convert to gas vol vol = moles * 22.4 convert to particles particles = moles * 6.02 * 10 23 convert...

CONVERT TO GAS VOL VOL = MOLES * 22.4

CONVERT TO PARTICLES

PARTICLES = MOLES * 6.02 * 1023

CONVERT TO MOLES VOLUME = MOLES/ M

RECOGNIZE: MASSGIVEN IS A MASS IN GRAMS, ANY PHASE.

RECOGNIZE:STP GAS

GIVEN IS A GAS (g) VOLUME AT STP

RECOGNIZE

GIVEN IS IN PARTICLES (ATOMS OR MOLECULES)

RECOGNIZE:VOLUME AND MOLARITY

GIVEN IS AN AQUIOUS SOLUTION (aq)

CONVERT TO MOLES

MOLES = MASS/GFM

CONVERT TO MOLES MOLES =VOL(L)/22.4L

CONVERT TO MOLES

MOLES = PARTICLES 6.02 * 1023

RATIO MOLES GIVEN TO MOLES OBJECTIVE TO SOLVE FOR MOLES OF OBJECTIVEUSE COEFFICIENT OF BALANCED REACTION

CONVERT TO MOLES MOLES =VOLUME * M

CONVERT TO MASS MASS = MOLES * GFM

STEP ONE: CONVERT KNOWN TO MOLES.

STEP TWO: MOLE RATIO

STEP THREE: CONVERT OBJECTIVE TO UNITS.

CALCULATE THE YEILD OF NH3 in grams IF 8 GRAMS OF H2 REACTS COMPLETLEY WITH EXCESS NITROGEN.

N2 + 3H2 2NH3





RECOGNIZE:

GIVEN IS A MASS IN GRAMS, ANY PHASE.

RECOGNIZE


RECOGNIZEGIVEN IS IN PARTICLES (ATOMS OR MOLECULES)

RECOGNIZE


CONVERT TO MOLES

MOLES = MASS/GFM


CONVERT TO MOLES








STEP 1 Identify known (the substance that can be converted to moles), choose the correct equation to convert to moles. In this problem 8.0 grams of H2 is a given mass.

CALCULATE THE YEILD OF NH3 in grams IF 8.0 GRAMS OF H2 REACTS COMPLETLEY WITH EXCESS NITROGEN.

N2 + 3H2 2NH3

MOLES = MASS/GFM MOLES = 8.00g/ 2.0 g/mol MOLES = 4.0 mol

STEP 2 RATIO known to objective, use reaction coefficients to compare H2 known) to NH3 (objective).

H2 = 3 = 4.0 mol , NH3 2 X X = 2.66 mol NH3

STEP 3 Convert Objective to required units. Convert ammonia from MOLES to GRAMS.

MOLES = MASS/GFM 2.66 = MASS/ 17.0 g/mol MASS = 45. g

CALCULATE THE REQUIRED VOLUME OF H2 GAS AT STP TO PRODUCE 40 GRAMS OF NH3?

N2 + 3H2 2NH3





RECOGNIZE:


RECOGNIZE



RECOGNIZE


CONVERT TO MOLES

MOLES = MASS/GFM


CONVERT TO MOLES








CALCULATE THE REQUIRED VOLUME OF H2 GAS AT STP TO PRODUCE 40.0 GRAMS OF NH3?

N2 + 3H2 2NH3

STEP 1 Identify known (the substance that can be converted to moles), choose the correct equation to convert to moles. In this problem 40 grams of NH3 is a given mass.

MOLES = MASS/GFM MOLES = 40.0g/ 17.0 g/mol MOLES = 2.352 mol NH3


H2 = 3 = X , NH3 2 2.352 X = 3.528 mol H2

STEP 3 Convert Objective to required units. Convert hydrogen from MOLES to STP gas Volume.. VOLUME = MOLES * 22.4L V = 3.528 mol H2 * 22.4L /mol V = 79.03 L

CALCULATE THE MASS OF HYDROGEN REQUIRED TO PRODUCE 67.2 L OF AMMONIA AT STP.

N2 + 3H2 2NH3





RECOGNIZE:


RECOGNIZE



RECOGNIZE


CONVERT TO MOLES

MOLES = MASS/GFM


CONVERT TO MOLES








STEP 3 Convert Objective to required units. Convert hydrogen from MOLES to MASS.

STEP 1 Identify known (the substance that can be converted to moles), choose the correct equation to convert to moles. In this problem 67.2 L OF AMMONIA IS GIVEN(KNOWN) GAS VOLUME.

MOLES = MASS/GFM 4.5 MOLES = MASS/ 2.0 g/mol MASS = 9.00 GRAMS H2


H2 = 3 = X , NH3 2 3 X = 4.50 mol H2

VOLUME = MOLES * 22.4L 67.2 = mol NH3 * 22.4L /mol MOL NH3 = 3

CALCULATE THE MASS OF HYDROGEN REQUIRED TO PRODUCE 67.2 L OF AMMONIA AT STP.

N2 + 3H2 2NH3

CALCULATE THE REQUIRED VOLUME OF N2 GAS AT STP TO PRODUCE 12.04 * 1023 MOLECULES OF

NH3?

N2(g) + 3H2(g) 2NH3(g)





RECOGNIZE:


RECOGNIZE



RECOGNIZE


CONVERT TO MOLES

MOLES = MASS/GFM


CONVERT TO MOLES








CALCULATE THE REQUIRED VOLUME OF N2 GAS AT STP TO PRODUCE 12.04 * 1023 MOLECULES OF NH3?

N2(g) + 3H2(g) 2NH3(g)

STEP 1 Identify known (the substance that can be converted to moles), choose the correct equation to convert to moles. In this problem 12.04 * 1023 MOLECULES (PARTICLES) OF NH3 IS THE KNOWN.

MOL= PART/6.02*1023 MOL=12.04*1023 / 6.02*1023 MOLES = 2.000 MOL NH3

STEP 2 RATIO known to objective, use reaction coefficients to compare N2 known) to NH3 (objective).

N2 = 1 = X , NH3 2 2.000 X = 1.000 mol N2

STEP 3 Convert Objective to required units. Convert hydrogen from MOLES to STP gas Volume.. VOLUME = MOLES * 22.4L V = 1.000 mol H2 * 22.4L /mol V = 22.40 L

convert to gas vol vol = moles * 22.4 convert to particles particles = moles * 6.02 * 10 23 convert...

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