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Nil Kamal Hazra is a PhD student with the Department of Mathematics andStatistics, Indian Institute of Science Education and Research (IISER) Kolkata.He has completed his BSc (Mathematics Honors), and MSc (Applied Mathe-matics) from Vidyasagar University, India.

Asok K. Nanda is a Professor with the Department of Mathematics and Statis-tics, Indian Institute of Science Education and Research (IISER) Kolkata. Hehas completed his BSc (Statistics Honors), and MSc (Statistics) from CalcuttaUniversity. He has obtained his PhD degree from Panjab University, Chandi-garh, India. His Post-doc is from the University of New Brunswick, Canada. Hewas Lecturer with the Department of Statistics, at Panjab University, Chandi-garh, India; and Assistant Professor with the Department of Mathematics, at In-dian Institute of Technology, Kharagpur, India. He was also visiting faculty withthe Department of Mathematics, University of Arizona, USA. He has publishedaround 70 papers on Reliability Analysis in different journals of internationalrepute. He is a regular reviewer of Mathematical Reviews of American Math-ematical Society. He is also an Associate Editor of the journals Statistics andProbability Letters, Journal of Indian Statistical Association, Communicationsin Statistics-Theory and Methods, and Communications in Statistics-Simulationand Computation.