contemporary engineering economics, 4 th edition, © 2007 interest formulas (gradient series)...
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![Page 1: Contemporary Engineering Economics, 4 th edition, © 2007 Interest Formulas (Gradient Series) Lecture No.8 Chapter 3 Contemporary Engineering Economics](https://reader035.vdocuments.net/reader035/viewer/2022062304/56649d225503460f949f7517/html5/thumbnails/1.jpg)
Interest Formulas(Gradient Series)
Lecture No.8Chapter 3Contemporary Engineering EconomicsCopyright © 2006
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Linear Gradient Series
P Gi i iN
i i
G P G i N
N
N
LNM
OQP
( )
( )
( / , , )
1 1
12
P
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Gradient Series as a Composite Series of a Uniform Series of N Payments of A1 and the Gradient Series of Increments of Constant Amount G.
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$1,000$1,250 $1,500
$1,750$2,000
1 2 3 4 50
P =?
How much do you have to deposit now in a savings account that earns a 12% annual interest, if you want to withdraw the annual series as shown in the figure?
Example – Present value calculation for a gradient series
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Method 1: Using the (P/F, i, N) Factor
$1,000$1,250 $1,500
$1,750$2,000
1 2 3 4 50
P =?
$1,000(P/F, 12%, 1) = $892.86$1,250(P/F, 12%, 2) = $996.49$1,500(P/F, 12%, 3) = $1,067.67$1,750(P/F, 12%, 4) = $1,112.16$2,000(P/F, 12%, 5) = $1,134.85
$5,204.03
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Method 2: Using the Gradient Factor
P P G2 12%,5
599 20
$250( / , )
$1, .P
$3, . $1, .
$5,204
604 08 599 20
P P A1 000 12%,5
604 80
$1, ( / , )
$3, .
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Gradient-to-Equal-Payment Series Conversion Factor, (A/G, i, N)
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Example 3.21 – Find the Equivalent Uniform Deposit Plan
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Solution:
1Given : $1,000, $300, 10%,and, 6
Find :
$1,000 $300( / ,10%,6)
$1,000 $300(2.22236)
$1,667.08
A G i N
A
A A G
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Example 3.22 Declining Linear Gradient Series
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Solution:
1 2
Equivalent Present Worth at = 0
1( / ,10%,5) $200( / ,10%,5) ( / ,10%,5)
$1,200(6.105) $200(6.862)(1.611)
$5,115
n
F F F
A F A P G F P
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Types of Geometric Gradient Series
0g
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Present Worth Factor
P Ag i
i gi g
NA i i g
N N
LNM
OQP
RS|T|
1
1
1 1 1
1
( ) ( )
/ ( ),
, if
if
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Example 3.23 Annual Power Cost if Repair is Not Performed
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Solution – Adopt the new compressed-air system
5 51 (1 0.07) (1 0.12)$54,440
0.12 0.07
$222,283
$54,440(1 0.23)( / ,12%,5)
$41,918.80(3.6048)
$151,109
Old
New
P
P P A
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Example 3.24 Jimmy Carpenter’s Retirement Plan – Save $1 Million
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What Should be the Size of his first Deposit (A1)?
20 20
20 1
1
1
1 (1 0.06) (1 0.08)
0.08 0.06
(72.6911)
$1,000,000
$1,000,000
72.6911$13,757
F A
A
A