desk work 4
TRANSCRIPT
Find the mean, variance, and standard deviation of the probability distribution.X P(x)2 0.154 0.206 0.258 0.35
10 0.05
Find the mean, variance, and standard deviation of the probability distribution.X P(x)2 0.154 0.206 0.258 0.35
10 0.05
π=β [π₯ βπ (π₯ )]
Find the mean, variance, and standard deviation of the probability distribution.X P(x)2 0.154 0.206 0.258 0.35
10 0.05
π=β [π₯ βπ (π₯ )]Create a column of xβP(x)
Find the mean, variance, and standard deviation of the probability distribution.
X P(x) xβP(x)2 0.154 0.206 0.258 0.3510 0.05
π=β [π₯ βπ (π₯ )]Create a column of xβP(x)
Find the mean, variance, and standard deviation of the probability distribution.
X P(x) xβP(x)2 0.15 2(0.15) = 0.304 0.206 0.258 0.3510 0.05
π=β [π₯ βπ (π₯ )]Create a column of xβP(x)
Find the mean, variance, and standard deviation of the probability distribution.
X P(x) xβP(x)2 0.15 2(0.15) = 0.304 0.20 4(0.20) = 0.806 0.258 0.3510 0.05
π=β [π₯ βπ (π₯ )]Create a column of xβP(x)
Find the mean, variance, and standard deviation of the probability distribution.
X P(x) xβP(x)2 0.15 2(0.15) = 0.304 0.20 4(0.20) = 0.806 0.25 6(0.25) = 1.508 0.3510 0.05
π=β [π₯ βπ (π₯ )]Create a column of xβP(x)
Find the mean, variance, and standard deviation of the probability distribution.
X P(x) xβP(x)2 0.15 2(0.15) = 0.304 0.20 4(0.20) = 0.806 0.25 6(0.25) = 1.508 0.35 8(0.35) = 2.8010 0.05
π=β [π₯ βπ (π₯ )]Create a column of xβP(x)
Find the mean, variance, and standard deviation of the probability distribution.
X P(x) xβP(x)2 0.15 2(0.15) = 0.304 0.20 4(0.20) = 0.806 0.25 6(0.25) = 1.508 0.35 8(0.35) = 2.8010 0.05 10(0.05) = 0.50
π=β [π₯ βπ (π₯ )]Create a column of xβP(x)
Find the mean, variance, and standard deviation of the probability distribution.
X P(x) xβP(x)2 0.15 2(0.15) = 0.304 0.20 4(0.20) = 0.806 0.25 6(0.25) = 1.508 0.35 8(0.35) = 2.8010 0.05 10(0.05) = 0.50
π=β [π₯ βπ (π₯ )]
Sum the column of xβP(x)
Find the mean, variance, and standard deviation of the probability distribution.
X P(x) xβP(x)2 0.15 2(0.15) = 0.304 0.20 4(0.20) = 0.806 0.25 6(0.25) = 1.508 0.35 8(0.35) = 2.8010 0.05 10(0.05) = 0.50
π=β [π₯ βπ (π₯ )]
Sum the column of xβP(x)
Ξ£[xβP(x)]=5.9
Find the mean, variance, and standard deviation of the probability distribution.
X P(x) xβP(x)2 0.15 2(0.15) = 0.304 0.20 4(0.20) = 0.806 0.25 6(0.25) = 1.508 0.35 8(0.35) = 2.8010 0.05 10(0.05) = 0.50
π=β [π₯ βπ (π₯ )]=5.9
Ξ£[xβP(x)]=5.9
Mean
Find the mean, variance, and standard deviation of the probability distribution.
X P(x) xβP(x)2 0.15 2(0.15) = 0.304 0.20 4(0.20) = 0.806 0.25 6(0.25) = 1.508 0.35 8(0.35) = 2.8010 0.05 10(0.05) = 0.50
π=β [π₯ βπ (π₯ )]=5.9
Ξ£[xβP(x)]=5.9
π 2=β [π₯2 βπ (π₯ )]βπ2
Create a column of x2
Find the mean, variance, and standard deviation of the probability distribution.
X P(x) xβP(x) x22 0.15 2(0.15) = 0.304 0.20 4(0.20) = 0.806 0.25 6(0.25) = 1.508 0.35 8(0.35) = 2.80
10 0.05 10(0.05) = 0.50
π=β [π₯ βπ (π₯ )]=5.9
Ξ£[xβP(x)]=5.9
π 2=β [π₯2 βπ (π₯ )]βπ2
Create a column of x2
Find the mean, variance, and standard deviation of the probability distribution.
X P(x) xβP(x) x22 0.15 2(0.15) = 0.30 22 = 44 0.20 4(0.20) = 0.806 0.25 6(0.25) = 1.508 0.35 8(0.35) = 2.80
10 0.05 10(0.05) = 0.50
π=β [π₯ βπ (π₯ )]=5.9
Ξ£[xβP(x)]=5.9
π 2=β [π₯2 βπ (π₯ )]βπ2
Create a column of x2
Find the mean, variance, and standard deviation of the probability distribution.
X P(x) xβP(x) x22 0.15 2(0.15) = 0.30 22 = 44 0.20 4(0.20) = 0.80 42 = 166 0.25 6(0.25) = 1.508 0.35 8(0.35) = 2.80
10 0.05 10(0.05) = 0.50
π=β [π₯ βπ (π₯ )]=5.9
Ξ£[xβP(x)]=5.9
π 2=β [π₯2 βπ (π₯ )]βπ2
Create a column of x2
Find the mean, variance, and standard deviation of the probability distribution.
X P(x) xβP(x) x22 0.15 2(0.15) = 0.30 22 = 44 0.20 4(0.20) = 0.80 42 = 166 0.25 6(0.25) = 1.50 62 = 368 0.35 8(0.35) = 2.80
10 0.05 10(0.05) = 0.50
π=β [π₯ βπ (π₯ )]=5.9
Ξ£[xβP(x)]=5.9
π 2=β [π₯2 βπ (π₯ )]βπ2
Create a column of x2
Find the mean, variance, and standard deviation of the probability distribution.
X P(x) xβP(x) x22 0.15 2(0.15) = 0.30 22 = 44 0.20 4(0.20) = 0.80 42 = 166 0.25 6(0.25) = 1.50 62 = 368 0.35 8(0.35) = 2.80 82 = 6410 0.05 10(0.05) = 0.50
π=β [π₯ βπ (π₯ )]=5.9
Ξ£[xβP(x)]=5.9
π 2=β [π₯2 βπ (π₯ )]βπ2
Create a column of x2
Find the mean, variance, and standard deviation of the probability distribution.
X P(x) xβP(x) x22 0.15 2(0.15) = 0.30 22 = 44 0.20 4(0.20) = 0.80 42 = 166 0.25 6(0.25) = 1.50 62 = 368 0.35 8(0.35) = 2.80 82 = 6410 0.05 10(0.05) = 0.50 102 = 100
π=β [π₯ βπ (π₯ )]=5.9
Ξ£[xβP(x)]=5.9
π 2=β [π₯2 βπ (π₯ )]βπ2
Create a column of x2
Find the mean, variance, and standard deviation of the probability distribution.
X P(x) xβP(x) x22 0.15 2(0.15) = 0.30 22 = 44 0.20 4(0.20) = 0.80 42 = 166 0.25 6(0.25) = 1.50 62 = 368 0.35 8(0.35) = 2.80 82 = 64
10 0.05 10(0.05) = 0.50 102 = 100
π=β [π₯ βπ (π₯ )]=5.9
Ξ£[xβP(x)]=5.9
π 2=β [π₯2 βπ (π₯ )]βπ2
Create a column of x2βP(x)
Find the mean, variance, and standard deviation of the probability distribution.
X P(x) xβP(x) x2 x2βP(x)2 0.15 2(0.15) = 0.30 22 = 4
4 0.20 4(0.20) = 0.80 42 = 16
6 0.25 6(0.25) = 1.50 62 = 36
8 0.35 8(0.35) = 2.80 82 = 64
10 0.05 10(0.05) = 0.50 102 = 100
π=β [π₯ βπ (π₯ )]=5.9
Ξ£[xβP(x)]=5.9
π 2=β [π₯2 βπ (π₯ )]βπ2
Create a column of x2βP(x)
Find the mean, variance, and standard deviation of the probability distribution.
X P(x) xβP(x) x2 x2βP(x)2 0.15 2(0.15) = 0.30 22 = 4 4(0.15) = 0.604 0.20 4(0.20) = 0.80 42 = 16
6 0.25 6(0.25) = 1.50 62 = 36
8 0.35 8(0.35) = 2.80 82 = 64
10 0.05 10(0.05) = 0.50 102 = 100
π=β [π₯ βπ (π₯ )]=5.9
Ξ£[xβP(x)]=5.9
π 2=β [π₯2 βπ (π₯ )]βπ2
Create a column of x2βP(x)
Find the mean, variance, and standard deviation of the probability distribution.
X P(x) xβP(x) x2 x2βP(x)2 0.15 2(0.15) = 0.30 22 = 4 4(0.15) = 0.604 0.20 4(0.20) = 0.80 42 = 16 16(0.20) = 3.206 0.25 6(0.25) = 1.50 62 = 368 0.35 8(0.35) = 2.80 82 = 64
10 0.05 10(0.05) = 0.50 102 = 100
π=β [π₯ βπ (π₯ )]=5.9
Ξ£[xβP(x)]=5.9
π 2=β [π₯2 βπ (π₯ )]βπ2
Create a column of x2βP(x)
Find the mean, variance, and standard deviation of the probability distribution.
X P(x) xβP(x) x2 x2βP(x)2 0.15 2(0.15) = 0.30 22 = 4 4(0.15) = 0.604 0.20 4(0.20) = 0.80 42 = 16 16(0.20) = 3.206 0.25 6(0.25) = 1.50 62 = 36 36(0.25) = 9.008 0.35 8(0.35) = 2.80 82 = 64
10 0.05 10(0.05) = 0.50 102 = 100
π=β [π₯ βπ (π₯ )]=5.9
Ξ£[xβP(x)]=5.9
π 2=β [π₯2 βπ (π₯ )]βπ2
Create a column of x2βP(x)
Find the mean, variance, and standard deviation of the probability distribution.
X P(x) xβP(x) x2 x2βP(x)2 0.15 2(0.15) = 0.30 22 = 4 4(0.15) = 0.604 0.20 4(0.20) = 0.80 42 = 16 16(0.20) = 3.206 0.25 6(0.25) = 1.50 62 = 36 36(0.25) = 9.008 0.35 8(0.35) = 2.80 82 = 64 64(0.35) = 22.40
10 0.05 10(0.05) = 0.50 102 = 100
π=β [π₯ βπ (π₯ )]=5.9
Ξ£[xβP(x)]=5.9
π 2=β [π₯2 βπ (π₯ )]βπ2
Create a column of x2βP(x)
Find the mean, variance, and standard deviation of the probability distribution.
X P(x) xβP(x) x2 x2βP(x)2 0.15 2(0.15) = 0.30 22 = 4 4(0.15) = 0.604 0.20 4(0.20) = 0.80 42 = 16 16(0.20) = 3.206 0.25 6(0.25) = 1.50 62 = 36 36(0.25) = 9.008 0.35 8(0.35) = 2.80 82 = 64 64(0.35) = 22.40
10 0.05 10(0.05) = 0.50 102 = 100 100(0.05) = 5.00
π=β [π₯ βπ (π₯ )]=5.9
Ξ£[xβP(x)]=5.9
π 2=β [π₯2 βπ (π₯ )]βπ2
Create a column of x2βP(x)
Find the mean, variance, and standard deviation of the probability distribution.
X P(x) xβP(x) x2 x2βP(x)2 0.15 2(0.15) = 0.30 22 = 4 4(0.15) = 0.604 0.20 4(0.20) = 0.80 42 = 16 16(0.20) = 3.206 0.25 6(0.25) = 1.50 62 = 36 36(0.25) = 9.008 0.35 8(0.35) = 2.80 82 = 64 64(0.35) = 22.40
10 0.05 10(0.05) = 0.50 102 = 100 100(0.05) = 5.00
π=β [π₯ βπ (π₯ )]=5.9
Ξ£[xβP(x)]=5.9
π 2=β [π₯2 βπ (π₯ )]βπ2
Sum the column of x2βP(x)
Find the mean, variance, and standard deviation of the probability distribution.
X P(x) xβP(x) x2 x2βP(x)2 0.15 2(0.15) = 0.30 22 = 4 4(0.15) = 0.604 0.20 4(0.20) = 0.80 42 = 16 16(0.20) = 3.206 0.25 6(0.25) = 1.50 62 = 36 36(0.25) = 9.008 0.35 8(0.35) = 2.80 82 = 64 64(0.35) = 22.40
10 0.05 10(0.05) = 0.50 102 = 100 100(0.05) = 5.00
π=β [π₯ βπ (π₯ )]=5.9
Ξ£[xβP(x)]=5.9
π 2=β [π₯2 βπ (π₯ )]βπ2
Sum the column of x2βP(x)Ξ£[x2βP(x)]=40.2
Find the mean, variance, and standard deviation of the probability distribution.
X P(x) xβP(x) x2 x2βP(x)2 0.15 2(0.15) = 0.30 22 = 4 4(0.15) = 0.604 0.20 4(0.20) = 0.80 42 = 16 16(0.20) = 3.206 0.25 6(0.25) = 1.50 62 = 36 36(0.25) = 9.008 0.35 8(0.35) = 2.80 82 = 64 64(0.35) = 22.40
10 0.05 10(0.05) = 0.50 102 = 100 100(0.05) = 5.00
π=β [π₯ βπ (π₯ )]=5.9
Ξ£[xβP(x)]=5.9 Ξ£[x2βP(x)]=40.2Variance
Find the mean, variance, and standard deviation of the probability distribution.
X P(x) xβP(x) x2 x2βP(x)2 0.15 2(0.15) = 0.30 22 = 4 4(0.15) = 0.604 0.20 4(0.20) = 0.80 42 = 16 16(0.20) = 3.206 0.25 6(0.25) = 1.50 62 = 36 36(0.25) = 9.008 0.35 8(0.35) = 2.80 82 = 64 64(0.35) = 22.40
10 0.05 10(0.05) = 0.50 102 = 100 100(0.05) = 5.00
π=β [π₯ βπ (π₯ )]=5.9
Ξ£[xβP(x)]=5.9 Ξ£[x2βP(x)]=40.2
π=βπ2
Find the mean, variance, and standard deviation of the probability distribution.
X P(x) xβP(x) x2 x2βP(x)2 0.15 2(0.15) = 0.30 22 = 4 4(0.15) = 0.604 0.20 4(0.20) = 0.80 42 = 16 16(0.20) = 3.206 0.25 6(0.25) = 1.50 62 = 36 36(0.25) = 9.008 0.35 8(0.35) = 2.80 82 = 64 64(0.35) = 22.40
10 0.05 10(0.05) = 0.50 102 = 100 100(0.05) = 5.00
π=β [π₯ βπ (π₯ )]=5.9
Ξ£[xβP(x)]=5.9 Ξ£[x2βP(x)]=40.2
π=βπ2=β5.39β2.32Standard Deviation