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Energy Review
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• The unit for kinetic energy.• Joule
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• The quantity represented by the kilowatt hour.Answer: Electric energy
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• The unit for charge.• Answer:Coulomb
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• The equation for power• Answer: P=IV
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• In the equation for Ohm’s Law, represented by the “I”
• Answer: Current
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• The equation to solve for current which includes charge and time.
• Answer: I = q/t
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• The equation for Ohm’s Law• Answer: V=IR
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• The rate at which energy is consumed• Answer: Power
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• The definition of electric current. • Answer: flow of electric charge
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• The relationship between current and resistance.
• Answer: direct
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• The quantity that slows down current in a circuit
• Answer:resistance
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• The unit for power.• Answer: watt
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• The quantity that expresses the amount of energy in a charge
• Answer: voltage
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• The flow of positive charges in a circuit• Answer: conventional current
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• The current through the starter motor of a car is 120 A. If the battery maintains 10 V across the motor, how much electric energy is delivered to the starter in 10 s? (Hint: calculate power first)
• Answer: Find power• P=IV=120 A(10V)=1200 W• Find Energy E=Pt E=1200 W(10s)=12,000J
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• In the equation for Coulomb’s Law, represented by the letter “q”
• Answer: charge
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• The type of relationship shown between current and voltage
• Answer:direct
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• The type of circuit in which one pathway exists• Answer:series
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• The quantity that represents potential difference.
• Answer:voltage
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• A flashlight bulb is rated at 9.0 W. If the light bulb drops 3.0 V, how much current goes through it?
• Answer: P=IV9.0W = I(3.0V)I=3 A
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• A drawing of a circuit using symbols• Answer: schematic
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• The outcome of adding resistors in a circuit when voltage does not change.
• Answer: decrease in current
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• The letter that represents resistance in Ohm’s Law.
• Answer: R
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• The symbol that represents a battery in a circuit
Answer:
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• The type of circuit in which total resistance is greater than a single resistor
• Answer: series
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• The total voltage drop across each resistor in a parallel circuit is ____ the total voltage in the circuit.
• Answer: equal to
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• The unit for resistance.• Answer: ohms
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• The current through a light bulb connected across the terminals of a 125 V outlet is 0.5 A. How much power is supplied to the bulb?
• Answer: » P=IV» P=(0.5A)(125V)» P=62.5 W
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• The connection required for a voltmeter. • Answer: Parallel
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• A lamp uses 6.0 V and 12 W when it is operating. What is the current through the lamp?
• Answer: P=IV12W=I(6.0V)I=2A
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• A 15 ohm and a 5 ohm resistor are connected in series. What is the equivalent resistance?
• Answer: 20 ohms
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• The behavior of current in a parallel circuit. • Answer: Adds up to total
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• A device for measuring current. • Answer: ammeter
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• Draw a parallel circuit with three lamps in parallel, and a battery.
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• Three types of energy which electric energy can be converted to
• Answer: sound, light, heat
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• A device for measuring voltage. • Answer: voltmeter
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• Type of circuit in which current is the same through each branch.
• Answer: series
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• The type of connection used for an ammeter• Answer: series
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• An outlet that prevents injuries that are caused when an electric appliance falls into water. It contains an electric circuit that detects an extra current path and opens the circuit.
• Answer: ground fault interrupter
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• The symbol for a resistor in a circuit.• Answer: Ώ
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• An automatic switch that opens when the current reaches a value greater than the rated value in the circuit.
• Answer: circuit breaker
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• A mobile source of electric power• Answer: battery
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• The man who created the first battery to produce a lasting current
• Answer: Volta
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• Type of circuit in which voltage is the same through each branch.
• Answer: parallel
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• The current that passes through a 6 ohm resistor and uses 12 V.
• Answer: V=IR» 12V=I (6.0 ohms)» I=2A
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• Draw a series circuit with one lamp, battery and ammeter.
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• The purpose of a resistor in a circuit.• Answer: decrease current
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• The flow of electric charge• Answer: current
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• One way in which current can be increased in a circuit.
• Answer: increase voltage or decrease resistance