do now: a 2.25 cm object is 8.5 cm to the left of a concave mirror of 5.5 cm focal length. 1. find...

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Do Now: A 2.25 cm object is 8.5 cm to the left of a concave mirror of 5.5 cm focal length. 1. Find the image position 2. Find the image height

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Page 1: Do Now: A 2.25 cm object is 8.5 cm to the left of a concave mirror of 5.5 cm focal length. 1. Find the image position 2. Find the image height

Do Now:

A 2.25 cm object is 8.5 cm to the left of a concave mirror of 5.5 cm focal length.

1. Find the image position2. Find the image height

Page 2: Do Now: A 2.25 cm object is 8.5 cm to the left of a concave mirror of 5.5 cm focal length. 1. Find the image position 2. Find the image height

Do Now:

A 3.5 cm object is 9 cm to the left of a concave mirror of 6 cm focal length. The image is located 18 cm from the mirror. Find the image height.

Page 3: Do Now: A 2.25 cm object is 8.5 cm to the left of a concave mirror of 5.5 cm focal length. 1. Find the image position 2. Find the image height

Do Now (5/14/12):1. Copy the following diagram exactly

onto your paper. 2. Draw a ray diagram and locate the

image3. Is the image reduced or enlarged?4. Is the image upright or inverted?

C F

Page 4: Do Now: A 2.25 cm object is 8.5 cm to the left of a concave mirror of 5.5 cm focal length. 1. Find the image position 2. Find the image height

Single Mirror Propertiesdo di m imagedo>C C>di>f Reduced,

invertedReal

C>do>f di>C Enlarged, inverted

Real

f>do (negative)

Enlarged Virtual

oi dd

For mirrors:

Page 5: Do Now: A 2.25 cm object is 8.5 cm to the left of a concave mirror of 5.5 cm focal length. 1. Find the image position 2. Find the image height

Lenses

Page 6: Do Now: A 2.25 cm object is 8.5 cm to the left of a concave mirror of 5.5 cm focal length. 1. Find the image position 2. Find the image height

LensA piece of transparent material

used to focus light and form an image◦Convex: thicker at the center◦Concave: thinner at the center

Page 7: Do Now: A 2.25 cm object is 8.5 cm to the left of a concave mirror of 5.5 cm focal length. 1. Find the image position 2. Find the image height

Lens Equations – same as Mirror Equations!

Thin Lens Equation

Magnification

io ddf

111

o

i

o

i

d

d

h

hm

Page 8: Do Now: A 2.25 cm object is 8.5 cm to the left of a concave mirror of 5.5 cm focal length. 1. Find the image position 2. Find the image height

Image Formation:

Page 9: Do Now: A 2.25 cm object is 8.5 cm to the left of a concave mirror of 5.5 cm focal length. 1. Find the image position 2. Find the image height

Ray Diagrams Step 1:

Page 10: Do Now: A 2.25 cm object is 8.5 cm to the left of a concave mirror of 5.5 cm focal length. 1. Find the image position 2. Find the image height

Ray Diagrams Step 2:

Page 11: Do Now: A 2.25 cm object is 8.5 cm to the left of a concave mirror of 5.5 cm focal length. 1. Find the image position 2. Find the image height

Ray Diagrams

Page 12: Do Now: A 2.25 cm object is 8.5 cm to the left of a concave mirror of 5.5 cm focal length. 1. Find the image position 2. Find the image height

D. Image at F

Page 13: Do Now: A 2.25 cm object is 8.5 cm to the left of a concave mirror of 5.5 cm focal length. 1. Find the image position 2. Find the image height

E. Object in front of F

Page 14: Do Now: A 2.25 cm object is 8.5 cm to the left of a concave mirror of 5.5 cm focal length. 1. Find the image position 2. Find the image height

Tomorrow:Short quiz on diagrams:

◦One mirror diagram◦One lens diagram

Bring any work you have done so far on your next art piece; I will have materials also

Page 15: Do Now: A 2.25 cm object is 8.5 cm to the left of a concave mirror of 5.5 cm focal length. 1. Find the image position 2. Find the image height

Practice:Complete BOTH SIDES of the

Lens Diagram sheet; it is due by the end of class

Once you finish, you may work on homework or Mirror diagram sheets

Prepare for quiz tomorrow

Page 16: Do Now: A 2.25 cm object is 8.5 cm to the left of a concave mirror of 5.5 cm focal length. 1. Find the image position 2. Find the image height

Do Now (5/15/12):1. Copy the following lens diagram

exactly onto your paper. 2. Draw a ray diagram and locate the

image3. Is the image reduced or enlarged?

upright or inverted? Real or virtual?

C FF

Page 17: Do Now: A 2.25 cm object is 8.5 cm to the left of a concave mirror of 5.5 cm focal length. 1. Find the image position 2. Find the image height

Do Now (5/17/12): Fill in the blank

1. Dispersion is the splitting of _________ into its _____________.

2. The index of refraction “n” is always greater than _______.

3. The speed of light is constant in _____.

4. ___________does not change as light moves to another medium.

Page 18: Do Now: A 2.25 cm object is 8.5 cm to the left of a concave mirror of 5.5 cm focal length. 1. Find the image position 2. Find the image height

Unit 5: LightThe electromagnetic spectrum

◦ Types of rays◦ Uses◦ Approximate sizes

Light behavior◦ Reflection◦ Refraction◦ Diffraction/dispersion

Mirrors◦ Equations◦ diagrams

Lenses ◦ Equations (same as mirror)◦ Diagrams

Page 19: Do Now: A 2.25 cm object is 8.5 cm to the left of a concave mirror of 5.5 cm focal length. 1. Find the image position 2. Find the image height

Practice:Use the rest of class to work on

your review packetIt is due next Friday, but

remember… this is a very big unit and you will not come to this class every day next week! Use this time to review

You may also work on your art piece

If you need any previous slide shows, please let me know

Page 20: Do Now: A 2.25 cm object is 8.5 cm to the left of a concave mirror of 5.5 cm focal length. 1. Find the image position 2. Find the image height

Do Now (5/18/12):

Pass in your Do Now’s and wait quietly for instructions. Happy Friday!