distributed loads

17
Distributed Loads Strip Loads (L/B > 9) Wall Footings Embankements Circular Loads (R) Storage Tanks Rectangular Loads (BxL) Spread Footings Mat Foundations Combination Loads

Upload: latona

Post on 10-Jan-2016

41 views

Category:

Documents


0 download

DESCRIPTION

Distributed Loads. Strip Loads (L/B > 9) Wall Footings Embankements Circular Loads (R) Storage Tanks Rectangular Loads (BxL) Spread Footings Mat Foundations Combination Loads. Strip Load Fig 5.12. D p/q= fn {2x/B, 2z/B} See Table 5.4. Stress Isobars. Fig 5.14. Example 5.5. - PowerPoint PPT Presentation

TRANSCRIPT

Page 1: Distributed Loads

Distributed Loads

Strip Loads (L/B > 9) Wall Footings Embankements

Circular Loads (R) Storage Tanks

Rectangular Loads (BxL) Spread Footings Mat Foundations

Combination Loads

Page 2: Distributed Loads

Strip LoadFig 5.12

p/q= fn {2x/B, 2z/B} See Table 5.4

Page 3: Distributed Loads

Stress Isobars

Page 4: Distributed Loads

Fig 5.14

Example 5.5

q=200 kN/m2, B=6m, z=3m

Page 5: Distributed Loads

Circular LoadsFig 5.15

/q=1-1/[(R/z)2+1]3/2

/q = fn {z/R} (Table 5.5)

Page 6: Distributed Loads

Circular LoadsFig 5.16

Page 7: Distributed Loads

Rectangular LoadsFig 5.17

/q = I2

I2 = fn {m=B/z, n=L/z} Fig 5.18

Page 8: Distributed Loads

Variation of I2

Page 9: Distributed Loads

Rectangular LoadsFig 5.19

A/ q = (I 2-1+ I 2-2+ I 2-3+ I 2-4)

Principle of Superposition

Page 10: Distributed Loads

Stress Isobars

Page 11: Distributed Loads

Combined AreasFig 5.22

Page 12: Distributed Loads

Combined AreasFig 5.23

Page 13: Distributed Loads

Newmark’s Chart

z

= (IV) q M

Page 14: Distributed Loads

Example 5.7

Page 15: Distributed Loads

Example 5.7

Z=3m

=(IV) q M

= 0.005 (600kN/9m2)(48.5) = 17.78 kN/m2

Page 16: Distributed Loads

Newmark’s Chart

Page 17: Distributed Loads

Rectangular LoadsFig 5.19

C’