copyright © 2013 pearson education, inc. section 2.4 formulas
TRANSCRIPT
Copyright © 2013 Pearson Education, Inc.
Section 2.4
Formulas
Example
A residential lot is shown.Find the area of this lot.SolutionThe area of the rectangle:
The area of the triangle:
Total area = 76,260 + 21,576 = 97,836 square feet.
205 ft
372 ft
116 ft
RA LW372 205RA 76,260 square feetRA
12TA bh
12 116 372TA 21,576 square feetTA
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Example
32033 wwww
A rectangular swimming pool is three times as long as it is wide. If the perimeter of the pool is 320 feet, what are the pool’s dimensions.?
Divide 8
Length is 3 times 40 length= 120
3w
wP=2w+2l
32062 ww
3208 w
40w
Example
In a triangle, the smaller angles are equal in measure and are one-third of the largest angle. Find the measure of each angle.SolutionLet x represent the measure of each of the two smaller angles. Then the measure of the largest angle is 3x, and the sum of the measures of the three angles is given by
3 180x x x
5 180x
5 180
5 5
x
36x
The measure of the largest angle is 3x, thus 36 ∙ 3 = 108°.
The measure of the three angles are 36°, 36°, and 108°.
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Find the volume and the surface area of the box shown.
SolutionThe volume of the box isV = lwhV = 12 ∙ 6 ∙ 5 V = 360 cm3
The surface area of the box is
Example
12 cm
6 cm
5 cm
2 2 2S LW WH LH 2(12)(5) 2(5)(6) 2(12)(6)S 120 60 144S 324 square centimetersS
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Example
Solve each equation for the indicated variable.a. b.
Solutiona.
Multiply by LCD which is 5
Subtract y
3 for 5
y zx z
for np nm nq p
3 5
y zx
15 x y z 15 x y z
15 z x y
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5 5..
Example
Solve each equation for the indicated variable.a. b.
Solutionb.
Subtract nm
GCF is n
Divide by GCF
3 for 5
y zx z
for np nm nq p
for np nm nq p
np nq nm
( )np n q m
( )n q mp
n
p q m
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Solving a Formula for a Variable
EXAMPLE
SOLUTION
Solve the formula y = mx + b for m
y = mx + b Think of m saying, “I really want to be alone.”
y – b = mx + b – b Subtract b from both sides.
y – b = mx Perform the addition. b – b = 0.
Divide both sides by x to find m.x
mx
x
by
mx
by
Solving a Formula for a Variable
543
yx
Solve for x
54443
yyyx
543
yx
)54(33
3 yx
1512 yx
)(2
1baA
Solve for length b
baA 2
)(2
122 baA
abaaA 2
baA 2
aAb 2
Other Formulas
To calculate a student’s GPA, the number of credits earned with a grade of A, B, C, D, and F must be known. If a, b, c, d, and f represent these credit counts respectively, then
4 3 2.
a b c dGPA
a b c d f
Slide 10
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Example
A student has earned 18 credits of A, 22 credits of B, 8 credits of C and 4 credits of D. Calculate the student’s GPA to the nearest hundredth.SolutionLet a = 18, b = 22, c = 8, d = 4 and f = 0
The student’s GPA is 3.04.
4 18 3 22 2 8 4
18 22 8 4 0GPA
158
52 3.04
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Example
The formula is used to convert degrees Fahrenheit to degrees Celsius. Use this formula to convert 23°F to an equivalent Celsius temperature.
Solution
59 32C F
= −5°C
532
9C F
25
329
3C
59
9C
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DONE
Objectives
• Formulas from Geometry
• Solving for a Variable
• Other Formulas
#20
#24
h
ha
h
hbA
2
Solving a Formula for a Variableproblem 20 on page 144
)(2
1bahA
Solve for a
Mult by 2 to remove 1/2
)(2 bahA
hbhaA 2
hbhbhahbA 2
hahbA 2
bh
A
h
hbAa
2or
2
1
3
Solving a Formula for a VariableCP 1, 3 on pages 136-137
wlA Divide by w
Solve for length l
Subtract D from both sides
Divide by p
w
lw
w
A
lw
A
pmDT
Solve for m
pmDDDT
pmDT
p
pm
p
DT
w
Al
p
DTm
Example
A tourist starts a trip with a full tank of gas and an odometer that reads 59,478 miles. At the end of the trip, it takes 8.6 gallons of gas to fill the tank, and the odometer reads 59,715 miles. Find the gas mileage for the car. SolutionThe distance traveled is 59,715 – 59, 478 = 237 miles and the number of gallons used is G = 8.6. Thus,
DM
G
6
237
8. 27.6 miles per gallon.
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Example
A cylindrical soup can has a radius of 2 ½ inches and a height of 5 5/8 inches. Find the volume of the can.
Solution h
r
2V r h2
45
8
5
2V
1125
32V
110.45 cubic inchesV
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