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CSC 9010: Special Topics, Natural Language Processing. Spring, 2005. Matuszek & Papalaskari 1 N-Grams CSC 9010: Special Topics. Natural Language Processing. Paula Matuszek, Mary-Angela Papalaskari Spring, 2005 Based on McCoy, http://www.cis.udel.edu/~mccoy/courses/cisc882.03f/lectures/lect5- ngrams.ppt/

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Page 1: CSC 9010: Special Topics, Natural Language Processing. Spring, 2005. Matuszek & Papalaskari 1 N-Grams CSC 9010: Special Topics. Natural Language Processing

CSC 9010: Special Topics, Natural Language Processing. Spring, 2005. Matuszek & Papalaskari 1

N-Grams

CSC 9010: Special Topics. Natural Language Processing.

Paula Matuszek, Mary-Angela Papalaskari

Spring, 2005

Based on McCoy, http://www.cis.udel.edu/~mccoy/courses/cisc882.03f/lectures/lect5-ngrams.ppt/

Page 2: CSC 9010: Special Topics, Natural Language Processing. Spring, 2005. Matuszek & Papalaskari 1 N-Grams CSC 9010: Special Topics. Natural Language Processing

CSC 9010: Special Topics, Natural Language Processing. Spring, 2005. Matuszek & Papalaskari 2

Free Association Exercise • I am going to say some phrases. Write down

the next word or two that occur to you.– Microsoft announced a new security ____– NHL commissioner cancels rest ____– One Fish, ______– Colorless green ideas ______– Conjunction Junction, what’s __________– Oh, say, can you see, by the dawn’s ______– After I finished my homework I went _____.

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Human Word Prediction• Clearly, at least some of us have the

ability to predict future words in an utterance.

• How?– Domain knowledge– Syntactic knowledge– Lexical knowledge

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Claim• A useful part of the knowledge needed

to allow Word Prediction can be captured using simple statistical techniques

• In particular, we'll rely on the notion of the probability of a sequence (a phrase, a sentence)

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CSC 9010: Special Topics, Natural Language Processing. Spring, 2005. Matuszek & Papalaskari 5

Applications• Why do we want to predict a word, given

some preceding words?– Rank the likelihood of sequences containing

various alternative hypotheses, e.g. for automated speech recognition, OCRing.

Theatre owners say popcorn/unicorn sales have doubled...

– Assess the likelihood/goodness of a sentence, e.g. for text generation or machine translation

Como mucho pescado. At the most fished.

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Real Word Spelling Errors• They are leaving in about fifteen minuets to go

to her house.• The study was conducted mainly be John Black.• The design an construction of the system will

take more than a year.• Hopefully, all with continue smoothly in my

absence.• Can they lave him my messages?• I need to notified the bank of….• He is trying to fine out.Example from Dorr, http://www.umiacs.umd.edu/~bonnie/courses/cmsc723-04/lecture-notes/Lecture5.ppt

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Language Modeling • Fundamental tool in NLP

• Main idea: – Some words are more likely than others to

follow each other– You can predict fairly accurately that

likelihood.

• In other words, you can build a language model

Adapted from Hearst, http://www.sims.berkeley.edu/courses/is290-2/f04/lectures/lecture4.ppt

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N-Grams• N-Grams are sequences of tokens.• The N stands for how many terms are used

– Unigram: 1 term– Bigram: 2 terms– Trigrams: 3 terms

• You can use different kinds of tokens– Character based n-grams– Word-based n-grams– POS-based n-grams

• N-Grams give us some idea of the context around the token we are looking at.

Adapted from Hearst, http://www.sims.berkeley.edu/courses/is290-2/f04/lectures/lecture4.ppt

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N-Gram Models of Language• A language model is a model that lets us

compute the probability, or likelihood, of a sentence S, P(S).

• N-Gram models use the previous N-1 words in a sequence to predict the next word– unigrams, bigrams, trigrams,…

• How do we construct or train these language models?– Count frequencies in very large corpora– Determine probabilities using Markov models,

similar to POS tagging.

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Counting Words in Corpora• What is a word?

– e.g., are cat and cats the same word?– September and Sept?– zero and oh?– Is _ a word? * ? ‘(‘ ?– How many words are there in don’t ?

Gonna ?– In Japanese and Chinese text -- how do we

identify a word?

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Terminology• Sentence: unit of written language• Utterance: unit of spoken language• Word Form: the inflected form that appears

in the corpus• Lemma: an abstract form, shared by word

forms having the same stem, part of speech, and word sense

• Types: number of distinct words in a corpus (vocabulary size)

• Tokens: total number of words

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Simple N-Grams• Assume a language has V word types in its

lexicon, how likely is word x to follow word y?– Simplest model of word probability: 1/ V– Alternative 1: estimate likelihood of x occurring in

new text based on its general frequency of occurrence estimated from a corpus (unigram probability)

popcorn is more likely to occur than unicorn

– Alternative 2: condition the likelihood of x occurring in the context of previous words (bigrams, trigrams,…)

mythical unicorn is more likely than mythical popcorn

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Computing the Probability of a Word Sequence

• Compute the product of component conditional probabilities?– P(the mythical unicorn) = P(the) P(mythical|the)

P(unicorn|the mythical)

• The longer the sequence, the less likely we are to find it in a training corpus

P(Most biologists and folklore specialists believe that in fact the mythical unicorn horns derived from the narwhal)

• Solution: approximate using n-grams

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Bigram Model• Approximate by

– P(unicorn|the mythical) by P(unicorn|mythical)

• Markov assumption: the probability of a word depends only on the probability of a limited history

• Generalization: the probability of a word depends only on the probability of the n previous words– Trigrams, 4-grams, …– The higher n is, the more data needed to train– The higher n is, the sparser the matrix.

• Leads us to backoff models

)11|( nn wwP )|( 1nn wwP

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• For N-gram models–

– P(wn-1,wn) = P(wn | wn-1) P(wn-1)

– By the Chain Rule we can decompose a joint probability, e.g. P(w1,w2,w3)

P(w1,w2, ...,wn) = P(w1|w2,w3,...,wn) P(w2|w3, ...,wn) … P(wn-1|wn) P(wn)

For bigrams then, the probability of a sequence is just the product of the conditional probabilities of its bigrams

P(the,mythical,unicorn) = P(unicorn|mythical) P(mythical|the) P(the|<start>)

Using N-Grams

)11|( nn wwP )1

1|(

nNnn wwP

n

kkkn wwPwP

111 )|()(

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A Simple Example– P(I want to eat Chinese food) =

P(I | <start>) * P(want | I)

P(to | want) * P(eat | to)

P(Chinese | eat) * P(food | Chinese)

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Counts from the Berkeley Restaurant Project

Nth term

N-1 term

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BeRP Bigram Table

Nth term

N-1 term

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A Simple Example– P(I want to eat Chinese food) =

P(I | <start>) * P(want | I)

P(to | want) * P(eat | to)

P(Chinese | eat) * P(food | Chinese)

•.25*.32*.65*.26*.02*.56 = .00015

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• P(I want to eat British food) = P(I|<start>) P(want|I) P(to|want) P(eat|to) P(British|eat) P(food|British) = .25*.32*.65*.26*.001*.60 = .000080

• vs. I want to eat Chinese food = .00015

• Probabilities seem to capture ``syntactic'' facts, ``world knowledge'' – eat is often followed by an NP– British food is not too popular

So What?

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What do we learn about the language?

• What's being captured with ...– P(want | I) = .32 – P(to | want) = .65– P(eat | to) = .26 – P(food | Chinese) = .56– P(lunch | eat) = .055

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What About These?• What about...

– P(I | I) = .0023– P(I | want) = .0025– P(I | food) = .013

• BeRP is a testbed for speech recognition.• We are getting:

– P(I | I) = .0023 I I I I want – P(I | want) = .0025 I want I want– P(I | food) = .013 the kind of food I want is ...

• In other words, our corpus includes disfluencies. Bad choice if we wanted to process text!

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Approximating Shakespeare• As we increase the value of N, the accuracy of the n-

gram model increases, since choice of next word becomes increasingly constrained

• Generating sentences with random unigrams...– Every enter now severally so, let– Hill he late speaks; or! a more to leg less first you enter

• With bigrams...– What means, sir. I confess she? then all sorts, he is trim,

captain.– Why dost stand forth thy canopy, forsooth; he is this

palpable hit the King Henry.

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• Trigrams– Sweet prince, Falstaff shall die.– This shall forbid it should be branded, if

renown made it empty.

• Quadrigrams– What! I will go seek the traitor Gloucester.– Will you not tell me who I am?

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• There are 884,647 tokens, with 29,066 word form types, in about a one million word Shakespeare corpus

• Shakespeare produced 300,000 bigram types out of 844 million possible bigrams: so, 99.96% of the possible bigrams were never seen (have zero entries in the table)

• Quadrigrams worse: What's coming out looks like Shakespeare because it is Shakespeare

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N-Gram Training Sensitivity• If we repeated the Shakespeare

experiment but trained our n-grams on a Wall Street Journal corpus, what would we get?

• This has major implications for corpus selection or design

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Some Useful Empirical Observations• A few events occur with high frequency• Many events occur with low frequency• You can quickly collect statistics on the high

frequency events• You might have to wait an arbitrarily long time

to get valid statistics on low frequency events• Some of the zeroes in the table are really

zeros But others are simply low frequency events you haven't seen yet. How to address?

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Zipf’s Law

George Kingsley Zipf (1902-1950) noted that for many frequency distributions, the n-th largest frequency is proportional to a negative power of the rank order n.

Let t range over the set of unique events. Let f(t) be the frequency of t and let r(t) be its rank. Then:

t r(t) c * f(t)-b for some constants b and c.•Applies to a surprising range of things.

•Including frequencies in corpora

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Smoothing Techniques• Every n-gram training matrix is sparse,

even for very large corpora (Zipf’s law)• Solution: estimate the likelihood of

unseen n-grams• Problems: how do you adjust the rest of

the corpus to accommodate these ‘phantom’ n-grams?

• Methods to handle this are called smoothing.

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Smoothing is like Robin Hood: Steal from the rich and give to the poor (in probability mass)

From Snow, http://www.stanford.edu/class/linguist236/lec11.ppt

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• For unigrams:– Add 1 to every word (type) count– Normalize by N (tokens) /(N (tokens) +V (types))– Smoothed count (adjusted for additions to N) is

– Normalize by N to get the new unigram probability:

• For bigrams:– Add 1 to every bigram c(wn-1 wn) + 1

– Incr unigram count by vocabulary size c(wn-1) + V

Add-one Smoothing

VNNci

1

VNc

ipi

1*

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And “Take from the “Rich”– Discount: ratio of new counts to old (e.g.

add-one smoothing changes the BeRP bigram (to|want) from 786 to 331 (dc=.42) and p(to|want) from .65 to .28)

– But this changes counts drastically: • too much weight given to unseen n-grams• in practice, unsmoothed bigrams often work

better!

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• A zero n-gram is just an n-gram you haven’t seen yet…but every n-gram in the corpus was unseen once…so...– How many times did we see an n-gram for the first time?

Once for each n-gram type (T)– Est. total probability of unseen bigrams as

– View training corpus as series of events, one for each token (N) and one for each new type (T)

• We can divide the probability mass equally among unseen bigrams….or we can condition the probability of an unseen bigram on the first word of the bigram

• Discount values for Witten-Bell are much more reasonable than Add-One

TNT

Witten-Bell Discounting

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Backoff methods• For e.g. a trigram model

– Compute unigram, bigram and trigram probabilities

– In use:• Where trigram unavailable back off to bigram if

available, o.w. unigram probability• E.g An omnivorous unicorn

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Summary• N-gram probabilities can be used to estimate the likelihood– Of a word occurring in a context (N-1)– Of a sentence occurring at all

• Smoothing techniques deal with problems of unseen words in a corpus

• N-grams are useful in a wide variety of NLP tasks