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Lecture 4
January 24, 2018
Statics - TAM 210 & TAM 211
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AnnouncementsMATLAB training sessions
Wed 24, Thu 25, Fri 26, and Mon 29
DCL 1440, Tutorial: 6:30-7:30 pm, Q&A: 7:30-8:00 pm
DRES accommodations
Send a private post with DRES letter on Piazza to Instructors, if you have not already directly contacted Prof. H-W
Upcoming deadlines:
Thursday (1/25)
Written Assignment 1
Friday (1/26)
Mastering Engineering Tutorial3
Tuesday (1/30)
Prairie Learn HW2
![Page 3: Statics - TAM 210 & TAM 211 - University Of Illinois · Mastering Engineering Tutorial3 Tuesday (1/30) Prairie Learn HW2. Recap from Lecture 3](https://reader031.vdocuments.net/reader031/viewer/2022021900/5b5d18e17f8b9a9c398d6a7d/html5/thumbnails/3.jpg)
Recap from Lecture 3
Position vector
Thus, the components of the positon vector r
may be formed by taking the coordinates of the tail
(point A) and subtracting them from the corresponding
coordinates of the head (point B).
Modification to notation introduced in lecture 3:Use rAB (not rBA) to be consistent with PL and
bookrAB
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Force vector directed along a line
The force vector F acting a long the rope can be
defined by the unit vector u (defined the
direction of the rope) and the magnitude F of
the force.
The unit vector u is specified by the position
vector r:
Such that 𝒖 =𝒓
𝒓
where𝒓 = (𝑥𝐵 − 𝑥𝐴) Ƹ𝒊+(𝑦𝐵 − 𝑦𝐴) Ƹ𝒋+(𝑧𝐵 − 𝑧𝐴)𝒌
𝑭 = 𝐹𝒖
Note that 𝒖 is unitless and
points in the direction of 𝒓.
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Force vector directed along a line
The man pulls on the cord with a force of 70 lb.
Represent the force F as a Cartesian vector.
𝑭
𝒖 𝒓
What is the “correct” (as per PrairieLearn
and textbook) notation for the position
vector r shown in green?
A) rAB
B) rBA
i>clicker time
𝒓𝑨𝑩 = (𝑥𝐵 − 𝑥𝐴) Ƹ𝒊+(𝑦𝐵 − 𝑦𝐴) Ƹ𝒋+(𝑧𝐵 − 𝑧𝐴)𝒌
![Page 6: Statics - TAM 210 & TAM 211 - University Of Illinois · Mastering Engineering Tutorial3 Tuesday (1/30) Prairie Learn HW2. Recap from Lecture 3](https://reader031.vdocuments.net/reader031/viewer/2022021900/5b5d18e17f8b9a9c398d6a7d/html5/thumbnails/6.jpg)
Force vector directed along a line
The man pulls on the cord with a force of 70 lb.
Represent the force F as a Cartesian vector.
𝑭
𝒖 𝒓
![Page 7: Statics - TAM 210 & TAM 211 - University Of Illinois · Mastering Engineering Tutorial3 Tuesday (1/30) Prairie Learn HW2. Recap from Lecture 3](https://reader031.vdocuments.net/reader031/viewer/2022021900/5b5d18e17f8b9a9c398d6a7d/html5/thumbnails/7.jpg)
Dot (or scalar) product
𝜃
The dot product of vectors A and B is defined as such
Cartesian vector formulation:
Note that:
Laws of operation:
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The scalar component of a vector along (parallel to) a line with unit vector u is given by:
u
Projection of vector onto parallel
and perpendicular lines
𝜃And thus the vector components and are given by:
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Cross (or vector) product
The cross product of vectors A and B yields the vector C, which is written
The magnitude of vector C is given by:
Geometric definition of the cross product: the magnitude of the cross product is given by the area of
a parallelogram
A
B
𝜃h
The vector C is perpendicular to the plane containing A and B
(specified by the right-hand rule). Hence,
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Laws of operation:
Cross (or vector) product
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The right-hand rule is a useful tool for determining the direction of the vector resulting from a
cross product. Note that a vector crossed into itself is zero, e.g., i i = 0
Cross (or vector) product
Considering the cross product in Cartesian coordinates
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Also, the cross product can be written as a determinant.
Each component can be determined using 2 2 determinants.
Cross (or vector) product