GameBoard Force and Motion
Forces Newton Free Body Diagrams
Friction
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400
500
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GameBoard Force
100 AContact Force
-push
-pull
Field Force
-gravity
-electrical
-magneticContact Forces
Frictional Force = FfrictTensional Force = FtensNormal Force = Fnorm
Air Resistance Force = FairApplied Force = FappSpring Force= Fspring
GameBoard Force
300
Analyze the following scenario and give the forces involved: A car being pulled by a towing cable.
Answer
GameBoard Force
400Solve for the components of the net force on a 5 kg balloon moving upward at 2.0 m/s2 at 25o.
Answer
GameBoard Newton
100
Explain the cause of acceleration. Provide the law that explains this
principle.
Answer
GameBoard
Newton
200
The term Newton uses in his first law to explain an objects tendency to maintain
its state of motion.
Answer
GameBoard
Newton
200A
Inertia
An object at rest stays in rest, an object in motion stays in motion, unless acted on
by an unbalanced force.
GameBoard Newton
300
A hammer drives a nail into a piece of wood. Identify the action-reaction pair in this
situation. Which of Newton’s laws explains this situation?
Answer
GameBoard Newton
300 A
The hammer exerts a force on the nail: the wood exerts a force on the wood.
Newton’s 3rd Law
GameBoard Newton
400As a basketball player starts to jump for a rebound, the player begins to move upward faster and faster until his shoes leave the floor. Describe the force of the floor on the shoes in relation to Fg at the moment the
player begins to jump.
Answer
GameBoard Newton
500A 1856 kg truck is moving to the right at a constant speed of 2.17 m/s2 . What is the net force on the car? What would it be if it
were to move in the opposite direction.
Answer
GameBoard Newton
500 A
Zero, at constant velocity the acceleration is zero. Therefore, the net force is zero regardless of
the direction.
GameBoard
Free Body Diagrams100
Describe three things that are represented in a free-body diagram.
Answer
GameBoard
Free Body Diagrams 100A
-the object
-forces as vectors (magnitude and direction)
-forces exerted on the object
GameBoard Free Body Diagrams
200A
In this diagram, there are normal and gravitational
forces on the book.
GameBoard Free Body Diagrams
300
A flying squirrel is gliding (no wing flaps) from a tree to the ground at constant velocity. Consider air resistance. A free body diagram for this situation looks like…
Answer
GameBoard Free Body Diagrams
300A
Gravity pulls down on the squirrel while air resistance keeps the squirrel in the air for a while.
GameBoard
Free Body Diagrams 400
Answer
Create a diagram for a car that runs out of gas and is coasting
down a hill.
GameBoard Free Body Diagrams
400AEven though the car is coasting down the hill, there is still the dragging friction of
the road (left pointing arrow) as well as gravity and
normal forces.
GameBoard Free Body Diagrams
500
Answer
A box is pulled across a surface at an angle, the box
only moves in the x direction. Write the
equations for the sum of the forces in the x and y
directions in terms of the variables in the picture.
GameBoard Friction
100AKinetic friction is the frictional force of an object in motion. Static friction is the frictional force that keeps an object from moving, the minimum amount of force that must be applied for an object to have motion.
GameBoard Friction
200A
μ does not have a unit because it is a ratio of the Force of friction
and the normal force. Therefore, the units cancel out.
GameBoard Friction
300
Answer
What happens to air resistance when an object accelerates? Why is it considered a form of friction?
GameBoard Friction
300 AIn most cases, air resistance
increases with increasing speed. Therefore, friction is a
retarding force so it can be classified as friction because it is opposing or slowing down
the motion.
GameBoard Friction
400
Answer
There are six books in a stack, each book weighs
5N. The coefficient of static friction between the books is 0.2. Determine what the horizontal force must be to begin sliding the top five books off the
bottom one.
GameBoard Friction
500
Answer
An ice skater moving at 10.0 m/s coasts to a halt in 1.0 x 102 m on a smooth ice surface. What is the coefficient of friction between the ice and the skates?
GameBoard
Friction 500A(1) Fx = Ff = ma
(2) Fy = 0, Fn = Fg
(3) Ff = μFn = μFg Fg = mg
Ff = μmg = ma Eq (1) and (3) combined
μmg = ma m cancels out
μg = a….so… μ = a/g
Solve for a….a = -(vi)2/2∆x = - 0.50 m/s2
μ = a/g = 0.50/9.81 = 0.051