flow through an oscillating rectangular duct for generalized maxwell fluid with fractional...
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Commun Nonlinear Sci Numer Simulat 17 (2012) 3219–3234
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Commun Nonlinear Sci Numer Simulat
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Flow through an oscillating rectangular duct for generalized Maxwellfluid with fractional derivatives
Mudassar Nazar ⇑, Muhammad Zulqarnain, Muhammad Saeed Akram, Muhammad AsifCentre for Advanced Studies in Pure and Applied Mathematics, Bahauddin Zakariya University, Multan, Pakistan
a r t i c l e i n f o a b s t r a c t
Article history:Received 6 April 2011Received in revised form 9 September 2011Accepted 2 October 2011Available online 14 January 2012
Keywords:Generalized Maxwell fluidOscillating rectangular ductVelocity field
1007-5704/$ - see front matter � 2011 Elsevier B.Vdoi:10.1016/j.cnsns.2011.10.002
⇑ Corresponding author.E-mail address: [email protected] (M. N
The velocity field and the associated shear stresses corresponding to the unsteady flow ofgeneralized Maxwell fluid on oscillating rectangular duct have been determined by meansof double finite Fourier sine and Laplace transforms. These solutions are also presented as asum of the steady-state and transient solutions. The solutions corresponding to Maxwellfluids, performing the same motion, appear as limiting cases of the solutions obtained here.In the absence of w, namely the frequency, and making a ? 1, all solutions that have beendetermined reduce to those corresponding to the Rayleigh Stokes problem on oscillatingrectangular duct for Maxwell fluids. Finally, some graphical representations confirm theabove assertions.
� 2011 Elsevier B.V. All rights reserved.
1. Introduction
How to predict the behavior of non-Newtonian fluids is still a considerable problem in fluid mechanics. The main reasonfor this is probably that non-Newtonian fluids help us to understand the wide variety of fluids that exist in the physicalworld. A constitutive equation relates a response to the perturbation associated with the response. Amongst the many mod-els like differential, rate and integral types which have been treated as non-Newtonian behavior, the fluids of rate type [1]have received special attention. Among the viscoelastic rate type model, which is used widely, is the Maxwell model [2].
Fetecau et al. [3] studied the velocity field and the adequate shear stress corresponding to the unsteady flow of a general-ized Maxwell fluid using Fourier sine and Laplace transforms. Zheng [4] obtained analytical solutions for generalized Max-well fluid flow due to oscillatory and constantly accelerating plate using the fractional calculus approach established theconstitutive relationship of fluid model. Vieru et al. [5] discussed the flow of a generalized Maxwell fluid induced by a con-stantly accelerating plate between two side walls.
Fractional calculus has encountered much success in the description of viscoelasticity and complex dynamical systems[6,7]. The starting point of the fractional derivative model of viscoelastic fluids is usually a classical differential equationwhich is modified by replacing the time derivative of an integer order by the Riemann–Liouville fractional calculus operator.This generalization allows one to define precisely non-integer order integrals or derivatives. A very good agreementis achieved with experimental data when the Maxwell model is used with its first order derivatives replaced by thefractional-order derivatives [8].
Nadeem et al. [9] discussed the Rayleigh Stokes problem for rectangular pipe in Maxwell and second grade fluids. Oscil-lating viscoelastic rectilinear flows in straight ducts due to an oscillating pressure gradient have been studied analytically byBroer [10] and Thurston [11,12] for a linear Maxwell fluid, by Jones and Walters [13,14] and Peev et al. [15] for a linearWalter B fluid, by Bhatnagar [16] for a Jeffrey fluid (linear Oldroyd), by Ramkissoon et al. [17] for a short memory Walters
. All rights reserved.
azar).
3220 M. Nazar et al. / Commun Nonlinear Sci Numer Simulat 17 (2012) 3219–3234
liquid B, and by Rahaman and Ramkissoon [18] for an upper convected Maxwell fluid. Furthermore, oscillating tube flow forviscoelastic fluids, mimicking human blood, has been considered by Walitza et al. [19].
The aim of this paper is to establish new exact solutions for generalised Maxwell fluid on oscillating rectangular duct bymeans of double finite Fourier sine and Laplace transforms for fractional calculus approach. The governing equation of mo-tion is a fractional order partial differential equation and obtain the velocity field and the shear stress. To solve such a prob-lem one has to use one additional initial condition, the first time derivative of the velocity is zero at time t = 0 [20,21].
2. Governing equations
Consider an incompressible generalized Maxwell fluid at rest in a duct of rectangular cross-section whose sides are atx = 0, x = d, y = 0 and y = h. At time t = 0+ the duct begin to oscillate along z-axis.
The velocity field is
vðx; y; tÞ ¼ wðx; y; tÞk ð1Þ
and the governing equation is
ð1þ kaDat Þ@wðx; y; tÞ
@t¼ m
@2wðx; y; tÞ@x2 þ @
2wðx; y; tÞ@y2
" #; ð2Þ
where
Dat f ðtÞ ¼ 1
Cð1� aÞ
Z t
0
f 0ðsÞðt � sÞa
ds;
is the Caputo’s fractional operator and C is the gamma function.We consider the following initial and boundary conditions
wðx; y;0Þ ¼ @wðx; y;0Þ@t
¼ 0; ð3aÞ
wð0; y; tÞ ¼ wðd; y; tÞ ¼ wðx;0; tÞ ¼ wðx; h; tÞ ¼ U cosðxtÞ ð3bÞ
or
wðx; y;0Þ ¼ @wðx; y;0Þ@t
¼ 0; ð4aÞ
wð0; y; tÞ ¼ wðd; y; tÞ ¼ wðx;0; tÞ ¼ wðx; h; tÞ ¼ U sinðxtÞ; ð4bÞ
We denote by u(x,y, t) the solution of problem (2), (3a), (3b) and by v(x,y, t) the solution of problem (2), (4a), (4b) and definethe complex velocity field
Fðx; y; tÞ ¼ uðx; y; tÞ þ ivðx; y; tÞ; ð5Þ
which is the solution of the following problem:
1þ kaDat
� � @Fðx; y; tÞ@t
¼ m@2Fðx; y; tÞ
@x2 þ @2Fðx; y; tÞ@y2
" #; ð6Þ
Fðx; y;0Þ ¼ @Fðx; y;0Þ@t
¼ 0; ð7Þ
Fð0; y; tÞ ¼ Fðd; y; tÞ ¼ Fðx;0; tÞ ¼ Fðx;h; tÞ ¼ Ueixt : ð8Þ
The fractional differential Eq. (6) with the initial and boundary conditions (7) and (8) will be solved by means of the Fouriersine and Laplace transforms.
3. Calculation of velocity field
Multiplying both sides of Eq. (6) by sin(amx) sin(bny), integrating with respect to xand y over [0,d] � [0,h] and usingEq. (8), we find that
1þ kaDat
� � @FmnðtÞ@t
þ m a2m þ b2
n
� �FmnðtÞ ¼ m½1� ð�1Þm�½1� ð�1Þn�a
2m þ b2
n
ambnUeixt ; ð9Þ
where am ¼ mpd ; bn ¼ np
h ; and the double Fourier sine transforms
FmnðtÞ ¼Z d
0
Z h
0Fðx; y; tÞ sinðamxÞ sinðbnyÞdxdy; m;n ¼ 1;2;3 . . . ð10Þ
M. Nazar et al. / Commun Nonlinear Sci Numer Simulat 17 (2012) 3219–3234 3221
of F(x,y, t) have to satisfy the initial conditions
Fmnð0Þ ¼ 0;@Fmnð0Þ@t
¼ 0; m;n ¼ 1;2;3 . . . ð11Þ
By applying the Laplace transforms to Eq. (9) with the initial conditions (11), we obtain
qþ kaqaþ1 þ m a2m þ b2
n
� �� �FmnðqÞ ¼ m½1� ð�1Þm�½1� ð�1Þn�a
2m þ b2
n
ambnU
1q�xi
; ð12Þ
which can be simplified as
FmnðqÞ ¼ mU½1� ð�1Þm�½1� ð�1Þn�a2m þ b2
n
ambn
1q�xi
1qþ kaqaþ1 þ m a2
m þ b2n
� �¼ amn
Uq�xi
� amnU 1þ ix1
q� ix
� �kaqa þ 1
kaqaþ1 þ qþ mkmn; ð13Þ
where
amn ¼1
ambn½1� ð�1Þm�½1� ð�1Þn�; kmn ¼ a2
m þ b2n; ð14Þ
and FmnðqÞ ¼R1
0 FmnðtÞe�qtdt is the Laplace transform of Fmn(t). In order to obtain the inverse Laplace transformFmnðtÞ ¼ L�1fFmnðqÞg, we consider the function
HmnðqÞ ¼kaqa þ 1
kaqaþ1 þ qþ mkmn; ð15Þ
which can be written in the following equivalent forms:
HmnðqÞ ¼kaðqa þ k�aÞ
kaq½ðqa þ k�aÞ þ mk�akmnq�1� ¼qa�1 þ k�aq�1
ðqa þ k�aÞ þ mk�akmnq�1¼X1k¼0
ð�1Þkðmk�akmnq�1Þkðqa�1 þ k�aq�1Þðqa þ k�aÞkþ1
¼X1k¼0
�mkmn
ka
� k qa�k�1 þ k�aq�k�1
ðqa þ k�aÞkþ1 : ð16Þ
Applying the double inverse Fourier sine transform to Eq. (13), we obtain
Fðx; y; qÞ ¼ 4Udh
1q�xi
X1m;n¼1
amn sinðamxÞ sinðbnyÞ � 4Udh
X1m;n¼1
amn 1þ ixq�xi
� �HmnðqÞ � sinðamxÞ sinðbnyÞ ð17Þ
Using the formula [22]
1 ¼ 4dh
X1m;n¼1
amn sinðamxÞ sinðbnyÞ;
we obtain for Fðx; y; qÞ the expression
Fðx; y; qÞ ¼ Uq�xi
� 16Udh
X1m;n¼1
sinðaMxÞaM
sinðbNyÞbN
1þ xiq�xi
� �HMNðqÞ; ð18Þ
where M ¼ 2m� 1; N ¼ 2n� 1; aM ¼ ð2m�1Þpd and bN ¼ ð2n�1Þp
h .By applying the inverse Laplace transform to Eq. (18), using (16) and the formula
L�1 qb
ðqa � dÞc �
¼ Ga;b;cðd; tÞ; Reðac � bÞ > 0; ReðqÞ > 0; jqaj > jdj;
we obtain for the complex velocity field F(x,y, t), the following expression:
Fðx; y; tÞ ¼ Ueixt � 16Udh
X1m;n¼1
sinðaMxÞaM
sinðbNyÞbN
X1k¼0
� mkMN
ka
� k
�(
Ga;a�k�1;kþ1ð�k�a; tÞ þ k�aGa;�k�1;kþ1ð�k�a; tÞ� �
þxiX1k¼0
� mkMN
ka
� k
�Z t
0eixðt�sÞ½Ga;a�k�1;kþ1ð�k�a; sÞ þ k�aGa;�k�1;kþ1ð�k�a; sÞ�ds
�: ð19Þ
In the above relations the generalized G-functions Ga,b,c(d, t) are defined by
Ga;b;cðd; tÞ ¼X1j¼0
djCðc þ jÞCðcÞCðjþ 1Þ
tðcþjÞa�b�1
C½ðc þ jÞa� b� : ð20Þ
3222 M. Nazar et al. / Commun Nonlinear Sci Numer Simulat 17 (2012) 3219–3234
Setting d = 2a, h = 2b and changing the origin of the coordinate system (taking x = x⁄ + a, y = y⁄ + b and dropping out the starnotation), the complex velocity can be written in the form
Fðx; y; tÞ ¼ Ueixt � 4Uab
X1m;n¼1
ð�1Þmþn cosðaMxÞaM
cosðbNyÞbN
X1k¼0
� mkMN
ka
� k
�(
½Ga;a�k�1;kþ1ð�k�a; tÞ
þ k�aGa;�k�1;kþ1ð�k�a; tÞ� þxiX1k¼0
� mkMN
ka
� k
�Z t
0eixðt�sÞ Ga;a�k�1;kþ1ð�k�a; sÞ þ k�aGa;�k�1;kþ1ð�k�a; sÞ
� �ds�: ð21Þ
The velocity field corresponding to the cosine oscillations of the duct, respectively to the sine oscillations of the duct are gi-ven by
uðx; y; tÞ ¼ Re½Fðx; y; tÞ�
¼ U cosðxtÞ þ 4Uab
X1m;n¼1
ð�1Þmþn cosðaMxÞaM
cosðbNyÞbN
X1k¼0
� mkMN
ka
� k
�(
½Ga;a�k�1;kþ1ð�k�a; tÞ
þ k�aGa;�k�1;kþ1ð�k�a; tÞ� �xX1k¼0
� mkMN
ka
� k
�Z t
0sinxðt � sÞ½Ga;a�k�1;kþ1ð�k�a; sÞ þ k�aGa;�k�1;kþ1ð�k�a; sÞ�ds
�; ð22Þ
vðx; y; tÞ ¼ Im½Fðx; y; tÞ�
¼ U sinðxtÞ þ 4Uab
X1m;n¼1
ð�1Þmþn cosðaMxÞaM
cosðbNyÞbN
X1k¼0
� mkMN
ka
� k
�(
½Ga;a�k�1;kþ1ð�k�a; tÞ
þ k�aGa;�k�1;kþ1ð�k�a; tÞ� þxX1k¼0
� mkMN
ka
� k
�Z t
0cos xðt � sÞ½Ga;a�k�1;kþ1ð�k�a; sÞ þ k�aGa;�k�1;kþ1ð�k�a; sÞ�ds
�: ð23Þ
4. Calculation of shear stresses
In the considered problem Sxx = Sxy = Syy = 0,
1þ kaDat
� �s1ðx; y; tÞ ¼ l @xðx; y; tÞ
@x; s1 ¼ Sxz; ð24Þ
1þ kaDat
� �s2ðx; y; tÞ ¼ l @xðx; y; tÞ
@y; s2 ¼ Syz; ð25Þ
1þ kaDat
� �rðx; y; tÞ ¼ 2k s1
@x@xþ s2
@x@y
� �; r ¼ Szz: ð26Þ
We denote by s1c, s2c the tensions for cosine oscillations, respectively s1s, s2s the tensions for sine oscillations of the duct.If we introduce
T1ðx; y; tÞ ¼ s1cðx; y; tÞ þ is1sðx; y; tÞ; ð27ÞT2ðx; y; tÞ ¼ s2cðx; y; tÞ þ is2sðx; y; tÞ; ð28Þ
we obtain
1þ kaDat
� �T1ðx; y; tÞ ¼ l @Fðx; y; tÞ
@x; ð29Þ
1þ kaDat
� �T2ðx; y; tÞ ¼ l @Fðx; y; tÞ
@y; ð30Þ
with F(x,y, t) given by (5).The fluid begins from rest at time t = 0, we have the initial conditions
T1ðx; y;0Þ ¼ T2ðx; y; 0Þ ¼ 0: ð31Þ
Applying the Laplace transforms to Eqs. (29) and (30) with the initial conditions (31), we obtainT1ðx; y; qÞ ¼l
kaqa þ 1@Fðx; y; qÞ
@x; ð32Þ
T2ðx; y; qÞ ¼l
kaqa þ 1@Fðx; y; qÞ
@y; ð33Þ
M. Nazar et al. / Commun Nonlinear Sci Numer Simulat 17 (2012) 3219–3234 3223
where
Fig. 1.parame
Fðx; y; qÞ ¼ Uq�xi
� 16Udh
X1m;n¼1
sinðaMxÞaM
sinðbNyÞbN
qq�xi
kaqa þ 1kaqaþ1 þ qþ mkMN
: ð34Þ
Introducing Eq. (34) into Eqs. (32) and (33), we get
T1ðx; y; qÞ ¼ �16lU
dh
X1m;n¼1
cosðaMxÞ sin bNybN
qðq�xiÞðkaqaþ1 þ qþ mkMNÞ
; ð35Þ
T2ðx; y; qÞ ¼ �16lU
dh
X1m;n¼1
sinðaMxÞaM
cosðbNyÞ qðq�xiÞðkaqaþ1 þ qþ mkMNÞ
: ð36Þ
Profiles of velocity u(x,y, t) given by Eq. (22) for x = 2, m = 0.0012, U = 0.001, a = 0.025, b = 0.02, k = 0.5 and different values of y, t and the fractionalter a.
3224 M. Nazar et al. / Commun Nonlinear Sci Numer Simulat 17 (2012) 3219–3234
Let us take
Fig. 2.parame
GmnðqÞ ¼q
ðq�xiÞðkaqaþ1 þ qþ mkmnÞ¼ 1
q�xiq
kaq½ðqa þ k�aÞ þ mkmnk�aq�1�
¼ 1q�xi
1ka
X1k¼0
� mkmn
ka
� k q�k
ðqa þ k�aÞkþ1 : ð37Þ
The inverse Laplace transform of the function Gmn(q) is
gmnðtÞ ¼1ka
X1k¼0
� mkmn
ka
� k Z t
0eixðt�sÞGa;�k;kþ1ð�k�a; sÞds: ð38Þ
Profiles of velocity u(x,y, t) given by Eq. (22) for x = 2, m = 0.0012, U = 0.001, a = 0.025, b = 0.02, k = 1.0 and different values of y, t and the fractionalter a.
M. Nazar et al. / Commun Nonlinear Sci Numer Simulat 17 (2012) 3219–3234 3225
Now we obtain the following expressions of the complex shear stresses:
Fig. 3.parame
T1ðx; y; tÞ ¼ �16lU
dh
X1m;n¼1
cosðaMxÞ sinðbNÞybN
1ka
X1k¼0
� mkMN
ka
� k Z t
0eixðt�sÞGa;�k;kþ1ð�k�a; sÞds; ð39Þ
T2ðx; y; tÞ ¼ �16lU
dh
X1m;n¼1
sinðaMxÞaM
cosðbNyÞ 1ka
X1k¼0
� mkMN
ka
� k Z t
0eixðt�sÞGa;�k;kþ1ð�k�a; sÞds: ð40Þ
The real tensions are given by
Profiles of velocity v(x,y, t) given by Eq. (23) for x = 2, m = 0.0012, U = 0.001, a = 0.025, b = 0.02, k = 0.5 and different values of y, t and the fractionalter a.
Fig. 4.parame
3226 M. Nazar et al. / Commun Nonlinear Sci Numer Simulat 17 (2012) 3219–3234
s1cðx; y; tÞ ¼ Re½T1ðx; y; tÞ�
¼ �16lUdh
X1m;n¼1
X1k¼0
cosðaMxÞka
sinðbNyÞbN
� mkMN
ka
� k
�Z t
0cos xðt � sÞGa;�k;kþ1ð�k�a; sÞds; ð41Þ
s2cðx; y; tÞ ¼ Re½T2ðx; y; tÞ�
¼ �16lUdh
X1m;n¼1
X1k¼0
sinðaMxÞaM
cosðbNyÞka � mkMN
ka
� k
�Z t
0cos xðt � sÞGa;�k;kþ1ð�k�a; sÞds; ð42Þ
Profiles of velocity v(x,y, t) given by Eq. (23) for x = 2, m = 0.0012, U = 0.001, a = 0.025, b = 0.02, k = 1.0 and different values of y, t and the fractionalter a.
M. Nazar et al. / Commun Nonlinear Sci Numer Simulat 17 (2012) 3219–3234 3227
for cosine oscillations of the duct, respectively
Fig. 5.fraction
s1sðx; y; tÞ ¼ Im½T1ðx; y; tÞ�
¼ �16lUdh
X1m;n¼1
X1k¼0
cosðaMxÞka
sinðbNyÞbN
� mkMN
ka
� k
�Z t
0sinxðt � sÞGa;�k;kþ1ð�k�a; sÞds; ð43Þ
s2sðx; y; tÞ ¼ Im½T2ðx; y; tÞ�
¼ �16lUdh
X1m;n¼1
X1k¼0
sinðaMxÞaM
cosðbNyÞka � mkMN
ka
� k
�Z t
0sinxðt � sÞGa;�k;kþ1ð�k�a; sÞds; ð44Þ
for sine oscillations of the duct.
5. Limiting cases
5.1. Maxwell fluids as a particular case of the generalized Maxwell fluids
Making a = 1 into Eq. (21) and using (A5) from the Appendix, we obtain the complex velocity field
Absolute values of the velocity u(x,y, t) given by Eq. (22) for x = 2, m = 0.0012, U = 0.001, a = 0.025, b = 0.02, k = 0.5, and different values of theal parameter a.
Fig. 6.fraction
3228 M. Nazar et al. / Commun Nonlinear Sci Numer Simulat 17 (2012) 3219–3234
Fðx; y; tÞ ¼ Ueixt � 4Uab
X1m;n¼1
ð�1Þmþn cosðaMxÞaM
cosðbNyÞbN
� coshumnt2k
� þ 1
umnsinh
umnt2k
� � �e�
t2k þxi
Z t
0eixðt�sÞ cosh
umns2k
� þ 1
umnsinh
umns2k
� � �e�
s2kds
�; ð45Þ
corresponding to an ordinary Maxwell fluid performing the same motion, where
umn ¼ffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi1� 4kmkmn
p: ð46Þ
Integrating by parts, after a straightforward calculation, function F(x,y, t) can be written in the simpler form
Fðx; y; tÞ ¼ Ueixt � 4Uab
X1m;n¼1
ð�1Þmþn cosðaMxÞaM
cosðbNyÞbN
� AMNeixt þ ð1� AMNÞ coshUMNt
2k
� þ 1þ 2kxi
UMNsinh
UMNt2k
� � �e�
t2k
�; ð47Þ
where
Amn ¼x2½1� kðmkmn � kx2Þ� þxmkmni
ðmkmn � kx2Þ2 þx2: ð48Þ
Absolute values of the velocity u(x,y, t) given by Eq. (23) for x = 2, m = 0.0012, U = 0.001, a = 0.025, b = 0.02, k = 0.5, and different values of theal parameter a.
M. Nazar et al. / Commun Nonlinear Sci Numer Simulat 17 (2012) 3219–3234 3229
We denote by
Fig. 7.
cmn ¼ ReðAmnÞ ¼x2½1� kðmkmn � kx2Þ�ðmkmn � kx2Þ2 þx2
; dmn ¼ ImðAmnÞ ¼xmkmn
ðmkmn � kx2Þ2 þx2; ð49Þ
and, from Eq. (47) we obtain
uðx; y; tÞ ¼ U cosðxtÞ � 4Uab
X1m;n¼1
ð�1Þmþn cosðaMxÞaM
� cosðbNyÞbN
cMN cosðxtÞ � dMN sinðxtÞ þ e�t
2k ð1� cMNÞ coshUMNt
2k
� þ 1� cMN þ 2kxdMN
UMNsinh
UMNt2k
� � � �;
ð50Þ
vðx; y; tÞ ¼ U sinðxtÞ � 4Uab
X1m;n¼1
ð�1Þmþn cosðaMxÞaM
� cosðbNyÞbN
cMN sinðxtÞ � dMN cosðxtÞ � e�t
2k dMN coshUMNt
2k
� þ dMN � 2kxð1� cMNÞ
UMNsinh
UMNt2k
� � � �:
ð51Þ
The shear stresses corresponding to the flow of a Maxwell fluid are obtained from Eqs. (39) and (40) for a = 1. Using (A9)(from Appendix) we obtain the following forms of the shear stresses:
Tension Sxz given by Eq. (52) for x = 2, m = 0.0012, l = 1.48, U = 0.001, a = 0.025, b = 0.02, k = 0.5, and different values of the fractional parameter a.
Fig. 8.
3230 M. Nazar et al. / Commun Nonlinear Sci Numer Simulat 17 (2012) 3219–3234
s1cðx; y; tÞ ¼ Re½T1ðx; y; tÞ� ¼ �16lU
dh
X1m;n¼1
cosðaMxÞ sinðbNyÞbN
eMN cosðxtÞ � fMN sinðxtÞf
þ e�t
2kxeMN þ 2mkMNfMN
xUMNsinh
UMNt2k
� � eMN cosh
UMNt2k
� � ��; ð52Þ
s2cðx; y; tÞ ¼ Re½T2ðx; y; tÞ� ¼ �16lU
dh
X1m;n¼1
cosðbNyÞ sinðaMxÞaM
eMN cosðxtÞ � fMN sinðxtÞf
þ e�t
2kxeMN þ 2mkMNfMN
xUMNsinh
UMNt2k
� � eMN cosh
UMNt2k
� � ��; ð53Þ
s1sðx; y; tÞ ¼ Im½T1ðx; y; tÞ� ¼ �16lU
dh
X1m;n¼1
cosðaMxÞ sinðbNyÞbN
fMN cosðxtÞ þ eMN sinðxtÞf
þ e�t
2kxfMN � 2mkMNeMN
xUMNsinh
UMNt2k
� � fMN cosh
UMNt2k
� � ��; ð54Þ
s2sðx; y; tÞ ¼ Im½T2ðx; y; tÞ� ¼ �16lU
dh
X1m;n¼1
cosðbNyÞ sinðaMxÞaM
fMN cosðxtÞ þ eMN sinðxtÞf
þ e�t
2kxfMN � 2mkMNeMN
xUMNsinh
UMNt2k
� � fMN cosh
UMNt2k
� � ��: ð55Þ
Tension Syz given by Eq. (53) for x = 2, m = 0.0012, l = 1.48, U = 0.001, a = 0.025, b = 0.02, k = 0.5, and different values of the fractional parameter a.
M. Nazar et al. / Commun Nonlinear Sci Numer Simulat 17 (2012) 3219–3234 3231
where
Fig. 9.
emn ¼x2
ðmkmn � kx2Þ2 þx2; f mn ¼
xðmkmn � kx2Þðmkmn � kx2Þ2 þx2
ð56Þ
6. Concluding remarks
Here we established exact solutions for the velocity field and the associated shear stresses corresponding to flows of aMaxwell fluid with fractional derivatives within an oscillating rectangular duct. Both cases of the cosine and sine oscillationsof the duct have been analyzed and the solutions have been determined by means of the Laplace and double finite sine Fou-rier transforms. The solutions corresponding to Maxwell fluids have been determined as particular case. Finally, some phys-ical aspects are revealed by graphical illustrations.
Figs. 1 and 2 are sketched to show the profiles of the velocity field, Eq. (22), for a Maxwell fluid with fractional derivatives,versus x 2 [�0.025,025] and for different values of the spatial coordinate y, fractional coefficient a and time t. From thesefigures, it is obvious to note that the velocity field is an increasing function of spatial variable y, and for large values of timet, the velocity is an increasing function of the fractional parameter a. Consequently, the fractional Maxwell fluid flows slowerin comparison with the arbitrary Maxwell fluid; the velocity field is a decreasing function for increasing relaxation time k.
Figs. 3 and 4 are sketched to show the profiles of the velocity field of a Maxwell fluid with fractional derivatives in the caseof sine oscillations of the duct, Eq. (23). From these figures, one can easily see that the velocity field has the similar behavioras in previous case.
Tension Sxz given by Eq. (54) for x = 2, m = 0.0012, l = 1.48, U = 0.001, a = 0.025, b = 0.02, k = 0.5, and different values of the fractional parameter a.
Fig. 10. Tension Syz given by Eq. (55) for x = 2, m = 0.0012, l = 1.48, U = 0.001, a = 0.025, b = 0.02, k = 0.5, and different values of the fractional parameter a.
3232 M. Nazar et al. / Commun Nonlinear Sci Numer Simulat 17 (2012) 3219–3234
In Figs. 5 and 6, we plotted the absolute values of the velocity field versus t for x = 0.01 m, y = 0 m, for both cosine and sineoscillations of the duct and for small and large values of time t. These diagrams are plotted for three values of the fractionalcoefficient a. It is clear that for small values of the time t, the velocity field is not monotonous function of the fractional coef-ficient a, while for large values of the time t, the velocity field is increasing for increasing a.
In Figs. 7–10, we drew diagrams of the shear stresses Sxz, Syz, versus t, for both cases of the oscillations of the duct and forthree values of fractional coefficient a. From these figures, it clearly results that for small values of time t, the tensions Sxz, Syz
change their monotony with respect to a, while for large values of time t these functions are increasing functions of a.
Acknowledgement
This article is fully supported by Higher Education Commission of Pakistan under the project entitled ‘‘Flow of Rate TypeFluid in Oscillating Rectangular Duct’’.
Appendix A
For a = 1, Eq. (15) becomes
HmnðqÞ ¼kqþ 1
kq2 þ qþ mkmn¼X1k¼0
� mkmn
k
� k q�k þ k�1q�k�1
ðqþ k�1Þkþ1 ; ðA1Þ
with the inverse Laplace transform
hmnðtÞ ¼X1k¼0
� mkmn
k
� k
G1;�k;kþ1 �1k; t
� þ 1
kG1;�k�1;kþ1 �
1k; t
� � �: ðA2Þ
M. Nazar et al. / Commun Nonlinear Sci Numer Simulat 17 (2012) 3219–3234 3233
On the other hand the function Hmn(q) can be written as
HmnðqÞ ¼kðqþ 1
kÞ
k qþ 1k
� �2 �ffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi1�4kmkmn
p2k
� 2" # ¼ qþ 1
2k
� �þ 1
2k
qþ 12k
� �2 � umn2k
� �2 ¼qþ 1
2k
� �qþ 1
2k
� �2 � un2k
� �2 þ1
umn
umn2k
qþ 12k
� �2 � umn2k
� �2 ;
umn ¼ffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi1� 4kmkmn
p; ðA3Þ
with the inverse Laplace transform
hmnðtÞ ¼ coshumn
2kt
� þ 1
umnsinh
umn
2kt
� � �e�
t2k: ðA4Þ
Comparing (A2) and (A4), we obtain that
X1k¼0
� mkmn
k
� k
G1;�k;kþ1 �1k; t
� þ 1
kG1;�k�1;kþ1 �
1k; t
� � �¼ cosh
umn
2kt
� þ 1
umnsinh
umn
2kt
� � �e�
t2k: ðA5Þ
Let us
GmnðqÞ ¼q
ðq�wiÞðkq2 þ qþ mkmnÞ¼ 1
q�wi1k
X1k¼0
� mkmn
k
� k q�k
ðqþ k�1Þkþ1 ; ðA6Þ
with the inverse Laplace transform
gmnðtÞ ¼1k
X1k¼0
� mkmn
k
� k Z t
0eiwðt�sÞG1;�k;kþ1 �
1k; s
� ds: ðA7Þ
On the other hand
GmnðqÞ ¼1
q�wiq
k qþ 12k
� �2 � umn2k
� �2h i ¼ 1
k1
q�wiqþ 1
2k
� �qþ 1
2k
� �2 � umn2k
� �2 �1
umn
umn2k
qþ 12k
� �2 � umn2k
� �2
" #; ðA8Þ
with the inverse Laplace transform
gmnðtÞ ¼1k
Z t
0eiwðt�sÞ cosh
umns2k
� � 1
umnsinh
umns2k
� � �e�
s2kds
¼ 1k
eiwtZ t
0e� iwþ 1
2kð Þs coshumns2k
� ds� 1
kumneiwt
Z t
0e� iwþ 1
2kð Þs sinhumns2k
� ds: ðA9Þ
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