correlation & regression - 3 presentation - unitedworld school of business
TRANSCRIPT
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7/28/2019 Correlation & Regression - 3 Presentation - Unitedworld School of Business
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Correlation-Regression
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Methods of Measuring correlation
1. Graphic Method2. Diagramatic Method- Scatter Diagram
3. Algebraic method
a. Karl Pearsons Coefficient of correlationb. Spearmans Rank Co-efficient Correlationc. Coefficient of Concurrent deviations
d. Least Squares Method
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Karl Pearsons Coefficient of Correlation
dx dy ( Gamma) = -------------------------
dx2 dy2
dx dy= -------------------------
N xy
dx = x-xbardy = y- ybar
dx dy = sum of products of deviations from respective
arithmetic means of both series
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Karl Pearsons Coefficient of Correlation
After calculating assumed or working mean Ax & Ay dx dy ( dx) *( dy) ( Gamma) = --------------------------------
[ N dx2 - ( dx)2 * [ Ndy2 - ( dy)2 ]
dx dy = total of products of deviation from assumedmeans of x and y series
dx = total of deviations of x series dy = total of deviations of y series
dx2 = total of squared deviations of x series dy2 = total of squared deviations of y series
N= No. of items ( no. of paired items
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Karl Pearsons Coefficient of CorrelationAfter calculating assumed or working mean Ax &
Ay
dx x dy
dx dy - ----------------N
( Gamma) = -------------------------
( dx)2
( dy)2
[ dx2 - --------- ] x [ dy2 - ------------]N N
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Assumptions of Karl Pearsons Coefficient of Correlation
1. Linear relationship exists between the variablesProperties of Karl Pearsons Coefficient of Correlation1.value lies between +1 & - 1
2.Zero means no correlation
3. ( Gamma) = bxy X byxWhere bxy X byx are regression coefficicent
Merit
Convenient for accurate interpretation as it gives degree &
direction of relationship between two variables
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Limitations
1. Assumes linear relationship , even though itmay not be
2. Method & process of calculation is difficult &
time consuming3. Affected by extreme values in distribution
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Probable Error of Karl Pearsons Coefficient of
Correlation
1- 2
Probable Error of ( Gamma) = 0.6745 -------- N
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Q7.Calculate coefficient of correlation for following data
X65 63 67 64 68 62 70 66 68 67 69 71
Y 68 66 68 65 69 66 68 65 71 67 68 70
Ans dx dy ( Gamma) = ------------------------- dx2 dy2
dx dy= -------------------
N xy
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1 2 3 4 5 6 7 8 9 10 11 12
Su
mX Xbar
X 65 63 67 64 68 62 70 66 68 67 69 71 800 66.67
Y 68 66 68 65 69 66 68 65 71 67 68 70 811 67.58
dx=x-xbar -1.67 -3.67 0.33 -2.67 1.33 -4.67 3.33 -0.67 1.33 0.33 2.33 4.33
dx2 2.78 13.44 0.11 7.11 1.78 21.78 11.11 0.44 1.78 0.11 5.44 18.78
84.
67
dx.dy -0.69 5.81 0.14 6.89 1.89 7.39 1.39 1.72 4.56 -0.19 0.97 10.47
40.
33
dy=y-ybar 0.42 -1.58 0.42 -2.58 1.42 -1.58 0.42 -2.58 3.42 -0.58 0.42 2.42
dy2 0.17 2.51 0.17 6.67 2.01 2.51 0.17 6.67 11.67 0.34 0.17 5.84
38.
92
dx dysum dx2*
sumdy2
3294.
9
dx2 dy2 57.40
coeff of
correlation = 0.70
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Q8. following information about age of husbands
& wives. Find correlation coefficient
Husband
23 27 28 29 30 31 33 35 36 39
Wife 18 22 23 24 25 26 28 29 30 32
( Gamma) =0.99
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1 2 3 4 5 6 7 8 9 10
Sum
X Xbar
X 23 27 28 29 30 31 33 35 36 39 311 31.10
Y 18 22 23 24 25 26 28 29 30 32 257 25.70
dx=x-
xbar -8.10 -4.10 -3.10 -2.10 -1.10 -0.10 1.90 3.90 4.90 7.90
dx2 65.61 16.81 9.61 4.41 1.21 0.01 3.61 15.21 24.01 62.41
202.
9
dx.dy 62.37 15.17 8.37 3.57 0.77 -0.03 4.37 12.87 21.07 49.77
178.
3
dy=y-
ybar -7.70 -3.70 -2.70 -1.70 -0.70 0.30 2.30 3.30 4.30 6.30
dy2 59.29 13.69 7.29 2.89 0.49 0.09 5.29 10.89 18.49 39.69
158.
1
dx dy sum dx2* sumdy232078.
49
dx2 dy2 179.10
coeff of correlation
= 1.00
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Q9. ten competitors in a cooking competition are
ranked by three judges in the following way .byusing rank coorelation method find out which
pair of judges have nearest approach
Ans P&Q= -0.21 , Q &R=--0.3 P &R = +0.64
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Q9. ten competitors in a cooking competition are ranked
by three judges in the following way .by using rank
coorelation method find out which pair of judges havenearest approach
P Q R
1 1 3 6
2 6 5 43 5 8 9
4 10 4 8
5 3 7 1
6 2 10 27 4 2 3
8 9 1 10
9 7 6 5
10 8 9 7
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Rank coefficient of correlation
6 d2 (rho) = 1 - -------------------
N3-N
d2 = total of squared differenceN = number of items
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P Q R
Rp-
Rq dpq2
Rq-
Rr dqr2
Rp-
Rr dpr2
1 1 3 6 -2 4 -3 9 -5 25
2 6 5 4 1 1 1 1 2 4
3 5 8 9 -3 9 -1 1 -4 16
4 10 4 8 6 36 -4 16 2 4
5 3 7 1 -4 16 6 36 2 4
6 2 10 2 -8 64 8 64 0 0
7 4 2 3 2 4 -1 1 1 1
8 9 1 10 8 64 -9 81 -1 1
9 7 6 5 1 1 1 1 2 4
10 8 9 7 -1 1 2 4 1 1
1000 200 214 0 60
6Sigma d2 1200 1284 360
N3-N 990 6Sigma d2/N3-N 1.21 1.297 0.3636
P= -0.21 -0.297 0.636364
C O i
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Campus Overview
907/A Uvarshad,
Gandhinagar
Highway, Ahmedabad382422.
Ahmedabad Kolkata
Infinity Benchmark,
10th Floor, Plot G1,
Block EP & GP,
Sector V, Salt-Lake,
Kolkata700091.
Mumbai
Goldline Business Centre
Linkway Estate,
Next to Chincholi Fire
Brigade, Malad (West),
Mumbai400 064.
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Thank You