empirical & molecular formula

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Chapter 11-12 Empirical & Molecular Formula

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Empirical & Molecular Formula. Chapter 11-12. The Empirical Formula. The lowest whole number ratio of elements in a compound. The molecular formula is the actual ratio of elements in a compound. CH 2 empirical formula C 2 H 4 molecular formula C 3 H 6 molecular formula. - PowerPoint PPT Presentation

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Page 1: Empirical & Molecular Formula

Chapter 11-12

Empirical & Molecular Formula

Page 2: Empirical & Molecular Formula

The Empirical FormulaThe lowest whole number ratio of

elements in a compound.The molecular formula is the actual

ratio of elements in a compound.

CH2 empirical formulaC2H4 molecular formulaC3H6 molecular formula

Page 3: Empirical & Molecular Formula

Finding Empirical Formulas

Just find the lowest whole number ratio

C6H12O6

CH4N2It is not just the ratio of atoms, it is also the ratio of moles of atoms.

Page 4: Empirical & Molecular Formula

Calculating Empirical Formulas

Means we can get ratio from percent composition.

Assume you have a 100 g.The percentages become grams.Turn grams to moles. Find lowest whole number ratio by dividing everything by the smallest moles.

Page 5: Empirical & Molecular Formula

ExampleCalculate the empirical formula of a

compound composed of 38.67 % C, 16.22 % H, and 45.11 %N.

Assume 100 g so38.67 g C x 1mol C = 3.22

mole C 12.0 gC 16.22 g H x 1mol H = 16.1 mole

H 1.0 gH45.11 g N x 1mol N = 3.22 mole

N 14.0 gN

Page 6: Empirical & Molecular Formula

ExampleThe ratio is 3.22 mol C = 1 mol C 3.22 molN 1 mol N

The ratio is 16.1 mol H = 5 mol H 3.22 molN 1 mol N

C1H5N1

Page 7: Empirical & Molecular Formula

Your Turn

Calculate the empirical formula of a compound composed of 25.14 % C, 7.19 % H, and 67.67 %N.

Page 8: Empirical & Molecular Formula

Empirical to molecularempirical formula = lowest ratio the actual molecule would weigh the same or more.

Divide the actual molar mass by the molar mass of the empirical formula.

Get a whole number.Multiply the empirical formula by this.

Page 9: Empirical & Molecular Formula

ExampleA compound has an empirical formula of

ClCH2 and a molar mass of 98.96 g/mol. What is its molecular formula?Cl = 35.5 g/mol X 1 = 35.5 g/molC = 12.0 g/mol X 1 = 12.0 g/molH = 1.0 g.mol X 2 = 2.0 g/mol

49.5 g/mol98.96 g/mol ÷ 49.5 g/mol = 22 (ClCH2) = Cl2C2H4

Gives us the Molecular Formula

Page 10: Empirical & Molecular Formula

Your TurnA compound has an empirical formula of CH2O and a molar mass of 180.0 g/mol. What is its molecular formula?

Page 11: Empirical & Molecular Formula

Percent to molecularTake the percent X the molar massThis gives you mass in one mole of the compound

Change this to molesYou will get whole numbersThese are the subscripts

Page 12: Empirical & Molecular Formula

ExampleCaffeine is 49.48% C, 5.15% H, 28.87% N and 16.49%

O. It has a molar mass of 194 g. What is its molecular formula?

49.48% C x 194g= 96g ÷ 12.0g/mol = 85.15% H x 194g = 10g ÷ 1.0g/mol = 1028.87% N x 194g = 56g ÷ 14.0g/mol = 416.49% O x 194g = 32g ÷ 16.0g/mol = 2

C8H10N4O2 Molecular FormulaEmpirical Formula….C4H5N2O

Page 13: Empirical & Molecular Formula

Your TurnIbuprofen is 75.69 % C, 8.80 % H, 15.51 % O, and has a molar mass of about 207 g/mol. What is its molecular formula?