electrical engineering cracked style

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Today’s experiment was a delayed one, it was supposed to be done earlier, but it  was done today, si mple enough to explain. It was about unders tanding Kirc hhoff’s rules and its applications in a working circuit. The experiment was a nightmare in recreation, but in all reality, it made its point known, by understanding the concept. It’s a frustration coming from a technician viewpoin t, that I have to rely on the theory of an application to actually have it work, but I suppose Electrical Engineering Theory is the basis for what my other colleagues are learning. I digress, let us dive in. Question 1 asks us to draw a sketch of the schematic for the series configuration, and dictating the current flow, and what the relationship between the current and voltage flow through each resistor. I could copy paste the already drawn circuit and write in big pink letters THIS IS HOW IT WORKS, but I’m not feeling that sarcastic today, so I’ll  just explain it . In circuit A, the fl ow or current mo ves away from the n egative side of th e 10V supply and follows clockwise to the positive side where it begins the cycle once again.  When the flow h its a resistor, the vo lt and current fa lls a wee bit, depen ding on the res istor capabilities. These resistors take off about 3.3 Volts per resistor, which results in an equal system. Question 2 asks us does this validate Kirchhoff’s rules. If I said no then I’d be lying because it does. Oh, and I have to explain my answer. Here is the explanation . The Common conclusion of Physicists everywhere

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7/28/2019 Electrical Engineering Cracked Style

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Today’s experiment was a delayed one, it was supposed to be done earlier, but it 

 was done today, simple enough to explain. It was about understanding Kirchhoff’s rules

and its applications in a working circuit. The experiment was a nightmare in recreation, but 

in all reality, it made its point known, by understanding the concept. It’s a frustrationcoming from a technician viewpoint, that I have to rely on the theory of an application to

actually have it work, but I suppose Electrical Engineering Theory is the basis for what my 

other colleagues are learning. I digress, let us dive in.

Question 1 asks us to draw a sketch of the schematic for the series configuration,

and dictating the current flow, and what the relationship between the current and voltage

flow through each resistor. I could copy paste the already drawn circuit and write in big 

pink letters THIS IS HOW IT WORKS, but I’m not feeling that sarcastic today, so I’ll

 just explain it. In circuit A, the flow or current moves away from the negative side of the

10V supply and follows clockwise to the positive side where it begins the cycle once again.

 When the flow hits a resistor, the volt and current falls a wee bit, depending on the resistor

capabilities. These resistors take off about 3.3 Volts per resistor, which results in an equal

system.

Question 2 asks us does this validate Kirchhoff’s rules. If I said no then I’d be lying 

because it does. Oh, and I have to explain my answer. Here is the explanation.

The Common conclusion of Physicists everywhere

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 And while some of the electrons pass on alleyway A, they either go down alleyway 

B, or alleyway C, only to find out the vagabond analogies apparently have a union meeting,

and they don’t plan on leaving until they have had their fill of canned meat and post war

time stories. In the end, everyone loses something, and the circuit returns to being zero.

It could’ve been summarized like this as well.

Question 4 asks us pretty much what question 1 and 2 asks, except for a parallel

circuit.

The answer is yes, it’s a rule, meaning that it stays adamant despite variation.

Like “No Television” means No Television, not turn on your Xbox and play Xbox.

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Question 5 asks to determine the amount and current flowing between junctions C

and B, if I had a drawing to show you, you would clearly see junction C and B, but instead

I provided you with a dapper elephant. So we will go back to basic explanation. So imagine

the previous analogy, these hardworking electrons returning home from electron school or

a rally for the National Transistor Party,

“We have the capacitance to resist all currents of negative transitions!”

“AMMETER!”

 And they are coming by the droves from the rally, and decide to take whatever path

they choose, A, B, or C. To be honest, the current wouldn’t really change from these

 junction points, because there are more electrons that are following right behind them, so it 

really doesn’t make a bit of difference what path they take, just as long as they vote for

Senator Watt Ohmers

Whose moustache could brush away corruption of a nation

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Question 6 asks ONCE AGAIN to draw a sketch of a circuit, and this time I

actually did. With some minor improve.

We are all parts of the great circuit of Senator Watt Ohmers.

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Question 7 asks us to do algebra to figure out if there are only two

independent loops within the whole loop of the circuit. I refer you to the aforementioned

picture.

Without the whole staring into your soul background….

Of course there are two independent loops, you don’t need algebra to figure that out, look 

at the picture and the known quality of the Kirchhoff Rule. It works because that’s the rule.

 When electrons leave their electron rallies, they run across hobos that take some voltage

from them and return them to zero back at the original rally. If 10 V of electricity leaves

Rally A, and runs across a hobo asking 5 V to take karate lessons to save his family, and 5 V of electricity leaves Rally B and runs across a homeless asking only for 2 V to take Billy 

Blanks Tae Bo to rescue his family, when the two groups meet up at the junction point,

and merge together in their personal shame of being fooled by kung Fu seeking homeless.

The individual groups of 5 and 3 become 8 volts, but then they get Capoeira chopped by 

Eddy Gordo and he takes away 8 Volts as prize money, leaving the charges to go their

separate ways back to the rallies

.

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Forward + Circle, X + Circle, X + Circle, X + Circle, X + Circle, X + Circle, X + Circle

The final question asks us to draw another hypothetical diagram and place

arrows to determine the direction of current flow, and why explain why the current

follows through that path. I have provided you with a cat riding a horse.

Because THIS is ALWAYS applicable to Physics!

I don’t really feel confident in my MS Paint skills; I’m not a DeviantArt artist. So

I’ll just explain through words. It all honestly depends on what the current is, and wherethe power supply is. If you have a power supply below the circuit it will result in a T circuit.

As seen in actual application, FOOL

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If you have multiple power supplies, then it will follow the flow of current from the

negative side of the power supply. Left and Right sided power supplies will result in a T

circuit 

I AM YOUR BASIC ELECTRIC PRINCIPAL FOOL

 Whereas a bottom and left, or bottom and right circuit will also result in a T circuit 

YOU CAN’T ESCAPE THE TRUTH FOOL

 \ 

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 And so I bring to conclusion my dissertation, I hope you enjoyed the writing styles I

have introduced to you, and brought a chuckle to yourself. You will probably take a whole

bunch of points of for not following the typical system, but because of the 1st  Amendment,

I have the right to do so, and technically I answered the entire field question, albeit with

snarky and silly answers.

USA! USA! USA! USA! USA! USA! USA! USA! USA! USA! USA!

Copyright 2013,

Joshua D. Stephens