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Page 1: MSPrograms Ellipsoidal Searches 199812

Page 8 MineSight®/MEDSYSTEM® BULLETIN December 1998

Technical Support Tips

Ellipsoidal Searches inMEDSYSTEM®

(Used in M620V1, M620V2, M621V1,M624IK, M624V1)

Differences in the structural character ofthe mineralization of an ore deposit alongvarious directions are described byanisotropy. Variograms along differentdirections can determine the existence ofanisotropy.

If anisotropy exists, an ellipse should beused to define a search neighborhood. Theellipse is centered on the point or thecenter of the block being estimated. Theellipse should be oriented with its majoraxis parallel to the direction of maximumcontinuity.

Once you have determined the orientationof the anisotropy axes and the length ofthose axes, you should:

1. Assign PAR1, PAR2 and PAR3 (x, yand z search distances respectively) sothe ellipse is included inside theparallelopiped formed by PAR1, PAR2and PAR3.

2. Assign PAR4 (max allowed searchdistance) equal to the length of themajor axis.

3. Include the ellipse search using thelengths and orientation of axes.

A search will be performed in thefollowing fashion:

1. Composites inside the box formed byPAR1, PAR2 and PAR3 arepreselected.

2. Selection is further limited inside theparallelopiped formed by the major,minor and vertical ellipse axes.

3. The points inside the ellipse:x2 *(RY/RX)2 + y2 + z2 *(RY/RZ)2 ≤ PAR42

are finally kept.

IOP6 (zero for real or one for adjusted)will determine if adjusted or real distanceswill be used and/or reported after theinitial ellipsoidal search.

In the kriging algorithm (M624IK,M624V1), ellipsoidal search and IOP6apply only to the selection of thecomposites, and not to the distances usedin variography. Kriging weights arecalculated from the variogramparameters.

In the IDW algorithm (M620V1,M620V2, M621V1), IOP6 will make adifference in the calculation of weights(weights are based either on true oradjusted distances).

The following example shows how theadjusted distances are calculated (a 2-Dsearch is assumed for simplicity):

Let us assume that two samples exist:

� comp1 along the minor axis of anellipse (40m from the block) and

comp2 inside the parallelogramdefined by major and minor axesbut outside the ellipse (50m from xand y axes; 70.7m direct distancefrom the block).

� a search of 100m (major), 50m(minor), 0m (vertical) with norotation is used.

The adjusted distance for comp1 wouldbe: (100/50)2*402= a2 ⇒ a=80m

The adjusted distance for comp2 wouldbe: (100/50)2*502+(100/100)2*502 = b2 ⇒b=111.8m

If PAR4 equals 100 (=RY), comp1 willbe included in calculations, whereascomp2 will not. If PAR4 were smallerthan 80, comp1 would not have beenconsidered either. If PAR4 were greaterthan 111.8, comp2 would also have beenused.

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