efflux time for a pipe with different exit
TRANSCRIPT
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EFFLUX TIME FORA PIPE WITH
DIFFERENT EXIT
PIPESLapidez, Allison Joy
Pecajas, Chelley Sharleene
Vidal, Gaelian Haryeth
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OBJECTIVES
To determine efflux time needed to drain a tank with a set of exit
pipes with different lengths and diameter
To derive a mathematical correlation between efflux time and the
pipe size and the tank diameter
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THEORY
Efflux
-outward flow, for example, the movement of chemicals or
other fluids from within a structure, such as a cell, to the outside
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TORRICELLIS THEOREM
The speed of liquid coming out through a hole at a depth h below
the free surface is the same as that of a particle fallen freely
through the height h under gravity. The speed of the liquid coming
out is called the speed of efflux.
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THE MATHEMATICAL MODEL
Derived by first considering the mass and mechanical energy
balances
Mass Balance
accumulation = in - out + generation
-Mechanical Energy Balance
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FOR LAMINAR
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FOR TURBULENT
Joye, D.D. and B.C. Barret
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MATERIALS
Efflux time apparatus
Calibrated pail
Stopwatch
Distilled water
Glycerol
Ruler
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SETUP
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PROCEDURE
1. Prepare the needed solutions.
3.5L distilled water
3.5L of 50% glycerol
2. Record the dimensions of the tankand pipes.
3. Prepare the stopwatch.
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PROCEDURE
4. Cover the orifice of the tank, thenslowly pour the water into the tank.
5. Record the time it takes to emptythe tank.
6. Attach pipe 1 to the orifice of the
tank and cover it again using yourhand then fill the tank with water.
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PROCEDURE
7. Allow the water to settle downbefore draining the tank.
8. Record the times at which theliquid level passes height intervals of2 cm.
9. Determine the efflux time. Makethree trials.
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PROCEDURE
10. Repeat steps 6-9 for each pipesize.
11. Repeat steps 4-9 using 50%glycerol solution as the sample.
12. Clean the tank and the pipesusing soap and water.
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Pipe
no. Diameter,cm Length,cm HeightInterval,cmAverageVelocity,cm/s Nre Le1 0.5 75.7 2 0.0532 3.311 0.19866
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0.06()for laminar
4.4()
for turbulent
= 0.0532 cm/s
. . .
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8
ln(1 +
) FOR LAMINAR FLOW
5
ln(1 +
) FOR TURBULENT FLOW:
Tank dimensionsdiameter,cm 16.9radius,cm 8.45
height,cm 20.2
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8(.82
)(75.7 )(8.5 )
(.9987
3) (98
)(.25)
ln(1 +2.2
75.7 )
=21.46 s