ekscentricno naprezanje

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  • 7/23/2019 Ekscentricno Naprezanje

    1/8

    1

    4

    u a33,3I = 4

    v a982,0I = kN166F

    4

    u a917,15I = 4

    v a917,8I = kN26F

    4

    u a908,40I = 4

    v a864,8I = a62,0an = a015,1bn = kN7,35F

    4

    u cm1081I = 4

    v cm175I = cm953,0an =

    cm697,3bn = kN5,60F

    4

    u cm1027I = 4

    v cm583I = cm17,3an = =nb

    kN144F

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    2

    4

    u cm3,7704I = 4

    v cm7,518I =

    cm38,0uD = cm65,5vD = kN676F

    4

    u a17,26I = 4

    v a56,4I = kN03,4F

    4

    u cm7,462I = 4

    v cm105I = kN101F

    4

    u a48I = 4

    v a3

    20I = kN6,106F

    4

    u a65,454I = 4

    v a6,57I = a85,0an = a12,2bn = 2

    max cm/kN34=

    4

    u a3

    20I = 4v a

    6

    37I = a

    36

    37an = a

    6

    5bn =

    2

    max cm/kN88,4=

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    3

    4

    u cm4507I = 4

    v cm1595I = cm84,3an =

    cm124,5bn = kN6,121F

    4

    u cm412I = 4

    v cm55,123I = kN50F

    4

    u a3

    68I = 4v a

    3

    8I = a33,0an = a83,2bn =

    kN3,182F

    4

    u a60I = 4

    v a4I = a33,0an = a745,0bn =

    kN5,201F

    4

    u a17,25I = 4

    v a1,16I = a68,2an = a6,3bn =

    kN4,96F

    4

    u a17,6I = 4

    v a82,3I = a37,11an = a88,0bn =

    cm2a

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    4

    4

    u a667,1I = 4

    v a333,1I = a666,0uD = a834,0vD =

    4

    u a5I = 4

    v a2I = cm33,1uD = cm33,3vD =

    4u cm7,273I =

    4v cm2,179I = kN5,77F

    4

    u cm5,134I = 4

    v cm3,98I = kN44,59F

    4

    u cm3904I = 4

    v cm777I = cm077,2an =

    cm78,4bn = kN6,154F

    4

    u cm9844I = 4

    v cm1546I = cm48,2an =

    cm41,6bn = kN6,219F

    4

    u cm1210I = 4

    v cm35,205I = kN48F

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    5

    4

    u cm33,37I =4

    v cm33,21I = 2cm/kN6,11=

    kN1,73Fkr =

    4

    u cm460I = 4

    v cm3,285I = 2

    D cm/kN9,33=

    4

    u cm3,4338I = 4

    v cm2,3366I = cm92,2an =

    cm95,2bn = 2

    max cm/kN317,0=

    4

    u cm15,5894I = 4

    v cm95,2993I = cm045,13an =

    cm56,8bn = 2

    max cm/kN73,2=

    4

    u a1710I = 4

    v a1674I = a599,1an1 = =n1b

    a599,1an2 = =n2b 2

    max cm/kN42,6=

    4

    ucm1228I = 4

    vcm34,550I = cm594,1a

    n=

    cm3,2bn = kN65,69F

    4

    u cm2962I = 4

    v cm7,622I = cm615,1an =

    cm19,4bn = kN431F

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    7

    4

    u a333,57I = 4

    v a0833,27I = a71,2an1 =

    a896,0bn1 = a231,1an2 = a583,3bn2 = 575,0F

    F

    2

    1 =

    4

    u a667,698I = 4

    v a667,162I = a4525,1an =

    a159,4bn = cm7325,0a

    Greda AB zadatog poprenog preseka optereena silom F

    prema slici.

    a) Odrediti jednainu neutralne linije i skicirati dijagram

    normalnih napona

    b) Odrediti veliinu sile F ako je: l=100 cm, a=2 cm, ||d=10 kN/cm2

    4

    u a6,20I = 4

    v a6,2I = u25,4v = kN6,5F

    4

    u cm4064I = 4

    v cm3284I = cm5,2a n = cm68,3bn = kN6,132F

    4

    u cm4064I = 4

    v cm3284I = cm574,1an =

    cm31265bn = cm067,1a

    4

    u a052,11I = 4

    v a448,1I = cm301,0an = cm658,0bn = kN584,7F

    4

    u a8I = 4

    v a286,1I = a30

    31uD = a2vD = kN44,4F

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    8

    4

    u a134I = 4

    v a5,53I = a981,1an1 =

    a4889,1bn1 = cm981,1an2 = acm722,3bn2 =

    5458,0F/F 2D1D =

    4

    u a67,56I = 4

    v a01,24I = a19,2a n1 =

    a01,1bn1 = a41,1an2 = a05,4bn =

    53,064/34F/F 2D1D ==

    4

    u cm4,869I = 4

    v cm317I = cm177,2an = cm199,2bn = kN58,90Fp kN5,208Fe