day 8 test review.notebook -...

Day 8 Test Review.notebook

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May 28, 2019

Mar 253:27 PM

Express these absolute value functions as piecewise functions.


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May 28, 2019

Jan 299:28 AM

PreCalculus 110Unit 6: Absolute Value Functions and Equations

May 28, 2019: Day #8

1. Test tomorrow

2. Review any textbook questions?


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May 28, 2019

Jan 299:29 AM

Curriculum Outcomes

AN1: Demonstrate an understanding of the absolute value of real numbers.

RF2. Graph and analyze absolute value functions (limited to linear and quadratic functions) to solve problems.


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May 28, 2019

May 277:46 PM

Topics:Absolute value expressionsAbsolute value graphs (linear and quadratic, domain and range,

intercepts)Piecewise FunctionsAbsolute value functions from tablesAbsolute value functions from graphsAbsolute value equations (linear and quadratic)Absolute value equations - graphical solution


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May 209:27 AM


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May 28, 2019

May 209:30 AM


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May 28, 2019

May 209:31 AM


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May 28, 2019

May 209:32 AM


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May 28, 2019

Jan 2910:15 AM

Textbook:

Minimum Preparation:

p. 410411 # 1, 2, 3, 6, 7, 8, 9, 11, 12

p. 413 # 1, 2, 3, 6, 7, 8, 9

g


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May 28, 2019

May 301:42 PM

Attachments

Standard Form Demor.GSP

Warm ups.notebook

SMART Notebook

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Apr 13-1:09 PM McGraw-Hill Ryerson Pre-Calculus 11 Chapter 6 Rational Expressions and Equations

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Apr 13-1:35 PM McGraw-Hill Ryerson Pre-Calculus 11 Teacher Notes 1. This lesson is designed to help students conceptualize the main ideas of Chapter 6. 2. The lesson was written using SMART Notebook 10.0. Other versions of the software do not offer the same functionality. 3. Minimum screen resolution is 1024 × 768. 4. For best results, set the view to Page Width. 5. When you exit this lesson, do not save changes.

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Apr 13-1:23 PM Answer Non-Permissible Values For each rational expression, determine all non-permissible values. State the domain for each expression. Use the pen tool to write your answers. Drag the Answer tab under each question to reveal the answer. Chapter 6 The non-permissible value is x = –2. The domain is { x ∈ R, x ≠ –2} The non-permissible value is p = 5. The domain is { p ∈ R, p ≠ 5} The non-permissible value is x = 0. The domain is { x ∈ R, x ≠ 0} The non-permissible values are x = 0 and y = 0. The domain is { x,y ∈ R, x ≠ 0 , y ≠ 0 } The non-permissible values are x = 2 and x = –2. The domain is { x ∈ R, x ≠± 2} The non-permissible values are x = y . The domain is { x,y ∈ R, x ≠ y } 1. 2. 3. 4. 5. 6. Hint A non-permissible value is any value for a variable that makes an expression undefined. In a rational expression, it is a value that results in a denominator of zero.

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Apr 13-1:23 PM Simplifying Rational Expressions Identify each of the following as true or false. Click on the box to reveal the solution. Chapter 6

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Apr 13-1:23 PM Apply Rational Expressions Chapter 6 The area of a rectangular garden can be represented by the polynomial x 2 + 3 x + 2 and its width by x + 1. Use the pen tool to answer the following: a) Write a rational expression that represents the length. b) Write the expression in simplest form. c) If x represents 1 unit of length, what is the ratio length : width for this garden? Solution , x > –1 , x > –1 a) b)

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Apr 13-1:23 PM Multiply Rational Expressions Chapter 6 Click here for the solution. ( ( ) ) Answer x = –7, 0, ± 3 Simplify. Use the pen tool to show your work. Hint 1. Factor expressions in the numerator and denominator. 2. State any restrictions on the variables. 3. Reduce to lowest terms by dividing out any common factors.

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Apr 13-1:23 PM Divide Rational Expressions Simplify. Use the pen tool to show your work. Chapter 6 Hint Click here for the solution. Hint 1. Factor expressions in the numerator and denominator. 2. Multiply by the reciprocal. 3. State any restrictions on the variables. 4. Reduce to lowest terms by dividing out any common factors. Answer

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Apr 13-1:23 PM Multiply and Divide Rational Expressions Simplify using the pen tool. State any restrictions on the variables. Chapter 6 Click here for the solution.

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Apr 13-1:23 PM x – 1 x + 6 Apply Rational Expressions Chapter 6 Determine the area of the triangular region if the area of A 1 is 2 x 2 + 10 x – 12 and has a width of x + 6. The area of A 2 is 2 x 2 – 3 x + 1 and has a width of x – 1. Use the pen tool to show your work. Hint Click on the rectangles to see the steps. Click on the triangle to see the solution for the area.

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Apr 13-1:23 PM Check Check Check Check Check Determine the LCD Check Check Check Check Check Use the pen tool to check the box that represents the lowest common denominator for the group of rational expressions listed. Click on Check to check your work. Chapter 6

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Apr 13-1:23 PM Equivalent Expressions Drag all expressions that are not equivalent to the expression , in the red box, to the trash can. If the expression is equivalent it cannot be thrown away. Chapter 6

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Apr 13-1:23 PM Add or Subtract Rational Expressions Click here for the solution. Use the pen tool to write the sum or difference below each expression. Chapter 6 Answer

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Apr 13-1:23 PM Rational Equations Click here for the solution. Chapter 6 Erin and Andrea set off at the same time on a 30-km walk for charity. Erin, who has trained all year for this event, walks 1 km/h faster than Andrea. Erin finishes the walk 1 h ahead of Andrea. How fast was each sister walking, and how long did it take for each sister to finish the walk? Use the pen tool to complete your answer. Let x represent Andrea's walking speed. Distance (km) Speed (km/h) Time (h) Erin Andrea

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Apr 13-1:23 PM Add and Subtract Rational Expressions Chapter 6 Drag the expressions from the right to arrange them in the correct order to simplify the given expression. Answer

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Apr 13-2:18 PM The following pages contain solutions for the previous questions.

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Apr 13-1:23 PM Solution 1 1 1 1 1 1 Go back to the question ( ( ) ) ) ) ( ( ( ( ) ) = = x = –7, 0, ± 3

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Apr 13-1:23 PM Hint Go back to the question 1 1 1 1 Solution

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Apr 13-2:20 PM Solution ab 2 xy 2 3 Go back to the question

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Apr 13-2:20 PM Solution Go back to the question

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Apr 13-1:23 PM Solution The difference in the times of the two sisters is 1 hour. Andrea's walking speed is 5 km/h, taking her 6 hours to finish. Erin's walking speed is 6 km/h taking her 5 hours to finish. –6 is an extraneous root which does not make sense in the context of walking speeds. Go back to the question Distance (km) Speed (km/h) Time (h) Erin 30 x + 1 Andrea 30 x

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