ell 58tv cf 52- · 2015. 2. 12. · periodic table and chemistry formulas l8 h l_0079) periodic...

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New Jersey Science League " Chemistry II Exam January 2015 YELLOW TEST Answer the following questions on the answer sheet provided. Each correct response is worth 4 points. Use the letters in parentheses for your answers. Choose the letter that best completes or answers the item' Be certain that erasures are complete. Please PRINT your name, school, atea #, and which test you are takins on the scan-tron. 1. The density of marble chips is determined by water displacement method and the following data are obtained. Mass (e) Volume (mL) 4.0 2.0 6.0 3.0 9.0 4.0 t2.0 5.0 15.0 6.0 25.0 10.0 The density of marble is 2.50 glmL. What is the closest to the percent error of the student's experimental determination? A. s.0% B. t5% c.20% D. 83% 2. The photoelectron spectrum (PES) below shows the binding energies for all electrons in neutral element Q. Rsiativ* *tagber cf r}rckaes PES *fekroelrt Q 58tV $etrr 13*S ell The element Q belongs to the Group _ 1** eV of the periodic table. c.14 D. 18 A.2 3. Which has the most C A. 10.0 mg of CaCO3 B.5 atoms? 4. For which pair of species is A. Na and Cl B. 12.0 mg of CaC2 C.4.0 mg of COz D. 8.0 mg of CO the difference in radii the sreatest? B. N/ and Cl- C. N:a* and 52- D. Cf and 52- NfSL Chem II fan 2015 Page 1

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  • New Jersey Science League" Chemistry II Exam January 2015 YELLOW TEST

    Answer the following questions on the answer sheet provided. Each correct response is worth 4 points.Use the letters in parentheses for your answers. Choose the letter that best completes or answers the item'

    Be certain that erasures are complete. Please PRINT your name, school, atea #, and which test you are

    takins on the scan-tron.1. The density of marble chips is determined by water displacement method and the followingdata are obtained.

    Mass (e) Volume (mL)4.0 2.06.0 3.09.0 4.0t2.0 5.015.0 6.025.0 10.0

    The density of marble is 2.50 glmL. What is the closest to the percent error of the student'sexperimental determination?

    A. s.0% B. t5% c.20% D. 83%

    2. The photoelectron spectrum (PES) below shows the binding energies for all electrons inneutral element Q.

    Rsiativ* *tagbercf r}rckaes

    PES *fekroelrt Q

    58tV $etrr13*S ellThe element Q belongs to the Group _

    1** eV

    of the periodic table.

    c.14 D. 18A.2

    3. Which has the most C

    A. 10.0 mg of CaCO3

    B.5

    atoms?

    4. For which pair of species isA. Na and Cl

    B. 12.0 mg of CaC2 C.4.0 mg of COz D. 8.0 mg of CO

    the difference in radii the sreatest?B. N/ and Cl- C. N:a* and 52- D. Cf and 52-

    NfSL Chem II fan 2015 Page 1

  • 5. 100.0 mL of a 0.10 M Pb(NIO3)2 aq. solution is added to 100.0 mL of a 0.30 M CaCl2 aq.solution. Which ion has the hiehest concentration in solution after the chemical reaction isterminated?

    A. Pb2* B. NO:- C, CT* D. CT

    6. Cu2S + HNO: -+ CuQ.{Or)2 + CuSOa + NO2 + HzO

    When the above equation is balanced using the smallest whole-number coefficients, thecoefficient of NOz will be equal to

    A.12 B. l0 c.8 D.6

    7 . 20.0 g of M2O7 react with excess Hz according to the following equation:MzOt + 7Hz -> 2M + THzO

    If only 5.20 gof water are produced, what is the identity of the metal?

    A. Mn B. Mo C. Ru D. Re

    8. 250.0 mL of a 0.10 M HCI are added to a beaker containing 1.00 g of CaCO:. The beaker isheated to dryness. What is the mass of the dry residue in the beaker?

    CaCO3(s) +2HCl(aq) + CaClz@q) + COz@) + H2O(l)

    A.1.73 g B. 1.11 g C.1.29 g D. 1.91 g

    9. In which of the following chemical equations did the oxidation state of N remain unchanged?A. Cu(s) + 8HNO3(aq) -+ Cu(NO:)z(aq) + 2NO(g) + }i1O(DB.2No(g) + Ozk) -+ 2Nozk)C. NzO:(s) + HzO(D -+ 2HNO3(aq)D. NFI+NO:(s) -+ NzO(S) + 2HzO(s)

    10. A compound is made of Mg, P and O. Which of the following compounds containsapproximately 50o/o of oxygen by mass?

    A. Mg3(PO4)2 B. Mg2P2O7 C. Mg(PO3)2 D. MgPO2

    11. What is the oxidation state of phosphorus in the compound POCI3?

    A.+5 B. +3 c.0 D. -3

    12. Copper has two naturally occurring isotopes: copper-63 and copper-65. The average atomicmass of copper is 63.54 amu. What is the ratio of the natural abundances of these two isotopes(copper-63 :copper-65)?

    A.2:l

    NISL Chem II fan 2015

    B. 1:3

    PageZ

    C.3:l D.4:3

  • 13. The term'.ALUM" refers to a class of compounds of general formula QZ(SOa)2.l2HzOwhere Q and Z aretwo different metals. A 25.00 g sample of a certain alum is heated to drive offthe crystal water; the anhydrous residue weighs 14.264 g. Treatment of the residue with excess

    NaOH precipitates all the Z as Z(OH): which weighs 5.355 g. Identify the two metals.

    A. K and Al B. Na and Al C. K and Cr D. K and Fe

    14. Ableach sample is analyzed for its NaCIO content. It is found that a 10.0 g sample of bleachrequires 40.50 mL of 0.500 M NazSzOg solution to reach the endpoint of titration. What is the

    mass percent of NaCIO in the bleach?

    NaCIO + 2Na2S2O3 + 2HCl -+ 3NaCl + NazSaOo + H2O

    A.7.54% B. 13.4% C.zA.l% D.26.4%

    15. A 1.500 g sample of solid CaCO: is dissolved in 25.00 mL of 1.000 M of HCI solution. Theexcess amount of HCI is titrated with 0.100 M NaOH solution. The endpoint of the titrationrequired 23.40 mL NaOH solution. What is the percent CaCOg in the sample?

    CaCQ(s) + 2HCl(aq) + CaClz@q) + COz(g) + H2O(D

    A.96.7% 8.75.3% C.50.8% D.25.4%

    16. Oxygen (Oz) and Ozone (O3) are allotropes of the element oxygen. Which of the followingpairs is NOT an allotropic pair?

    A. Cgraphite and C6irrron4B. rhombic sulfur and amorphous sulfurC. white tin and gray tinD. nitrogen-I4 and nitrogen-l5

    17. Green light breaks the bond between two chlorine atoms. Which of the following lights canalso break the bond between the chlorine atoms?

    A. Blue B. Yellow C. Red D. Orange

    C. Chromium(Vl) carbonateD. Chromium(Vl) carbonite

    19. Which species canact as an oxidizingagent but NOT as a reducing agent?

    A. NOz B. NO:- C. Cu* D. CIO-

    20. What is the ground state electron configuration of the nickelous ion?

    A. [Ar] 3d 4s2 B.tArl 3f 4s2

    18. The correct name of Cr(COz): isA. Chromium carbonateB. Chromium carbonite

    NISL Chem II fan 2015 Page 3

    C. tArl 3l D. ttul 3d 4st.

  • 21. Consider the following equation:2CaH1s +13Oz -+ 8COz + 10H2O

    when 100.0 g of caHro react with 100.0 $ of 02, the maximum amount of coz produced is

    A. 84.6 g 8.42.3 g C.194 s D. 304 g

    22. Consider the following reactions:QClz@d + Z(s) -) no reactionMrCrzi.rld +Q(s) +M(s) +QClz(s)MClz/.rld + Z(s) + M(s) + ZCl2@q)

    What is the correct order of increasing activity for the metals M, Q and Z?

    A.M

  • Periodic Table and Chemistry Formulas

    l8

    Hl_0079

    ) Periodic Table of the Elemlamu to 5 significant digits]

    3 6 I 9 t0

    nts t3 l4 15 16 t71

    He4.m/26

    J

    Li4

    Be9.Or22

    l1 12

    5

    B6

    Cl2.0lt

    7

    Nrtw

    E

    o9

    Fl0Ne

    ltNa Mg

    t3

    A1t4

    Sit5

    Pl6

    Sl7

    CIl8Ar

    t9

    K20

    Cazl

    Sc Ti23

    V24

    Crt<

    Mn26

    Fe27

    Co2a

    Ni29

    Cu50

    Zn31

    Ga32

    Ge33

    As34

    Se35

    Br36

    Kr

    Rb38

    Sr39

    Y40

    Zr4lNb92.906

    42

    Mo43

    TcuRu

    45

    Rht6

    Pd Ag48

    Cd49

    In50

    Sn119 1l

    5t

    Sb52

    Te5J

    I54

    Xe

    Cs56

    Ba7lLur74.97

    a)

    Hf Tal8{r..x

    74w Re76

    Os77

    Ir78

    Pt79

    Au 'hgt1

    TIa2

    Pb83

    Bit4Po

    t5

    At86

    Rn

    a1

    Fr88

    Ra103

    Lr104

    Rf105

    Db106

    Sgl07

    Bh108

    Hsla11\

    109

    Mt110

    DslllRg

    lt2Uub

    113

    Uutattrl

    tt4uuq

    atas)

    uuplt6 tt7 ll8

    LanthanidtSeries

    ActinideSeries

    CHEMISTRY FORMULASGASES, LIQUIDS,

    SOLUTIONSPV: NRT

    (P + n2a) (V-nb) - nRTv'

    P4: P1o14 r X4

    Rota:Pe + PB + Pc+

    n=r4M

    Kelvin:'C +273

    P1V1 : P2V2

    Yr:&Tr T2

    prvr=&_\!Tr T2

    KEp"rrol""ut": -!4y'z

    KE pe. mole =

    Fnr=\ M

    rt@;: \M,

    d:laV

    P: pressureV: volume

    T: Temperaturen : number of moles

    d: densityln: MASS

    v: velocitywhere Xa: moles A

    total moles

    ums : root-mean-square-rootKE: Kinetic energyr: rate of effusionM: Molar mass

    n: osmotic pressurei = van't Hoff factor

    K6: molal freezing pointconstant

    K5: molal boiling pointconstant

    Q: reaction quotientI :current in amperes

    q: charge in coulombst: time

    Eo : standard reductionpotential

    Keq : equilibrium constant

    R, Gas constant : 8.3 I JoulesMole Kelvin

    :0.0821 liter atmmole Kelvin

    :8.31 volts coulombsmole Kelvin

    Boltzmann's constant,k : 1.38 x 10-23 Joule

    KKr*"t",: 1.86 Kelvin /molal

    Kb wate. : 0.512 Kelvin /molal

    STP:0.00 oC, 1.00 atm (101.3 kPa)

    I faraday 5 :96,500 coulombs/ mole ofelectrons

    3RT2

    M. molarity : moles soluteliter of solution

    molality: moles of solutekg of solvent

    ATl: iKsr molality

    AT6:iK6omolality

    n: nRTiV

    3kt

    m

  • ATOMTC STRUCTUREAE:hvc=v),

    En=

    L: hmv

    p:mv

    -2J-78-xl-Q*n joulen2

    E : energYv : frequencyl" : wavelengthp - momentumv : velocity

    n: principal quantum numberc : speed of light 3.00 x l0o m/s

    h : Planck's constant: 6.63 x lO-3aJoule sk: Boltzmann

    constant : 1.38 x I 0-23 joule/K -Avogadro's number: 6.02 x 10"

    molecules/mole

    e : electron charge : -l .602 x I 0-1ecoulomb

    I electron volt/atom = 96.5 x 1023 kj/mole

    OXIDATION-REDUCTIONELECTROCHEMISTRY

    a: LCfrDIllAr[Bl"

    where aB+ bB

  • d0& tr90r tr80r tr70r tr601tr50r tr40r tr30r c201 tr10rtr9r tr8r tr7- tr6r tr5rtr41 tr3r .2a tr1: tr0r

    PART 1

    r'lT

    z;tom

    Fn.}

    =rx

    =|--

    @

    e3

    39p6

    ?6@5-er

    Fa6E!@nm

    m,mI

    U'=vx2an2zo

    triitnci!-I

    drnrno:oz

    I

    N

    :\

    I

    ;=

    m

    I

    ,(r) (F)*-

    1*trBr2*trBr3.A= trB:4.A= trBr5.A= trBr6 .A' {r7 .A= cBr8 cA: tt9.A= trB:

    10 cA: 511

    - trBtr

    12 trAr trBr13 trAr trBl14

    - trBr

    15 trA: rD16 trAr trBr17 * trBr18.A= trBr19 cA: r|r20 .A= trBr21 * trBr22 trAr tf23 trAr rD24 .A- trBr25 * trBr26 .A= trBr27 .Ar trBr28 .A= trBr29 .A= cBr30.A. trBr

    KEY

    tr3r *trCr trDr trErtrCr trD: trErtrCr tts EEr

    f cD: trErtrCr f; cf:trCr trDr trErcQ: ap cf:trCr trDr trEr

    f cP: trEltrCr trDr trErrCr trDr trE:

    f cD: trErtrCr

    - trEr

    trCr trD: trErtrCr trDr trErcC: lF rE:trCr trDr tr ErtrCr ilF trErtrCr trDr trEr

    - trDr trEr

    trCr trDr trErtrCr trDr trE:trCr trDr trErcQr rlr trE:trCr trDr trE:trCr trDr trErtrCr trDr trEltrCr trD: trErtrCr trDr trErtrCr trDr trEr

    31 trAr trBr32 trAr trBr33 .A= EBr34 .At trBr35 .Ar trBr36 -A= trBr37.A= trBr38 -A= trBr39 -A= trBr40 .A. trBr41 trAr trBr42 trAr trBr43 .A- trBr44.A= trBr45 trAr trBr46 trAr trBr47.A= trBl48 .A= trBr49 trAr trBr50 trA:.Br

    trCr trDr trE:trCr trDr trEltrCr trDr trErtrC: trDr trErtrCr trDr trEltrC: trDr trErtrCr trDr rEltrCr trDr trErtrCr trDr trEltrCr trDr trErtrCr trDr trErtrCr trDr trErtrCr trDr trErtrC: trDr trErtrCtr trDr trErtrCr trDr trErtrC: trDr trEltrCr trDr rErtrCr trDr trErtrCr trDr trEr

    q

    !I

    I

    q 6s =E eA n

    # =il

    E_ m= x;P-inEmx'tol3

    io3

    6o+eq i ,di EE 8Et -il um=! =

    fi,^

    i i"= *H5 5 9 >Eo = =mo* HQ-4 :i no4liEP

    imT

    IMG_0032IMG_0033IMG_0034IMG_0035IMG_0036IMG_0037IMG_0038