do now solve. course 2 7-8 populations and samples 2. n/6 – 9 = 16 hwk: 65 1. -2n + 20 = 44

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Do Now Solve. Course 2 7-8 Populations and Samples 2. n/6 – 9 = 16 Hwk: 65 1. -2N + 20 = 44

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Page 1: Do Now Solve. Course 2 7-8 Populations and Samples 2. n/6 – 9 = 16 Hwk: 65 1. -2N + 20 = 44

Do NowSolve.

Course 2

7-8 Populations and Samples

2. n/6 – 9 = 16

Hwk: 65

1. -2N + 20 = 44

Page 2: Do Now Solve. Course 2 7-8 Populations and Samples 2. n/6 – 9 = 16 Hwk: 65 1. -2N + 20 = 44

EQ: How do I compare and analyze sampling methods?

Course 2

7-8 Populations and Samples

GPS: M7A2a Given a problem define a variable, write an equation, solve the equation, and interpret the solution.

Page 3: Do Now Solve. Course 2 7-8 Populations and Samples 2. n/6 – 9 = 16 Hwk: 65 1. -2N + 20 = 44

VocabularyPopulation – entire group of objects or

individuals considered for a surveySample – part of a populationRandom sample – sample in which each

individual or object in the entire population has an equal chance of being selected

Course 2

7-8 Populations and Samples

Page 4: Do Now Solve. Course 2 7-8 Populations and Samples 2. n/6 – 9 = 16 Hwk: 65 1. -2N + 20 = 44

convenience sample – sample based on members of the population that are readily available.

biased sample – does not fairly represent the population

Page 5: Do Now Solve. Course 2 7-8 Populations and Samples 2. n/6 – 9 = 16 Hwk: 65 1. -2N + 20 = 44

Course 3

Samples and Surveys

Sampling Method

How Members are Chosen

Random By chance

Systematic According to a rule or formula

Stratified At random from randomly chosen subgroups

Convenience Easiest to reach

Voluntary-response

Members choose to be in the sample

Page 6: Do Now Solve. Course 2 7-8 Populations and Samples 2. n/6 – 9 = 16 Hwk: 65 1. -2N + 20 = 44

In 2002, there were claims that Chronic Wasting Disease (CWD), or Mad Elk Disease, was spreading westward across North America. In order to verify claims such as these, the elk population had to be tested.

When information is gathered about a group, such as the elk in North America, the entire group is called the population. Because testing each member of a large group can be difficult or impossible, researchers often study a part of the population, called a sample.

Course 2

7-8 Populations and Samples

Page 7: Do Now Solve. Course 2 7-8 Populations and Samples 2. n/6 – 9 = 16 Hwk: 65 1. -2N + 20 = 44

Course 2

7-8 Populations and Samples

For a random sample, members of the population are chosen at random. This gives every member of the population an equal chance of being chosen. A convenience sample is based on members of the population that are readily available, such as 30 elk in a wildlife preservation area.

A random sample is more likely to be representative of a population than a convenience sample is.

Helpful Hint

Page 8: Do Now Solve. Course 2 7-8 Populations and Samples 2. n/6 – 9 = 16 Hwk: 65 1. -2N + 20 = 44

Determine which sampling method will better represent the entire population. Justify your answer.

Additional Example 1: Analyzing Sampling Methods

Course 2

7-8 Populations and Samples

Sampling methodMaria surveys only the band students she knows personally.

Results84% want blue uniforms

Jon writes each band student’s name on a card. He questions those students whose name he draws.

61% want blue uniforms

Jon’s sample is a random sample, giving every band member equal chance to be surveyed, so it is the better method.

Page 9: Do Now Solve. Course 2 7-8 Populations and Samples 2. n/6 – 9 = 16 Hwk: 65 1. -2N + 20 = 44

Determine which sampling method will better represent the entire population. Justify your answer.

Check It Out: Example 1

Course 2

7-8 Populations and Samples

Sampling methodFerdinand surveys every other swimmer on the team.

Results72% want practice early

Anna-Maria questions the swimmers who are in her Biology class.

50% want practice early

Ferdinand’s sample is a random sample, giving results that better represent the entire swimming team, so it is the better method.

Page 10: Do Now Solve. Course 2 7-8 Populations and Samples 2. n/6 – 9 = 16 Hwk: 65 1. -2N + 20 = 44

Course 3

9-1 Samples and Surveys

Additional Example 1A: Identifying Sampling Methods

Identify the sampling method used.

In a county survey, Democratic Party members whose names begin with the

letter D are chosen.

systematic The rule is to survey members whose names begin with D.

Page 11: Do Now Solve. Course 2 7-8 Populations and Samples 2. n/6 – 9 = 16 Hwk: 65 1. -2N + 20 = 44

Course 3

9-1 Samples and Surveys

A telephone company randomly chooses customers to survey about its service.

random Customers are chosen by chance.

Additional Example 1B: Identifying Sampling Methods

Identify the sampling method used.

Page 12: Do Now Solve. Course 2 7-8 Populations and Samples 2. n/6 – 9 = 16 Hwk: 65 1. -2N + 20 = 44

Course 3

9-1 Samples and Surveys

A high school randomly chooses three classes from each grade and then draws

three random names from each class to poll about lunch menus.

stratified The three classes are the random subgroups. Names are chosen

randomly from within the classes.

Additional Example 1C: Identifying Sampling Methods

Identify the sampling method used.

Page 13: Do Now Solve. Course 2 7-8 Populations and Samples 2. n/6 – 9 = 16 Hwk: 65 1. -2N + 20 = 44

Course 3

9-1 Samples and Surveys

Check It Out: Example 1A

Identify the sampling method used.

In a county survey, families with 3 or more children are chosen.

systematic The rule is to survey families with 3 or more children.

Page 14: Do Now Solve. Course 2 7-8 Populations and Samples 2. n/6 – 9 = 16 Hwk: 65 1. -2N + 20 = 44

Course 3

9-1 Samples and Surveys

Check It Out: Example 1A

Identify the sampling method used.

In a county survey, families with 3 or more children are chosen.

systematic The rule is to survey families with 3 or more children.

Page 15: Do Now Solve. Course 2 7-8 Populations and Samples 2. n/6 – 9 = 16 Hwk: 65 1. -2N + 20 = 44

Course 3

9-1 Samples and Surveys

Check It Out: Example 1A

Identify the sampling method used.

In a county survey, families with 3 or more children are chosen.

systematic The rule is to survey families with 3 or more children.

Page 16: Do Now Solve. Course 2 7-8 Populations and Samples 2. n/6 – 9 = 16 Hwk: 65 1. -2N + 20 = 44

A biased sample does not fairly represent the population. A study of 50 elk belonging to a breeder could be biased because the breeder’s elk might be less likely to have Mad Elk Disease than elk in the wild.

Course 2

7-8 Populations and Samples

Page 17: Do Now Solve. Course 2 7-8 Populations and Samples 2. n/6 – 9 = 16 Hwk: 65 1. -2N + 20 = 44

Determine whether each sample may be biased. Explain.

Additional Example 2: Identifying Potentially Biased Samples

A. The mayor surveys 100 supporters at a rally about the most important issues to be addressed by the city council.

Course 2

7-8 Populations and Samples

The sample is biased. The supporters may have different ideas than those not at the rally.

B. The principal sends out questionnaires to all of the students to find out what kind of music students prefer at dances.The sample is random. The students all have a chance to respond.

Page 18: Do Now Solve. Course 2 7-8 Populations and Samples 2. n/6 – 9 = 16 Hwk: 65 1. -2N + 20 = 44

Determine whether each sample may be biased. Explain.

Check It Out: Example 2

Course 2

7-8 Populations and Samples

A. The owner of a record shop surveys only customers over the age of 18 who shop at his store.This is not random. Customers under the age of 18 do not have a chance of being chosen.

B. The teacher writes the name of each student on a piece of paper and questions the students whose names are drawn.

This sampling method is random. Each student has an equal chance of being chosen.

Page 19: Do Now Solve. Course 2 7-8 Populations and Samples 2. n/6 – 9 = 16 Hwk: 65 1. -2N + 20 = 44

Course 3

Samples and Surveys

People attending a baseball game were asked if they support the construction of a new

stadium in the city.

City residents

People attending a

game

People that attend a baseball game are

more likely to support the construction of a

new stadium.

Check It Out: Example 2C

Identify the population and the sample. Give a reason why the sample could be biased.

Population Sample Possible Bias

Page 20: Do Now Solve. Course 2 7-8 Populations and Samples 2. n/6 – 9 = 16 Hwk: 65 1. -2N + 20 = 44

Course 3

9-1 Samples and Surveys

Eighth-grade students with a 3.0 GPA or higher were polled to determine how long

students study each day.

Eighth grade students

Students with 3.0 or higher

GPA

Students with lower grades are less likely

to study as long.

Check It Out: Example 2B

Identify the population and the sample. Give a reason why the sample could be biased.

Population Sample Possible Bias

Page 21: Do Now Solve. Course 2 7-8 Populations and Samples 2. n/6 – 9 = 16 Hwk: 65 1. -2N + 20 = 44

Course 3

9-1 Samples and Surveys

Check It Out: Example 2A

The first 5 people leaving a movie theater at a sneak preview were asked how they liked

the movie.

People that went to the

movie

The first five people that

left

People that really enjoy a movie are

less likely to be one of the first ones to

leave.

Population Sample Possible Bias

Identify the population and the sample. Give a reason why the sample could be biased.

Page 22: Do Now Solve. Course 2 7-8 Populations and Samples 2. n/6 – 9 = 16 Hwk: 65 1. -2N + 20 = 44

A principal of a school with 1,500 students estimates that about 400 students will attend a band festival on Saturday. A random sample of 25 students showed that 6 of them will attend. Determine whether the principal’s estimate is likely to be accurate.

Additional Example 3: Verifying Claims Based on Statistical Data

Course 2

7-8 Populations and Samples

Set up a proportion to predict the total number of students that will attend.

Students attending sample # of Students sampled

Students attending Student Population

=

Page 23: Do Now Solve. Course 2 7-8 Populations and Samples 2. n/6 – 9 = 16 Hwk: 65 1. -2N + 20 = 44

Additional Example 3 Continued

Course 2

7-8 Populations and Samples

6 25

x 1500

=

360 = x

The estimate is not accurate because the data shows that 360 students are likely to attend.

Page 24: Do Now Solve. Course 2 7-8 Populations and Samples 2. n/6 – 9 = 16 Hwk: 65 1. -2N + 20 = 44

The owner of a large chain restaurant with 1,200 employees estimates that about 250 employees will ask for winter vacation. A random sample of 40 employees showed that 8 of them will ask for the time off. Determine whether the owner’s estimate is likely to be accurate.

Check It Out: Example 3

Course 2

7-8 Populations and Samples

Set up a proportion to predict the total number of students that will attend.

Employees surveyed for time off # of Employees surveyed

Employees asking for time off Total # of Employees

=

Page 25: Do Now Solve. Course 2 7-8 Populations and Samples 2. n/6 – 9 = 16 Hwk: 65 1. -2N + 20 = 44

Check It Out: Example 3 Continued

Course 2

7-8 Populations and Samples

8 40

x 1200

=

240 = x

The estimate is accurate because the data shows that 240 employees will ask for time off.

Page 26: Do Now Solve. Course 2 7-8 Populations and Samples 2. n/6 – 9 = 16 Hwk: 65 1. -2N + 20 = 44

a. A TV ratings service is surveying residents of Orlando who bought TVs in the last month about their favorite TV show.

b. A TV ratings service called residents of Orlando randomly selected from the phone directory to conduct a survey about their favorite show.

TOTD

Course 2

7-8 Populations and Samples

b1. Determine which sample better represents the

entire population.

Page 27: Do Now Solve. Course 2 7-8 Populations and Samples 2. n/6 – 9 = 16 Hwk: 65 1. -2N + 20 = 44

2. Determine whether each sample may be biased. Explain.

TOTD

Course 2

7-8 Populations and Samples

Biased; at other times of the day, customers may have different preferences.

a. A convenience store surveys customers one morning to determine what products they may like the store to stock.

b. Each student’s name is written on a slip of paper and placed in a box. One slip of paper is selected to determine the student to be the homeroom representative.Not biased; the sample is random.

Page 28: Do Now Solve. Course 2 7-8 Populations and Samples 2. n/6 – 9 = 16 Hwk: 65 1. -2N + 20 = 44

3. A local middle school has 2500 students. Morgan interviewed 75 of the students about their library habits. She found that 45 of the students checked out a book weekly. Predict the number of students likely to check out books weekly.

TOTD

Course 2

7-8 Populations and Samples

1500