DHANALAKSHMI COLLEGE OF ENGINEERING, CHENNAI

DEPARTMENT OF ELECTRICAL AND ELECTRONICS ENGINEERING

EE6801- ELECTRICAL ENERGY GENERATION, UTILIZATION AND CONSERVATION

UNIT- I : ELECTRIC DRIVES AND TRACTION

PART – A (2 Marks)

1. What is meant by electrical drives? Systems employed for motion control are called "Drives" and many employ any of the prime movers such as, diesel or petrol engines, gas or steam turbines, hydraulic motors and electric motors for supplying mechanical energy for motion control. Drives employing electrical motors are known as "Electrical drives"

2. What are the different types of drives? i. Group drive ii. Individual drive iii. Multi motor drive

3. What are the different types of electrical drives? i. DC drives ii. AC drives

4. What are the advantages of electric drives? i. They have flexible control characteristics. The steady state and dynamic characteristics of electrical drives can be shaped to satisfy load requirements. ii. Drives can be provided with automatic fault detection systems. Programmable logic controllers and computers can be employed to automatically control the drive operations in a desired sequence.

iii. They are available in wide range of torque, speed and power. iv. It can operate in all the four quadrants of speed-torque plane. Electric braking gives smooth deceleration and increases life of the equipment compound to other forms of braking v. Control gear enquired for speed control, starting and braking is usually simple and easy to operate.

5. Mention the different factors for the selection of electric drives. i. Steady state operation requirements

ii. Transient operation requirements iii. Requirements related to the source

iv. Capital and running cost, maintenance needs, life

v. Environment and location

vi. Reliability.

6. What are the parts of electrical drives? i. Electrical motors and load ii. Power modulator iii. Sources iv. Control unit v. Sensing unit

7. What are the applications of electrical drives? i. Paper mills ii. Electric traction iii. Cement mills iv. Steel mills

8. What is an individual drive? If a single motor is used to drive a single machine and all the connected mechanisms belonging to the same machine then the system is called individual drive system.

9. What are the disadvantages of an individual drive? Initial cost is high.

10. What are the advantages of group drive?

i. Initial cost is less ii. Less space is required in group drive iii. Maintenance cost is less iv. Group drive system is useful because all operation are stopped simultaneously.

11. What are the factors that influence the choice of electrical drives? i. Shaft power & speed

ii. Power range

iii. Speed range

iv. Starting torque

v. Efficiency

vi. Starting torque

12. Draw the basic block diagram of electric drive.

13. What are the advantages of electric traction system? (N -13, N -14) i. In electric traction electric motors are used as the drives, the system is clean and pollution

free and it has high starting torque therefore high acceleration is possible.

ii. Electric traction is most suitable for urban and suburban areas where frequent starting and stopping and high schedule speeds are required.

iii. The coefficient of adhesion is high, therefore for the same tractive effort electric locomotives are lighter and hence higher speeds on gradients are possible.

iv. Over loading of electric motors is possible.

v. Centre of gravity of electric locomotive is lower than that of steam locomotive.

14. What are the requirements of ideal traction system? i. The coefficient of adhesion should be high, so that high tractive effort at start is possible and rapid acceleration of the train can be obtained.

ii. It should be possible to overload the equipment for short periods.

iii. It should be pollution free.

iv. The locomotive or train unit should be self-contained It should be possible to use regenerative braking.

What are the supply systems for electric Traction?

i. The direct current system ii. The Single phase AC system iii. The 3 phase Ac system

15. How would you analyse the speed time curve for electric train? The Speed time curve can be analysed with respect to i. Acceleration ii. Speed Constant or free running iii. Period of wasting

16. What is crest speed? It is the maximum speed attained by a train during a run.

17. Define - Tractive Effort in traction system (N -13) It is an effective force on the wheel of a locomotive which is required for its propulsion. The

tractive effort is a vector quantity and it is tangential to wheel. It is measured in Newton.

18. Write the formula for tractive effort of an electric train. (A -14) The tractive effort is given by

Ft =Fa + Fg + FrWhere Fa = Force to overcome linear or angular motion,Fg = Force to overcome effect of gravity, Fr = Tractive effort to overcome the frictional resistance.

19. Why DC series motors are preferred for electric traction? Series motors exert high starting torque. If the torque is increased the speed of the series

motor decreases automatically. The free running speed of the series motor is sufficiently high.

20. What are the mechanical characteristics of traction motor? i. As the motor has to withstand the vibrations continuously the motor should be robust. ii.The motor should have minimum possible weight.

21. Why a three phase induction motor is more suitable for traction purpose? It has constant speed characteristics. It has shunt type speed torque characteristics even during braking. Possibility of applying regenerative braking on gradient. Its robust construction in absence of commutator. High efficiency.

22. What are the methods of electric braking? i. Plugging ii. Rheostatic braking iii. Regenerative braking

23. What is rheostatic braking? In this method of braking, this motor is disconnected from the supply and run as a generator driven by the remaining kinetic energy of the equipment. i.e by the energy stored in motor and load which are to be broken.

24. What is regenerative braking? In this type of braking, the motor is not disconnected from the supply but remains connected to it and it feeds back the braking energy to its kinetic energy to the supply system.

25. What is meant by mechanical braking? For completely hauling the train in addition to electric brakes, mechanical brakes are also required Initial retardation is achieved by applying electric brakes but for completely stopping the train, it is necessary to apply the mechanical brakes.

26. What are the advantages of pantograph current collector? Due to absence of points and grooved crossings, the overhead construction on points is

simplified. 1. There is no risk of the collector leaving the wire at junctions. 2. The pantograph collector is reversible i.e. suitable for operation in either direction of motion. 3. Speeds as high as 150 kmph can be obtained.

27. What is traction motor control? The traction motor control is required for starting without drawing excess current from the supply for providing acceleration without sudden shock, to avoid damage to couplings and inconvenience to the passengers and for speed control depending upon the type of service. The control equipment may be operated manually or it may be fully automatic.

28. What are the speed control methods of three phase induction motors? i. Rheostatic control ii. Pole changing iii. Cascade control iv. A combination of pole changing andcascade control

29. What is multiple unit control?

The coaches where electric motors are installed are known as Motor coaches. Each motor coach may have 2 or 4 motors and it’s desirable that it should be possible to control the operation of all the motors in train from a single point and this control system is known as multiple unit control.

30. What are the equipment required for control purposes on a motor coach? Master controller, Series parallel motor controller, Multi core cable for control circuits, Accelerating relays, a motor generator set or a battery or tapped line connected potential divider supplied to the control circuit

31. What type of braking is employed on a tram car driven by two series motor? (A -15) Rheostatic braking or dynamic braking is employed on a tram car driven by two series motors.

32. What are the disadvantages of electric traction? (A-13,N-4) High capital cost, Problem of supply failure, Additional equipment is required for achieving electric braking and control, The leakage of current from the distribution mains and drop of volts in the track are to be kept within the prescribed limits., The electrically operated vehicles have to move on guided track only.

33. What are the recent trends in electric traction? (A -13, A -14, N – 14) Development of practical electric vehicles has been completed. Motor selection becomes clear, Battery trend becomes also clear, Components are almost completed.

34. Define – Crest Speed of a train (N -12)

It is the maximum speed of train, which affects the schedule speed as for fixed acceleration, retardation, and constant distance between the stops. If the crest speed increases, the actual running time of train decreases. The high crest speed of train will increases its schedule speed.

35. What are the requirements for an electric traction system? (N -12) The coefficient of adhesion should be high, so that high tractive effort at start is possible and rapid acceleration of the train can be obtained. It should be possible to overload the equipment for short periods. It should be pollution free. The locomotive or train unit should be self contained. It should be possible to use regenerative braking.

36. Define specific energy consumption and discuss the factors that affects the specific energy consumption of trains operation at a given schedule speed. (N -12, M –15)

It is the energy consumed (in Wh) per tonne mass of the train per km length of the run. The specific energy consumption of a train running at a given schedule speed is influenced by

i. Distance between stops ii. Acceleration iii. Retardation iv. Maximum speed v. Type of train and equipment vi. Track configuration.

PART – B (16 Marks)

1. (i) Explain the principle and operation of a modern ac locomotive. (A -15)

(ii) What are the various types of electric braking used in traction? Discuss in detail. (A -15)

2. The distance between two stations is 1.6km and the average speed of the train is 40 kmph. The

acceleration is 2kmphps, retardation during coasting is 0.16 kmphps and braking is 3.2kmphps

respectively. assuming a simplified quadrilateral speed time curve, determine duration of

acceleration, coasting and barking periods and distance covered during braking period. (N -14)

3. Explain supply system of electric traction in details. (N -14)

4. (i) A suburban electric train has a maximum speed of 65km/hr. The scheduled including a station

stop of 30 sec is 43.5 km/hr. If the acceleration is 1.3 kmphps , find the value of retardation when

the averages distance between stops in 3km. (A-15)

(ii)Write a short note on Trolley bus. (A -13)

5. A train weighing 203 tonnes accelerates uniforms from the rest to a speed of 45kmph up a gradient

of 1 in 500, the time taken being 30 seconds. The power is then cut off the coasts down as uniform

gradient of 1 in 1000 for a period of 40 seconds when brakes are applied for period of 15 seconds so

as to bring the train uniformly to the rest on this gradient. Calculate (i) the maximum power output from

the driving axle. (ii) The energy taken from the conductor rails in kWh. Assume efficiency is 60%,

traction effort is 44 Newton/Tonne at all speed, rotational inertia is 10%. (A -13)

6. (i)List the merits of electric traction. Compare with conventional system.

(ii)A 250 tonnes train with 10% rotational effect is started with uniform acceleration and reaches a

speed of 50 kmphps in 265 seconds on level road. Find the specific energy consumption if the

journey is to be made according to trapezoidal speed. Time curve acceleration=2kmphps, Tracking

retardation=3 kmphps; Distance between the stations is 2.4 km; Efficiency=0.9; Traction

resistance=5 kg/tones. (N -12)

7. (i)Define specific energy consumption and discuss the factors that affects the specific energy

consumption of trains operation at a given schedule speed. (N -12)

(ii)Explain regenerative braking when used for DC series traction motors. How does it differ from the

regenerative braking as used for shunt motors? (N -12)

8. (i) Draw the speed time curve of a traction system. Also explain various speeds and actions

(N -13)

(ii) Explain the various electric traction systems (N -13)

9. (i) List the requirements of electric traction system (A -14)

(ii)Explain about multi motor speed control (A -15)

10. Explain the DC series traction motor control. (A -14)

11. Explain in detail about the various types of electric drives.

12. Explain the factors governing the selection of motors.

UNIT - II : ILLUMINATION ENGINEERING

1. Define – Light Light may be defined as that radiant energy in form of waves which produces a sensation of vision upon human eye.

2. Define – Luminous Flux Luminous flux is defined as the energy in the form of light waves radiated per second from a luminous body. Eg for a luminous body is an incandescent lamp.

3. Define – Illumination or Illuminance or Degree of Illumination When the light falls on the surface it is illuminated. The illuminance is defined as the luminous flux received per unit area. Let the incident luminous flux on a small area dA be dF then

Illuminance= dF/dA= lumens/area.

4. Define – Lumen (A –14, N -14) Lumen is the unit of flux and is defined as the luminous flux per unit angle from a source 1 candle power. Lumens= candle power x solid angle= candle power x ω

5. Define – Candle Power Candle power is the number of lumens per unit solid angle. Candle power= lumens/ω.

6. Define – Plane Angle When two straight lines lying in the same plane meet at a point, there will be an angle between these converging lines at the meeting point. This angle is termed as plane angle. The plane angle is represented by radians.

7. What is solid angle? The angle subtended by a point in space by an area is termed as solid angle. This solid angle represents the volume which is enclosed by numerous lines lying on the surface and meeting at a point. It is denoted by the symbol ω.

8. Define – Luminous Intensity The luminous intensity is the measure of luminous flux in lumens emitted per unit solid angle by a point source and is denoted by I, I = Φ/ω

9. What are the two laws of illumination? i. Inverse square law. ii. Lambert’s cosine law.

10. State inverse square law.

This law states that illumination of a surface is inversely proportional to the square of the distance of the surface from the source of light, under the condition that source is the point source.

11. State Lambert’s law. This law states that illumination of a surface at any point is dependent upon the cube of cosine of the angle between the line of flux and the normal at that point.

12. Define – Brightness or Luminance. It is defined as the flux emitted per unit area or the luminous intensity per unit projected area of the

source in a direction perpendicular to the surface. The unit of brightness is candles per sq.m.

13. Define – Utilization Factor in the design of the lighting scheme Utilization factor is defined as the total lumens utilized on working plane to the total lumens radiated by lamp.

14. Define – Waste Light Factor When a surface is illuminated by number of lamps, there is certain amount of wastage due to overlapping of light waves. Its value for rectangular areas= 1.2. Irregular areas= 1.5.

15. Mention any two uses of flood lighting. i. Flood lighting is used for enhancing the beauty of old monument. ii. It is used for advertisement and for illuminating sports stadium, quarries, and railway yards

16. Mention some of the reflectors commonly used in industrial lighting. i. Standard reflectors.

ii. Diffusing fitting. iii. Concentrating reflectors.4Angle reflectors.

17. Define – Luminous Efficacy. (N -12, A -13) The ratio of the total luminous flux to the total radiant flux of an emitting source.

18. List the type of lighting system. (A -13, N -14) Incandescent, Tungsten-halogen, Compact Fluorescent Lamps, Tubular fluorescent fixtures, High- intensity discharge (HID)

19. List the various factors for designing the lighting scheme. The various factors should be taken into consideration for designing the lighting scheme are i. Space height ratio ii. Utilization factor iii. Depreciation factor iv. Waste light factor

20. What is the importance of street lighting system? (N -12) i. To reduce the occurrence of accident. ii. To avoid the theft

21. Specify any four energy efficient lamps (N -13) Energy efficient fluorescent lamps, Compact Fluorescent Lamps, Metal Halides Lamps, LED

‘

22. Why tungsten is used as filament material (N -13) Pure tungsten has properties including the highest melting point (3695 K), lowest vapour pressure, and greatest tensile strength out of all the metals.

23. List the types of lamps. (A - 14) Sodium vapour lamps, fluorescent lamp, neon lamp, mercury vapour lamp

24. How does operation of a fluorescent tube differ when it is used on ac and dc supply? (A – 15)

Fluorescent lamps can run directly from a direct current (DC) supply of sufficient voltage to strike an arc. The ballast must be resistive, and would consume about as much power as the lamp. When operated from DC, the starting switch is often arranged to reverse the polarity of the supply to the lamp each time it is started; otherwise, the mercury accumulates at one end of the tube. Fluorescent lamps are (almost) never operated directly from DC for those reasons. Instead, an inverter converts the DC into AC and provides the current-limiting function for electronic ballasts.

25. If the total lumens required are 7200 and coefficient of utilization is 0.3, calculate lamp lumens required. (A -15)

PART – B (16 Marks)

1. (i) Discuss laws of illumination and its limitations in actual practice. (A -14, A -15)

With the neat diagram explain the construction and working of CFL lamp. (A -15)

2. Describe the construction and principle of operation and application of a.Filament lamp. b.

Sodiumvapour lamp. c. Fluorescent lamp.

3. Explain the working of high pressure mercury vapour lamp with a neat sketch. (D –12, A -14)

4. Explain the various factors to be taken into account for designing schemes for

1. Street lighting.

2. Flood lighting.

3. High way lighting. (N -12, N -13, A -14)

5. (i) Explain the various steps followed in the calculation of illumination for designing the

residential lightning. (A -15)

(ii) Explain how you proceed to design a choke and a capacitor for a fluorescent tube?

6. i) A hall 30m long and 12m wide is to be illuminated and the illumination require is 50 lumens per

m 2 calculate the number of fitting required taking depreciation factors of 1.3 and utilisation factor

of 0.5. Given that the outputs of different types of lamp or given below. (N -14)

Watts 100 200 300 500 1000

Lumens 1615 3650 4700 9950 21500

(ii) Explain the factors affecting the design of lighting system. (M –13)

7. (i) A lamp of uniform intensity of 200 C.P is enclosed dins glass globe. 25% of light emitted by

lamp is absorbed by the globe. Determine the brightness of globe, C.P of globe if diameter of globe

is 30cm. (A -13)

(ii).A lamp of 500CP is placed 2m below a plane mirror which reflects 80% of light falling on it.

Determine illumination at a point 5m away from the foot of the lamp which is hung 5m above the

ground. (N -12)

8. A 2000 square metre shop floor area of an engineering industry is to be illuminated with a light level of

200 lux with 250 watts metal halide lamp fittings .The coefficient of light utilisation is 0.6 and depreciation

is 1.2 .Calculate the no of lamp fittings required and total lighting power required Luminous efficacy of

metal halide lamps is90 lumens per watt (N -13)

9. Two street lamps are 20m apart and fitted with 500C.P lamp at a height of 8m above the ground

each. Find the illumination at a point (i) Under the lamps each. (ii)Mid way between the lamps.

(N -14)

10. Design the street lighting of a road of 300m long which is required to be illuminated by providing

40W fluorescent lamp. The width of a road is 4 m. Illumination is 0.6 lux. Assume the efficacy

of lamp as 70Lumen/Watt. (A -15)

UNIT – III : HEATING AND WELDING

1. Why the electric heating is considered to be superior when compared to the other methods of heating?

i. Cleanliness ii. Ease of control iii. Uniform heating. iv. Low attention and maintenance cost.

2. Write short notes on indirect resistance heating. In this method the current is passed through a high resistance wire known as heating element. The heat produced due to I2R loss in the element is transmitted by radiation or convection to the body to be heated. This method is used in room heater, immersion water heaters, and in various types of resistance ovens and salt bath furnaces.

3. Write short notes on direct resistance heating. In this method of heating, current is passed through the body to be heated. The resistance offered by the body to the flow of current produces ohmic losses I2R which results in heating the body. This method is quite efficient and therefore it is employed in resistance welding, in the electrode boiler for heating water and in the salt furnace.

4. What are the requirements of a good heating material? (A -14, N -14) i. High specific resistance ii. High melting point iii. Free from oxidation iv. Low temperature coefficient of resistance.

5. What is the principle of arc furnace? When voltage across s two electrodes separated by an air gap is increased, a stage is reached when voltage gradients in the air gap is such that air in the gap becomes good conductor of electricity. Arc is said to exist when electric current passes through the air gap.

6. What are the characteristics of induction heating? i. The current flows on the outer surface of the metal disc and in so doing, heats this surface. ii. The current flow is restricted axially to the surface of the metal which is contained within the

turn. iii. The heat energy is transferred to the metal at a rapid rate, much faster than any conventional

method of heating metal. iv. The heat energy is generated within the metal without any physical contact between the

source of electrical energy and the metal being heated. v. If the current continues to flow in the disc, the surface would attain extremely higher

temperatures which can’t be obtained by any other method.

7. Differentiate core type and coreless type induction furnaces.

Core type Coreless type

The leakage reactance is very high No leakage reactance

Crucible of any shape can be used Standard form is used

Operation cost is high Operation cost is low.

8. What are the advantages of Ajax Wyatt furnace?

i. Good operating conditions for the refractory lining, no part of the furnace being hotter than the metal itself. ii. Accurate temperature control, uniform castings, minimum metal losses.

9. What is the principle of dielectric heating? When an insulating material is subjected to an alternating electric field, the atoms get stressed and due to the inter atomic friction heat is produced.

10. What are the advantages of dielectric heating? i. This method of heating non conducting material can be done in the fast manner.

ii. Normally material heated by this method is combustible which cannot be heated by the flame.

11. What is meant by welding? Welding is a process where in metals are joined together by fusion.

12. List the advantages of electric heating. (M–13, A -14) The main advantages of electric heating over other systems of heating such as coal, oil or gas heating are given below.

Economical, Cleanliness, Absence of flue gases, Ease of control or adaptation Automatic protection, Upper limit of temperature Special heating features, High efficiency of utilisation Better working conditions, Safety, Heating of non-conducting materials

13. Classify the methods of electric heating. Kinds of electric heating

Power frequency heating High frequency heating

Resistance heating i)Direct resistance heating ii)Indirect resistance heating iii)Infrared heating

Arc heating i)Direct arc heating ii)Indirect arc heating

Induction heating i)Direct induction heating ii)Indirect induction heating

Dielectric heating

14. What is meant by indirect resistance heating? 1. In this method, the current is passed through a high resistance wire known as heating element. The heat produced due to I2R loss in the element is transmitted by radiation or convection to the body to be heated.

2. Applications are room heaters, in bimetallic strip used in starters, immersion water heaters and in domestic and commercial cooking and salt bath furnace.

15. What are the causes of failure of heating elements? Principle causes are Formation of hot spots

1. General oxidation of the element and intermittency of operation 2. Embrittlement caused by grain growth 3. Contamination of element or corrosion

16. What is the basic principle of induction heating? It works on the principle of electromagnetic induction as same as a transformer. It has a metal disc surrounded by a copper coil in which a.c supply is flowing. The disc has a finite value of diameter and thickness and is spaced a given distance from the coil and concentric to it. We find that a secondary current is caused to circulate around the outer surface of the disc.

17. What are the different types of resistance welding? The different types are as follows i..Butt welding ii. Spot welding iii. Projection welding iv. Seam welding

vi. Percussion welding

18. Compare DC welding and AC welding.

Sl.No. Factors D.C welding A.C welding

1 Equipment Motor-generator set or rectifier is required in case of availability of a supply; otherwise oil generator set is required.

Only a transformer is required.

2 Prime Cost Two or three times of transformer.

Comparatively low

3 Operating efficiency Low High 85%

4 No-Load voltage Low Too high

5 Power factor High Low

6 Heating Uniform heating Non-uniform heating

7 Arc stability Higher -

8 Arc blow Pronounced Not so pronounced with AC

19. What is meant by resistance welding? (A -13) Electric resistance welding (ERW) refers to a group of welding processes such as spot and seam welding that produce coalescence of faying surfaces where heat to form the weld is generated by the electrical resistance of material vs. the time and the force used to hold the materials together during welding.

20. Give the methods of control temperature in arc furnace? (D –12) i. Changing the resistance of elements.

ii. Changing the applied voltage to the elements (or) current passing through the elements.

iii. Changing the ratio of the on-and-off times of the supply.

21. List some steps taken to minimize skin effect in induction heating? (N -12) i. By using copper-clad steel wire ii. By using low frequency iii. By reducing the thickness of the laminate or strips iv. By using hollow conductor

22. Mention the applications of dielectric heating. (N -13) Plastic welding, plastic preheating, textile drying, wood glue drying, food drying, post bake moisture removal, pasteurisation, sterilisation, preheating.

24. What is meant by electric arc welding? What are the different types of electrodes used and Its applicability? (A -14) / (N -14)

Arc welding is a type of welding that uses a power supply to create an electric arc between an electrode and the base material to melt the metals at the welding point. They can use either direct (DC) or alternating (AC) current, and consumable or non-consumable electrodes. purpose is to join two metals. Fabrication, ship building and riveting.

24. Mention the factors which limit the choice of frequency in induction and dielectric heating? (A -15) Induction Heating: a) Thickness of the surface to be heated b) Time of continuous heating c) Temperature. Dielectric Heating: a) Thickness b) Potential gradient c) breakdown voltage d) insulation 25. What is meant by arc welding and also list its types? (A –15)

Arc welding is a type of welding that uses a power supply to create an electric arc between an electrode and the base material to melt the metals at the welding point. Different types of arc welding are Flux-cored arc welding (FCAW), Gas metal arc welding (GMAW),Gas tungsten arc welding (GTAW), Plasma arc welding, Shielded metal arc welding, Submerged arc welding.

PART – B (16 Marks)

1. (i) Draw a neat sketch of induction furnace and explain its working. (A -15)

(ii) an insulating material 2 cm thick and 150 sqcm in area is to be heated by dielectric heating. The

material has a permittivity of 4 and p.f. as 0.04.Power required is 400W and frequency of

40Mhz.Determine the voltage and the current that will flow through the material, if the voltage were

limited to 700V,what will be the frequency to get same loss. (A -15)

2. Explain with neat sketch the principle and operation application and control methods of Ajax

Wyatt furnace. (A -14)

3. (i) Explain the principle of arc welding and the difference between carbon and metal arc welding

and their relative merits and demerits. (A -15)

(ii) Explain the characteristic of welding transformer. (A -15)

4. Discuss in detail about any two types of resistance welding. (N -14)

5. Explain the process & various methods of electric arc welding. (A -13)

6. (i) A furnace consuming 5Kw take 15 mins to just melt 2.5kg of aluminium. The initial temperature

being 15° C. Find the efficiency of the furnace when the specific heat of aluminium is

0.212cal/gm/°C. Melting point is 658°C and latent heat of fusion is 320J/gm.

(ii) What is the difference of AC welding & DC Welding? (A -13)

7. (i) Explain the working of coreless induction furnace and list its merits. (N -12)

(ii) Calculate the time taken to melt 3 metric tones of steel in a three phase arc furnace having

the following data: current=5000A, Arc voltage=60V, Resistance of transformer=0.003 ohms;

Reactance of transformer=0.005 ohms, Melting point of steel=1370 c; initial temperature of

steel=18 Assume overall efficiency as 60%. (N -12)

8. (i)Explain the various types of electric arc welding. (N -12)

(ii)Explain the principle and working of welding transformer. (N -12)

9. (i) Explain the method of controlling temperature in resistance heating? (N -13)

(ii) What are the requirements of good welding? (N -13)

10. Determine the efficiency of a high frequency induction furnace which takes 10 minutes to melt

1.815kg of aluminium. The input to the furnace being 5KW and the initial temperature 15 Degree

centigrade, Specific heat of aluminiuA -0.212K Cal/KgoC, Melting point- 660 Degree centigrade,

Latent heat of fusion of aluminiuA -76.8K Cal/Kg.

(A -14)

UNIT - IV : SOLAR RADIATION AND SOLAR ENERGY COLLECTORS

1. Define – Solar Collector

A Solar Collector is a device for collecting solar radiation and transfers the energy to a fluid passing

in contact with it. Utilisation of solar energy requires solar collectors.

2. What are the different types of solar collectors?

Solar collectors are classified into two types, they are

(i) Non-concentrating or flat plate type solar collector

(ii) Concentrating (Focusing) type solar collector.

3. What are the different types of concentrating type solar collector?

The main types of Concentrating (Focusing) type solar collector are

(i) Parabolic trough collector

(ii) Mirror Strip reflector

(iii) Fresnel Lens collector

(iv) Flat Plate collector with adjustable mirror

(v) Compound parabolic concentrated (CPC)

(vi)

4. What are the different types of Flat-Plate type solar collector?

The Flat plate solar collectors may be divided into two main classification based on the type of heat

transfer fluid. They are,

(i) Liquid heating collector and

(ii) Solar air heater.

5. What are major components of Flat plate collector?

The majority of the flat plate collector have five main components as follows:

(i) A transparent cover

(ii) Tubes, Fins, Passages or Channel

(iii) Absorber Plate

(iv) Insulation

(v) Casing or Container.

6. What are the main advantages of concentrator system over flat plate system?

(i) It can be used for electric power generation, because of high temperature of working fluid

obtained.

(ii) The heat storage cost will be less, because of the high temperature attainable and high

temperature storage made possible.

(iii) Solar Heating and cooling applications system can attain higher efficiencies

(iv) Anti-freeze and other liquid to protect the absorbers may not be required.

7. What are the disadvantages concentrator system over flat plate system?

(i) Non uniform flux on the absorber can not be avoided.

(ii) Costly tracking system may be necessary for higher CR

(iii) Only beam radiation is collected and diffuse component cannot be reflected and is thus lost.

(iv) Maintenance is difficult and costs more specially to keep reflecting surfaces clean and bright.

8. Define – Heat Removal factor(FR)

Heat Removal factor(FR) is defined as the ratio of actual useful energy collected to the useful

energy collected if the entire collector absorber surface were at the temperature of the fluid

entering the collector.

Heat Removal factor(FR) = Actual useful energy collected/ Useful energy collected if the entire collector absorber surface were at the temperature of the fluid entering the collector.

9. State Wien’s Law.

Wien’s Law states that, the emission increases with temperature. The re-emitted light is so

progressively shorter wavelength and greater energy as the temperature of blackbody increases.

This is expressed by Wien’s Law, which can be written as,

λ max T = Constant = 2989μm Kelvin

where, λ—wavelength

T—Temperature of the black surface in K.

10. State Planck’s Law.

Planck’s Law states that the spectral emissive power of a black surface is given by

1/exp

2

2

5

1

TC

Ceb

Where, C1 and C2 are constants whose values are 0.596x10-16 M-m2 and 0.014387m-K resoectively, λ—wavelength and T—Temperature of the black surface in K.

11. State Stefan- Boltzmann Law.

The Stefan- Boltzmann Law is obtained by integrating Planck’s law overall the wavelengths from 0

to and states that the emissive power of a black surface is given by 4Teb

Where, T—Temperature of the black surface in K

-- constant called the Stefan- Boltzmann constant = 5.670x10-18W/m2-K4.

12. Define – Solar Constant

The Solar constant Isc is the rate at which energy is received from the sun on a unit area perpendicular to the rays of the sun, at the mean distance of the earth from the sun. Based on experimental investigation and subsequent measurement, the value of Isc is 1367W/m2 has been recommended.

13. Define the following terms.

(i) Direct radiation: Solar radiation received at the earth’s surface without change of direction, ie.,

in line with the sun is called Beam or direct radiation.

(ii) Diffuse Radiation: The radiation received at the earth’s surface from all parts of the sky’s

hemisphere (after being subjected to scattering in the admosphere) is called diffuse radiation.

(iii) Global Radiation: The sum of the beam radiation and diffuse radiation is referred as total or global radiation.

14. Define – Air Mass

Air Mass is often used as a measures of the distance travelled by beam radiation through the

atmosphere before it reaches a location on the earth’s surface. It is defined as the ratio of the

mass of the atmosphere through which the beam radiation passes to the mass it would pass

through if the sun is directly overhead. ( ie., at its zenith).

15. Name the instruments used to measure the solar radiation and sunshine.

Solar radiation flux is usually measured with the help of a pyranometer or a pyrheliometer. The duration of bright sunshine in a day measured by means of a sunshine recorder.

16. What are the different types of Air heaters?

Basically air heaters are classified into the following two categories,

(i) Non- Porous type air heaters

(ii) Porous type air heaters.

17. How the performance of Air heater is improved?

Performance of of Air heater is improved by,

(i) Roughing the rear of the plate to promote turbulence and improve the convective heat transfer

co efficient.

(ii) Adding fins to increase the heat transfer surface, usually turbulence is also increasedwith enhances the convective heat transfer.

18. List some of the applications of Solar Air heaters.

The Solar Air heaters are used for the following processes:

(i) Heating Building

(ii) Drying agricultural produce and lumber

(iii) Heating green houses

(iv) Using air heaters as the heat source for a heat engine which as Brayton or Stirling Cycle.

19. List the advantages of Flat-Plate Collectors.

(i) It uses both the beam and diffuse solar radiation.

(ii) They do not require orientation towards the sun

(iii) They require the little maintenance.

(iv) They are the mechanically simpler than the concentrating reflectors, absorbing surface and orientation devices of focusing collectors.

20. Give the relationship between transmissivity, reflectivity and absorptivity.

0

Where, transmissivity

-- reflectivity

absorptivity

Case(i): For Opaque surface, = 0

Case (ii): For Perfectly transparent, =1

21. What are the different losses occur in solar collector?

(i) Conductive losses,

(ii) Convective losses and

(iii) Radiative losses

22. Write down the energy balance equation for solar collector.

The energy balance equation on the whole collector can be written as,

sludbc QQQHRHRA

Where, Qu—Rate of useful heat transfer to a working fluid in the solar heat exchanger.

Ql—Rate of energy loss

Qs—Rate of energy storage in the collector.

23. Define – Collector Efficiency

Collector Efficiency ( c ) is a collector performance and it is defined as the ratio of the useful gain

over any time period to the incident solar energy over the same time period.

HRdT

dTQuc

24. Define – Fin Eficiency

Fin Eficiency is used to indicate the effectiveness of a fin in transferring a given quantity of heat.

Fin efficiency is defined as,

Fin Eficiency = .etemperaturbaseatwereareafinentireiftransferedbewouldwhichHeat

transferedheatActual

25. Mention the temperature range of different types of solar collectors.

Types of Solar Collectors Concentration ratio Typical working temperature range ( C)

Flat Plate Collector 1 ≤70

High efficiency flat plate collector

1 60 – 120

Fixed Concentrator 3 – 5 100 – 150

Parabolic trough collector 10 – 50 150 – 350

Parabolic dish collector 200 – 500 250 – 700

Central receiver 500 - >3000 500 - > 1000

26. What are the different types of heat transfer mechanism?

Heat transfer occurs by three basic mechanisms

1. Radiation,

2. Conduction and

3. Convection

27. Define – Concentration Ratio

It is the ratio of the effective are of the aperture to the surface area of the absorber.

28. Define – Selective Surface.

A selective surface is a surface that has a high absorptance for short wave radiation (less than 2.5μm) and low emittance of long wave radiation ( more than 2.5μm)

29. State Snell’s law.

The incident and refracted beams are related to each other by Snell’s law which states that,

1

2

2

1

n

n

Sin

Sin

Where, θ1= angle of incidence

θ2 = angle of refraction

n1, n2 = refractive indices of the two medium.

30. What are the properties of materials used in Flat-Plate type solar collector?

The following three properties considered for selecting materials for Flat-Plate type solar

collector

(i) Thermo- physical,

(ii) Physical and

(iii) Environment properties.

PART – B (16 Marks)

1. What are the reasons for variation in solar radiation reaching the earth than received at the outside

of the atmosphere? Explain.

2. Write short notes on Beam and Diffuse radiation.

3. Define the terms (i) Altitude angle. (ii) Incident angle, (ii) Zenith angle, (iv) Solar azimuth angle, (v)

Latitude angle, (vi) Declination angle and (vii) Hour angle.

4. Calculate the angle made by the beam radiation with the normal to a flat plate collector, pointing

due south located in New Delhi (28 38’ N, 77 17’ E) at (:00 hour, solar time on December 1. The

collector is tilted at angle 36 with the horizontal.

5. Calculate the sunset hour angle and day length at location latitude of 35 N, on February 14.

6. What is the difference between a Pyrheliometer and a pyranometer? Describe the principle of

Angstrom type Pyrheliometer.

7. Estimate the daily global radiation on a horizontal surface at Baroda (22 13’ N, 73 13’ E) during

the month of March. If constants a and b are given equal to 0.28 and 0.48 respectively and average

sunshine hours for day are 9.5

8. Explain the principle of conversion of solar energy into heat.

9. What are the main components of a flat plate solar collector, explain the function of each.

10. How solar air collectors are classified? What are the main applications of a drier?

11. Enumerate the different types of concentrating type collectors.

12. Why orientation is needed in concentrating type collectors? Describe the different methods of sun

tracking.

13. What are the advantages and disadvantages of concentrating collectors over a flat plate collector?

14. Enumerate the different main applications of solar energy. Describe a hot water supply system.

UNIT - V : WIND ENERGY

1. Define – Wind

Wind results from air motion. Air in motion arises from a pressure gradient. The circulation of

air in the atmosphere is caused by the non- uniform heating of the earth’s surface by the sun.

2. Why utilisation of wind is considered as part of solar technology?

The major forcing function causing surface winds from the poles toward the equator is

convective circulation. Solar radiation heats the air near the equator, and this low density

heated air is buoyed up. At the surface it is displaced by cooler more dense higher pressure

air flowing from the poles. In the upper atmosphere near the equator the air thus tends to flow

back towards the poles and away from the equator. The net result is a global convective

circulation with surface winds from north to south in the northern hemisphere. It is clear from

the above explanation that the wind is basically caused by the solar energy irradiating the

earth. This is why utilisation of wind is considered as part of solar technology.

3. What are the different causes of local winds?

Local winds are caused by two mechanisms, they are

(i) Differential heating of land and water

(ii) Air heating in hills and mountain sides.

4. Give the relationship between wind speed and height.

Wind speeds increase with height. They have traditionally been measured at a standard height

of 10m where they are found to be 20 – 25% greater than close to the surface. At the height of

60m they may be 30 – 60% higher because of the reduction in the drag effect of earth’s

surface.

5. What are the factors that determine the output from a wind energy converter?

The following three factors determine the output from a wind energy converter

(i) The wind speed

(ii) The cross section of wind swept by rotor

(iii) The overall conversion efficiency of the rotor, transmission system and generator

6. What are the conversion losses available in wind energy conversion system?

A 100% efficient aerogenerator would be able to convert upto a maximum 60% of the available energy in wind into mechanical energy. Well- designed blades will typically extract 70% of the theoretical maximum, but losses incurred in the gearbox, transmission system and generator or pump could decrease overall wind turbine efficiency to 35% or less.

7. Give the expression for available wind power.

Available wind power )(8

1 32 wattsVDP

Where, ρ—Density of Air (ρ= 1.225kg/m3 at sea level)

N -Circular Diameter in horizontal axis aeroturbines.

V—Velocity of Air

8. Define – Power Co-efficient

The fraction of the free flow wind power that can be extracted by a rotor is called the Power

Co-efficient.

Power Co-efficient = Power of wind rotor / power available in the wind.

The maximum theoretical value of power co-efficient is equal to 16/27 or 0.593.

9. What are the advantages of selecting sites with annual mean wind speeds and building larger

wind generator rather than smaller wind generator?

(i) The power available in the wind increases as the cube of the wind speed; doubling the

wind speed increases the power available by eight fold

(ii) Doubling the diameter of the turbine’s rotor quadruples the swept area and hence the

power output from the device.

10. Write the energy flow equation in terms of wind energy conversion.

In WECS, considering the incoming air between ‘i’ and ‘a’ as a thermodynamic system and

assuming that air density remains constant, potential energy is zero and no heat or work are

added or removed between ‘i’ and ‘a’, the general energy equation reduces to the kinetic and

flow energy terms only. Thus, c

a

a

c

i

ig

VvP

g

VvP

22

22

Where, Pv -- Flow energy

cg

V

2

2

__ Kinetic energy

11. Write down the condition for maximum power generation in wind energy conversion system.

The condition for maximum power generation in wind energy conversion system is given by

22

4

1,0 eiei

ce

VVVVAg

PwheredV

dP

023 2 ieie VVVV , Solving the above quadratic equation we get ie VV and

,3

1ie VV only the second solution is physically acceptable. Thus, opteV

iV3

1

12. Write down the expression for maximum power generated for an ideal wind turbine with

horizontal axis.

Pmax = totali

c

PPandAVg

595.027

8max

3 where c

totalg

P2

1 3

iAV

13. What are the different types of forces acting on propeller type wind turbine?

There are two types of forces which are acting on the blades, They are

(i) Circumferential force- acting in the direction of wheel rotation that provides the torque.

(ii) Axial force- acting in the direction of wind stream that provides an axial thrust that must be

counteracted by proper mechanical design.

14. What is the function of backup in small producers?

For small producers, back up can take the form of

(i) Battery storage

(ii) Connection with the local electricity distribution system

(iii) A standby generator powered by liquid or gaseous fuels.

15. What are the mechanisms for producing forces from wind?

There are two primary mechanisms for producing forces from wind, they are

(i) Lift force

(ii) Drag force

16. Define – Stalling

When lift force decreases and the drag force increases quite substantially. This phenomenon is known is stalling. For efficient operation, a wind turbine blade needs to function with as much lift and as little drag as possible, because drag dissipates energy.

17. Define – Airfoil

Lift forces are produced by changing velocity of the air stream flowing over either side of lifting surface. Speeding up the air flow causes the pressure to drop, while slowing the air stream down leads to increasing pressure. This pressure difference produces a force that begins to act on the high pressure side and moves towards the low pressure side of the lifting surface which is called Airfoil.

18. Define – Magnus Effect

Magnus Effect caused by spinning a cylinder in an air stream at the high speed of rotation. The spinning slow down the air speed on the side where the cylinder is moving into wind and increases it on the other side, the result is similar to an airfoil. This principal has been put to practical use in one or two cases but it is not generally employed.

19. Define – Thwaits slot

To blow air through narrow slots in a cylinder, so that it emerges tangentially; this is known as a Thwaits slot. This also creates a rotation of air flow, whch in turn generate lift. Because the lift drag ratio of airfoils is generally much better than those of rotating or slotted cylinders, the latter techniques probably have little practical potential.

20. What are the factors affects the nature of the wind in earth surface?

The factors which affect the nature of the wind close to the earth surface, they are

(i) Latitude of the place,

(ii) Altitude of the place,

(iii) Topography of the place,

(iv) Scale of the hours, months or year.

21. Give some important factors consider for site selection of WECS.

(i) High annual average wind speed

(ii) Availability of anemometry data

(iii) Altitude of the proposed site.

(iv) Terrain and its aerodynamics

(v) Local ecology

(vi) Nearness of site to local centre/users.

22. What are the major components of WCS?

The major components of WCS are

(i) Aeroturbine

(ii) Gearing

(iii) Coupling

(iv) Generator and

(v) Controller

23. What are the broad classification of WECS?

There are two broad classifications of WECS, they are

(i) Horizontal axis machines and

(ii) Vertical axis machines.

24. List the advantages of WECS.

The advantages of wind energy are,

(i) It is a renewable source of energy,

(ii) Non-polluting,

(iii) Avoid fuel provision and transport,

(iv) Small scale upto few KW system is less costly.

25. List the Disadvantages of WECS.

The disadvantages of wind energy are,

(i) Wind energy available in dilute and fluctuating in nature.

(ii) Unlike water energy wind energy needs storage capacity because of its irregularity,

(iii) WECS are noisy in operation, and

(iv) Large areas are needed, typically propellers 1 to 3m in diameter, delivers power in the 30 to 300 watts range.

26. What are the different types of Horizontal axial machines.

(i) Horizontal axis using two aerodynamic blades

(ii) Horizontal axis propeller type using single blade

(iii) Horizontal axis multibladed type.

(iv) Horizontal axis wind mill- Dutch type.

(v) Sail type.

27. List some advantages and disadvantages of horizontal axis propeller type using single blade.

Advantages:

(i) Simple blade controls

(ii) Counter weight costs less than the second blade

(iii) Counter weight can be inclined to reduce blade coning

(iv) Pitch bearing do not carry centrifugal force.

Disadvantages:

(i) Vibration produced due to aerodynamic torque

(ii) Unconventional appearance

(iii) Large blade root bending moment

(iv) Starting torque reduced by ground boundary layer.

28. Define – Tip Speed Ratio (TSR)

The ratio of the speed of the rotor blade tips to the speed of the wind is called Tip Speed Ratio.

TSR= V

Vtip

29. Define – Solidity

Solidity is normally defined as the fraction of the total circumference that contains blade,

numerically it can be expressed as, S=D

NC

Where, N-- Number of blades

C—Average breadth of a blade

D—Diameter of the circle described by a blade.

30. Define – Torque Co-efficient

Torque Co-efficient is defined as maxT

TCT

Where, T—Shaft torque

Tmax—Torque at maximum efficiency.

31. Give some advantages of vertical axis wind turbine over horizontal axis wind turbine.

(i) They will react to wind from any direction and therefore do not need yawing equipment to

turn the rotor into wind

(ii) They can require less structural support because heavy components (like gearbox and

generator) can be locates at the ground level

(iii) Require less maintenance and easy installation.

(iv) Since the blade do not turn end over end, the rotor is not subjected to continuous cyclic gravity loads.

32. What are the different types of vertical axis wind turbines?

(i) Savonious rotor type machines and

(ii) Darrieus type machine.

33. Give different scheme for electric generation by WECS.

(i) Constant Speed Constant Frequency systems (CSCF)

(ii) Variable Speed Constant Frequency systems (VSCF)

(iii) Variable Speed Variable Frequency systems (VSVF)

34. Give some environmental effects due to wind turbine.

The following are the main effects due to a wind turbine,

(i) Electromagnetic Interference,

(ii) Noise,

(iii) Visual effects

(iv) Bird Life and Risk.

PART – B (16 Marks)

1. What is the basic principle of Wind energy conversion?

2. Derive the expression for power developed due to wind.

3. Prove that in case of horizontal axis wind turbine maximum power can be obtained when: Exit

velocity = 1/3 times wind velocity and .27

8 3

max AVP

4. Wind at 1 standard atmospheric pressure and 15 C temperature has a velocity of 10m/s. The

turbine has diameter of 120m and its operating speed in 40 rpm at maximum efficiency.

Calculate : (a) the total power density in the wind stream, (b) the maximum obtainable power

density assuming η= 40%, (c) the total power produced (in KW) and (d) the torque and axial

thrust.

5. Describe the main considerations in selecting a site for wind generators.

6. Describe with a neat sketch the working of a wind energy system (WECS) with main

components.

7. How are WEC system classified? Discuss in brief.

8. Discuss the advantages and disadvantages of WECS?

9. Describe horizontal axis type aerogenerators.

10. Discuss the advantages and disadvantages of horizontal and vertical axis windmill. What

methods are used to overcome the fluctuating power generation of windmill?

11. Write short notes on:

(i) Applications of wind energy, giving neat sketches.

(ii) Savonius rotor

(iii) Darrius rotor

(iv) Wind energy storage.

12. Describe the different schemes for wind electric generation or describe the generating systems.

Also describe the generator control schemes.