device constructions with hyperbolas - lsu mathematics presentation (final).pdf · device...
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Device Constructions with Hyperbolas
Alfonso Croeze1 William Kelly1 William Smith2
1Department of MathematicsLouisiana State University
Baton Rouge, LA
2Department of MathematicsUniversity of Mississippi
Oxford, MS
July 8, 2011
Croeze, Kelly, Smith LSU&UoM
Device Constructions with Hyperbolas
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Hyperbola Definition
Conic Section
Croeze, Kelly, Smith LSU&UoM
Device Constructions with Hyperbolas
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Hyperbola Definition
Conic Section
Two Foci
Focus and Directrix
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Device Constructions with Hyperbolas
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The Project
Basic constructions
Constructing a Hyperbola
Advanced constructions
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Device Constructions with Hyperbolas
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Rusty Compass
Theorem
Given a circle centered at a point A with radius r and any point Cdifferent from A, it is possible to construct a circle centered at Cthat is congruent to the circle centered at A with a compass andstraightedge.
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Device Constructions with Hyperbolas
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C A
B
X
Y
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Device Constructions with Hyperbolas
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C A
B
X
Y
D
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Device Constructions with Hyperbolas
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Angle Duplication
A X
A B X Y
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Device Constructions with Hyperbolas
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Angle Duplication
A X
A B X Y
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Device Constructions with Hyperbolas
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A B
C
X Y
Z
A B
C
X Y
Z
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Device Constructions with Hyperbolas
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A B
C
X Y
Z
A B
C
X Y
Z
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Device Constructions with Hyperbolas
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Constructing a Perpendicular
C
A B
C
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Device Constructions with Hyperbolas
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A B
C
X
Y
A B
C
X
Y
O
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Device Constructions with Hyperbolas
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We Need to Draw a Hyperbola!
Trisection of an angle and doubling the cube cannot beaccomplished with a straightedge and compass.
We needed a way to draw a hyperbola.
Items we needed:
one cork boardone poster boardone pair of scissorsone roll of stringa box of push pinssome paper if you do not already have somea writing utensilsome straws, which we picked up at McDonald’s
Croeze, Kelly, Smith LSU&UoM
Device Constructions with Hyperbolas
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We Need to Draw a Hyperbola!
Trisection of an angle and doubling the cube cannot beaccomplished with a straightedge and compass.
We needed a way to draw a hyperbola.
Items we needed:
one cork boardone poster boardone pair of scissorsone roll of stringa box of push pinssome paper if you do not already have somea writing utensilsome straws, which we picked up at McDonald’s
Croeze, Kelly, Smith LSU&UoM
Device Constructions with Hyperbolas
![Page 16: Device Constructions with Hyperbolas - LSU Mathematics Presentation (Final).pdf · Device Constructions with Hyperbolas Alfonso Croeze1 William Kelly1 William Smith2 1Department of](https://reader030.vdocuments.net/reader030/viewer/2022040805/5e4448f6062163406d697cdb/html5/thumbnails/16.jpg)
We Need to Draw a Hyperbola!
Trisection of an angle and doubling the cube cannot beaccomplished with a straightedge and compass.
We needed a way to draw a hyperbola.
Items we needed:
one cork boardone poster boardone pair of scissorsone roll of stringa box of push pinssome paper if you do not already have somea writing utensilsome straws, which we picked up at McDonald’s
Croeze, Kelly, Smith LSU&UoM
Device Constructions with Hyperbolas
![Page 17: Device Constructions with Hyperbolas - LSU Mathematics Presentation (Final).pdf · Device Constructions with Hyperbolas Alfonso Croeze1 William Kelly1 William Smith2 1Department of](https://reader030.vdocuments.net/reader030/viewer/2022040805/5e4448f6062163406d697cdb/html5/thumbnails/17.jpg)
The Device
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Device Constructions with Hyperbolas
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F2 F1
P
R = length of tube
C = length of string
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Device Constructions with Hyperbolas
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F2 F1
P
C = PF1 + (R – PF2) + R
PF1 – PF2 = C – 2R
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Device Constructions with Hyperbolas
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Hyperbolas and Triangles
Lemma
Let 4ABP be a triangle with the following property: point P liesalong the hyperbola with eccentricity 2, B as its focus, and theperpendicular bisector of AB as its directrix. Then ∠B = 2∠A.
A B
P
c c
ah
g
b
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Device Constructions with Hyperbolas
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Proof.
h2 = a2 − (c − b)2
h2 = g2 − (c + b)2
...a
b= 2
...
2
(h
g
)(b + c
g
)=
h
a
2 sin(∠A) cos(∠A) = sin(∠B)
sin(2∠A) = sin(∠B)
2∠A = ∠B
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Device Constructions with Hyperbolas
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Lemma
Let 4ABP be a triangle such that ∠B = 2∠A. Then point P liesalong the hyperbola with eccentricity 2, B as its focus, and theperpendicular bisector of AB as its directrix.
A B
P
c c
ah
g
b
Croeze, Kelly, Smith LSU&UoM
Device Constructions with Hyperbolas
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Proof.
2∠A = ∠B
sin(2∠A) = sin(∠B)
2 sin(∠A) cos(∠A) = sin(∠B)
2
(h
g
)(b + c
g
)=
h
a...
(a− 2b)(2c − a) = 0a
b= 2
Croeze, Kelly, Smith LSU&UoM
Device Constructions with Hyperbolas
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Result
Theorem
Let AB be a fixed line segment. Then the locus of points P suchthat ∠PBA = 2∠PAB is a hyperbola with eccentricity 2, withfocus B, and the perpendicular bisector of AB as its directrix.
A B
P
c c
ah
g
b
Croeze, Kelly, Smith LSU&UoM
Device Constructions with Hyperbolas
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Trisecting the Angle - The Classical Construction
Let O denote the vertex of theangle.
Use a compass to draw a circlecentered at O, and obtain thepoints A and B on the angle.
Construct the hyperbola witheccentricity ε = 2, focus B,and directrix the perpendicularbisector of AB.
Let this hyperbola intersect thecircle at P.
Then OP trisects the angle.
A
B
O
P
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Device Constructions with Hyperbolas
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Trisecting the Angle
Given an angle ∠O, mark a point A on on the the given rays.
A
O
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Device Constructions with Hyperbolas
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Trisecting the Angle
Draw a circle, centered at O with radius OA. Mark theintersection on the second ray B, and draw the segment AB.
A B
O
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Device Constructions with Hyperbolas
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Trisecting the Angle
Draw a circle, centered at O with radius OA. Mark theintersection on the second ray B, and draw the segment AB.
A B
O
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Device Constructions with Hyperbolas
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Divide the segment AB into 6 equal parts: to do this, we pick apoint G1, not on AB, and draw the ray AG1. Mark points G2, G3,G4, G5, and G6 on the ray such that:
AG1 = G1G2 = G2G3 = G3G4 = G4G5 = G5G6.
A B
G1
G2
G3
G4
G5
G6
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Device Constructions with Hyperbolas
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Draw G6B. Draw lines through G1, G2, G3, G4 and G5 parallel toG6B. Each intersection produces equal length line segments onAB. Mark each intersection as shown, and treat each segment as aunit length of one.
A B
G1
G2
G3
G4
G5
G6
C D1 V
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Device Constructions with Hyperbolas
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Extend AB past A a length of 2 units as shown below. Mark thispoint F2. Construct a line perpendicular to AB through the pointD1. Using F2 and B as the foci and V as the vertex, use the deviceto construct a hyperbola, called h. Since the distance from the thecenter, C , to F1 is 4 units and the distance C to the vertex, V , is2 units, the hyperbola has eccentricity of 2 as required.
F2 A BC D1 V
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Device Constructions with Hyperbolas
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Mark the intersection point between the hyperbola, h, and thecircle OA as P. Draw the segment OP. The angle ∠POB trisects∠AOB.
A
P
BC D1 V
O
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Device Constructions with Hyperbolas
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Constructing 3√
2
Start with a given unit length of AB.
A B
Construct a square with side AB and mark the point shown.
A B
E
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Device Constructions with Hyperbolas
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Constructing 3√
2
Start with a given unit length of AB.
A B
Construct a square with side AB and mark the point shown.
A B
E
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Device Constructions with Hyperbolas
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Draw a line l through the points A and E . Extend line AB past Ba unit length of AB. Draw a circle, centered at A, with radius ACand mark the intersection on l as V . Draw a circle centered at Ewith radius AE and mark the intersection on l as F1. Draw thecircle centered at A with radius AF1 and mark that intersection onl as F2. Bisect the segment EB and mark the point O.
A
B C
E
O
V
F1
F2
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Device Constructions with Hyperbolas
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Draw a circle centered at O with a radius of OA. Using the device,draw a hyperbola with foci F1 and F2 and vertex V .
A
B C
E
O
V
F1
F2
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Device Constructions with Hyperbolas
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The circle intersects the hyperbola twice. Mark the leftmostintersection X and draw a perpendicular line from AC to X . Thissegment has length 3
√2.
A
C
D
X
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Device Constructions with Hyperbolas
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Construction Proof
We can easily prove that the above construction is valid if wetranslate the above into Cartesian coordinates.
If we allow the point A to be treated as the origin of the x - yplane and B be the point (1, 0), we can write the equations ofthe circle and hyperbola.
The circle is centered at 1 unit to the right and 12 units up,
giving it a center of (1, 12) and a radius of√
54 . This gives the
circle the equation:
(x − 1)2 +
(y − 1
2
)2
=5
4.
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Device Constructions with Hyperbolas
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The hyperbola, being rectangular with vertex (√2,√2), has
the equation xy = 2, so y = 2/x .
Substituting this expression into the circle’s equation andsolving for x yields the following:
(x − 1)2 +
(2
x− 1
2
)2
=5
4
x2 − 2x +4
x2− 2
x= 0
x4 − 2x − 2x3 + 4 = 0
(x3 − 2)(x − 2) = 0
From here we can see that both x = 3√2 and x = 2 are
solutions.
This proves that the horizontal distance from the y -axis to thepoint X is 3
√2.
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Bibliography
Heath, T., A History of Greek Mathematics, DoverPublications, New York, 1981.
Apostol, T.M. and Mnatsakanian, M.N., Ellipse to Hyperbola:With This String I Thee Wed, Mathematics Magazine 84(2011) 83-97.
http://en.wikipedia.org/wiki/Compass equivalence theorem
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Acknowledgements
Dr. Mark Davidson
Dr. Larry Smolinsky
Irina Holmes
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Device Constructions with Hyperbolas