Download - Physics P1,2,3 Melaka 08 Skema
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JABATAN PELAJARAN NEGERI MELAKA
PEPERIKSAAN PERCUBAAN SPM 2008PHYSICS PAPER 1
SKEMA JAWAPAN
1 B 6 D 11 D 16 B 21 C 26 D 31 D 36 C 41 A 46 A
2 A 7 C 12 B 17 A 22 A 27 D 32 A 37 A 42 D 47 C
3 B 8 A 13 B 18 A 23 A 28 A 33 C 38 A 43 D 48 C
4 C 9 C 14 B 19 C 24 C 29 D 34 D 39 B 44 A 49 B
5 B 10 D 15 D 20 C 25 B 30 B 35 C 40 B 45 A 50 E
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PEPERIKSAAN PERCUBAAN MELAKA 2008
MARKING SCHEME : PAPER 2
1(a) Racet 1
(b) The ratchet knob prevents over tightening // avoid extra pressure 1
(c) 1st : 1.5 + 0.35 = 1.85 mm
2nd
: 1.85 (- 0.02) = 1.87 mm
1
1
TOTAL 4
2(a)(i) Bernoullis principle 1
(a)(ii) Y 1
(b) The air moves with a high speed 1
(c) 1st: The atmospheric pressure which is higher pushes the liquid up through the
narrow tube.2nd : The jet air will force the liquid to be sprayed as fine spray liquid
1
1
TOTAL 5
3(a) Velocity = displacementTime
1
(b) Region AB 1
(c)(i) a = 10 0
10 0
= 1 ms-2
1
1
(c)(ii) s = (10)(10) + (10)(10)= 150 m
11
TOTAL 6
4(a)(i) / / 1(a)(ii) 1
st: The radioactive emission enters the tube through the mica window
2nd
:ionizes the neon gas.3rd : The electron and positive ion are attracted towards the anode and cathode
respectively thus produces a pulse of current.
Any two marks
1
2
(b) Background readings // natural radioactivity in the ground, bricks or buildings and 1
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cosmic radiation.
(c) 1st
: show on the graph
2nd
: half life = 4 hours
2
(d) Industries : smoke detectors / detect thickness of papers / detect leaks inunderground pipe water
Medicine : radioactive tracers/ sterilization,/cancer treatment
1
TOTAL 7
5(a) Attraction force 1
(b)(i) same magnitude // opposite direction 1
(b)(ii) Same forces / equal in magnitudes // opposite direction 1
(c)(i) Zero 1
(c)(ii) Equal 1
(d)(i) 1st
: The nett force is zero, the object is stationary
2nd
: The nett force is zero, moves with uniform velocity
1
1
(d)(ii) Equilibrium of forces 1
TOTAL 8
6(a) Heat is a form of energy 1
6(b)(i) Diagram 6.2 is higher // vice versa 1
(b)(ii) The temperature in Diagram 6.2 is higher // vice versa 1
(b)(iii) Volume 1
(b)(iv) When volume is higher, the temperature is higher // directly proportional 1
(c) Charles Law 1
(c)(i) = absolute zero 1
(c)(ii) Volume of air is zero // the air molecules is at rest //kinetic energy is zero 1
TOTAL 8
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7(a)(i) Transverse wave // mechanical wave 1
(a)(ii) The gap is bigger than the wavelength 1
(b) 1st
: smaller amplitude
2nd
: same wavelength
2
(c)(i) 1st
: made of concrete2nd : because concrete is strong
2
(c)(ii) 1st : make many holes on the wall
2nd
: diffraction // spread of energy
2
(d) 1st
: The water is shallow
2nd
: load and unload by using small boats
2
TOTAL 10
8(a) Power = the rate of work done / the rate of energy transformed
@ P = WT
1
(b)(i) 1st : R2 is located at the base terminal
2nd
: to limit the base current
1
1
(b)(ii) 1st
: R1 and LDR are in series2nd : to function as potential divider
11
(b)(iii) 1st
: the collector terminal is connected to positive terminal of the battery2nd : reverse bias
11
(c) Circuit K 1
(d) Light controlled switch/ switches on the bulb at night, switches off the bulb at
daytime.
1
(e)(i) 5 V 1
(e)(ii) VRY = Ry x V
( Rx + Ry)
1000
610001
R
R = 6000 1000 = 5000
1
1
TOTAL 12
State the meaning of symbols
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9(a)(i) Magnetic field is a region of magnetic force. 1
(a)(ii) 1st : The direction of the magnetic field on the left coil is counter/anti clockwise,
/diagram
2nd
: The direction of the magnetic field on the right coil is clockwise // diagram
3rd : As the result the magnetic fields in the middle of the coil are in the same
direction, upward. So the magnetic field will be stronger in the middle
1
1
1
(b)(i) 1st : Both diagram 9.2 and diagram 9.3 have the same pattern of the magnetic
field,ie, circular with the wire in the middle
2nd
: The direction of the magnetic field for Diagram 9.2 is clockwise, while in
Diagram9.3 is counter clockwise/ anti-clockwise.
1
1
(b)(ii) The pattern of the magnetic field in Diagram 9.4 is not uniform compared toDiagram 9.2 and Diagram 9.3
1
(b)(iii) The resultant force acting on the left wire is downward while the resultant force
acting on the right wire is upward / opposite to each other.
1
(b)(iv) 1st
: Instrument which uses the same principle is electrical motor.2nd : The electric motor has 2 forces acting on the opposite side caused by the
counter react between a current carrying conductor in a magnetic field/
diagram
11
(c)(i) 1st : The shape of the magnet is cylindrical
2nd
: It will produce uniform magnetic field
1
1
(c)(ii) 1st
: The coil is placed surrounding/fit to the magnet and it is attached to a cone
2nd : to increase the effectiveness of the counter react between the magnetic fields.
1
1
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(c)(iii) 1st : The cone is made from a light material / paper
2nd : It can easily vibrate
2
(c)(iv) 1st : Type of electrical supply is alternate current power supply
2nd
: The audio signal varies with the current.
2
(c)(v) 1st
: material used for the body of the loudspeaker is metal / wood2nd : to ensure the loudspeaker is strong 2
TOTAL 20
10(a)(i) Real image is an image which can be seen on a screen. 1
(a)(ii) 1st
: the object distance in diagram 10.1 is longer than diagram 10.22nd : the image distance in diagram 10.2 is longer than diagram 10.1
3rd : the size of the image in diagram 10.2 is larger
4th
: the longer the image distance, the bigger the size of the image
5th
: The smaller the object distance the larger the size of the image / the objectdistance is inversely proportional to size of the image.
5
(b) 1st
: The convex lens with its holder is aimed at a distant object like a tree.
2nd
: Adjust a screen until you see a very sharp and clear image of the distantobject.
3rd :When parallel light rays from a distant object pass through a convex lens, theywill converge to a point called focal point/ label on a diagram
4th
: Measure the distance between the convex lens and screen./ label on a diagram
4
(c)(i) 1st : draws the objective and eyepiece lenses.
2nd : correct label of objective and eyepiece
3rd
: label fO and fe correctly
4
th
: draw the correct position for the object ( fo < u1 < 2fo)5th : draw ray diagrams to show the position of image 1
6th
: draw ray diagrams to show the final image
6
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(c)(ii) 1st : Use a concave mirror2
nd: converge light to the microscope.
2
(c)(iii) 1st
: Decrease the object distance / decrease the focal length of the eyepiece lens /decrease the focal length of the objective lens.
2nd
: increase the magnification factor.
2
TOTAL 20
11(a)(i) 240 V, 80 W means the bulb transforms energy of 80 J/s if connected to 240 V
power supply.
1
(a)(ii) 1st
: the resistance of metal Z is constant / The resistance of metal Y is increasing
2nd
: The suitable material to be used as filament of the bulb is metal Y3rd : resistance increases as the temperature increases
4th
: the higher the resistance the brighter the bulb.
4
(b)(i) 1st
: The cross-sectional area is small
2nd
: because it can release more heat/ resistance is higher3rd : Melting point is high
4th
: so it cannot be melt easily at high temperature.
5th
: The specific heat capacity is low
6th : so it can release heat in a shorter time7th : length of the heating element is long
8th
: it can be shaped as a coil and release more heat.
8
(b)(ii) 1st
: The best heating element is L2nd : It has a small cross-sectional area, high melting point, low specific heat
capacity and long.
2
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(c) (i)
5.1
3
1
3
11
R
R
1
1
(c) (ii)
AI 23
6
2
/ V = 46)12
2
(
V
P = )2()2( 22 RI / P =2
422
R
V
= 8 W
1
1
1
TOTAL 20
12(a) Buoyant force is an upward force resulting from an object being wholly orpartially immerse in fluid.
1
(b) 1st : When the ballast tank is filled with water,
2nd
: The buoyant force is smaller than the weight of the submarine. It will
sink/submerges3rd : When the ballast tank is filled with air / when the water pumps out,
4th
: the buoyant force is larger than the weight of the submarine, and it will float.
4
(c) 1st
: Horizontal cross section: front side is narrow and pointed
2nd
: reduce the water resistance3rd : The hull material is made of aluminium4
th: It is lighter and strong
5
th
: Hull ability : hydrodynamic6th : The ability to withstand shock waves, weather collisions and groundings.
7th : Fuel used is diesel
8th
: The cost is cheaper
9th
: The best watercraft is Q10th : because the horizontal cross section of front side is narrow and pointed, the
hull material is made of aluminium, the hull ability is hydrodynamic and the
fuel used is diesel.
1
111
11
1
1
11
(d)(i) W = mg
= (200) (10) = 2000 N
1
1
(d)(ii) W (boat) + W(load) = Vg
2000 + W = (1000) (4) (10)W = 38 000 N
m = 3,800 kg
11
1
TOTAL 20
END OF MARKING SCHEME
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Marking Scheme K3 Fizik Peperiksaan Percubaan SPM 2008
No Marking Criteria Mark
1 (a) (i) Mass//m 1
(ii) Temperature//2 // 1
(iii) Type of liquid// time 1
m/g 1/m/g-1
2/0C /
0C
50 0.020 46.0 16.0
100 0.010 38.0 8.0
150 0.007 35.5 5.5
200 0.005 34.0 4.0
250 0.004 33.0 3.0
(b)
1. label for all the quantities 1
2. state the unit for m, 1/m, 2 and 1
3. all value for 1/m correct 1
4. all value for 2 correct 1
5. all value for correct 1
6. value for 1/m, 2, and consistent decimal point 1
Total 6
(c) 1. at axis-y and at 1/m axis-x 2 correct unit for both axes 3. suitable scale both axes start from zero and
uniform scale
4. all the values plotted correctly 5 or 4 values plotted correctly
5. best straight line 6. size min scale (10 x 8 ) cm 7 ticks 5
5-6 ticks 43-4 ticks 3
2 ticks 2
1 tick 1Total 5
(d) is directly proportional to
m
1 1
(e) Stir the water constantly// position of the eye
perpendicular to the scale of thermometer1
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Total 16
No Marking Criteria Mark 2 (a) (i) A1 1
(ii) A2 1
(b) (i) IB = 0 1
(ii) Ic = 0 1
(c) IB is directly proportional to IC 1
(d) Show on the graph 1
64 mA 1
(e) Draw a large triangle min (4 x 5) cm 1
Correct substitution (follow students triangle)
80 x 10-3
0.5 x 10-6
1
State the answer without unit
1.6 x 105
1
(f) 1. Eyes must be perpendicular to the scale of ammeter 1
2. Switch off the circuit when not taking any reading 1
Total 12
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No Marking Criteria Mark
3 (a)
(b)
(c)(i)
(ii)
(iii)
(iv)(v)
(vi)
(vii)
(viii)
(ix)
The length of catapult rubber depends on the force
The bigger the force, the longer the extension of the catapultrubber
To investigate the relationship between the force and extension ofa spring
Manipulated variable : Force
Responding variable : ExtensionConstant variable : Length of the spring//diameter of the spring
//type of spring
Spring, retort stand, ruler, slotted weight
State a functionable arrangement of the apparatusMeasure the initial length of the spring, l1Put one slotted mass, 20 g/m1 at the end of the spring.
Measure the length of the spring, l2Calculate extension of the spring, x = l2 l1
Repeat the experiment for the mass 40 g, 60 g, 80 g, 100 g.(Repeat at least 4 times)
Tabulate the data
Force(N)/Mass(g) Extension(cm)/Length ofthe spring (cm)
Plot graph of extension /length of spring against force/mass//graphExtension (cm)
1
1
1
1
1
1
1
1
1
1
1
1
Total
12
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Force(N)
No Marking Criteria Mark
4 (a)
(b)(c)(i)
(ii)
(iii)
(iv)
(v)
(vi)
(vii)(viii)
(ix)
The amount of lifted scrap metal depends on the current
The higher the current, the stronger the electromagnetism.To investigate the relationship between the current and the
electromagnetism.
Manipulated variable : CurrentResponding variable : Electromagnetism
Constant variable : Number of turns
Copper wire, soft iron, ammater, rheostat, batteries, pins/paperclips
State a functionable arrangement of the apparatus
Adjust the rheostat to supply a current, I1 / 0.1A
Count the number of pins/paper clips attract by the electromagnetAdjust the rheostat for 4 different current 0.2A, 0.3A, 0.4A and
0.5A.(Repeat at least 4 times)
Tabulate the data
Current(A) Number of pins/paper
clips
Plot graph of number of pins against current // graphNumber of pins
1
1
1
1
1
1
1
1
1
1
1
1
Total
12
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Current(A)