Transcript
Page 1: Fall 2006Costas Busch - RPI1 Regular Expressions

Fall 2006 Costas Busch - RPI 1

Regular Expressions

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Regular ExpressionsRegular expressions describe regular languages

Example:

describes the language

*)( cba

,...,,,,,*, bcaabcaabcabca

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Recursive Definition

,,

1

1

21

21

*

r

r

rr

rr

Are regular expressions

Primitive regular expressions:

2r1rGiven regular expressions and

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Examples

)(* ccbaA regular expression:

baNot a regular expression:

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Languages of Regular Expressions : language of regular expression

Example

rL r

,...,,,,,*)( bcaabcaabcacbaL

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Definition

For primitive regular expressions:

aaL

L

L

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Definition (continued)

For regular expressions and

1r 2r

2121 rLrLrrL

2121 rLrLrrL

** 11 rLrL

11 rLrL

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ExampleRegular expression: *aba

*abaL *aLbaL *aLbaL *aLbLaL

*aba ,...,,,, aaaaaaba

,...,,,...,,, baababaaaaaa

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Example

Regular expression bbabar *

,...,,,,, bbbbaabbaabbarL

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Example

Regular expression bbbaar **

}0,:{ 22 mnbbarL mn

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Example

Regular expression *)10(00*)10( r

)(rL = { all strings containing substring 00 }

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Example

Regular expression )0(*)011( r

)(rL = { all strings without substring 00 }

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Equivalent Regular Expressions

Definition:

Regular expressions and

are equivalent if

1r 2r

)()( 21 rLrL

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Example L= { all strings without substring 00 }

)0(*)011(1 r

)0(*1)0(**)011*1(2 r

LrLrL )()( 211r 2rand

are equivalentregular expressions

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Regular Expressionsand

Regular Languages

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Theorem

LanguagesGenerated byRegular Expressions

RegularLanguages

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LanguagesGenerated byRegular Expressions

RegularLanguages

LanguagesGenerated byRegular Expressions

RegularLanguages

Proof:

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Proof - Part 1

r)(rL

For any regular expression

the language is regular

LanguagesGenerated byRegular Expressions

RegularLanguages

Proof by induction on the size of r

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Induction BasisPrimitive Regular Expressions: ,,Corresponding NFAs

)()( 1 LML

)(}{)( 2 LML

)(}{)( 3 aLaML

regularlanguages

a

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Inductive Hypothesis Suppose that for regular expressions and , and are regular languages

1r 2r)( 1rL )( 2rL

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Inductive StepWe will prove:

1

1

21

21

*

rL

rL

rrL

rrL

Are regular Languages

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By definition of regular expressions:

11

11

2121

2121

**

rLrL

rLrL

rLrLrrL

rLrLrrL

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)( 1rL )( 2rLBy inductive hypothesis we know: and are regular languages

Regular languages are closed under:

*1

21

21

rL

rLrL

rLrL Union

Concatenation

Star

We also know:

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Therefore:

** 11

2121

2121

rLrL

rLrLrrL

rLrLrrL

Are regularlanguages

)())(( 11 rLrL is trivially a regular language(by induction hypothesis)

End of Proof-Part 1

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Using the regular closure of these operations,we can construct recursively the NFA that accepts

M)()( rLML

Example: 21 rrr )()( 11 rLML

)()( 22 rLML

)()( rLML

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For any regular language there is a regular expression with

Proof - Part 2

LanguagesGenerated byRegular Expressions

RegularLanguages

Lr LrL )(

We will convert an NFA that accepts to a regular expression

L

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Since is regular, there is aNFA that accepts it

LM

LML )(

Take it with a single final state

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From construct the equivalentGeneralized Transition Graphin which transition labels are regular

expressions

M

Example:

a

ba,

cM

a

ba

c

CorrespondingGeneralized transition graph

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Another Example:

ba a

b

b

0q 1q 2q

ba,a

b

b

0q 1q 2q

b

bTransition labels are regular expressions

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Reducing the states:

ba a

b

b

0q 1q 2q

b

0q 2q

babb*

)(* babb

Transition labels are regular expressions

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Resulting Regular Expression:

0q 2q

babb*

)(* babb

*)(**)*( bbabbabbr

LMLrL )()(

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In GeneralRemoving a state:

iq q jqa b

cde

iq jq

dae* bce*dce*

bae*

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0q fq

1r

2r

3r4r

*)*(* 213421 rrrrrrr LMLrL )()(

The resulting regular expression:

By repeating the process until two states are left, the resulting graph is

Initial graph Resulting graph

End of Proof-Part 2

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Standard Representations of Regular Languages

Regular Languages

DFAs

NFAsRegularExpressions

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When we say: We are given a Regular Language

We mean:

L

Language is in a standard representation

L

(DFA, NFA, or Regular Expression)


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